In nursing one procedure for determining the dosage for a child ischild dosageage of child in yearsage of child+12- adult dosageIf the adult dosage of a drug is 328 ml., how much should a 10-year old child receive? Round your answer to the nearest hundredth.
Answers
Given:
[tex]child\text{ dosage=}\frac{age\text{ of child in year }}{\text{age of child}+12}\times adult\text{ dosage}[/tex]To determine: Child dosage given that
[tex]\begin{gathered} \text{age of chld = 10,} \\ \text{adult dosage = 328ml} \end{gathered}[/tex]Solution:
In other to determine the child dosage, we would substitute the age of the child given and the adult dosage into the formula
[tex]\begin{gathered} child\text{ dosage=}\frac{age\text{ of child in year }}{\text{age of child}+12}\times adult\text{ dosage} \\ child\text{ dosage=}\frac{10}{10+12}\times328ml \\ child\text{ dosage=}\frac{10}{22}\times328ml \end{gathered}[/tex][tex]\begin{gathered} child\text{ dosage=}\frac{3280ml}{22} \\ child\text{ dosage=}149.090909ml \\ child\text{ dosage=}149.09ml(\text{nearest hundredth)} \end{gathered}[/tex]Hence, a 10-year old child would receive to the nearest hundredth 149.09 ml
Related Questions
solve the system by elimination,
x - y = 11
2x + y = 19
Answers
Answer:
(10, - 1 )
Step-by-step explanation:
x - y = 11 → (1)
2x + y = 19 → (2)
add (1) and (2) term by term to eliminate y
3x + 0 = 30
3x = 30 ( divide both sides by 3 )
x = 10
substitute x = 10 into either of the 2 equations and solve for y
substituting into (2)
2(10) + y = 19
20 + y = 19 ( subtract 20 from both sides )
y = - 1
solution is (10, - 1 )
x = 14 and y = 3
Step-by-step explanation:
Let
[tex]{ \purple{ \tt{x - y = 11}}}→{ \red{ \tt{ {eq}^{n} (1)}}}[/tex]
[tex]{ \purple{ \tt{2x + y = 19}}}→{ \red{ \tt{ {eq}^{n} (2)}}}[/tex]
Multiply Eqⁿ (1) by 2, then Eqⁿ (1) becomes
[tex]{ \purple{ \tt{2x - 2y = 22}}}[/tex]
Subtract Eqⁿ (1) and (2)
[tex]{ \purple{ \tt{2x - 2y = 22}}}[/tex]
[tex]{ \purple{ \tt{2x + y \: = 19}}}[/tex]
[tex]{ \red{ \tt{( - ) \: ( - ) \: \: \: ( - )}}}[/tex]
___________________
[tex]{ \purple{ \tt{ \: \: \: \: \: \: \: \: \: y \: = 3}}}[/tex]
Substitute the value of y in Eqⁿ (1), then
[tex]{ \purple{ \tt{x - 3 = 11}}}[/tex]
[tex]{ \purple{ \tt{x = 11+3}}}[/tex]
[tex]{ \purple{ \tt{x = 14}}}[/tex]
I couldn’t finish the photo but it’s find the equation of the linear function represented by the table below in the slope- intercept form .
Answers
So we have a table of values that belong to a linear function. The slope-intercept form of these type of functions is:
[tex]y=mx+b[/tex]Where m is the slope and b the y-intercept. If we substitute any of the x values in place of x in the equation it will give us the corresponding y values. In order to find m and b we need to take two rows of the table, substitute their x and y values in the equation and consequently build two equations for m and b. Let's take the first two rows. Then we have x=-1 and y=3 in the first equation and x=2 and y=9 in the second:
[tex]\begin{gathered} y=mx+b \\ 3=-m+b\text{ first equation} \\ 9=2m+b\text{ second equation} \end{gathered}[/tex]So now we have to solve these two equations, let's begin with the first one by adding m at both sides of the equal symbol:
[tex]\begin{gathered} 3=-m+b \\ 3+m=-m+m+b \\ 3+m=b \end{gathered}[/tex]So now we have an expression for b that depends on m. The following step is to substitute this in place of m in the first equation:
[tex]\begin{gathered} 9=2m+b \\ 9=2m+(m+3) \\ 9=2m+m+3 \\ 9-3=3m \\ 6=3m \\ m=\frac{6}{3}=2 \end{gathered}[/tex]So now we know that m=2. If we substitute this value in the expression for b we get:
[tex]\begin{gathered} b=3+m \\ b=3+2=5 \end{gathered}[/tex]So now that we have found the values of m and b we can write the equation of the linear function represented in the table:
[tex]y=2x+5[/tex]Which is the answer to our problem.
