in the faculty lecture, dr. salon mentioned a survey that was taken in the slums in nairobi. from this survey, how long did the average person live in the slums?

By performing these statistical computations, you can analyze and interpret the central tendency of your dataset, which helps in understanding the overall pattern and distribution of the data.

It looks like you're seeking information on further statistical computation related to mean, mode, and median.

To calculate the mean, mode, and median of a dataset, follow these steps:

1. Mean: The mean is the average of all data points in a dataset.
  - Step 1: Add up all the data points.
  - Step 2: Divide the sum by the total number of data points.

2. Mode: The mode is the data point that occurs most frequently in a dataset.
  - Step 1: Count the frequency of each data point.
  - Step 2: Identify the data point(s) with the highest frequency.

3. Median: The median is the middle value in a dataset when the data points are arranged in ascending order.
  - Step 1: Arrange the data points in ascending order.
  - Step 2: If there is an odd number of data points, the median is the middle value. If there is an even number of data points, the median is the average of the two middle values.

By performing these statistical computations, you can analyze and interpret the central tendency of your dataset, which helps in understanding the overall pattern and distribution of the data.

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a. The most typical case is desired: Mode. The mode is a useful measure of central tendency when the most typical or common value is of relevance since it denotes the value or category that occurs most frequently in a data collection.

b. The distribution is open-ended: Median. The median is the middle value in a data set when arranged in ascending or descending order. It is a suitable measure of central tendency when the distribution is open-ended or skewed, as it is less affected by extreme values compared to the mean.

c. The data collection has an extreme value: the median. The median is less sensitive to extreme values compared to the mean, making it a better measure of central tendency in data sets with extreme values or outliers.

d. The data are categorical: Mode. The mode is appropriate for categorical data, as it represents the most frequently occurring category or value in the data set.

e. Further statistical computations will be needed: This statement does not indicate a specific measure of central tendency. Further statistical computations may be needed to determine the appropriate measure of central tendency depending on the characteristics of the data and the specific objectives of the analysis.

f. The numbers should be split into two roughly equal groups, one of which should contain the higher values and the other should contain the smaller values: Median.  The median is the value that separates a data set into two equal halves, making it suitable for dividing data into two approximately equal groups based on their values.

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COMPLETE QUESTION-

For these situations, state which measure of central tendency - mean, median, or mode-should be used.

a. The most typical case is desired.

b. The distribution is open-ended.

c. There is an extreme value in the data set.

d. The data are categorical.

e. Further statistical computations will be needed.

f. The values are to be divided into two approximately equal groups, one group containing the larger values and one containing the smaller values.

The value of the length marked x is 61.5

Trigonometric ratios in trigonometry relate the ratio of sides of a right triangle to the respective angle.  The basic trigonometric ratios are sine, cosine, and tangent ratios.  The other important trig ratios, cosec, sec, and cot can be derived using the sin, cos and tan respectively.

First using left hand side

Cos = Adj/Hypo

Cos22 = Adj/50

Adj = 50 * Cos 22

The adj = 50*0.9272

The adj = 46.4

The to find x, using

Cos 41 = 46.4/x

xCos41 =46.4

x = 46.4/Cos41

x = 46.4/.0755

Therefore the value of x = 61.5

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Since BC = 12 and AB = 16, segment BF must be 9, which is one-half of 16.

A triangle is a three-sided polygon that is one of the basic shapes in geometry. It is defined by three points that are connected by three line segments. Triangles have three angles, which add up to 180 degrees, and three sides, which add up to the sum of the lengths of the other two sides. The three sides of a triangle are typically referred to as the base, the height, and the hypotenuse. Triangles come in a variety of forms, from the equilateral triangle, which has three sides of equal length, to the isosceles triangle, which has two sides of equal length, to the scalene triangle, which has three sides of different lengths.

The correct answer is: Segment BF = 9. This can be proved true using the given theorem, since segment DE is parallel to segment BC and segment EF is parallel to AB. Therefore, since BC = 12 and AB = 16, segment BF must be 9, which is one-half of 16.

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The cube roots of 216 written in the rectangular (standard) form are 3 + 3√3, -3+3√3, and 6.

In mathematics, the cube root formula is used to represent any number as its cube root, for example, any number x will have the cube root 3x = x1/3. For instance, 5 is the cube root of 125 as 5 5 5 equals 125.

3√216 = 3√(2x2x2)x(3x3x3)

= 2 x 3 = 6

the prime factors are represented as cubes by grouping them into pairs of three. As a result, the necessary number, which is 216's cube root, is 6.

