Answer:
Hello ♡
The answer to your question is 7.3333333333 .
Step-by-step explanation:
Hope this helps u ;)
Answer:
d = 4Step-by-step explanation:
[tex]a_1=2\,,\quad a_4=14\\\\a_n=a_1+d(n-1)\\\\a_4=a_1+d(4-1)\\\\14=2+3d\\\\12=3d\\\\d=4[/tex]
I WAS IN THE HOSPITAL AND MISSED A MATH LESSON HELP PLZZZ
Answer:
30 ft
Step-by-step explanation:
[tex]C=\frac{n^2}{5} +175\\\\355=\frac{n^2}{5} +175\\\\180=\frac{n^2}{5}\\\\n^2=900\\\sqrt{n^2} =\sqrt{900} \\n=30[/tex]
fine the missing side lengths for x and y
Answer:
Letter A is the answer pls
9514 1404 393
Answer:
[tex]x=\dfrac{4\sqrt{3}}{3};\ y=\dfrac{8\sqrt{3}}{3}[/tex]
Step-by-step explanation:
The side ratios of a 30°-60°-90° triangle are ...
1 : √3 : 2
In your triangle, they are ...
x : 4 : y
In order to get these values, we need to multiply the reduced ratio by 4/√3 = (4√3)/3. Then we have ...
x : 4 : y = (4√3)/3 : 4 : (8√3)/3
and we can see that ...
x = (4√3)/3y = (8√3)/33x^2=20-7x
factor step by step please?
Answer:
x=5/3 or x=-4
Step-by-step explanation:
Watch ne
The diameter of a circle is 4 m. Find its area to the nearest tenth.
m
Answer A=
Answer:
area = 12.6 m²
Step-by-step explanation:
r = 4/2 = 2
area = πr² = (3.14)(2²) = 12.56 m²
Jenya graphed a scatter plot of number of potholes (y) and length of a road in miles (x). She drew the trend line and calculated its equation to be y = 3x +5. What is the predicted number of potholes for a road that is 10 miles long?
Answer: 35
Step-by-step explanation:
3•10=30, 30+5=35
Find the surface area of a number cube if the height is 3cm.
I'll give brainliest
Answer:
54 unit sq
Step-by-step explanation:
Answer:
54 i think
Step-by-step explanation:
i need help plzzzzzzzzzzzzzzzzzzzzzzzzzzzz
Answer:
The answer is 7
Step-by-step explanation:
Q11-4=7
Hope this helped!!!
A train is spotted 10 miles south and 8 miles west of an observer at 2:00 pm. At 3:00 pm the train is spotted 5 miles north and 16 miles east of the observer. a. How far did the train travel in the first hour? b. If the train continues at this pace where will it be in relation to the observer at 5:00 pm? Write a function that will give the train's position at any given time c. d. At 2:00 pm a cyclist is traveling due east and is next to the observer. If the cyclist is traveling at 10 mph, do they collide with the train when the bike goes over the train tracks?
Answer:
a. The distance the train travelled in the first hour is approximately 28.3 miles
b. The location of the train at 5:00 p.m. is 53 miles east, and 46 miles west
c. The location of the train at any given time by the function, f(t) = (-8 + 24·t, -10 + 15·t)
d. The train does not collide with the cyclist when the bike goes over the train tracks
Step-by-step explanation:
a. The given information on the train's motion are;
The location south the train is spotted = 10 miles south and 8 miles west
The time the observer spotted the train = 2:00 pm
The location the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east
Therefore, the difference between the two times the train was spotted, t = 3:00 p.m. - 2:00 p.m. = 1 hour
Making use of the coordinate plane for the two locations the train was spotted, we have;
The initial location of the train = (-10, -8)
The final location of the train = (5, 16)
Therefore the distance the train travelled in the first hour is given by the formula for finding the distance, 'd', between two points, (x₁, y₁) and (x₂, y₂) as follows;
[tex]d = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}[/tex]
Therefore;
[tex]d = \sqrt{\left (5-(-10) \right )^{2}+\left (16-(-8) \right )^{2}} = 3 \cdot\sqrt{89}[/tex]
The distance the train travelled in the first hour, d = 3·√89 ≈ 28.3 miles
b. The speed of the train, v = (Distance travelled by the train)/Time
∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour
The speed of the train in the first hour, v ≈ 28.3 mph
The direction of the train, θ, is given by the arctangent of the slope, 'm', of the path of the train;
[tex]\therefore The \ slope \ of \ the \ path \ of \ the \ train, \, m =tan(\theta) = \dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
∴ m = tan(θ) = (5 - (-10))/(16 - (-8)) = 0.625
c. Distance = Velocity × Time
At 5:00 p.m., we have;
The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours
The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles
Using trigonometry, we have the horizonal distance travelled, 'Δx', in the 2 hours is given as follows;
Δx = d₁ × cos(θ)
∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48
The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles
