In a tank full of water, the pressure on a surface 2 meters below the water level is 1.5 kPA. What's the pressure on a surface 6 meters below the water level ?

Answers

Answer 1

Answer:

P = 40.7kPa

Explanation:

To find the pressure on a surface 6 meter below you use the following formula, which takes into account the heights in which pressures are measured and also the density of the fluid and the gravitational acceleration:

[tex]P_2-P_1=-\rho g(y_2-y_1)[/tex]             (1)

P2: pressure for a height of -6 m = ?

P1: pressure for a height of -2 m = 1.5kPa = 1500 Pa

ρ: density of water = 1000kg/m^3

g: gravitational acceleration = 9.8 ms^2

y2: -6m

y1: -2m

(the height is measure from the water level, because of that, the heights are negative)

You solve the equation (1) for P1:

[tex]P_1=P_2-\rho g(y_2-y_1)[/tex]         (2)

Next, you replace the values of all variables in equation (2):

[tex]P_2=1500Pa-(1000kg/m^3)(9.8m/s^2)(-6-(-2))m=40700Pa\\\\P_2=40.7kPa[/tex]

hence, the pressure on a surface 6 m below the water level is 40.7kPa


Related Questions

If a truck if it is accelerating at a rate of 5m/s2 and hits a parked car with a force of 16,000 newtons what is its mass?

Answers

Answer:

3200kg

Explanation:

F=ma

16000=5m

m=3200kg

Hope this helps!

The mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.

What is mass?

A tangible body's mass is the amount of matter it possesses. It's also a metric of inertia or the resistance to velocity when a net force is exerted.

It is given that:

If a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons

As we know,

Newton's second law:

F = ma

Here F is the force acting on an object.

m is the mass of the object

a is the acceleration of the object.

a = 5 m/s²

F = 16,000 N

m = 3200kg

16000 = 5m

3200 kg

Thus, the mass of the parked car is 3200 kg if a truck if it is accelerating at a rate of 5 m/s² and hits a parked car with a force of 16,000 newtons.

Learn more about the mass here:

https://brainly.com/question/15959704

#SPJ2

A lamp hangs from the ceiling at a height of 2.6 m. The lamp has a mass of 3.8 kg. The screws holding the lamp break, and it falls to the ground. a. How much gravitational potential energy does the lamp have before it falls? b. How much kinetic energy does the lamp have when it reaches the ground? c. How fast is the lamp moving when it hits the ground?

Whoever answers will get the Brainliest.

Answers

Answer:

Explanation:

Given height of lamp from the ceiling = 2.6m

mass of the lamp = 3.8kg

acceleration due to gravity = 9.81m/s²

As the body falls to the ground, it falls under the influence of gravity.

Gravitational potential energy = mass*acc due to gravity * height

Gravitational potential energy  = 3.8*2.6*9.81

Gravitational potential energy  = 96.923 Joules

b) Kinetic energy = 1/2 mv²

m = mass of the body (in kg)

v = velocity of the body (in m/s²)

To get the velocity v, we will use the equation of motion [tex]v^{2} = u^{2}+2gh[/tex]

[tex]v^{2} = 0^{2}+2(9.81)(2.6) \\v^{2} = 51.012\\v =\sqrt{51.012}\\ v = 7.14m/s[/tex]

Since mass = 3.8kg

[tex]K.E = 1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules[/tex]

c) To know how fast the lamp is moving when it hits the ground, we will use the formula. When the body hits the ground, the height covered will be 0m. this means that the body is not moving once it hits the ground. It stays in one position. The energy possessed by the body at this point is potential energy. The correct answer is therefore 0 m/s

Using newtons law How much force is accelerated a 66kg skier 2m/s2

Answers

Answer:

SUPONIENDO QUE NO HAY FRICCIÓN

Explanation:

F = 66 kg([tex]2 m/s^{2}[/tex]) = 132 N

HELP ASAP!

Why is it misleading to include too many significant figures in a laboratory report?

Answers

Answer:

The last significant figure is inherently uncertain because of the rounding off. The rounding-off uncertainty is usually half of the last figure's decimal-place value if no other uncertainty is expressed. As a rule of thumb results of measurements and calculations have a limited number of significant figures.

Does the speed of the object affect friction?
So which one would increase friction, going slowly, or going fast.
If possible an explanation? Thanks a bunch. :D

Answers

Answer:

it would

Explanation:

this is because as something rubs against a surface fast, friction heats it up, like when you rub a surface fast and it gets warm on the palm of your hand, that is friction. hope it helped :)

A high surface tension results from _____.

Answers

Answer:

Capillary Action.

Explanation:

Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.

