In right triangle ΔABC, ∠C is a right angle, AC = 20 and m∠A = 41º. Find AB to the nearest tenth.
I NEED HELP ASAP
PLEASE!!!!!!!! STEP BY STEP

Answers

Answer 1

Answer:

AB = 26.5º

Step-by-step explanation:

cosA = adj/hyp

cosA = AC/AB

cos41 = 20/AB

Multiply both sides by AB

AB * cos41 = 20

Divide both sides by cos41

AB = 20/cos41

AB = 26.5º

Answer 2

Answer:

AB = 26.5

Explanation:

ΔABC is right in the angle ∠C

in this case AB is the hypotenuse of the triangle ABC

according to the given data we will use the length of AC which is the adjacent side to the angle ∠A and the Cosine of the angle ∠A in the following formula:

the hypothenuse = adjacent side / cosine of the angle

AB = 20 / cos(41°)

AB = 26.5


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Answers

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Step-by-step explanation:

Given

See attachment for complete question

Required

The bacteria with the smaller initial population

The initial population is at x = 0

For bacteria A;

[tex]A(x) = 600[/tex] when [tex]x = 0[/tex]

For bacteria B, we have:

[tex]B(x) = 500(2)^x[/tex]

Substitute 0 for x

[tex]B(x) = 500(2)^0[/tex]

[tex]B(x) = 500*1[/tex]

[tex]B(x) = 500[/tex]

So; when x = 0

[tex]A(x) = 600[/tex] and [tex]B(x) = 500[/tex]

Because; 500 < 600

We can conclude that B has a smaller initial population of 500

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