It is a right triangle is the ratio of the length of one leg to the
length of the other leg = x/x =1/1. C.
In a 45-45-90 right triangle, the two acute angles are each 45 degrees, and the right angle is 90 degrees.
The special property of a 45-45-90 triangle is that its two legs are congruent, meaning they have the same length.
Let's denote the length of each leg as "x."
To determine the ratio of the length of one leg to the length of the other leg, we can compare the lengths.
Let's call the length of one leg "a" and the length of the other leg "b."
Since the two legs are congruent, we have a = b = x.
The ratio of the length of one leg to the length of the other leg is a:b = x:x.
Simplifying the ratio, we have a:b = 1:1.
This means that the length of one leg is equal to the length of the other leg in a 45-45-90 right triangle.
To recap:
Both legs have the same length, which is a property unique to this type of triangle.
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100 Points! Algebra question. Photo attached. Find the exact value of the expression. Please show as much work as possible. Thank you!
Answer:
[tex]2-\sqrt{3}[/tex]
Step-by-step explanation:
Find the exact value of the expression, tan(15°).
The method I am about to show you will allow you to solve this problem without any tables or calculators. Although, memorizing the unit circle and trigonometric identities is required.
[tex]\tan(15 \textdegree)\\\\\Longrightarrow \tan(\frac{30 \textdegree}{2} )\\\\\text{Use the half-angle identity:} \ \tan(\frac{A}{2})=\pm \sqrt{\frac{1-\cos(A)}{1+\cos(A)} }=\frac{\sin(A)}{1+\cos(A)} =\frac{1-\cos(A)}{\sin(A)} \\\\\Longrightarrow\frac{1-\cos(30 \textdegree)}{\sin(30 \textdegree)} \\\\\text{From the unit circle:} \ \cos(30 \textdegree)=\frac{\sqrt{3} }{2} \ \text{and} \ \sin(30 \textdegree)=\frac{1}{2}\\[/tex]
[tex]\Longrightarrow \frac{1-\frac{\sqrt{3} }{2}}{\frac{1}{2}}\\\\\Longrightarrow 2(1-\frac{\sqrt{3} }{2})\\\\\therefore \boxed{\boxed{\tan(15 \textdegree)=2-\sqrt{3} }}[/tex]
Thus, the problem is solved.
Answer:
[tex]\tan 15^{\circ} = 2 - \sqrt{3}[/tex]
Step-by-step explanation:
To find the exact value of tan 15°, we can use trigonometric identities and the unit circle.
We know that tan(x) can be expressed as the ratio of sin(x) and cos(x). We can also write 15° as (60° - 45°).
Therefore, tan 15° can be expressed as:
[tex]\tan15^{\circ}=\tan(60^{\circ}-45^{\circ})=\dfrac{\sin(60^{\circ}-45^{\circ})}{\cos(60^{\circ}-45^{\circ})}[/tex]
Now use the trigonometric angle identities to rewrite the ratio in terms of sin 60°, cos 60°, sin 45° and cos 45°.
