In Circle P, m EA=58, m BC=42, m CD=90, find:
1. m∠EDA
2. m∠BDC
3. m∠BEC
4. m arc AB
5. m∠AEB
6. m∠ECA
7. m∠BAC
8. m arc ED
9. m∠ECD
10. m∠ACB
11. m∠EBD
12. m∠ADB
13. m∠CAD
14. m∠EAB
15. m∠EBC
PLEASE HELP AHHHHH

Applying the inscribed angle theorem, the missing measures are:

1. m∠EDA = 29°

2. m∠BDC = 21°

3. m∠BDC = 21°

4. measure of arc AB = 80°

5. m∠AEB = 40°

6. m∠AEB = 29°

7. m∠BAC = 21°

8. measure of arc ED = 90°

9. m∠ECD = 45°

10. m∠ACB = 40°

11. m∠EBD = 45°

12. m∠ADB = 40°

13. m∠CAD = 45°

14. m∠EAB = 111°

15. m∠EBC = 90°

The inscribed angle theorem states that, if ∠a is an inscribed angle, that intercepts arc AB, therefore: m∠a = ½(measure of arc AB).

The diagram showing circle P is attached below. We are given the following:

measure of arc EA = 58°

measure of arc BC = 42°

measure of arc CD = 90°

Thus:

1. m∠EDA = ½(measure of arc EA)

m∠EDA = ½(58)

m∠EDA = 29°

2. m∠BDC = ½(measure of arc EA)

m∠BDC = ½(42)

m∠BDC = 21°

3. m∠BEC = ½(measure of arc BC)

m∠BDC = ½(42)

m∠BDC = 21°

4. measure of arc AB = 180 - 58 - 42

measure of arc AB = 80°

5. m∠AEB = ½(measure of arc AB)

m∠AEB = ½(80)

m∠AEB = 40°

6. m∠ECA = ½(measure of arc EA)

m∠AEB = ½(58)

m∠AEB = 29°

7. m∠BAC = ½(measure of arc BC)

m∠BAC = ½(42)

m∠BAC = 21°

8. measure of arc ED = 180 - 90

measure of arc ED = 90°

9. m∠ECD = ½(measure of arc ED)

m∠ECD = ½(90)

m∠ECD = 45°

10. m∠ACB = ½(measure of arc AB)

m∠ACB = ½(80)

m∠ACB = 40°

11. m∠EBD = ½(measure of arc ED)

m∠EBD = ½(90)

m∠EBD = 45°

12. m∠ADB = ½(measure of arc AB)

m∠ADB = ½(80)

m∠ADB = 40°

13. m∠CAD = ½(measure of arc CD)

m∠CAD = ½(90)

m∠CAD = 45°

14. m∠EAB =  ½(180 + 42)

m∠EAB = ½(222)

m∠EAB = 111°

15. m∠EBC = ½(measure of arc EDC)

m∠EBC = ½(180)

m∠EBC = 90°

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