In terms of energy, when atoms chemically bond to form a stable compound:_____.
A. Energy is released.
B. Energy can either be released or consumed depending upon the bond formed.
C. Energy is transferred from one atom to another.
D. Energy is consumed.

The complete question is as follows: If 1.04 g of chlorine gas occupies a volume of 872 mL at a particular temperature and pressure, what volume will 2.08 g of chlorine gas occupy under the same conditions ?

Answer: A volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.

Explanation:

Given: [tex]Mass_1[/tex] = 1.04 g,      [tex]V_{1}[/tex] = 872 mL

[tex]Mass_2[/tex] = 2.08 g,                [tex]V_{2}[/tex] = ?

As molar mass of chlorine is 35.5 g/mol.

Number of moles is the mass of a substance divided by its molar mass.

Hence, moles of chlorine present in 1.04 g chlorine gas is calculated as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.04 g}{35.5 g/mol}\\= 0.029 mol[/tex]

Also, moles of chlorine present in 2.08 g chlorine gas is calculated as follows.

[tex]Moles = \frac{2.08 g}{35.5 g/mol}\\= 0.058 mol[/tex]

Formula used to calculate the volume occupied by 2.08 g of chlorine gas is as follows.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{872 L}{0.029 mol} = \frac{V_{2}}{0.058 mol}\\V_{2} = 1744 L[/tex]

Thus, we can conclude that a volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.

Answer:

3s and 3p

Explanation:

From the question given above, the following data were obtained:

Electronic configuration =>

1s² 2s²2p⁶ 3s²3p⁴

Location of valence electron =?

From the electronic configuration given above, we can see clearly that the atom has three (3) shells.

Valence electron(s) are located at the outer most shell of an atom.

The outer most shell of the atom above is 3s and 3p.

Therefore, 3s and 3p will contain the valence electron(s)

Answer:

P = 5.70 atm

Explanation:

Use PV = nRT

P(1.52 L) = (0.52 moles)(0.0821)(203 K)

P = 5.701628947 atm

Answer:

Precise but not accurate.

Explanation:

We can tell the performance of the balance is precise, because the repeated measurements give values close to one another.

However, the performance of the balance is not accurate, as the mean value of the repeated measurements (195.587) is not close to the value considered as true (in this case the standard calibration mass with a certified value of 200.002 g).

Answer:

The total energy absorbed is 32.171 kilojoules.

Explanation:

The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:

[tex]Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})][/tex] (1)

Where:

[tex]m[/tex] - Mass of the ice, in kilograms.

[tex]c_{i}[/tex] - Specific heat of ice, in kilojoules per kilogram-degree Celsius.

[tex]c_{w}[/tex] - Specific heat of water, in kilojoules per kilogram-degree Celsius.

[tex]L_{f}[/tex] - Latent heat of fusion, in kilojoules per degree Celsius.

[tex]T_{1}[/tex] - Initial temperature of water, in degrees Celsius.

[tex]T_{2}[/tex] - Fusion point of water, in degrees Celsius.

[tex]T_{3}[/tex] - Final temperature of water, in degree Celsius.

[tex]Q[/tex] - Total energy absorbed, in kilojoules.

If we know that [tex]m = 50.5\times 10^{-3}\,kg[/tex], [tex]c_{i} = 2.090 \,\frac{kJ}{kg\cdot^{\circ}C}[/tex], [tex]c_{w} = 4.180\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]L_{f} = 334\,\frac{kJ}{kg}[/tex], [tex]T_{1} = -15\,^{\circ}C[/tex], [tex]T_{2} = 0\,^{\circ}C[/tex] and [tex]T_{3} = 65\,^{\circ}C[/tex], then the total energy absorbed is:

[tex]Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right][/tex][tex]Q = 32.171\,kJ[/tex]

The total energy absorbed is 32.171 kilojoules.

Answer:

HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER

Answer:

Explanation:

The Chemical Equation for each one of these compounds would be the following

Sodium Chloride: NaCl  

This compound contains 1 Sodium atom and 1 Chlorine atom

Sodium Oxide: Na₂O

This compound contains 2 Sodium atoms and 1 Oxygen atom.

Answer:

Explanation:

What do you understand about equivalent weight for lime requirement?

If field data are not available, lime requirements can be determined with the solution is added to a given weight or volume of soil and the pH is measured.  Each milligram per liter of sodium bicarbonate is equal to 0.56 mg/L of alkalinity. A winter wheat crop grown on a light sand soil in a low rainfall area will mean an

N2 + 3H2  -->  2NH3

Answer: 6 moles of hydrogen are needed to react with two moles of nitrogen.