[tex]\boxed{\begin{minipage}{6.5 cm}\underline{Trigonometric Angle Identities}\\\\$\sin (A - B)=\sin A \cos B - \cos A \sin B$\\\\$\cos (A - B)=\cos A \cos B + \sin A \sin B$\\\end{minipage}}[/tex]
Therefore:
[tex]\begin{aligned}\tan15^{\circ}&=\dfrac{\sin(60^{\circ}-45^{\circ})}{\cos(60^{\circ}-45^{\circ})}\\\\&=\dfrac{\sin60^{\circ}\cos45^{\circ}-\cos60^{\circ}\sin45^{\circ}}{\cos 60^{\circ} \cos 45^{\circ}+ \sin 60^{\circ}\sin 45^{\circ}}\end{aligned}[/tex]
In the unit circle, the cosine of an angle is represented by the x-coordinate of a point on the circle, and the sine of an angle is represented by the y-coordinate of that same point → (x, y) = (cos θ, sin θ). Therefore, we can use the unit circle to identity the values of sin 60°, cos 60°, sin 45° and cos 45°:
[tex]\sin 60^{\circ}=\dfrac{\sqrt{3}}{2}[/tex]
[tex]\cos 60^{\circ}=\dfrac{1}{2}[/tex]
[tex]\sin 45^{\circ}=\dfrac{\sqrt{2}}{2}[/tex]
[tex]\cos 45^{\circ}=\dfrac{\sqrt{2}}{2}[/tex]
Substitute these into the equation and simplify:
[tex]\begin{aligned}\tan15^{\circ}&=\dfrac{\sin(60^{\circ}-45^{\circ})}{\cos(60^{\circ}-45^{\circ})}\\\\&=\dfrac{\sin60^{\circ}\cos45^{\circ}-\cos60^{\circ}\sin45^{\circ}}{\cos 60^{\circ} \cos 45^{\circ}+ \sin 60^{\circ}\sin 45^{\circ}}\\\\&=\dfrac{\dfrac{\sqrt{3}}{2}\cdot \dfrac{\sqrt{2}}{2}-\dfrac{1}{2}\cdot \dfrac{\sqrt{2}}{2}}{\dfrac{1}{2}\cdot \dfrac{\sqrt{2}}{2}+ \dfrac{\sqrt{3}}{2}\cdot \dfrac{\sqrt{2}}{2}}\\\\\end{aligned}[/tex]
[tex]\begin{aligned}&=\dfrac{\dfrac{\sqrt{2}}{2} \left(\dfrac{\sqrt{3}}{2}-\dfrac{1}{2}\right)}{\dfrac{\sqrt{2}}{2} \left(\dfrac{1}{2}+ \dfrac{\sqrt{3}}{2}\right)}\\\\&=\dfrac{\dfrac{\sqrt{3}}{2}-\dfrac{1}{2}}{ \dfrac{1}{2}+ \dfrac{\sqrt{3}}{2}}\\\\&=\dfrac{\dfrac{\sqrt{3}-1}{2}}{\dfrac{1+\sqrt{3}}{2}}\\\\&=\dfrac{\sqrt{3}-1}{1+\sqrt{3}}\end{aligned}[/tex]
Simplify further by multiplying the numerator and denominator by the conjugate of the denominator:
[tex]\begin{aligned}&=\dfrac{\sqrt{3}-1}{1+\sqrt{3}}\cdot \dfrac{1-\sqrt{3}}{1-\sqrt{3}}\\\\&=\dfrac{(\sqrt{3}-1)(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\&=\dfrac{\sqrt{3}-3-1+\sqrt{3}}{1-\sqrt{3}+\sqrt{3}-3}\\\\&=\dfrac{2\sqrt{3}-4}{-2}\\\\&=-\sqrt{3}+2\\\\&=2-\sqrt{3}\end{aligned}[/tex]
Therefore, the exact value of tan 15° is (2 - √3).
The diameter of a circle is 14m. Find its area to the nearest whole number
The area of the circle is A = 154 m²
Given data ,
Let the diameter of the circle be d = 14 m
So , the radius of the circle is r = d/2
r = 7 m
Now , area of circle is A = πr²
On simplifying , we get
A = ( 3.14 ) ( 7 )²
A = 154 m²
Hence , the area of circle is A = 154 m²
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How do I find the reference angle for the following?
Answer: 1.4 pi, and pi/180
Step-by-step explanation:
b)
this is a negative angle; It is also less than 0.5pi, (pi/2, which is the border of the first quadrant). therefore the reference angle is just the positive version:
so 1.4pi is the reference angle
c)
pi/180 is already in the first quadrant. so pi/180 would be the reference angle.
