In a city with an air-pollution problem, a bus has no combustion engine. It runs on energy drawn from a large, rapidly rotating flywheel under the floor of the bus. The flywheel is spun up to its maximum rotation rate of 4000 rev/min by an electric motor at the bus terminal. Every time the bus speeds up, the flywheel slows down slightly. The bus is equipped with regenerative braking so that the flywheel can speed up when the bus slows down. The flywheel is a uniform solid cylinder with mass 1600 kg and radius 0.650 m. The bus body does work against air resistance and rolling resistance at the average rate of 18.0 hp as it travels with an average speed of 40 km/h. How far can the bus travel before the flywheel has to be spun up to speed again

Answer:

i҈ d҈o҈n҈t҈ k҈n҈o҈w҈ w҈h҈a҈t҈ y҈o҈u҈r҈ s҈a҈y҈i҈n҈v҈ b҈c҈h҈

Answer:

[tex]m^{3}kg^{-1} s^{-2}[/tex]

Explanation:

Answer:

D

Explanation:

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects.

Answer:

Explanation:

There are countless household appliances in every single house. One appliance with a low power rating would be a ceiling fan. On average ceiling fans consume roughly 60w and are found in the majority of houses. On the other side of the spectrum, we have a high power-rating appliance such as a microwave. Microwaves use anywhere between 1000w to 1800w of power in order to function correctly. This is very large power consumption and one of the highest power ratings found for appliances in a household.

Answer:

Graph C

Explanation:

With the same force and more mass, the position in time will still be parabolic

i.e.  x = ½at², but the rate of acceleration will be lower so the position curve will be broader.

Answer:

123.2newtons

Explanation:

weight =mass × gravity

w= m×g

gravitational pull is approximately 10N/Kg

w= 12.32kg×10n/kg

=123.2newtons or 12.3N

the answer is the first one

Answer:

the answer is B from negative pole to positive pole

Answer:

v = 0.375 m/s

Explanation:

Given that,

The wavelength of a wave is 0.75 m/cycle

The period of a wave is 2s/cycle

We need to find the speed of the wave. We know that,

[tex]v=\dfrac{d}{t}[/tex]

Substitute all the values,

[tex]v=\dfrac{0.75}{2}\\\\v=0.375\ m/s[/tex]

So, the speed of the wave is equal to 0.375 m/s.

Answer:

An unconformity shows where some rock layers have been lost because of erosion. To date rock layers, geologists first give a relative age to a layer of rock at one location and then give the same age to matching layers at other locations. Certain fossils, called index fossils, help geologists match rock layers.

Explanation:

Answer:

The limitations of sending information using electromagnetic waves is that when the electromagnetic waves move outward in all directions, wave transmitters need to be focused to transmit their signals to a single specified location.

Answer:

can y

Explanation:

jj

The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.

The equation for the settling velocity of a particle:

V_s = (2/9) * (ρ_p - ρ_w) * g * r^2 / η

where V_s is the settling velocity, ρ_p is the particle density, ρ_w is the water density, g is the acceleration due to gravity, r is the particle radius, and η is the water viscosity.

1. We can rearrange the equation to solve for the particle radius:

r = [9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)

We want to find the particle diameter, which is twice the radius, so we can substitute 2r for d in the following equation:

d = 2r = 2[9ηV_s / (2(ρ_p - ρ_w)g)]^(1/2)

To remove the smallest particles, we want to use the smallest settling velocity possible, which corresponds to a particle just barely settling to the bottom of the clarifier. Therefore, we can set V_s equal to the minimum settling velocity required for particles to be removed:

V_s = Q / (A * X)

where Q is the flow rate (25 MGD), A is the surface area of one clarifier (πr^2), and X is the overflow rate, which is the flow rate per unit area of the clarifier. A typical overflow rate for a sedimentation basin is 600-1200 gallons per day per square foot (gpd/ft^2), or 2.5-5 m^3/day/m^2. We will use the lower end of this range, 2.5 m^3/day/m^2.

