In a classroom demonstration, students are using a Slinky to observe and learn about wave properties. If the Slinky has a period of 0.333 seconds, what is the frequency?

Answer:

If both parents had a recessive allele for blue eyes and they had a brown phenotype it is completely possible for the child to have blue eyes.

Explanation:

Chromosomes play the role of transfering the encoded strands of DNA to the child. Genotypes are the traits or groups of traits transferred and need to carry the trait of blue eyes in order for the child to have them. As long as the parents had a recessive allele for blue eyes they could have a blue eyed child.

(apologies for the incomplete answer, I accidentally hit send)

Answer:

It's true.

And this makes the state of the sun to be "plasma"

Answer: It is False.

Explanation: I am on my final test for Astronomy. And I study really hard and I know its the right answer.

Answer:

635 years old

Explanation:

The light reaching the earth from the sun will travel at a speed called the speed of light, and this has a universal value of 3 × 10⁸ m/s. Bearing this in mind, let us calculate the age of the light reaching the Earth from the sun:

Distance of star from Earth = 6.1 × 10⁸m

Speed of light = 3 × 10⁸ m/s

We have distance and speed, let us calculate the time of travel of the light from the star to the earth.

Distance = speed × time

6.1 × 10⁸ = 3 × 10⁸ × time

[tex]time = \frac{6.1 \times 10^{18}}{3 \times 10^8}[/tex]

In order to do the division above, we will divide the whole numbers normally, then we will apply the law of indices to the power that says:

Xᵃ ÷ Xᵇ = X⁽ᵃ⁻ᵇ⁾

[tex]\therefore time = \frac{6.1 \times 10^{18}}{3 \times 10^8}\\= \frac{2.03 \times 10^{(18-8)}}{1} \\= 2.03 \times 10^{10}}\ seconds[/tex]

Next, we are told that there are 3.2 × 10⁷ seconds in a year.

∴ The number of years travelled by the light from the star:

[tex]3.2\ \times 10^7\ seconds = 1\ year\\1\ second = \frac{1}{3.2\ \times 10^7} \\\therefore 2.03 \times 10^{10}\ seconds = \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}[/tex]

please note that:

2.03 × 10¹⁰ = 20300000000

3.2 × 10⁷ = 32000000

[tex]\therefore \frac{2.03 \times 10^{10}}{3.2\ \times 10^7}\\= \frac{20300000000}{32000000} \\\\= \frac{20300}{32} \\= 634.347\ years\\[/tex]

The closest answer in the option is 635 years, and we are short of this by some points due probably to approximations in the calculation.

Answer:

v=f* lamba

f=v/lamba

f= 335/55

f=6.45 hertz

Answer:

a b c d

Explanation:

Answer:

Using wood also helps keep carbon out of the atmosphere, helping to mitigate climate change.

Deforestation.  

Explanation:

Trees store carbon dioxide as they grow. After harvest, wood products continue to store much of this carbon. These benefits continue when wood is reclaimed to manufacture other products.

Extraction of wood within the supply areas clearly affects the forest and the environment. Some of these impacts can be seen in the study areas. The rainfall is increasingly irregular, biodiversity has been lost. Communities have experienced flooding and drought, which adversely affects the most important sector in the country's economy, that of agriculture. The local populations are concerned about these impacts, which affect not only the environment but the whole social economy.

As wood of the trees is made from the carbon and after burning its produces carbon again that adds to air. When you increase this carbon concertation in the air climate starts to change.

It leads to respiratory problems and air pollution.

Learn more about the two environmental effects of using wood as an energy resource.

brainly.in/question/17875160.

Answer:

Explanation:

False

Answer:

it would be conduction but i dont know the answer choices

Explanation:

and convection would be the movement caused within a fluid by the tendency of hotter and therefore less dense material to rise, and colder, denser material to sink under the influence of gravity, which consequently results in transfer of heat.

Answer:

14.42 units

Explanation:

The waves are given as follows :

[tex]y_1(x,t)=10.2\sin(4x-700t)\\\\y_2(x,t)=10.2\sin(4x-700t-7.9)[/tex]

We need to find the amplitude of the resultant wave at interference. Let it be A. So,

[tex]A=\sqrt{10.2^2+10.2^2} \\\\=14.42\ units[/tex]

So, the amplitude of the resultant wave is equal to 14.42 units.