Explanation:

Answer:

1. 2.510kJ  

2. Q = 1.5 kJ

Explanation:

Hello there!

In this case, according to the given information for this calorimetry problem, we can proceed as follows:

1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:

[tex]1cal=4.184J\\\\1kJ=1000J[/tex]

Then, we perform the conversion as follows:

[tex]600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ[/tex]

2. Here, we use the general heat equation:

[tex]Q=mC(T_2-T_1)[/tex]

And we plug in the given mass, specific heat and initial and final temperature to obtain:

[tex]Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ[/tex]

Regards!

Answer:

false

Explanation:

this is because , high temperature speeds up the the random motion of particles which leads to high dissolution

Answer:

decreases by 10 gram

Explanation:

Answer:

Ok

Explanation:

Answer:

2

Explanation:

Step 1: Write the generic decomposition reaction

KClOₓ ⇒ KCl + O₂

Step 2: Calculate the moles of O₂

At STP, 1 mole of an ideal gas occupies 22.4 L.

50.4 L × 1 mol/22.4 L = 2.25 mol

Step 3: Calculate the mass corresponding to 2.25 moles of O₂

The molar mass of O₂ is 32.00 g/mol.

2.25 mol × 32.00 g/mol = 72 g

Step 4: Determine the value of x

Every 156 g of KClOₓ there are 72 g of oxygen. The mass percent of O is:

%O: 72 g/156 g × 100% = 46.2%

In KClO, the mass percent of O is: 32.00 g/90.5 g × 100% = 35.4%

In KClO₂, the mass percent of O is: 64.00 g/138.5 g × 100% = 46.2%

Then, x = 2

Answer:

the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

Explanation:

Given the data in the question;

[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄  [tex]CaY^{2-[/tex]

Formation constant Kf

Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = 5.0 × 10¹⁰

Now,

[[tex]y^{4-[/tex]] = [tex]\alpha _4CH_4Y[/tex]; ∝₄ = 0.35

so the equilibrium is;

[tex]Ca^{2+[/tex] + [tex]H_4Y[/tex] ⇄  [tex]CaY^{2-[/tex] + 4H⁺

Given that; [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex]     { 1 mol [tex]Ca^{2+[/tex]  reacts with 1 mol [tex]H_4Y[/tex]  }

so at equilibrium, [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] = x

∴

[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄  [tex]CaY^{2-[/tex]

x        + x         0.010-x

since Kf is high, them x will be small so, 0.010-x is approximately 0.010

so;

Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) =  [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] )  = 5.0 × 10¹⁰

⇒ [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] )  = 5.0 × 10¹⁰

⇒ 0.010 / ( [x][ 0.35 × x] )  = 5.0 × 10¹⁰

⇒ 0.010 / 0.35x²  = 5.0 × 10¹⁰

⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 0.010 / 1.75 × 10¹⁰

⇒ x² = 5.7142857 × 10⁻¹³

⇒ x = √(5.7142857 × 10⁻¹³)

⇒ x = 7.559 × 10⁻⁷

Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷

Answer:

Molarity: 0.522M

Percentage by mass: 2.36 (w/w) %

Explanation:

Formic acid, HCOOH reacts with NaOH as follows:

HCOOH + NaOH → NaCOOH + H₂O

To solve this question we must find the moles of NaOH added = Moles formic acid. Taken into account the dilution that was made we can find the moles -And molarity of formic acid and its percentage by mass as follows:

Moles NaOH = Moles HCOOH:

0.01580L * (0.1322mol / L) =0.002089 moles HCOOH

Moles in the original solution:

0.002089 moles HCOOH * (25mL / 10mL) = 0.005222 moles HCOOH

Molarity of the solution:

0.005222 moles HCOOH / 0.01000L =

Mass HCOOH in 1L -Molar mass: 46.03g/mol-

0.522moles * (46.03g / mol) = 24.04g HCOOH

Mass solution:

1L = 1000mL * (1.02g / mL) = 1020g solution

Mass percent:

24.04g HCOOH / 1020g solution * 100

2.36 (w/w) %

Answer:

33.30 grams of CaCl2 will be required

Explanation:

Given,

Volume of solution, V= 250 ml

Molarity of solution, M= 1.20 mol/L

Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111

We know,

Required mass, W= SVM/1000

Now,

W = (111 X 250 X 1.20)/1000

    = 33300/1000

    = 33.30

Therefore, 33.30 grams of Calcium Chloride will be required.