This year, there are seven freshmen, ten sophomores, nine juniors, and seven seniors are eligible to
be on a committee.
a) In how many ways can a dance committee of 8 students be chosen?
b) In how many ways can a dance committee be chosen if it is to consist of 2 freshmen, 2
sophomores, 2 juniors, and 2 seniors.
c) In how many ways can a dance committee be chosen if it is to consist of 4 juniors and 4 seniors.
d) Determine the probability of selecting a committee consisting of 2 freshmen, 2 sophomores, 2
juniors, and 2 seniors. Write your answer in decimal form, rounded to the nearest thousandth.
e) Determine the probability of selecting a committee consisting of 4 juniors and 4 senions. Write
your answer in decimal form, rounded to the nearest thousandth.
a) there are 8,535,316 ways to choose a dance committee of 8 students. b) there are 497,070 ways to choose a dance committee consisting of 2 freshmen, 2 sophomores, 2 juniors, and 2 seniors. c) there are 4,410 ways to choose a dance committee consisting of 4 juniors and 4 seniors.
Answers to the aforementioned questionsa) To determine the number of ways a dance committee of 8 students can be chosen, we need to consider the total number of eligible students and choose a group of 8 from them.
Total number of eligible students = 7 freshmen + 10 sophomores + 9 juniors + 7 seniors = 33 students
The number of ways to choose a committee of 8 students from a pool of 33 is given by the combination formula:
C(33, 8) = 33! / (8!(33-8)!) = 8,535,316
Therefore, there are 8,535,316 ways to choose a dance committee of 8 students.
b) To choose a dance committee consisting of 2 freshmen, 2 sophomores, 2 juniors, and 2 seniors,
Number of ways to choose 2 freshmen from 7 freshmen = C(7, 2) = 21
Number of ways to choose 2 sophomores from 10 sophomores = C(10, 2) = 45
Number of ways to choose 2 juniors from 9 juniors = C(9, 2) = 36
Number of ways to choose 2 seniors from 7 seniors = C(7, 2) = 21
Total number of ways to choose the dance committee = 21 * 45 * 36 * 21 = 497,070
Therefore, there are 497,070 ways to choose a dance committee consisting of 2 freshmen, 2 sophomores, 2 juniors, and 2 seniors.
c) To choose a dance committee consisting of 4 juniors and 4 seniors,
Number of ways to choose 4 juniors from 9 juniors = C(9, 4) = 126
Number of ways to choose 4 seniors from 7 seniors = C(7, 4) = 35
Total number of ways to choose the dance committee = 126 * 35 = 4,410
Therefore, there are 4,410 ways to choose a dance committee consisting of 4 juniors and 4 seniors.
d) The probability of selecting a committee consisting of 2 freshmen, 2 sophomores, 2 juniors, and 2 seniors
Favorable outcomes = 497,070 (from part b)
Total possible outcomes = 8,535,316 (from part a)
Probability = Favorable outcomes / Total possible outcomes
= 497,070 / 8,535,316
≈ 0.058 (rounded to the nearest thousandth)
Therefore, the probability of selecting a committee consisting of 2 freshmen, 2 sophomores, 2 juniors, and 2 seniors is approximately 0.058.
e) The probability of selecting a committee consisting of 4 juniors and 4 seniors
Favorable outcomes = 4,410 (from part c)
Total possible outcomes = 8,535,316
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find the average cost function C for the given total cost function
C(x) = 2,100 + 4x − 0.0003x2
The average cost function for the given total cost function is AC(x) = 2,100/x + 4 - 0.0003x.
To find the average cost function C, we need to divide the total cost function C(x) by the quantity of output produced, which is represented by x.
The formula for average cost (AC) is:
AC(x) = C(x) / x
Plugging in the given values, we have:
AC(x) = (2,100 + 4x - 0.0003x2) / x
Simplifying this expression, we get:
AC(x) = 2,100/x + 4 - 0.0003x
Therefore, the average cost function C(x) is:
C(x) = 2,100/x + 4x - 0.0003x2
This function represents the average cost per unit of output, taking into account fixed costs (2,100) and variable costs (4x - 0.0003x) that increase as output increases.
It's important to note that the cost function C(x) is quadratic, which means that the average cost function C(x) will have a U-shaped curve.
This is because initially, as output increases, fixed costs are spread out over a larger quantity of output, leading to a decrease in average cost.