Answer:

Hello There!!

Explanation:

The answer is=>A.blue, base.

hope this helps,have a great day!!

~Pinky~

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

A.blue, base.

Answer:

b. Thermal energy will flow from your hand to the snowball.

Explanation:

Answer:

B

Explanation:

Answer:

Refraction is the slowing down of light waves as they pass into a different medium and speeding as they pass out.

hope it helps. plz mark me as brainliest.

Answer:

The heavier something is, the harder it is to slow down. As such, higher amounts of mass result in a lower rate of slowing.

Answer:

vf = 7 m/s

Explanation:

The final velocity of the ball right before it hits the ground can be found by using the third equation of motion:

[tex]2gh = v_f^2 - v_i^2[/tex]

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 2.5 m

vf = final velocity = ?

vi = initial velocity =  0 m/s

Therefore,

[tex]2(9.81\ m/s^2)(2.5\ m) = v_f^2 - (0\ m/s)^2\\v_f = \sqrt{49.05\ m^2/s^2}\\[/tex]

vf = 7 m/s

Answer:

Plzzzz answer fast......

Answer:

We know that the electronic charge is 1.6 E-19 coulombs

Therefore 1 coulomb of charge contains 1.6  E19 electrons

A charge of 16.7 E6 coulombs therefore contains

N = 16.7 E6 * 1.6 * E-19 = 2.67 E-12 electrons

Also, the charge on the proton equals that on the electron

Answer:

new Moon.

waxing crescent Moon.

first quarter Moon.

waxing gibbous Moon.

full Moon.

waning gibbous Moon.

last quarter Moon.

waning crescent Moon.

Explanation:

Answer:

NEW MOON

WAXING CRESCENT

FIRST QUARTER

WAXING GIBBOUS

FULL MOON

THIRD QUARTER

WANING GIBBOUS

WANING CRESCENT

Explanation:

HOPE IT HELPS

Answer:

I think it's red so yeah hdjjdbebe

Answer:

Distance a load moves when acted on by a load force. 8 Effort Force & Effort Distance Effort Force: Force exerted by a person (or motor) when using a machine to lift a load. Effort Distance: The distance over which the effort force acts in a simple machine.

Answer:

Load Distance: Distance a load moves when acted on by a load force. 8 Effort Force & Effort Distance Effort Force: Force exerted by a person (or motor) when using a machine to lift a load. Effort Distance: The distance over which the effort force acts in a simple machine

Explanation:

Load Distance: Distance a load moves when acted on by a load force. 8 Effort Force & Effort Distance Effort Force: Force exerted by a person (or motor) when using a machine to lift a load. Effort Distance: The distance over which the effort force acts in a simple machine

Answer:

Part A;

The charges are;

Q₁ = 1.32687 μC and Q₂ = 92.67313 μC

Part B

Q₁ = 95.29042 μC, Q₂ = -1.29042 μC

Explanation:

Part A

The total charge on the two nonconducting spheres = 94.0 μC

The force exerted by each on the other when placed 31 cm apart = 11.5 N

Let Q₁ = x represent the charge on one of the spheres and let Q₂ represent the charge on the other sphere

The force, 'F', exerted by a charge is given as follows;

[tex]F = k \times \dfrac{\left | Q_1 \right | \cdot \left | Q_2 \right | }{d^2}[/tex]

Where;

d = The distance between the spheres = 31 cm = 0.31 m

k = 8.9875 × 10⁹ N·m²/C²

Where F = 11.5 N

Q₁ + Q₂ = 94.0 μC

∴ Q₂ = 94.0 - Q₁ = 94.0 - x

We get;

[tex]F =11.5 = 8.9875 \times 10^9 \times \dfrac{x\times (94.0-x) \times 10^{-12}}{0.31^2}[/tex]

Therefore;

94·x - x² - 122.965 = 0

x² - 94·x + 122.965

x = (94 ± √((-94)² - 4×1×122.965))/(2 × 1)