Therefore, the cube roots of 216 are 3 + 3√3, -3+3√3, and 6.

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Answer:

x<-1/5

Step-by-step explanation:

Imma assume the _ is a - soo

3x-1<-2x

5x<-1

x<-1/5

In the 8 Axioms, 4 and 6 axioms fails to holds and S is not a vector space. Rest of the axioms try to hold the vector space.

To demonstrate that S is not a vector space, we must demonstrate that at least one of the eight vector space axioms fails to hold. Let us examine each axiom in turn:

Therefore, axioms 4 and 6 fail to hold, and S is not a vector space.

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The correct question:

Let S be the set of all ordered pairs of real numbers. Define scalar multiplication and addition on S by α(x₁, x₂) = (αx₁, αx₂); (x₁, x₂) ⊕ (y₁, y₂) = (x₁ + y₁, 0). We use the symbol ⊕ to denote the addition operation for this system in order to avoid confusion with the usual addition x + y of row vectors. Show that S, together with the ordinary scalar multiplication and the addition operation ⊕, is not a vector space. Which of the eight axioms fail to hold?

Answer: about 169.65

Step-by-step explanation:

You do pi r squared multiplied by height over 3.

28.27 is the area of the circle and you multiply is by six because 18/3=6. 28.27x6 = about 169.65

Answer:

C

Step-by-step explanation:

3x - 9y = 9 → (1)

- 2x +2y = 8 ( subtract 2y from both sides )

- 2x = - 2y + 8 ( divide through by - 2 )

x = y - 4

substitute x = y - 4 into (1)

3(y - 4) - 9y = 9

3y - 12 - 9y = 9

- 6y - 12 = 9 ( add 12 to both sides )

- 6y = 21 ( divide both sides by - 6 )

y = [tex]\frac{21}{-6}[/tex] = - [tex]\frac{7}{2}[/tex]

The statement "Some twins are sisters. All twins are siblings. Therefore, some siblings are sisters" is true.

Usually an illustration of a substantial deductive contention in which the conclusion takes coherently from the premises.

The primary introduction states that a few twins are sisters, which suggests that they are female twins. The moment preface states that all twins are kin, which implies that they are related by blood.

In this manner, on the off chance that a few twins are sisters and all twins are kin, it consistently takes after that a few kin are sisters.

It is imperative to note that the conclusion isn't essentially genuine for all kin, as a few kin may be brothers or mixed-gender twins. Be that as it may, the contention is still consistently substantial since the conclusion takes after coherently from the premises 

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If $18,000 is invested at 5. 2% compounded then the full sum of the investment after 7 long years is roughly $24,810.89.

we are able to utilize the equation for compound intrigued:

A = P(1 + r/n)[tex]^{nt}[/tex]

where A is the entire sum of the venture after t a long time, P is the foremost speculation sum, r is the yearly intrigued rate as a decimal, n is the number of times the intrigued is compounded per year, and t is the number of a long time.

In this case, P = $18,000, r = 0.052 (since the intrigued rate is 5.2%), n = 1 (since the intrigued is compounded every year), and t = 7 (since we need to discover the full sum after 7 a long time). Substituting these values into the equation, we get: A = 18000(1 + 0.052/1)[tex]^{1*7}[/tex]

= 18000(1.052)[tex]^{7}[/tex]

= $24,810.89 (adjusted to the closest cent)

thus, the full sum of the venture after 7 a long time is roughly $24,810.89.

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It depends on the rotational speed of the wheel. To calculate this speed, we need to know the angular velocity of the wheel.

The maximum speed of a point on the outside of the wheel, 15 cm from the axle, if we assume that the wheel is rotating at a constant rate, we can use the formula v = rω, where v is the speed of the point on the outside of the wheel, r is the radius of the wheel (15 cm in this case), and ω is the angular velocity of the wheel. Therefore, the maximum speed of a point on the outside of the wheel would be directly proportional to the angular velocity of the wheel.
The formula to calculate the maximum linear speed (v) is:
v = ω × r
where v is the linear speed, ω is the angular velocity in radians per second, and r is the distance from the axle (15 cm, or 0.15 meters in this case).
Once you have the angular velocity (ω) of the wheel, you can plug it into the formula and find the maximum speed of a point on the outside of the wheel.

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Rotate triangle △C'D'E' counterclockwise by approximately -0.785 radians about the origin:

[tex]x1' = 1 \times cos(-0.785) - (-4) \times sin(-0.785) \approx 0.436[/tex]

[tex]y1' = 1 \times sin(-0.785) + (-4) \times cos(-0.785) \approx -3.678[/tex]

[tex]x2' = -7 \times cos(-0.785) - 8[/tex]

The given point [tex]s C(2, -8), D(-6, 4),[/tex] and [tex]E(0, 4)[/tex] form the triangle △CDE, and the points U(1, -4), V(-3, 2), and W(0, 2) form the triangle △UVW, with △CDE being the preimage of △UVW.

