In the activity, Heavy Flying, we looked at constraints for transporting packages from Careful Calculators and Charlie's
Chicken Feed
• Charlie's Chicken Feed containers weigh 40 pounds and are 2 cubic feet in volume.
• Careful Calculators containers weigh 50 pounds and are 3 cubic feet in volume.
On Monday, the pilot transferred containers that totaled 30,000 pounds and 1,600 cubic feet in volume.
1. Write a system of equations to model this situation.
2. Write a matrix equation to model this situation.
3. Solve. How many of each container was transported?
Show your work by uploading a picture or typing in the text box.

Answer: 500 chicken feed and 200 careful calculators

Step-by-step explanation:

2x+3y=1,600

40x+50y=30,000

those are your first two equations

your first matrix equation for A is 2, 3,40,50 and B is 1,600 and 30,000 when you enter those in your calculator and 500 and 200 should be your result.

a) The system of equations are 2x + 3y = 1600 and 40x + 50y = 30000

b) The matrix equations are solved

c) The solution to the system of equations is

The number of chicken feed = 500

The number of careful calculators = 200

The product of two matrices A and B is defined if the number of columns of A is equal to the number of rows of B. The first matrix must have the same number of columns as the second matrix has rows. The number of rows of the resulting matrix equals the number of rows of the first matrix, and the number of columns of the resulting matrix equals the number of columns of the second matrix

Given data ,

Let the number of chicken feed be represented as x

Let the number of careful calculators be y

Now , the equation will be

Charlie's Chicken Feed containers weigh 40 pounds and are 2 cubic feet in volume

And , Careful Calculators containers weigh 50 pounds and are 3 cubic feet in volume

Substituting the values in the matrices , we get

[tex]\left[\begin{array}{ccc}2 &3 \\ 40 &50 \\\end{array}\right] * \left[\begin{array}{ccc}x\\y\\\end{array}\right]= \left[\begin{array}{ccc}1600\\30000\\\end{array}\right][/tex]

On simplifying the matrix equation , we get

2x + 3y = 1600   be equation (1)

40x + 50y = 30000   be equation (2)

Now , multiply equation (1) by 20 , we get

40x + 60y = 32000   be equation (3)

Subtracting equation (2) from equation (3) , we get

10y = 2000

Divide by 10 on both sides of the equation , we get

y = 200 careful calculators

Substituting the value of y in equation (1) , we get

2x + 3 ( 200 ) = 1600

2x + 600 = 1600

Subtracting 600 on both sides of the equation , we get

2x = 1000

Divide by 2 on both sides of the equation , we get

x = 500 chicken feeds

Therefore , the value of x and y are 500 and 200 respectively

Hence , the system of matrix equations are solved

To learn more about matrix multiplication click :

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