However, at a certain point, the increasing variable costs will outweigh the decreasing fixed costs, causing average cost to increase again.
Overall, knowing the average cost function can be useful for businesses to make decisions about pricing, production levels, and cost management strategies.
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Find the solutions of the quadratic equation x2 + 7x + 10 = 0.
OA) X=-7, -3
B) x=2,5
OC) x = 7,3
OD) x = -2, -5
Answer:
OD) x = -2, -5
Step-by-step explanation:
To solve the quadratic equation x^2 + 7x + 10 = 0, we can use factoring or the quadratic formula.
Using factoring:
We need to find two numbers whose sum is 7 and whose product is 10. These numbers are 2 and 5. So, we can write x^2 + 7x + 10 = 0 as (x + 2)(x + 5) = 0.
Setting each factor to 0, we get x + 2 = 0 or x + 5 = 0. Solving for x, we get x = -2 or x = -5.
Using the quadratic formula:
The quadratic formula is x = (-b ± sqrt(b^2 - 4ac)) / 2a, where a, b, and c are the coefficients of the quadratic equation. In this case, a = 1, b = 7, and c = 10.
Substituting these values into the formula, we get x = (-7 ± sqrt(7^2 - 4(1)(10))) / 2(1)
Simplifying, we get x = (-7 ± sqrt(9)) / 2
Therefore, x = (-7 + 3) / 2 or x = (-7 - 3) / 2
Solving for x, we get x = -2 or x = -5.
Thus, the solutions of the quadratic equation x^2 + 7x + 10 = 0 are x = -2 or x = -5.
Therefore, the answer is (OD) x = -2, -5.
The coefficient of xyk in the expansion of (x + y)" equals
(H).
OA. True
B. False
The statement that the [tex]x^ky^{n-k}[/tex] in the expansion of ( x + y )ⁿ equals [tex]\binom{k}{n}[/tex] is False.
Why is this coefficient statement false ?The coefficient of the term [tex]x^ky^{n-k}[/tex] in the expansion of ( x + y )ⁿ is given by the binomial coefficient C ( n, k ), not C ( k, n ) . It should therefore be written as C ( n, k ), not C ( k, n ).
Stated alternatively, the quantity in question is the combination of k items selected from a pool of n items, rather than the inverse arrangement. As a result, the accurate binomial coefficient has been determined such that:
C ( n, k ) = n! / [ k! ( n - k ) ! ], where " ! " denotes the factorial function.
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The question is:
The coefficient of [tex]x^ky^{n-k}[/tex] in the expansion of ( x + y )ⁿ equals [tex]\binom{k}{n}[/tex]
True
False.
Find the length of side a to the nearest tenth.
Answer: 0.71
Step-by-step explanation:
[tex]a^2+b^2=c^2\\a=b\\so\\2a^2=c^2\\c=1 here\\2a^2=1^2\\a=\sqrt{1/2} \\a=0.71[/tex]
Measure the length of this segment in centimeters.
a line segment over a ruler
0.62 cm
8.3 cm
6.2 cm
0.83 cm
To measure the length of the segment, place a ruler measured in centimeters on the surface and record the length of choice.
How to determine a line segmentIf you want to determine any line segment, use a ruler that is calibrated in centimeters (as is the case in the above), inches, or meters. Place the ruler on the paper or drawing platform and draw a line that matches the corresponding figure.
If the measure of the line segment is 8.3 cm then trace that length on the surface. To bisect the line segment, draw a vertical line across the horizontal one and divide the opposite sides by 2.