Substituting in the values for Q, A, and X, we get:

V_s = (25 MGD) / (π(8 m)^2 * 2.5 m^3/day/m^2) = 0.00159 m/s

Now we can substitute the values for η, ρ_p, ρ_w, g, and V_s into the equation for the particle diameter:

d = 2[9(1 g/(m*s))(0.00159 m/s) / (2(1200 kg/m^3 - 998.2 kg/m^3)(9.81 m/s^2))]^(1/2) = 0.0257 mm

So, the smallest particles that can be removed by these clarifiers have a diameter of approximately 0.0257 mm.

2. To find the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1, we can use the same overflow rate and flow rate as before, and we can assume a depth of 3 m. The surface area of one clarifier must still be the same as before, so we can use the equation for the surface area of a rectangle:

A = L * W

where L is the length and W is the width.

Substituting in the values for Q, X, and A, we get:

W = (25 MGD) / (5 * 24 hr/day * 60 min/hr * 60 s/min * 2.5 m^3/day/m^2 * 5 * L)

Simplifying, we get:

W = 0.023 L

So, the minimum width of a rectangular clarifier with a length-to-width ratio of 5:1 is 0.023 times the length.

Therefore, The smallest particles that can be removed by these clarifiers have a diameter of 0.0257 mm, and a rectangular clarifier's minimum width is 0.023 times the length when the length-to-width ratio is 5:1.

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Answer:

C. Remains of living things

Explanation:

They are made up of dead animals or plants. Coal, Oil, and Natural Gas are the three types of fossil fuels and all of them come from dead organisms. Even the name Fossil Fuels, sounds like a name for something like this.

Hope this Helps ʕ•ᴥ•ʔ

Answer:

C

Explanation:

took the test

Answer:

[tex]22.84\ \text{N}[/tex]

Explanation:

[tex]\rho[/tex] = Density = [tex]7800\ \text{kg/m}^3[/tex]

h = Length of rod = 95 cm

d = Diameter of rod = 2 cm

r = Radius = [tex]\dfrac{d}{2}=1\ \text{cm}[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

V = Volume of rod = [tex]\pi r^2h[/tex]

Mass is given by

[tex]m=V\rho[/tex]

Weight is given by

[tex]w=mg=V\rho g\\\Rightarrow w=\pi r^2h\rho g\\\Rightarrow w=\pi\times (1\times 10^{-2})^2\times (95\times 10^{-2})\times 7800\times 9.81\\\Rightarrow w=22.84\ \text{N}[/tex]

The weight of the rod is [tex]22.84\ \text{N}[/tex].

Answer:

6.726 m/s

Explanation:

Given that

Applied force, F = 870 N

Distance moves by the force, d = 1.3 cm = 0.013 m

Mass of the hand, m = 0.50 kg

From the given values, first thing is to find the work done by the force. Work done is given as

W = fd.

W = 870 * 0.013

W = 11.31 J

To find the velocity, next we use the formula for finding Kinetic Energy

K.E = 1/2mv²

Where K.E = 11.31

11.31 = 1/2 * 0.5 * v²

22.62 = 0.5v²

v² = 45.24

v = √45.24

v = 6.726 m/s

To break the board with a blow from the hand the speed of the hand will be [tex]v=6.726\ \frac{m}{s}[/tex]

Speed is defined as the distance traveled by any object with respect to the time.