I need help working out and simplifying this question, and I’ll need a tutor to help! ( please show work )
Answers
Multiply the top numbers (numerators) and the bottom numbers ( denominators)
[tex]\frac{2\times1}{9\times2}=\frac{2}{18}[/tex]Simplify by 2 ( divide both the numerator and denominator by 2 )
[tex]\frac{2\div2}{18\div2}=\frac{1}{9}[/tex]Answer: 1/9
Marcus wants to decorate his box that is in the shape of a cube. He decides to cover theentire box with red colored paper except the circle with his name on it. The box is shownbelow. Rounded to the nearest square centimeter, how much red paper is needed to cover Marcus'sbox?
Answers
Answer: C. 130
Explanation:
Area of red paper needed to cover Marcus's box =Surface area of cube - area of circle
The formula for calculating the surface area of a cube is expressed as
Surface area = 6a^2
where
a is the length of each side
From the information given,
a = 5
Thus,
Surface area= 6 x r5^2 = 150
The formula for calculating the area of a circle is expressed as
Area = πr^2
where
r is the radus of the circle
π is a constant whose value is 3.14
From the information given
diameter of circle = 5
radius = diameter/2 = 5/2
r = 2.5
Thus,
area of circle = 3.14 x 2.5^2 = 19.625
Area of red paper needed to cover Marcus's box = 150 - 19.625
Area of red paper needed to cover Marcus's box = 130.375
Rounding to the nearest square centimeter,
Area of red paper needed to cover Marcus's box = 130
Convert 20 inches per minute to cm per second. Round to one decimal place. Use 1 inch = 2.54 cm.
Answers
We will convert it as follows:
[tex]20in\cdot\frac{2.54\operatorname{cm}}{1in}=50.8\operatorname{cm}[/tex]From this, we have that 20 inches are equal to 50.8 centimeters.
For males in a certain town, the systolic blood pressure is normally distributed with amean of 135 and a standard deviation of 9. Using the empirical rule, determine theinterval of systolic blood pressures that represent the middle 95% of males.
Answers
From the question, we are given the following parameters;
Mean x = 135
standard deviation s = 9
The following are true based on the empirical rule;
1) 68% values lie within 1 standard deviation of the mean
2) 95% values lie within 2 standard deviation of the mean
Since we are to determine the interval of systolic blood pressures that represent the middle 95% of males, we will apply the second empirical rule as shown;
The interval will be between (x-2s, x+2s)
Substitute the given parameters into the interval a shown;
Interval of values = (135-2(9), 135+2(9))
Interval of values = (135-18, 135+18)
Interval of values = (117, 153)
Hence the interval from 117 to 153 contains the systolic blood pressure of middle 95% of the males in the town
An art club is choosing the site for a school mural
Answers
Solution
[tex]The\text{ }4\frac{\text{ }1}{2}\text{ }by\text{ }12\text{ }feet\text{ wall have the greater area}[/tex]Sketch the graph of the linear inequality. y < 6x + 1
Answers
The given inequality is:
y < 6x + 1
The graph of the inequality is shown below:
Note this is a straight line inequality in the form:
y < mx + c
where The slope, m = 6
and y-intercepty, c = 1
What is the yearly rate of interest on a loan if the monthly rate is 2%?
Answers
Given:
the monthly rate is 2%
1 year = 12 months
So, the yearly rate of interest = 12 * 2% = 24%
So, the answer will be 24%
2/1 = x/12
24%
:)
Find the domain and range of the relation. Age of Person 65 36 29 29. Books Read 42 37 37 17.