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Can someone help me with this? Use f and g to preform the following operations and match them to correct answer
The operations between two functions:
Case 1: f(x) + g(x) = 2 - x - x²
Case 2: g(x) - f(x) = x² - x
Case 3: g(x) · f(x) = (1 - x) · (1 - x²) = 1 - x - x² + x³
Case 4: f(x) - g(x) = x - x²
How to perform operations between functions
In this problem we need to perform operations between two functions, one operator for each case. There are three operations used in this problem:
Addition
(f + g) (x) = f(x) + g(x)
Subtraction
(f - g) (x) = f(x) - g(x)
Multiplication
(f · g) (x) = f(x) · g(x)
If we know that f(x) = 1 - x² and g(x) = 1 - x, then the operations between functions are:
Case 1
f(x) + g(x) = 2 - x - x²
Case 2
g(x) - f(x) = x² - x
Case 3
g(x) · f(x) = (1 - x) · (1 - x²) = 1 - x - x² + x³
Case 4
f(x) - g(x) = x - x²
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help i need to pass this edmentum
Answer:
Pick c, 2/27
Step-by-step explanation:
Bag #1 has 4 + 6 + 3 + 5 = 18 total tiles.
4 are black.
So prob (black) from bag 1 = 4/18.
Bag #2 has 3 + 2 + 3 + 1 = 9 total tiles.
3 are black.
So prob(black) from bag 2 = 3/9.
Multiply those 2 independent probabilities together.
(4/18) x (3/9) = (2/27)
what is the lowest number that must be added to 2000 so that the sum is divisible exactly by 10 12 16 and 18
In the diagram below of circle O, tangent EC is drawn to diameter AC. Chord BC is parallel to the secant ADE and the chord AB is drawn.
The location of the angles and the parallel lines [tex]\overline{BE}[/tex] and [tex]\overline{ADE}[/tex] indicates;
(a) ΔABC ~ ΔECA by Angle Angle similarity
(b) The ratio of corresponding sides in similar triangles indicates; BC/CA = AB/EC
What are parallel lines?Parallel lines are lines that continues indefinitely, maintaining the same distance between each other.
9. The specified dimensions of the geometric figures are;
[tex]\overline{EC}[/tex] is a tangent to the circle O
[tex]\overline{AC}[/tex] is a diameter of the circle
[tex]\overline{BC}[/tex] is parallel to secant [tex]\overline{ADE}[/tex]
Therefore, the angle ∠ABC is a right angle (Angle at the circumference formed by the diameter of a circle
∠ACE = 90° (The tangent is perpendicular to the radius of a circle)
∠ABC ≅ ∠ACE (Definition of congruent angles)
m∠ABC = m∠ACE = 90° (Definition of congruence)
∠BCA ≅ ∠EAC (Alternate interior angles)
ΔABC ~ ΔECA by AA congruence rule(b) The similarity between the triangles and the ratio of the corresponding sides indicates;
BC/CA = AC/AE
Therefore
Segment BC in triangle ΔABC corresponds to segment CA in triangle ΔECA
Segment CA in triangle ΔABC corresponds to segment AE in triangle ΔECA
Which indicates;
Segment AB in triangle ΔABC corresponds to segment EC in triangle ΔECA
The ratio of the corresponding sides is therefore;
BC/CA = AB/EC
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Extra Credit:
18
60°
V =
Hello guys I need help
Thank you
Answer:
[tex]\bold{V=7048.48 ft^3}[/tex]
Step-by-step explanation:
Solution Given:
radius(r)=12
In right-angled triangle
Hypotenuse = 18
base angle =60°
Note:
In a right-angled triangle, we can use the trigonometric ratios sine, cosine, and tangent to relate the angles and sides of the triangle.
Here are the trigonometric ratios for a right-angled triangle:
Sine (sin): The sine of an angle is the ratio of the length of the side opposite the angle to the length of the hypotenuse.
[tex]\boxed{\bold{sin(A) =\frac{ opposite}{hypotenuse}}}[/tex]
Cosine (cos): The cosine of an angle is the ratio of the length of the side adjacent to the angle to the length of the hypotenuse.
[tex]\boxed{\bold{cos(A) = \frac{adjacent}{hypotenuse}}}[/tex]
Tangent (tan): The tangent of an angle is the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle.