Now it is given that

Applied force, F = 870 N

Distance moves by the force, d = 1.3 cm = 0.013 m

Mass of the hand, m = 0.50 kg

From the given values, first thing is to find the work done by the force. Work done is given as

[tex]W=F\times d[/tex]

[tex]W=870\times 0.013[/tex]

W = 11.31 J

To find the velocity, next we use the formula for finding Kinetic Energy

[tex]KE=\dfrac{1}{2}mv^2[/tex]

Where K.E = 11.31

[tex]11.31=\frac{1}2}\times 0.5\times v^2[/tex]

[tex]0.5v^2=22.62[/tex]

[tex]v^2=45.24[/tex]

[tex]v=6.726\ \ \frac{m}{s}[/tex]

Hence to break the board with a blow from the hand the speed of the hand will be [tex]v=6.726\ \frac{m}{s}[/tex]

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Answer:

2.8s

Explanation:

=>a = v-u/t

=> t = v - u / t

= 28-0 / 10

= 2.8 s

It needs fuse of size 3A to be operated

Answer: 10 A

Explanation: The 3a and 5 a will blow immediately which would not allow you to use the coffee machine

The 13 a is too high and might lead to damage to the coffee machine or a fire being started

10 A is perfect because its low enough that if their was a power surge it would be blown without damaging anything else and it is high enough to let the coffee machine work without any trouble

Answer;

gram

Explanation

Answer:

[tex]3 \times 10 {}^6[/tex]

Answer:

isobaric

Explanation:

According to the attached figure, the process would be isobaric as the gas would be expanded at the time when it maintains the constant pressure

The ideal gas law derives

PV = nRT

As the flame is there at the bottom side so atoms or molecules of gas would get heat up slowly also their temperature would be increased. Thus in the case when piston would not be permitted to move so the pressure would rise having maintaining the constant volume and after this the process could be isochronic but in the given case, the piston would be permitted to move slowly upward so that there is a rise in the volume. However, the gas particles would be adjust themselves in order to maintain constant pressure so the given process represent isobaric  

Answer:

Part 1:

Option B is correct (It will remain unchanged).

Part 2:

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Option E is correct (It will be half as fast/long.)

Part 4:

Option C is correct (It will increase by a factor of √ 2.)

Explanation:

Formula we are going to use:

V=f*λ

Where:

V is the speed of Sound

f is the frequency of wave

λ is the wavelength.

The speed of wave , tension and linear density have following relation:

[tex]V=\sqrt{F/\rho}[/tex]

Where:

V is the speed of Sound (Initial)

F is the tension in string (Initial)

[tex]\rho[/tex] is the linear density of string (Constant)

Terms:

V' is the new speed

f' is the new frequency

λ' is the wavelength

Solution:

Part 1:

From [tex]V=\sqrt{F/\rho}[/tex]:

Speed of Sound is independent of the frequency of shaking so speed well remain unchanged.

Option B is correct (It will remain unchanged)

Part 2:

If F'=2F then

[tex]V=\sqrt{F/\rho}[/tex]

[tex]V'=\sqrt{F'/\rho}\\V'=\sqrt{2F/\rho}\\V'= \sqrt{2} * \sqrt{F/\rho}\\V'=\sqrt{2}V[/tex]

Option C is correct (It will increase by a factor of √ 2)

Part 3:

Formula we are going to use:

V=f*λ

Given f'=2f,

Even though frequency is doubled we will keep velocities same. V=V' in order to find the changing wavelength.

V'=f'*λ'

f*λ=f'*λ'

f*λ=2f*λ'

Solving above Equation:

λ'=λ/2

Option E is correct (It will be half as fast/long.)

Part 4:

T'=2T means [tex]V'=\sqrt{2}V[/tex] (From Part 1)

f'=f

Now:

V'=f'*λ'

[tex]\sqrt{2}f*\lambda=f'*\lambda '\\\sqrt{2}f*\lambda=f*\lambda '\\ \lambda '=\sqrt{2}*\lambda[/tex]

Option C is correct (It will increase by a factor of √ 2.)

Answer:

Hello There!!

Explanation:

The answer is=>C. It changes the activation energy required for the reaction.

hope this helps,have a great day!!

~Pinky~

The true statement for a catalyst used in a reaction is that it makes a reaction faster by adding energy. The correct option is D.