Number of atoms present in 1 mole of oxygen atom

Answers

Answer:

1 mole of every substance has 6.022 × 10^23 particles. This is called Avagadro's constant

A car starts 10 m north of a reference point. It moves at a constant velocity over the next 5 s, reaching a position of 10 m south of the reference point. What is the car's average velocity?

Answers

Answer:

  v = -4 m / s

Explanation:

The average speed of a body is defined by the distance traveled in a given time interval

     v = (x₂ -x₁) / (t₂ -t₁)

in this case the end point is x₂ = -10 m and the start point is x₁ = 10 m, the negative sign is because the point is below the reference that can be considered as zero point

let's calculate

     v = (-10 - 10) / 5

     v = -20 / 5

      v = -4 m / s

AS WE CLIMB UP, THE PRESSURE INSIDE OUR BODY WILL BE.................. *
1 )low
2)high
3)very high
4)same

Answers

Less depth means less pressure,as we go up in elevation,or height,air pressure decreases.
Prob low since the higher we go, the pressure/ our heart starts to feel heavy (drop low)
Take riding a Roller Coaster for an example, When you go down or up fast, your heart starts dropping as if it’s heavier than it was.

ASAP! HELP!
A 66.4 kg person sits on the right end of a seesaw, 2.35m from the fulcrum. On the other end, how far from the fulcrum should a 84.2kg person sit to balance the seesaw?
1: 1.92 m
2: 1.85m
3: 2.08m
4: 1.61 m

Answers

Answer:

2. 1.85

Explanation:

the equations weight * distance / other persons weight = distance from fulcrum. so 66.4*2.35/84.2=1.8532 round down to 1.85

The________ is a membrane that surrounds a cell Nucleus

Answers

Answer:

nuclear envelope

Explanation:

it surrounds the nucleus and all of its contents

nuclear envelope
The nuclear envelope, also known as the nuclear membrane, is made up of two lipid bilayer membranes which in eukaryotic cells surrounds the nucleus, which encases the genetic material. The nuclear envelope consists of two lipid bilayer membranes, an inner nuclear membrane, and an outer nuclear membrane.

factorise x^3 - 3x^2 - 9x - 5​

Answers

Answer:

(x +1), (x -5) and (x +1)

Explanation:

The computation of the factorization is shown below

Data provided in the question

[tex]X^3 - 3x^2 - 9x - 5[/tex]

Based on the above information, the factors are

Now we have to open these equations in order to get the factors which are as follows

[tex]= x^3 + x^2 - 4x^2 - 4x - 5x - 5[/tex]

[tex]= x^2( x + 1) - 4x ( x + 1) - 5(x + 1)[/tex]

[tex]= (x + 1) (x^2 - 4x - 5)[/tex]

[tex]= (x + 1)(x^2 -5x + x - 5)[/tex]

So,

= (x + 1) (x - 5) (x + 1)

Therefore the (x +1), (x -5) and (x +1) are the factors of the mention polynomial give in the question

When an object is located 32 cm to the left of the lens, the image is formed 17 cm to the right of the lens. What is the focal length of the lens?

Answers

Answer: 11.1cm

Explanation:

Object distance (u) = 32cm

Image distance(v) = 17cm

Focal length(f) =?

Lens formular:

1/f = 1/u + 1/v

1/f = 1/32 + 1/17

Taking the L. C. M of 17 and 32

1/f = (17 + 32) / 544

1/f = 49/544

Taking the reciprocal

f = 544/49

f = 11.1 cm

Therefore, Focal length of the lens is 11.1cm

need help with ASAP please

Answers

Answer:

first blank is chemical second blank is kinetic energy

The length of a wooden rod is 25.5 cm. What is this length in:
(a) millimetres?
(b) metres?​

Answers

Answer:

[tex](a)255mm \\ (b)0.255m[/tex]

Explanation:

[tex](a)1cm = 10mm \\ 25.5cm = x[/tex]

Cross multiply

[tex]1x = 25.5 \times 10 \\ x = 255mm[/tex]

[tex](b)100cm = 1m \\ 25.5cm = x[/tex]

cross multiply

[tex]100x = 25.5 \\ \frac{100x}{100} = \frac{25.5}{100} \\ x = 0.255m[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

A. 255

B. 0.255

Explanation:

10mm = 1cm

100cm = 1m

<a href="https://en.wikiafripedia.org/wiki/Centimetre">Learn more</a>

https://en.wikiafripedia.org/wiki/Centimetre

Amina has a mass of 48.4kg, what is her weight.please show calculation

Answers

G=m×g

since g=10N,

G=48.4×10

G=484

I hope it's true .d

good luck

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