[tex]\boxed{\bold{tan(A) =\frac{ opposite}{adjacent}}}[/tex]
Now for the question:
Over here the relation between opposite or height and hypotenuse is given by Sine, So using this formula:
[tex]\bold{sin(60^0) =\frac{ opposite\:or\ height}{18}}[/tex]
doing criss-cross multiplication:
Sin 60°*18=opposite or height
[tex]\frac{\sqrt{3}}{2}*18[/tex] =opposite or height
opposite or height(h)=[tex]9\sqrt{3}[/tex]
Again,
We have
[tex]\boxed{\bold{Volume\:of\:cylinder= \pi * r^2 * h}}[/tex]
where:
π (pi) is a mathematical constant approximately equal to 3.14
r is the radius of the base of the cylinder
h is the height of the cylinder
Now Substituting value
[tex]Volume = \pi * r^2 * h\\Volume=3.14*12^2*9\sqrt{3}\\Volume=\bold{7048.48 ft^3}[/tex]
TIME SENSITIVE, 50 POINTS, MULTIPLE CHOICE
Approximate the solution to the equation above using three iterations of successive approximation. Use the graph below as a starting point.
Using iterations, the solution to the above equation 6⁽⁻ˣ⁾ +4 = 3x -1 is Option C = 27/16. See the graph attached.
How is this so?The question requires you to state the solution of the equation. On the graph, this would be the point of intersection of both curves.
To solve for x, we'll continue using an iterative method called the fixed-point iteration ..
Rewrite the equation in the form x = g(x):
g(x) = (6⁽⁻ˣ⁾ + 5) / 3
Start with an initial guess, let's say x0 = 1.
Iterate using the formula x(n+1) = g( x(n )) until convergence, where n is the iteration number:
x (1) = g(x 0)
x (2 ) = g (x(1))
x( 3) = g(x (2))
Let's perform three iterations to approximate the solution
Iteration 1
x (1) = g( x0) = (6⁻¹ + 5) / 3
= (1/ 6 +5) / 3
= (1 /6 + 30/6) / 3
= 31/18
≈ 1.7222
Second iteration is
x(2) = g(x (1)) = ([tex]6^{1.72222}[/tex] + 5) / 3 ≈ 1.6806
Iteration 3:
x(3) = g(x (2)) = ([tex]6^-1.6806[/tex] + 5) / 3 ≈ 1.6875
After three iterations, the approximate solution to the equation 6⁽⁻ˣ⁾ + 4 = 3x - 1 is x ≈ 1.6875, which can also be expressed as the fraction 27/16.
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Please help with this 6-7
Expand each logarithm.
1. Log 2^8XYZ
2. Log 9^8lx/y
3. Log 5^5x^3
4. Log 6 3√x
The logarithmic expressions when expanded are
1. [tex]\log2^{8yz}[/tex] = 8xyz log(2)
2. [tex]\log9^{81x/y}[/tex] = 81x/y log(9)
3. [tex]\log5^{x^3}[/tex] = x³ log(5)
4. [tex]\log6^{\sqrt[3]{x}}[/tex] = ∛x log(6)
How to expand the logarithmic expressionFrom the question, we have the following parameters that can be used in our computation:
The logarithmic expressions
The logarithmic expressions can be expanded using power rule of logarithm which states that
logaᵇ = b log(a)
Using the above as a guide, we have the following:
[tex]\log2^{8yz}[/tex] = 8xyz log(2)
[tex]\log9^{81x/y}[/tex] = 81x/y log(9)
[tex]\log5^{x^3}[/tex] = x³ log(5)
[tex]\log6^{\sqrt[3]{x}}[/tex] = ∛x log(6)
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Please help, thanks!
Find the volume. Round your answer to the nearest tenth.
4 yd
3 yd
3 yd
Step-by-step explanation:
Volume of the square pyramid = 1/3 * base area * height
= 1/3 (3 x 3) * 4 = 12 yd^3
HELPPPP I NEED HELP PLEASE IT'S MATH
Answer:
b. 5, 11, 6
Step-by-step explanation:
Let the sides of a triangle be a, b, and c, where a < b < c. Then, we know that a + b > c. If we use this identity to solve this problem, then we can find that answer choice b does not satisfy it. Thus, b does NOT have the lengths of a triangle.
find the equation of the line with gradient m that passes through the point (x1,y1) when A) m=-4 and (x1,y1=(-2, -3 ) b) m= 3 and (x1, y1 )=(-2,1) C) m= 1/2 and (x1, Y1) = (-4 , 10) pls pls help... i need it for today pls
The equation of the line is y = -4x - 11.