Answers
Domain is a set of real numbers which is independent
and
Range is a set of real numbers which is dependent with the domain.
From the given problem, We have two factors, the age of a person
and the number of book read.
We can say that the numbers of books read is dependent on the age of a person.
So the domain would be the age
and the range will be the number of books read.
From the table :
Age : 65, 36, 29, 29
Books Read : 42, 37, 37, 17
Remember that in listing the domain and range, there must be NO duplicates
So the domain is : 29, 36, 65
and
the range is : 17, 37, 42
The correct answer is Choice D.
In ∆QRS, the measure of
Answers
Notice that the given triagle is a right triangle. Remember the definition of the cosine of an angle on a right triangle.
[tex]\cos (\theta)=\frac{\text{Side adjacent to }\theta}{\text{ Hypotenuse}}[/tex]Plugging in the information of the diagram:
[tex]\cos (\angle SQR)=\frac{SQ}{QR}[/tex]Substitute the given values of each segment:
[tex]\cos (29)=\frac{5}{x}[/tex]Isolate x and use a calculator to find a decimal expression for x:
[tex]\begin{gathered} x=\frac{5}{\cos (29)} \\ \Rightarrow x=5.716770339\ldots \\ \Rightarrow x\approx5.7 \end{gathered}[/tex]Therefore, the length of the side QR, to the nearest tenth of a foot is:
[tex]5.7[/tex]Amanda is saving to but a new bike that costs $300. Each week she saves $12. Which of the following could be used to determine how many weeks (w) it will take for her to save enough money for the bike?Options 1) 12w=3002) w - 12= 3003) 12+ w = 3004) w/12= 300
Answers
Each week Amanda saves $12, so, if "w" is the numberof weeks, she saves 12w in "w" weeks
Answer:
Option 1: 12w = 300
Solve the inequality 4|x - 1|< 24
Answers
You want to solve the inequality:
[tex]4|x-1|<24[/tex]We can first of all divide both sides by 4, so that the inequality becomes
[tex]|x-1|<6[/tex]Because of the absolute value, the inequality can be written as:
[tex]-6The inequality now has three sides.Adding 1 to all three parts, we have
[tex]\begin{gathered} -6+1Therefore, the solution to the given inequality is in the interval (-5, 7)I need to check if I am heading to the right way.
Answers
Answer:
[tex]12\sqrt[]{2}[/tex]Explanation:
The sketch of the situation is given below
We need to find length B.
Now Pythagoras's theorem gives
[tex]B^2+(4\sqrt[]{7})^2=20^2[/tex]which simplifies to
[tex]B^2+112=400[/tex]subtracting 112 from both sides gives
[tex]B^2=400-112[/tex][tex]B^2=288[/tex]Taking the square root of both sides gives
[tex]B=\sqrt[]{288}[/tex][tex]\boxed{B=12\sqrt[]{2}\text{.}}[/tex]which is our answer!
explain the difference between six times the sum of x and y. And the sum of six times x and y.
Answers
We want to express mathematically the following expressions:
1. six times the sum of x and y
2. the sum of six times x and y
1Since the sum of x and y is expressed by
x + y
then six times it is expressed by their multiplication by 6:
6 · (x + y)
2Since six times x is expressed by the multiplication
6x
and six times y is expressed by the multiplication
6y
then the sum of them is expressed by
6x + 6y
Find the value of x. Assume that all segments that appear to be tangent.5.68.4
Answers
Answer:
11.2
Explanation:
We can use the Pythagorean theorem to solve for x as shown below;
[tex](5.6+8.4)^2=x^2+8.4^2[/tex][tex]\begin{gathered} 14^2=x^2+70.56 \\ x^2=196-70.56 \\ x^2=125.44 \end{gathered}[/tex]We can now take the square root of both sides of the equation;;
[tex]\begin{gathered} x=\sqrt[]{125.44} \\ x=11.2 \end{gathered}[/tex]can someone help me with my problem
Answers
To find the area of the composite figure, we need to break it apart into known shapes.