The vertical distance increase in the two hours, Δy is given as follows;
Δy = 56.6 × sin(arctan(0.625)) ≈ 30
The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles
Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)
The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west
c. The function, 'f', that would give the train's position at time-t is given as follows;
The P = f(28.3·t, θ)
Where;
28.3·t = √(x² + y²)
θ = arctan(y/x)
Parametric equations
y - 5 = 0.625·(x - 16)
∴ y = 0.625·x - 10 + 5
The equation of the train's track is therefore, presented as follows;
y = 0.625·x - 5
d = 28.3·t
The y-component of the velocity, [tex]v_y[/tex] = 3*√89 mph × sin(arctan(0.625)) = 15 mph
Therefore, we have;
y = -10 + 15·t
The x-component of the velocity, vₓ = 3*√89 mph × cos(arctan(0.625)) = 24 mph
Therefore, we have;
x = -8 + 24·t
The location of the train at any given time, 't', f(t) = (-8 + 24·t, -10 + 15·t)
d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph
The distance of the cyclist from the track = The x-intercept = 5/0.625 = 8
The distance of the cyclist from the track = 8 miles
The time it would take the cyclist to react the track, t = 8 miles/10 mph = 0.8 hours
The location of the train in 0.8 hours, is f(0.8) = (-8 + 24×0.8, -10 + 15×0.8)
∴ f(0.8) = (11.2, 2)
At the time the cyclist is at the track along the east-west axis, at the point (8, 0), the train is at the point (11.2, 2) therefore, the train does not collide with the cyclist when the bike goes over the train tracks.
If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.
The location south the train is spotted = 10 miles south and 8 miles west
The time the observer spotted the train = 2:00 pm
The location of the train is spotted at 3:00 p.m. = 5 miles north and 16 miles east
Thus, the difference between the two times the train was spotted,
t = 3:00 p.m. - 2:00 p.m. = 1 hour
What is the distance?The distance is the product of velocity and time.
Distance = Velocity × Time
The initial location of the train = (-10, -8)
The final location of the train = (5, 16)
Therefore the distance the train travelled in the first hour
[tex]d = \sqrt{(x_{2} -x_{1} )^{2} +(y_{2} -y_{1} )^{2} } \\d = \sqrt{(5 -(-10) )^{2} +(16-(-8) )^{2} }[/tex]
d = 3√89
The distance the train travelled in the first hour, d = 28.3 miles
b. The speed of the train, v = (Distance travelled by train)/Time
∴ v ≈ 28.3 miles/(1 hour) = 28.3 miles per hour
The speed of the train in the first hour, v ≈ 28.3 mph
The direction of the train, θ, is given by the arc tangent of the slope, 'm', of the path of the train;
∴ m = tan(θ) = (5 - (-10))/(16 - (-8))
m = 0.625
c. Distance = Velocity × Time
At 5:00 p.m., we have;
The time difference, Δt = 5:00 p.m. - 3:00 p.m. = 2 hours
The distance, d₁ = (28.3 mph × 2 hours = 56.6 miles
Using trigonometry, we have the horizontal distance travelled, 'Δx', in the 2 hours is given as follows;
Δx = d₁ × cos(θ)
∴ Δx = 56.6 × cos(arctan(0.625)) ≈ 48
The increase in the horizontal position of the train, relative to the point (5, 16), Δx ≈ 48 miles
The vertical distance increase in the two hours, Δy is given as follows;
Δy = 56.6 × sin(arctan(0.625)) ≈ 30
The increase in the vertical position of the train, relative to the point (5, 16), Δy ≈ 30 miles miles
Therefore; the location of the train at 5:00 p.m. = ((5 + 48), (16 + 30)) = (53, 46)
The location of the train at 5:00 p.m. = 53 miles east, and 46 miles west
c. The function, 'f', that would give the train's position at time-t is given as follows;
The P = f(28.3·t, θ)
28.3·t = √(x² + y²)
θ = arctan(y/x)
Parametric equations
y - 5 = 0.625·(x - 16)
∴ y = 0.625·x - 10 + 5
The equation of the train's track is, therefore, presented as follows;
y = 0.625·x - 5
d = 28.3·t
The y-component of the velocity,
= 3 × √89 mph × sin(arctan(0.625)) = 15 mph
Therefore, we have
y = -10 + 15·t
The x-component of the velocity,
vₓ = 3 × √89 mph × cos(arctan(0.625))
= 24 mph
Therefore, we have;
x = -8 + 24·t
The location of the train at any given time, 't',
f(t) = (-8 + 24·t, -10 + 15·t)
d. The speed of the cyclist next to the observer at 2:00 p.m., v = 10 mph
The distance of the cyclist from the track = The x-intercept
= 5/0.625 = 8
The distance of the cyclist from the track = 8 miles
The time it would take the cyclist to reach the track, t = 8 miles/10 mph = 0.8 hours
The location of the train in 0.8 hours, is f(0.8)
= (-8 + 24×0.8, -10 + 15×0.8)
∴ f(0.8) = (11.2, 2)
therefore, If the cyclist is travelling at 10 mph the train does not collide with the cyclist when the bike goes over the train tracks.
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Liam puts $60 in savings in March and 150% of this amount in savings in April. How much does Liam put in savings in April? Round to the nearest whole dollar. *
Answer:
Savings in March: $60
Savings in April: $60 + 150% of $60=$60 +$90=$150
Step-by-step explanation:
Liam adds another 150% of the original amount to his savings. So, his total amount does not change but the amount increases by $90 (150% of $60).
What is mU?
A. 17
B. 29
C. 46
D. 134
Answer:
I think its A
Step-by-step explanation:
because it's a tighter angle than 29,46,and 134 degrees i might not be right but i hope it is :)
Find (gºf)(3)
f(x) = |x+ 2|
g(x) = -x?
a. -25
b. 1
C. 4
d. -15
Please select the best answer from the choices provided
A
B
C
D
Answer:
A. -25
Step-by-step explanation:
sana nakatulong :-)
The price of tire is $45.50. The store marks it Up 60%. What is the total?
Answer:
$72.80
Step-by-step explanation:
1.) Find 60% of 45.50
0.60 * 45.50 = 27.3
2.) Add this to the cost
27.30 + 45.50 = 72.80
Tamia is getting balloons for her father's birthday party. She wants each balloon string to be 6 feet long. At the party store, string is sold by the yard. If Tamia wants to get 59 balloons, how many yards of string will she need?
Answer:
118 yards
Step-by-step explanation:
Tamia is getting balloons for her father's birthday party
She wants each balloon to be 6 feet long
Tamia wants to get 59 balloons
Therefore the yards of string needed can be calculated as follows
= 59×6
= 354 feet to yards
= 118 yards
Hence the number of yards needed is 118 yards
evaluate the expression 6n2 when n=5
Answer:
652
Step-by-step explanation:
Answer: 60
Step-by-step explanation:
6n2
n=5
6(5)2
6×10 = 60
Thalia's next class is 8 units to the right and 5 units down on the map from where she is now. In what room is Thalia's next class? Find the ordered pair that represents the location of that room.
Answer: (6,-4) music
Step-by-step explanation:
Kevin knit scarves for his friends. Altogether, the scarves had a total length of
442.8 in. If he knit 9 scarves, and each scarf was the same length, how long
was each scarf? Write your answer in feet.
Kevin knit 9 scarves, and each scarf was 49.2 inches long.
Converting this length to feet, we find that each scarf is 4.1 feet long.
Let's use the variable "L" to represent the length of each scarf in inches. Since Kevin knit 9 scarves, we can write the equation for the total length of all scarves as:
[tex]\(L_{\text{total}} = L \times 9\)[/tex]
We are given that the total length of all scarves is 442.8 inches. So, we can write:
[tex]\(442.8 \text{ inches} = L \times 9\)[/tex]
To find the length of each scarf, we need to isolate "L" on one side of the equation. To do that, we can perform the following steps:
Divide both sides of the equation by 9 to get:
[tex]\(\frac{{442.8 \text{ inches}}}{{9}} = \frac{{L \times 9}}{{9}}\)[/tex]
Simplifying, we get:
[tex]\(49.2 \text{ inches} = L\)[/tex]
Now, we have found the length of each scarf in inches (49.2 inches). To convert this length to feet, we know that 1 foot is equal to 12 inches. So, to find the length in feet, we divide the length in inches by 12:
[tex]\(L_{\text{feet}} = \frac{{L_{\text{inches}}}}{{12}}\)[/tex]
Substituting the value of [tex]\(L_{\text{inches}}\)[/tex] with 49.2 inches:
[tex]\(L_{\text{feet}} = \frac{{49.2 \text{ inches}}}{{12}}\)[/tex]
Now, let's perform the division:
[tex]\(L_{\text{feet}} = 4.1 \text{ feet}\)[/tex]
So, each scarf is 4.1 feet long.
Kevin knit 9 scarves, and each scarf was 49.2 inches long.
Converting this length to feet, we find that each scarf is 4.1 feet long.
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Solve. 382.04 – 6,3 *
I need help
i don't understand this can someone help me please
Answer:
Total interest to be paid: $210
Total amount to be repaid: $3,710
Step-by-step explanation:
You can ignore the monthly payment for this problem.
For simple interest, the formula is I = PRT where I = interest earned, P = principal amount borrowed/deposited, R = rate as a decimal, and T = time in years.
I = (3,500)(0.06)(1)
I = 210
Then add that to the amount borrowed ($3,500) and you're done.
3,500 + 210 = $3,710
Please let me know if you have questions.
URGENT!!!!!!!! PLEASE HELP ASAP TIMED!!!!!!!!!!!!!!! HELP!!!!!!!!!!!!!!!!!
Answer:
Height of building = 86.9 ft
Step-by-step explanation:
I've drawn a triangle image to depict this question and I have attached it.
From the attached image, we can see that ABC is the height of the building.
We can see the distance from your eye to the ground indicated and also the distance from the horizontal distance from the building to you indicated.
We can use pythagoras theorem to find AB.
AB/57 = tan 55°
AB = 57 × 1.4281
AB = 81.4 ft
Now, total height of the building is AB + BC.
BC = 5.5 ft since B is parallel to your eye and height from there to the ground is 5.5 ft.
Thus;. Height of building = 81.4 + 5.5 = 86.9 ft
help with this nth term homework please answer true of false
How to add 12.50, 18.50, 20, 20, 13, 12
Answer:
96
Step-by-step explanation:
12.50 + 18.50 + 20 + 20 + 13 + 12 = 96
rekitha arekitha kandaralu
Answer:
khing chong
Step-by-step explanation:
Mr. Thomsen is buying two types of gift
cards to give as prizes to employees at a
company meeting. He will buy restaurant
gift cards that each cost $50. He will also
buy movie theater gift cards that each
cost $20. He has $450 to buy a total of
15 gift cards. How many of each type of gift cards can he buy?
Answer:
he can buy 6 gift cards, 7 theatre cards with a remainder of $10.
Step-by-step explanation:
Can anyone help me with this math question please I will give brainlist!!
Answer:
b. (6, 4)
Step-by-step explanation:
i hope this helps :)
Answer:
B. (6,4)
Step-by-step explanation:
The point is inside the triangle.
Mel begins playing video games at the time on the left clock. If she stops playing video games at the time on the right clock, how many minutes did Mel spend playing video games?
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required clocks are not given.
To answer this question, I will give an illustration of how to calculate the difference between times.
Note that: I assume you can read the time on a clock
Assume that:
[tex]Left\ clock = 2:15pm[/tex]
[tex]Right\ clock = 3:05pm[/tex]
The difference is calculated as:
[tex]Difference = Right\ clock - Left\ clock[/tex]
[tex]Difference = 3:05pm - 2:15pm[/tex]
From 2:15pm to 3:05pm is 50 minutes.
So:
[tex]Difference = 50\ minutes[/tex]
Another assumption:
[tex]Left\ clock = 2:15pm[/tex]
[tex]Right\ clock = 3:32pm[/tex]
The difference is calculated as:
[tex]Difference = Right\ clock - Left\ clock[/tex]
[tex]Difference = 3:32pm - 2:15pm[/tex]
For ease of calculation, we split the time to 2.
(1) From 2:15pm to 3:15pm
(2) From 3:15pm to 3:32pm
(1) From 2:15pm to 3:15pm: This is 1 hour
(2) From 3:15pm to 3:32pm: This is 17 minutes (i.e. 32 - 15)
So, the difference is:
[tex]Difference = 1hr + 17min[/tex]
[tex]Difference = 1\ hour\ 17minutes[/tex]
-9+3y=24 write an equivalent equation in slope intercept form
ig hanganaahajssislaalalla
Round your answer to the nearest tenth if necessary. Use 3.14 for it.
A drum has a diameter of 26 inches and is 19 inches deep. Find the volume of his drum.
The volume of this drum is approximately
in.
Answer:
volume = 10,082.5 in³
Step-by-step explanation:
radius = 26/2 = 13
volume = πr²L = (3.14)(13²)(19) = 10,082.54 in³
Probability that the next baby born at a hospital will be a boy
I cant do this please help me i will give brainliest
Answer:
Here, I graphed this especially for you.
Check attachment.
I need this question really badly
Answer:
yeah same for me but with ice cream