The equation of the line is y = 3x + 7.
The equation of the line is y = (1/2)x + 12.
We have,
A)
The equation of the line with gradient m = -4 that passes through the point (-2,-3) is:
y - y1 = m(x - x1)
y - (-3) = -4(x - (-2))
y + 3 = -4(x + 2)
y + 3 = -4x - 8
y = -4x - 11
B)
The equation of the line with gradient m=3 that passes through the point (-2,1) is:
y - y1 = m(x - x1)
y - 1 = 3(x - (-2))
y - 1 = 3(x + 2)
y = 3x + 7
C)
The equation of the line with gradient m=1/2 that passes through the point (-4,10) is:
y - y1 = m(x - x1)
y - 10 = (1/2)(x - (-4))
y - 10 = (1/2)(x + 4)
y = (1/2)x + 12
Therefore,
The equation of the line is y = -4x - 11.
The equation of the line is y = 3x + 7.
The equation of the line is y = (1/2)x + 12.
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what is that square root of 107.6
The square root of 107.6 is approximately 10.372
To find the square root of 107.6, we can use a calculator or use the following procedure:
Make an initial estimate:
We know that the square root of 100 is 10, so we can estimate that the square root of 107.6 is slightly more than 10.
Use the formula: We can use the following formula to improve our estimate:
x(n+1) = (x(n) + a/x(n))/2
where x(n) is the nth estimate of the square root of a, and a is the number we want to find the square root of.
Apply the formula: Using the estimate of 10, we get:
x(1) = (10 + 107.6/10)/2 = 10.38
Now we use this new estimate to get a better one:
x(2) = (10.38 + 107.6/10.38)/2 = 10.371
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Which statement correctly compares the function shown on this graph with the function y=-x+4? C 15 10 10 KE IN Tak LII 467 bottlen LI A. The function shown on the graph has the same rate of change, but a higher starting point. B. The function shown on the graph has a greater rate of change, but the same starting point. C. The function shown on the graph has a smaller rate of change, but the same starting point. D. The function shown on the graph has the same rate of change, but a lower starting point.
It can be said that the statement that correctly compares the function shown on this graph with the function y =4x + 2 is
'The expresion indicated on the graph has a smaller rate of change, but a higher starting point.' (Option A)
How is this so?We have the expression - y = mx + c, where m is the slope and
c is known as the y-intercept"
For given question,
We have been given a expresion which states: y = 4x + 2
This function represents a line.
Looking at the above function side by side with slop-intercept form of the line.
We can state that we have slope of the line = 4 and y - intercept = 2
Note that the pace of change of the line is given by the slope.
This means that the required pace of change of function y = 4x + 2 will be 4.
A beginning point of a function is the commencement value in a linear expression .
The beginning point of above function f(x) is 2.
The graph of the line passes via points (-1, 1) and (0, 4)
So using slope formula,
m1 = (4-1)/(0-(-1))
m1 = 3
This means that the pace of change of function shown on the graph is 3.
This means, the pace of change of function shown on the graph is smaller than the pace of change of function y = 4x + 2
The expression of the function shown on the graph would be y = 3x + 4
The point of incetion of the function shown on the graph is 4.
This signifies that the starting point of the graphed function is higher than the starting point of the function y = 4x + 2.
As a result, the accurate statement comparing the function displayed on this graph to the function y=4x + 2 is 'The function shown on the graph has a lesser rate of change, but a higher beginning point.'
The correct answer is option (A)
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Please help asap!!! I will give points !!!
Of all registered automobiles in Colorado, 8% fail the emissions test. Twelve automobiles are selected at random to undergo an emission test. Find the probability that more than two of them fail the test.
The probability that more than two out of the twelve automobiles fail the test is approximately 29. 35%.