We find area of all the broken pieces and sum it to find the area of the whole.
Let's see the composite figure, broken down:
• Region 1 is a trapezoid
,• Region 2 is another trapezoid but exactly same area as the first
,• Region 3 is a rectangle
,• Region 4 is a triangle
Now, let's label the figure with side lengths. The picture is shown below:
Now let's find the area of each region by using respective formulas for areas of shapes we know:
Area of Region 1
Region 1 is a trapezoid and the area will be:
[tex]A=\frac{1}{2}(b_1+b_2)h[/tex]Where
b1 and b2 are the two bases (top and bottom) respectively and h is the height
Given,
b1 = 2
b2 = 6
h = 2
The area is:
[tex]\begin{gathered} A=\frac{1}{2}(b_1+b_2)h \\ A=\frac{1}{2}(2+6)(2) \\ A=\frac{1}{2}(8)(2) \\ A=8 \end{gathered}[/tex]Area of Region 2
This trapezoid is exactly same as the Region 1 trapezoid.
Its area would also be "8".
Area of Region 3
This is a rectangle with length "12" and height "4".
The area is found by multiplying the length and height, thus:
A = 12 * 4 = 48
Area of Region 4
This is a triangle. The area is given by the formula:
[tex]A=\frac{1}{2}bh[/tex]Where
b is the base and h is the height
Given,
b = 12
h = 4
So, we have:
[tex]\begin{gathered} A=\frac{1}{2}bh \\ A=\frac{1}{2}(12)(4) \\ A=24 \end{gathered}[/tex]Thus,
The Total Area of the composite figure is:
8 + 8 + 48 + 24 = 88 square units(square root)7 - x = x + 5. Find x
Answers
.We have the following equation,
[tex]\sqrt[]{7-x}=x+5[/tex]First, we can note that the term into the radical must be zero or positive, that is,
[tex]\begin{gathered} 7-x\ge0 \\ \text{which means} \\ x\le7 \end{gathered}[/tex]Then, by squaring both sides, we have
[tex]\begin{gathered} 7-x=(x+5)^2 \\ or\text{ equivalently,} \\ 7-x=x^2+10x+25 \end{gathered}[/tex]Now, by subtracting 7 to both sides, we have
[tex]-x=x^2+10x+18[/tex]and by adding x to both sides, we get
[tex]\begin{gathered} 0=x^2+11x+18 \\ or\text{ equivalently,} \\ x^2+11x+18=0 \end{gathered}[/tex]Now, we can use the quadratic formula, that is,
[tex]x=\frac{-11\pm\sqrt[]{11^2-4(1)(18)}}{2}[/tex]which gives
[tex]\begin{gathered} x=\frac{-11\pm\sqrt[]{121-72}}{2} \\ x=\frac{-11\pm\sqrt[]{49}}{2} \\ x=\frac{-11\pm7}{2} \end{gathered}[/tex]then, the solutions are
[tex]\begin{gathered} x=\frac{-4}{2}=-2 \\ \text{and} \\ x=\frac{-18}{2}=-9 \end{gathered}[/tex]Now, we know that an extraneous solution is a solution that does not work. Then, by substituting x=-9 into the given equation, we have
[tex]\sqrt[]{7-(-9)}=-9+5[/tex]which gives
[tex]\begin{gathered} \sqrt[]{7+9}=-4 \\ \sqrt[]{16}=-4 \\ 4=-4 \end{gathered}[/tex]which is an absurd result. Then, x=-9 is an extraneous solution.
On the other hand, by substituting x=-2, we obtain
[tex]\begin{gathered} \sqrt[]{7-(-2)}=-2+5 \\ \sqrt[]{7+2}=3 \\ \sqrt[]{9}=3 \\ 3=3 \end{gathered}[/tex]which is correct.
