In order to drive from your home to the store, there has to be at least one operating route. Once a bridge is closed on a route, that route is no longer operating. The probability that bridge 1 is open is 0.8, bridge 2 is 0.93, bridge 3 is 0.9, bridge 4 is 0.92, and bridge 5 is 0.94. What is the probability you can drive to the store? Answer to 3 decimals.
Answers
Answer:
The probability of driving to the store is 0.969
Step-by-step explanation:
The remaining part of the question is attached
Solution
There are only two possible ways –
a) Route comprising of bridges 123
b) Route comprising of bridge 45
Probability of success while traveling through Route 123 = P(Bridge 1 open) x P(Bridge 2 open) x P(Bridge 3 open)
= 0.9 x 0.92 x 0.91
= 0.75348
P(Route 123 is closed) = 1 - 0.75348 = 0.24652
Probability of success while traveling through Route 45 =
P(Bridge 4 open) x P(Bridge 5 open)
= 0.94 x 0.93
= 0.8742
P(Route 45 is closed) = 1 - 0.8742 = 0.1258
To travel to store, atleast one route from 123 and 45 should be open.
Probability that you can drive to store :
= P(atleast one route from 123 and 45 is open)
= 1 - P(Both routes 123 and 45 are closed)
= 1 - P(123 is closed)*P(45 is closed)
= 1 - 0.24652*0.1258
= 1 - 0.031012216
= 0.968987784
~ 0.969
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AB ≅ CD
DB ≅ DC
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Answers
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Step-by-step explanation:
\frac{-3y}{-3}=\frac{-6}{-3}
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That should be right
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Step-by-step explanation:
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good luck :)
i hope this helps
brainliest would be highly appreciated
have a nice day!
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Step-by-step explanation:
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Answers
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How to solve for the probabilityWe have the following details to solve the problem with
The people that did not purchase any costume = 103
Those that purchased exactly one costume = 161
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We are to find the probability that the next would purchase more than 1 costume.
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Read more on probability here:
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Step-by-step explanation:
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[tex] \underline{ \underline{ \large{ \red{ \tt{✧ E\: X \: P \: L \: A \: N \: A \: T\: I \:O\: N}}}}} : [/tex]
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⟶Function is a special type of relation. Function is the refinement of relation. In a relation from A to B , every element of Set A has only one ( distinct ) image in B. In other words , if no two different ordered pairs have the same first component , then it is a function.
# STUDY TIP :
♕ Have a hard time memorising ?
Read it 10 times Say it 10 times Write it 2 timesツ Hope I helped! ♡
✎ Let me know if you have any questions!
[tex] ♪ \underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning ☄}}}[/tex]
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Answers
Answer:
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Answers
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Step-by-step explanation:
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