In parallelogram MNPQ, m∠M=6x+10°m∠M=6x+10° and m∠N=5x+10.5°m∠N=5x+10.5°. How many degrees is ∠M?

15YD

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

Yes. Explanations vary. Sample explanation: The weight itself doubles, so

any measurement of the weight using the same units will also double. We

can also see that by saying if the weight is x pounds, then double that weight

would be 2x pounds. The weight in kilograms will be x ÷ 2.2, and the double

weight will be or (2x) ÷ 2.2 2(x ÷ 2.2), which is also double.

Answer: 2

Step-by-step explanation: It is 2. You can use the vertex formula x= (-b/2a) 4/2(1), which is 2 and x=2 is the x intercept.

Step-by-step explanation:

what number you need help with

Answer:

=

Step-by-step explanation:

|-8|?|8|

8 ? 8
8 = 8
Hope this helps :)

The equation can be used to find the missing leg in the triangle [tex]20^{2} = 16^{2} +a^{2}[/tex].

A right-angle triangle is a triangle that has a side opposite to the right angle the largest side and is referred to as the hypotenuse.

It is given that a right triangle has a side length of 16 meters and a hypotenuse of 20 meters.

From a Pythagoras theorem

[tex]b^{2} = c^{2} +a^{2} \\20^{2} = 16^{2} +a^{2}\\20^{2}-16^{2} =a^{2}\\a^{2} = 20^{2}-16^{2} \\[/tex]

Thus, the equation can be used to find the missing leg in the triangle [tex]20^{2}-16^{2} =a^{2}[/tex].

Learn more about the right-angle triangle;

https://brainly.com/question/5474676

Answer:

Its C
a2 + 162 =202

Step-by-step explanation:

Answer:

Portugal in 1815 colonize Brazil.

The volume of the larger cone is about 18.8 cubic inches greater than the volume of the small cone

The volume of a cone is calculated as:

For the small cone, we have the following parameters:

Diameter = 3 inches

Height = 3.5 inches

Diameter = 4.5 inches

Height = 5.1 inches

So, the volume of the large cone is:

Calculate the difference of both volumes

Hence, the volume of the larger cone is about 18.8 cubic inches greater than the volume of the small cone

Read more about volumes at:

brainly.com/question/8994737

Answer:

The area is about 96.06 or 96.1

Step-by-step explanation:

I tried my best to solve it, I'm sorry if it's wrong.

Scalene triangle: if none of the three sides of a triangle are equal to each other, it is called a scalene triangle.

Equilateral triangle: An equilateral triangle is a triangle in which all three sides have the same length.

Isosceles triangle: An isosceles triangle is a triangle that has two sides of equal length.

Acute Triangle: An acute triangle is a triangle with three acute angles.

Right Triangle: A triangle in which one of the interior angles is 90° is called a right triangle.

Obtuse Triangle: An obtuse triangle is a triangle with one obtuse angle and two acute angles.

Answer:

fx is 4, gx is 3, hx is anything greater than, not equal to, 4.

Hope this helps!

[tex]S=\frac{1}{2}\times4\times4=8\ {\rm units}^2[/tex]

[tex]\left\{co\ calculate\right.\ \ \ \ \ \ \ \ \ \ \left\{S=\frac{1}{2}\right.\left.\ ah\right\}[/tex]

I hope this helps you

:)

Answer: 40 degrees

Step-by-step explanation:

Answer:

  a. 314.2 in²

  b. 36 m²

  c. 60 m²

Step-by-step explanation:

The areas of these plane figures can be found by substituting the given dimensions into the area formula.

The area of a circle can be found from its diameter to be ...

  A = (π/4)d²

  A = (π/4)(20 in)² = 100π in² ≈ 314.2 in²

__

The area of a parallelogram can be found as ...

  A = bh

  A = (9 m)(4 m) = 36 m²

__

The area of a triangle can be found from ...

  A = 1/2bh

  A = 1/2(15 m)(8 m) = 60 m²

_____

Additional comment

A triangle with sides 17 and 15 and height 8 cannot be obtuse. It is a right triangle. (Those side lengths are a Pythagorean triple.)

Answer:

10 + (8 - 4)2÷2

10 + (4)2 ÷2

10 + 8 ÷ 2

10 + 4

= 14

Answer:

x = 3

Step-by-step explanation:

A only 1 solution

B

4(2x - 5) = 4 ( divide both sides by 4 )

2x - 5 = 1 ( add 5 to both sides )

2x = 6 ( divide both sides by 2 )

x = 3

Answer:

Step-by-step explanation:

Isolate it by the term of x from one side of the equation.

First, divide by 4 from both sides.

[tex]\sf{\dfrac{4\left(2x-5\right)}{4}=\dfrac{4}{4}}[/tex]

Then, solve.

4/4=1

Rewrite the problem down.

2x-5=1

Add by 5 from both sides.

[tex]\sf{2x-5+5=1+5}[/tex]

Solve.

1+5=6

2x=6

Divide by 2 from both sides.

2x/2=6/2

Solve.

Divide the numbers from left to right.

6/2=3

x=3

I hope this helps you! Let me know if my answer is wrong or not.

Answer:

B) [tex]x^{2} -16x+64=-21+64[/tex]

Step-by-step explanation:

The first step to completing the square is by dividing "b" by 2, squaring that number, and adding it on both sides. In this case, 16/2 = 8 and 8 squared = 64. In answer choice B, this is correctly added to both sides of the equation.