Therefore, the answers are:
[tex]\begin{gathered} \text{Extraneous solution: x=-9} \\ \text{True solution: x=-2} \end{gathered}[/tex]A tractor dealer puts a markup of 22% on cost on a part for which it paid $480.Finda)the selling price as a percent of cost, b) the selling price, c)the mark up
Answers
Cost = $480
Markup = 22% or 22/100 = 0.22
Thus,
Markup = 0.22 of 480
or,
0.22 * 480 = 105.6
Markup = $105.60
The Selling Price is cost + markup, thus,
Selling Price = 480 + 105.60 = $585.60
a)
We need to find selling price as a percentage of cost.
For that, we divide selling price by cost and multiply by 100. So,
[tex]\frac{SP}{C}=\frac{585.60}{480}\times100=122\%[/tex]Answer:
122%b)
The selling price is
$585.60c)
The markup is
$105.60
Two angles <1 and <2 are supplementary. <1 is a right angle. What type of angle is <2
Answers
Supplementary angles are angles that add up to 180 degrees.
So, if angle 1 is a right angle it means that is 90 degrees.
So:
angle 1 + angle 2 = 180°
90°+ angle 2 = 180°
angle 2 = 180°-90°
dividing polynomials simplify (p^3-6) ÷ (p-1)
Answers
To divide
(p³ - 6) by (p-1)
set the division symbol and insert the numbers.
Divide p³ by p, the result is p²
write the result on top of the root sign
Multiply p² by (p-1)
write the result below (p³ ) inside the root sign
subtract
Divide p² by p, the reust is p
write the p on top of the root sign
multiply p by (p-1) and write the result inside the root sign
subtract
Take down 6
Divide p by p
The result is 1
write the result at the top of the root sign
Multiply p-1 by 1
write the result inside the root sign
subtract
write
The reuslt when you divide (p³ - 6) by (p-1) is;
[tex](p^2+p-1)+\frac{5}{(p-1)}[/tex]A cake normally priced at $14.00 is discounted 15%. What is the new price of the cake?
Answers
The original price of the cake was $14.We were told that it was discounted 15%. Recall, percentage is expressed in terms of 100. Thus, the amount by which it was discounted is
15/100 x 14
= 2.1
To get the new price, we would subtract the amount by which it was discounted from the original price. Thus, the new price of the cake is
12 - 2.1
= 11.9
The new price of the cake is $11.9
Solve 2 log 5 + log; x = logz 100.
Answers
The given expression is
[tex]2\log _75+\log _7x=\log _7100[/tex]First, we have to use the power property of logarithms, which states
[tex]a\log x=\log x^a[/tex]So, we have
[tex]\log _75^2+\log _7x=\log _7100[/tex]Now, we use the product property of logarithm, which states
[tex]\log a+\log b=\log a\cdot b[/tex]Then, we have
[tex]\log _75^2\cdot x=\log _7100[/tex]We can eliminate logarithms
[tex]5^2\cdot x=100[/tex]Now, we solve for x
[tex]\begin{gathered} 25x=100 \\ x=\frac{100}{25}=4 \end{gathered}[/tex]Therefore, the right answer is 4.Back-to-school SuppliesPOW ID: 1669PrintProblemHeather spent part of her Labor Day getting the last of her school supplies. Shepurchased the following:one box of 216 tissues for $1.29one calculator for $7.99five 3-subject notebooks for 5.69 each• one 10-pack of blue pens for $.99. one dozen No. 2 pencils for $1.09one 5-pack of colored pens for $2.49o two 150-sheet packs of loose-leaf paper for $.99 each• one 3-ring binder for $1.99• one glue stick for $.44Help Heather calculate her total bill, keeping in mind that she must pay 5% sales tax.Your short answer should state the total using a complete sentence. Be sure your explanation includeshow to calculate 5% tax
Answers
Given Data:
The cost of one box of 216 tissues is $1.29.
The cost of one calculator is $ 7.99.
The cost of five 3-subject notebooks is $ 0.69 each.
The cost of one 10-pack blue pens is $ 0.99.
The cost of one dozen No.2 pencils is $ 1.09.
The cost of one 5-pack of colored pens is $ 2.49.