Solving gives;

x ≈ 1.32687 × 10⁻⁶ C or x = 92.67313 × 10⁻⁶ C

Therefore, the charges are;

Q₁ = 1.32687 × 10⁻⁶ C and Q₂ = 92.67313 × 10⁻⁶ C

Q₁ = 1.32687 μC and Q₂ = 92.67313 μC

Part B

For attractive force, we have;

Q₁ + Q₂ = 94 × 10⁻⁶...(1)

[tex]11.5 = 8.9875 \times 10^9 \times \dfrac{-x\times (94.0-x)}{0.31^2} = 8.9875 \times 10^9 \times \dfrac{-Q_1\times Q_2}{0.31^2}[/tex]

-Q₁ × Q₂ = 11.5 × 0.31²/(8.9875 × 10⁹) = 1.2296523 × 10⁻¹⁰...(2)

∴ Q₂ = -1.2296523 × 10⁻¹⁰/(Q₁)

Q₁ + Q₂ = Q₁  - 1.2296523 × 10⁻¹⁰/(Q₁) = 94 × 10⁻⁶

Q₁² - 94 × 10⁻⁶·Q₁ - 1.2296523 × 10⁻¹⁰ = 0

∴ Q₁ = (94 × 10⁻⁶ ± √((-94 × 10⁻⁶)² - 4 × 1 × 1.2296523 × 10⁻¹⁰))/(2×1)

Q₁ = 9.529042 × 10⁵ C or -1.29042 × 10⁻⁶ C

Therefore, Q₁ = 9.529042 × 10⁵ C and Q₂ = -1.29042 × 10⁻⁶ C

Q₁ = 95.29042 μC and Q₂ = -1.29042 μC

Answer:

[tex]a'=1.285\ m/s^2[/tex]

Explanation:

Let m be the mass of a little car and m' be the mass of another car.

We know that,

Force = mass × acceleration

ATQ,

m × a = 2m × a'

a = 2 × a'

[tex]a'=\dfrac{a}{2}\\\\a'=\dfrac{2.57}{2}\\\\a'=1.285\ m/s^2[/tex]

So, the acceleration of another little car is equal to [tex]1.285\ m/s^2[/tex].

Answer:

if bother parents have brown eyes but they carry the allele for blue eyes a quarter of the kids will have blue eyes and three quarters will have brown eyes. hope this help I'm sorry if it doesn't.

Answer:

2) 6.22 × 10^-13

3) 4.56 × 10^-4

Explanation:

Explanation:

The magnetic field around a wire is given by :

[tex]B=\dfrac{\mu_o I}{2\pi r}[/tex] .......(1)

Where

I is current

r is the distance from wire

The magnetic field around the solenoid is given by :

[tex]B=\mu_o NI[/tex] .....(2)

Where

N is the no. of turns per unit length

From equation (1) and (2), it is clear that the strength of the magnetic field in both current-carrying wire and the solenoid is directly proportional to the current. So, as current intensity increases, the strength of the magnetic field around both a current-carrying wire and solenoid increases. The given statement is false.

Answer:

gamma rays

Explanation:

they have longer wave lengths than the others

Answer:

2000 pascal

Hope it helps

Answer:

Static Friction - acts on objects when they are resting on a surface

Sliding Friction -  friction that acts on objects when they are sliding over a surface

Rolling Friction - friction that acts on objects when they are rolling over a surface

Fluid Friction - friction that acts on objects that are moving through a fluid

Explanation:

Examples of static include papers on a tabletop, towel hanging on a rack, bookmark in a book , car parked on a hill.

Example of sliding include sledding, pushing an object across a surface, rubbing one's hands together, a car sliding on ice.

Examples of rolling include truck tires, ball bearings, bike wheels, and car tires.

Examples of fluid include water pushing against a swimmer's body as they move through it , the movement of your coffee as you stir it with a spoon,  sucking water through a straw, submarine moving through water.

Answer:

Input work is the work done on a machine as the input force acts through the input distance .Other ways it would be the work done on a body or system, that is, forces that are applied to the body or system. This is in contrast to output work which is a force that is applied by the body or system to something else. Output work is the work done by a machine as the output force acts through the output distance. The machine does to the object to increase the output distance.

Explanation: