In casting experiments performed using a certain alloy.

Answers

Answer 1
Answer:
A) Cm = 2.232 s/mm²
B) Time taken to solidify = 74.3 seconds
Explanation:
(A) Since a side is 50mm and all sides of a cube are equal, thus, Volume of the cube is;V = 50 x 50 x 50 = 125,000 mm³
There are 6 faces of the cube, thus Surface Area A = 6 x (50 x 50) = 15,000 mm²
So, Volume/Area = (V/A) = 125,000/15,000 = 8.333 mm
Cm is given by the formula; Cm =[Tts] /(V/A)² where Tts is time taken to solidify and it's 155 seconds in the question. Thus;
Cm = 155/(8.333)²= 2.232 s/mm²
(B) For;Cylindrical casting with D = 30 mm and L = 50 mm.;
Volume of cylinder is;
V = (πD²L) /4
So,V = (π x 30² x 50)/4 = 35,343mm³
Surface area of cylinder is;
A = (2πD²)/4 + (πDL)
Thus, A = ((π x 30²)/2) + (π x 30 x 50) = 6126 mm²
Volume/Area is;
V/A = 35,343/6126 = 5.77 mm
Same alloy and mold type was hsed as in a above, thus, Cm is still 2.232 s/mm²
Since Cm =[Tts] /(V/A)²
Making Tts the subject, we have;
Tts =Cm x (V/A)²
Tts = 2.232 x (5.77)² = 74.3 seconds

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Answer:

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A on EDGENUNITY

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Answers

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From the complete question, we have the following highlights

The graph has three horizontal linesOne of the lines is on the x-axisThe other lines represent high and low, and they have intervals of 30 and 60 seconds, respectively

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Answer:

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