See the full steps for completing the square below. If you're still stuck on this, I suggest watching the completing the square video on Tutors.com. It is very helpful!

Have a great day!

other points:

x    y

-2  12

-1   3

0   0

1    3

2   12

Let's see

Take some cordinates

Graph attached

Answer:

Check the last answer...

Step-by-step explanation:

Look at image above...

Answer:

answer is a

Step-by-step explanation:

ur welcome

Answer

20.5

Step-by-step explanation:

You multiply 5.4 and 3 to get 16.2. Then you add 16.2 and 4.3 to get 20.5.

Answer:

There are many areas but

Step-by-step explanation:

Area of square is L × W

where you multiply both length × width you get the answers squared

Area of a cube is L × W × H

this is where you multiply all length × width × height and get the answer cube

Answer:

34

Step-by-step explanation:

Sum of two numbers = 7

1+6

2+5

3+4

34+9=43

Answer/Step-by-step explanation:

 All of the solutions to the equation 3x^2 - 12 = 0 are x = 12 and x = -2

Answer: False

Explanation:

[tex]3x^2-12+12=0+12[/tex]

[tex]3x^2=12[/tex]

[tex]\frac{3x^2}{3}=\frac{12}{3}[/tex]

[tex]x^2=4[/tex]

[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=\sqrt{4},\:x=-\sqrt{4}[/tex]

[tex]x=2,\:x=-2[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

There are two unique solutions to the equations (x-3)^2 = 16

Note: Each variable in the matrix can have only one possible value, and this is how you know that this matrix has one unique solution.

Answer: True

Explanation:

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=7,\:x=-1[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Ths solutions for the equation 2(x-3)^3 - 18 = 0 are x = 6 and x = 0

Answer: False

Explanation:

[tex]2\left(x-3\right)^3-18+18=0+18[/tex]

[tex]2\left(x-3\right)^3=18[/tex]

[tex]\frac{2\left(x-3\right)^3}{2}=\frac{18}{2}[/tex]

[tex]\left(x-3\right)^3=9[/tex]

[tex]\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}[/tex]

[tex]=\sqrt[3]{9}+3,\:x=\frac{6-\sqrt[3]{9}}{2}+i\frac{\sqrt[3]{9}\sqrt{3}}{2},\:x=\frac{6-\sqrt[3]{9}}{2}-i\frac{\sqrt[3]{9}\sqrt{3}}{2}[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~The solutions for the equation 2(x-5)^2-8=0 are x = 7 and x = -7

Answer: False

Explanation:

[tex]2\left(x-5\right)^2-8+8=0+8[/tex]

[tex]2\left(x-5\right)^2=8[/tex]

[tex]\frac{2\left(x-5\right)^2}{2}=\frac{8}{2}[/tex]

[tex]\left(x-5\right)^2=4[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=7,\:x=3[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation (x + 3)^2-25 = -8 are x = 2 and x = -8

Answer: False

Explanation:

[tex]\left(x+3\right)^2-25+25=-8+25[/tex]

[tex]\left(x+3\right)^2=17[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=\sqrt{17}-3,\:x=-\sqrt{17}-3[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 2(2x-1)^2=18 are x = 5 and x = -4

Answer: False

Explanation:

[tex]\frac{2\left(2x-1\right)^2}{2}=\frac{18}{2}[/tex]

[tex]\left(2x-1\right)^2=9[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=2,x=-1[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The only solution for equation (2x-1)^2-49=0 is x = 4

Answer: False
Explanation:

[tex]\left(2x-1\right)^2-49+49=0+49[/tex]

[tex]\left(2x-1\right)^2=49[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=4,\:x=-3[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 3(x+2)^2 - 3 = 0 are x = -3 and x = -1

Answer: True
Explanation:

[tex]3\left(x+2\right)^2-3+3=0+3[/tex]

[tex]3\left(x+2\right)^2=3[/tex]

[tex]\frac{3\left(x+2\right)^2}{3}=\frac{3}{3}[/tex]

[tex]\left(x+2\right)^2=1[/tex]

[tex]\mathrm{For\:}\left(g\left(x\right)\right)^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=-1,\:x=-3[/tex]

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The solutions for the equation 5x^2 - 180 = 0 are x = 6 and x  = -6

Answer: True

Explanation:

[tex]5x^2-180+180=0+180[/tex]

[tex]5x^2=180[/tex]

[tex]\frac{5x^2}{5}=\frac{180}{5}[/tex]

[tex]x^2=36[/tex]

[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]

[tex]x=\sqrt{36},\:x=-\sqrt{36}[/tex]

[tex]x=6,\:x=-6[/tex]

~Lenvy~

To prove that circle A is similar to circle B, it needs to be moved 1 unit right and 6 units up and then dilated by a scale factor of 3/4

Transformation is the movement of a point from its initial location to a new location.

Types of transformation are rotation, translation, dilation and reflection.

To prove that circle A is similar to circle B, it needs to be moved 1 unit right and 6 units up and then dilated by a scale factor of 3/4

Find out more on transformation at: https://brainly.com/question/4057530

Answer:

102 dollars

Step-by-step explanation:

Answer:

the correct answer is x = 3

Step-by-step explanation:

you solve this by moving all the terms that dont contain x to the right side and solve the equation.

hope this helps

have an awesome day -TJ

pls mark brainliest if this helps you :)