A catalyst is a substance that increases the chemical reaction rate without undergoing any permanent chemical change in itself. It makes the reaction faster.

The correct option is D.

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Answer:

D

Explanation:

Answer:

d = 0.343 m

Explanation:

Given that,

The speed of a longitudinal wave, v = 343 m/s

Your ear is capable of differentiating sounds that arrive at the ear just 1.00 milliseconds apart.

We need to find the minimum distance between two speakers that produce sounds that arrive at noticeably different times.

Let the distance be d. So,

[tex]d=v\times t\\\\=343\times 10^{-3}\\\\=0.343\ m[/tex]

So, the required distance is equal to 0.343 m.

Answer:

the period of the physical pendulum is 0.498 s

Explanation:

Given the data in the question;

[tex]T_{simple[/tex] = 0.61 s

we know that, the relationship between T and angular frequency is;

T = 2π/ω ---------- let this be equation 1

Also, the angular frequency of physical pendulum is;

ω = √(mgL / [tex]I[/tex] ) ------ let this equation 2

where m is mass of pendulum, L is distance between axis of rotation and the center of gravity of rod and [tex]I[/tex]  is moment of inertia of rod.

Now, moment of inertia of thin uniform rod D is;

[tex]I[/tex] = [tex]\frac{1}{3}[/tex]mD²

since we were not given the length of the rod but rather the period of the simple pendulum, lets combine this three equations.

we substitute equation 2 into equation 1

we have;

T = 2π/ω OR T = 2π/√(mgL/[tex]I[/tex]) OR T = 2π√([tex]I[/tex]/mgL)

so we can use [tex]I[/tex] = [tex]\frac{1}{3}[/tex]mD² for moment of inertia of the rod

Since center of gravity of the uniform rod lies at the center of rod

so that L =  [tex]\frac{1}{2}[/tex]D.

now, substituting these equations, the period becomes;

T = 2π/√([tex]I[/tex]/mgL) OR T = [tex]2\pi \sqrt{\frac{\frac{1}{3}mD^2 }{mg(\frac{1}{2})D } }[/tex] OR T = 2π√(2D/3g )  ----- equation 3

length of rod D is still unknown, so from equation 1 and 2 ( period of pendulum ),

we have;

ω[tex]_{simple[/tex] = 2π/[tex]T_{simple[/tex] OR  ω[tex]_{simple[/tex] = √(g/D) OR  ω[tex]_{simple[/tex] = 2π√( D/g )  

so we simple solve for D/g and insert into equation 3

so we have;

T = √(2/3) × [tex]T_{simple[/tex]

we substitute in value of [tex]T_{simple[/tex]

T = √(2/3) × 0.61 s

T = 0.498 s

Therefore, the period of the physical pendulum is 0.498 s

Answer:

T = 4 N

Explanation:

Given that,

Weight of a car, W = 80 N

We know that,

Weight = mg

80 = 10m

m = 8 kg

If the acceleration of the car is 0.5 m/s², then force becomes,

F = 8 × 0.5

F= 4 N

So, the required tension force is 4 N.

Answer:

450 since in series we add the resistance

Answer:

t = 0.4 seconds

Explanation:

Given that,

Mass of the object, m = 2 kg

Initial speed of the object, u = 3 m/s

Finally, it stops, v = 0

Constant force applied to the object, F = 15 N

We know that,

Force, F = ma

[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{2\times (0-3)}{15}\\\\=0.4\ s[/tex]

So, it will take 0.4 seconds to stop the mass.

Answer:

C. Sleep Apnea

Explanation:

Sleep Apnea is when someone who snores and stops breathing while sleeping

Someone who snorts and stop breathing during sleep may be suffering from Sleep Apnea. Hence, option (c) is correct.

Breathing repeatedly stops and begins while you sleep, which is a frequent symptom of sleep apnea. Your body may not receive enough oxygen as a result.

There are two different forms of sleep apnea.

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