The cost of two 150-sheet packs of loose-leaf paper is $ 0.99 each.
The cost of one 3-ring binder is $1.99.
The cost of one glue stick is $0.44.
The sales tax is 5%.
The total cost excluding sales tax can be determined as,
[tex]\begin{gathered} c=(1.29)+(7.99)+(3\times0.69)+(0.99)+(1.09)+(2.49)+(2\times0.99)+(1.99)+(0.44) \\ =21.71. \end{gathered}[/tex]The sales tax can be determined as,
[tex]\begin{gathered} ST=c\times\frac{5}{100} \\ =21.71\times\frac{5}{100} \\ =1.0855 \end{gathered}[/tex]Thus, the sales tax is 1.0855.
The total bill can be determined as,
[tex]\begin{gathered} A=c+ST \\ =21.71+1.0855 \\ =22.7955 \end{gathered}[/tex]Thus, the total bill including sales tax is $ 22.7955.
Archeologists found a previously unknown pyramid in Central America, shown in the figure. The media is interested in the volume of this pyramid. Find the volume of the pyramid.
Answers
SOLUTION:
We are to find the volume of the given pyramid;
[tex]\text{Volume = }\frac{base\text{ area X height}}{3}[/tex][tex]\begin{gathered} \text{Length of the base square = 8 yd.} \\ \text{height of the pyramid = 3 yd.} \end{gathered}[/tex]The volume of the pyramid is;
[tex]\frac{8X8X3}{3}=64yd.^3[/tex]CONCLUSION:
The volume of the given pyramid is 64 cubic yards.
Samira wants to randomly choose her first day of a seven-day vacation sometime between the first week of June and the middle of July Which of the following would be the most appropriate sampling technique? OA. She could roll a six-sided cube, with each side representing Sunday through Friday. CB. She could create a frequency table to represent the different days. oc. She could use a random number generator with each day assigned one number D. She could flip a coin to determine which month to go on vacation.
Answers
Answer
Option C is correct.
She could use a random number generator with each day assigned one number.
Explanation
The thing about sampling of this matter is that it must be very random. And for random sampling, all the possible outcomes must have the same chance of happening.
Option A cannot be correct because a six-sided cube has only spaces for 6 days. This leaves out one of the 7 days.
Option B cannot be correct too as a frequency table would mean that that she recorded the days that she has picked to start the vacation a couple of times. This isn't random enough as not all of the days will evidently have the same chance of being picked.
Option C seems to be the most correct option because it is the most random of the techniques. She assigns different numbers to each of the 7 days, one for each day. Then she uses the random number generator to pick one number and subsequently pick the day that corresponds to that number.
Option D cannot be correct. This is because a coin only has two possible outcomes, and we have 7 outcomes to test for.
Hope this Helps!!!
log(1098) - () A. 106 B. 60 C. X O D. 6x
Answers
Given:
[tex]\log (10^{6x})=?[/tex]By the logarithmic property, we have:
[tex]\log (a^b)=b\log a[/tex]We have,
[tex]\log (10^{6x})=6x\log 10[/tex]Now, we know that log 10 =1, so
[tex]\begin{gathered} \log (10^{6x})=6x\log 10 \\ =6x\times1 \\ =6x \end{gathered}[/tex]Hence, the required answer is 6x.
Therefore, OPTION D) 6x is correct.
What isb the area of the cylinder with a radius of 4ft and height of 10 ft
Answers
R = 4ft
h = 10 ft
Formula
[tex]\begin{gathered} A=2\pi r(r+h) \\ A=2\pi\cdot4(4+10) \\ A=2\pi\cdot4(14) \\ A=2\pi\cdot56 \\ A=351.68 \end{gathered}[/tex]The area would be 351.7 ft^2
__________ Angles: Two angles whose sum is 180°
Answers
We have that Supplementary Angles are those angles whose sum is 180 degrees.
If we have For example, msupplementary angles.
mTherefore, the answer is Supplementary Angles.
simplify [tex] \sqrt{324} [/tex]A. 16B. 17C. 18D. 19
Answers
The solution as I explained is C. 18.