Answer:

Sunlight, Soil, Rocks, Temperature and dead deer

Explanation:

You could say the dead tree is now an abiotic factor because biotic factors refer to living things

Answer:

[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to  write the chemical equation for this reaction as shown below:

[tex]CoS(s)\rightleftharpoons Co^{2+}(aq)+S^{2-}(aq)[/tex]

Thus, since solids are not included in equilibrium expressions, we can set this one up as follows:

[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]

Regards!

Answer:

[tex]V_2=600mL[/tex]

Explanation:

Hello there!

In this case, according to this dilution process, it is possible for us to solve this problem via the following equation:

[tex]V_2M_2=V_1M_1[/tex]

Thus, since we were given the initial and final concentrations but just the initial volume, we calculate the final one as shown below:

[tex]V_2=\frac{V_1M_1}{M_2}\\\\ V_2=\frac{100.0mL*18M}{3.0M}\\\\V_2=600mL[/tex]

Regards!

Answer:

668.9K is the final temperature

Explanation:

The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:

ΔS = n*Cv*ln (T2/T1)

Where ΔS is change in entropy = 200J/K

n are moles = 20.0mol

Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)

T2 is final Temperature and T1 initial temperature = 300K

Replacing:

ΔS = n*Cv*ln (T2/T1)

200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)

0.80186 = ln (T2/300K)

2.23 = T2 / 300K

Given

Li - 59.7 %

N - 40.3 %

Solution,

First get the molar mass of each Atom,

Li- 6.941

N- 14.00

Second find the moles of both atom,

moles of Li = 59.7/6.941 = 8.60

Moles of N = 40.3/14 = 2.87

Third devide both the moles with smaller mole,

first- 8.6÷2.87 = 2.99 ~ 3

second 2.87÷2.87 = 1

Ratio of Li to N is 3:1

The compound is Li3N.

Answer:

A. 201 kPa

Explanation:

We can solve this problem by using Boyle's law, which states:

Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:

We input the data:

And solve for P₂:

Answer:

a. participate in proton transfer - His

b. acts as a nucleophile - Ser

Explanation:

Enzymes are regulated because they are proteins. They are categorize based on how they catalyze. Heat weakens and inactivates the enzymes because of non covalent interaction. His amino acid participate in proton transfer because it is able to act as an acid as well as a base while Ser amino acid can act as nucleophile.

Answer:

covalent bonds

Explanation:

covalent bonds hold together the hydrogen and oxygen atoms of individual H2O molecules. Covalent bonds occur when two atoms share electrons with each other.

Explanation:

It's argon

As argon has atomic number 18 so it's configuration is

1s2, 2s2, 2p6,3s2, 3p6

Hope it will help :)❤

The given electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).

Each number and letter in the electron configuration corresponds to a specific electron orbital and the number of electrons present in that orbital.

In this case, the electron configuration indicates that:

The first shell (n=1) has 2 electrons in the 1s orbital.

The second shell (n=2) has 2 electrons in the 2s orbital and 6 electrons in the 2p orbital.

The third shell (n=3) has 2 electrons in the 3s orbital and 6 electrons in the 3p orbital.

By adding up the total number of electrons (2 + 2 + 6 + 2 + 6), we find that the configuration represents 18 electrons. The element that has 18 electrons is argon, which has an atomic number of 18.

Therefore, the electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).

Know more about argon:

https://brainly.com/question/12032224

#SPJ2

Answer:

A substance that protects cells from the damage caused by free radicals (unstable molecules made by the process of oxidation during normal metabolism). Free radicals may play a part in cancer, heart disease, stroke, and other diseases of aging.

Answer:

Fe(NO₃)₃ = 0.23; FeCl₃ = 0.34

Explanation:

Mass fraction is defined as the ratio between the mass of iron in 1 mol of the compound and the mass of the complete compound.

In Fe(NO₃)₃ there is just 1 atom of Fe that has a molar mass of 55.845g/mol. The molar mass of this compound is 241.86g/mol. Thus, mass fraction is:

55.845g/mol / 241.86g/mol =

In FeCl₃ there is 1 atom of Fe that has a molar mass of 55.845g/mol. The molar mass of this compound is 162.2g/mol. Thus, mass fraction is:

55.845g/mol / 162.2g/mol =