How to find the probability ?The probability of more than two automobiles failing the emissions test would be:
= 1 - Probability that none fails - Probability that 1 fails - Probability that 2 fail
The probabilities are :
P (0 fail) = C (12, 0) x ( 0.08 ⁰) x (0.92 ¹² )
= 1 x 1 x 0. 2785
= 0. 2785
P(1 fail) = C (12, 1) x (0.08 ¹ ) x ( 0.92 ¹¹ )
= 12 x 0. 08 x 0. 3016
= 0. 2899
P (2 fail) = C (12, 2) x (0.08 ² ) x ( 0.92 ¹⁰)
= 66 x 0. 0064 x 0.3259
= 0.1381
The probability that more than two fail is:
= 1 - (0.2785 + 0.2899 + 0.1381)
= 0.2935
= 29. 35 %
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HELPPP!! Business Math!
What is the yield on a corporate bond with a $1000 face value purchased at a discount price of $850, if it pays 6% fixed interest for the duration of the bond?yield = [?] %
Give your answer as a percent rounded to the nearest hundredth.
Based on the calculations, the yield on this corporate bond is found as 9.14%
Given as For a $1000 face value purchased at a discount price of $850, if it pays 6% fixed interest for the duration of the bond is the yield on a corporate bond mathematically given as
Yield = 6.5%
Interest paid = value of bond x Interest rate
Interest paid = 1000 * 6%
Interest paid = 60
Therefore
Yield = Interest paid / Price paid
Yield = (60 / 850)x 100
Yield = 9.14%
In conclusion, the yield on a corporate bond is
Yield = 9.14%
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Answer: 7.06
Step-by-step explanation: accelus
Heres a question I've been trying to solve for a while. Not sure what to do, hopefully someone here can make something out of it?
19. Beverly is serving hamburgers and hot dogs at her cookout. Hamburger meat costs $3 per pound, and hot dogs cost $2 per pound.
She wants to spend no more than $30.
a. Write an inequality to describe the situation.
x= hamburger y= hot dogs
____x ______ ____y ____ 30 (3/2) (+/-) (3/2) (≤ / ≥)
An inequality to describe the situation is 3x + 2y ≤ 30.
We are given that;
Cost of hamburger meat= $3
Cost of hot dog=$2
Now,
The total cost of hamburger meat and hot dogs is no more than $30. The variable x represents the number of pounds of hamburger meat, and the variable y represents the number of pounds of hot dogs. The coefficient 3 is the cost per pound of hamburger meat, and the coefficient 2 is the cost per pound of hot dogs.
Therefore, by the inequality the answer will be 3x + 2y ≤ 30
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Aplica la propiedad conmutativa y calcula M +N:
29 x M=31 x (N + 2)
Using the commutative property we can get an equation that depends on the sum of the two variables:
(M + N) = (62 - 2N)/29
How to apply the commutative property?The commutative property of the multiplication and sum means that we can permutate the variables:
A*B = B*A
A + B = B + A
In this case, we have the equation:
29*M = 31*(N + 2)
We can distribute the product to get:
29*M = 31*N + 31*2
29*M = 31*N + 62
Now we want to find the value of the sum of the variables, because we have only one equation we can't do that (two variables means that we need two equations) But we can write an expression that depends on the sum of the two variables.
29M + 31N = 62
And now use the commutative property to write:
(29M + 29N) + 2N = 62
(M + N) = (62 - 2N)/29
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P(Pink, Blue)
Enter your answer as a fraction in simplest terms in the box.
The probability that the selection will be P(pink, blue) is: 9/64
What is the probability of the spinner?The total number of sections on the spinner are 8 sections.
Now, out of the 8 sections, the divisions are as follows:
Yellow sections = 2
Blue sections = 3
Pink sections = 3
Thus:
P(first is pink) = 3/8
P(second is blue) = 3/8
Thus:
P(pink, blue) = (3/8) * (3/8)
= 9/64
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Find domain and range thank you for the help have a great afternoon
Step-by-step explanation:
Domain : (-5,4]
Range [-2,0)