To represent the transformation algebraically, we can use a combination of translations and rotations.

Translation:

To translate a point (x, y) by a vector (h, k), we add h to the x-coordinate and k to the y-coordinate of the point.

To transform triangle △CDE to triangle △UVW, we can first translate triangle △CDE by a vector (h, k) to obtain triangle △C'D'E', where C' = C + (h, k), D' = D + (h, k), and E' = E + (h, k).

Since the coordinates of C are (2, -8) and the coordinates of U are (1, -4), we can calculate the translation vector (h, k) as follows:

[tex]h = 1 - 2 = -1[/tex]

[tex]k = -4 - (-8) = 4[/tex]

So the translation vector is [tex](-1, 4).[/tex]

Rotation:

To rotate a point (x, y) by an angle θ counterclockwise about the origin, we use the following formulas:

[tex]x' = x \times \cos(\theta) - y times \sin(\theta)[/tex]

[tex]y' = x \times \sin(\theta) + y \times \cos(\theta)[/tex]

To transform triangle △C'D'E' to triangle △UVW, we can apply a rotation of angle θ counterclockwise about the origin to triangle △C'D'E', where C' = (x1', y1'), D' = (x2', y2'), and E' = (x3', y3'). Since the coordinates of C' are (2, -8) after translation, and the coordinates of U are (1, -4), we can calculate the rotation angle θ as follows:

[tex]\theta = atan2(y1' - y2', x1' - x2') - atan2(y1 - y2, x1 - x2)= atan2((-8 + 4) - (-4), (2 + 1) - (-6 + 3)) - atan2((-8) - (-4), 2 - (-6))[/tex]

Using a calculator, we can find θ to be approximately -0.785 radians.

So, the algebraic representation of the transformation that maps triangle [tex]\triangle CDE[/tex] to triangle [tex]\triangle UVW[/tex]  is:

Translate triangle △CDE by the vector (-1, 4) to obtain triangle △C'D'E':

[tex]C' = (2, -8) + (-1, 4) = (1, -4)[/tex]

[tex]D' = (-6, 4) + (-1, 4) = (-7, 8)[/tex]

[tex]E' = (0, 4) + (-1, 4) = (-1, 8)[/tex]

Therefore, Rotate triangle △C'D'E' counterclockwise by approximately -0.785 radians about the origin:

[tex]x1' = 1 \times cos(-0.785) - (-4) \times sin(-0.785) \approx 0.436[/tex]

[tex]y1' = 1 \times sin(-0.785) + (-4) \times cos(-0.785) \approx -3.678[/tex]

[tex]x2' = -7 \times cos(-0.785) - 8[/tex]

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Step-by-step explanation:

hope this will help you Thanks

To compute the covariance matrix of the variables in the data, the "matrix-operation" which should be used is ([tex]X^{t}[/tex] × X)/n.

The "Covariance" matrix is defined as a symmetric and positive semi-definite, with the entries representing the covariance between pairs of variables in the data.

The "diagonal-entries" represent the variances of individual variables, and the off-diagonal entries represent the covariances between pairs of variables.

Step(1) : Compute the transpose of the centered data matrix X, denoted as [tex]X^{t}[/tex]. The "transpose" of a matrix is found by inter-changing its rows and columns.

Step(2) : Compute the "dot-product" of [tex]X^{t}[/tex] with itself, denoted as [tex]X^{t}[/tex] × X.

The dot product of two matrices is computed by multiplying corresponding entries of the matrices and summing them up.

Step(3) : Divide the result obtained in step(2) by the number of samples in the data, denoted as "n", to get the covariance matrix.

This step scales the sum of the products by 1/n, which is equivalent to taking the average.

So, the covariance matrix "C" of variables in "centered-data" matrix X can be expressed as: C = ([tex]X^{t}[/tex] × X)/n.

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The given question is incomplete, the complete question is

Let X be a matrix of centered data with a column for each field in the data and a row for each sample. Then, not including a scalar multiple, how can we use matrix operations to compute the covariance matrix of the variables in the data?

Answer:

Add 1 1/4 x 1 1/4

Step-by-step explanation:

Therefore, the company made $48.3 million (written in scientific notation as 4.83 x 10⁷) that year from selling new cars.

An equation is a mathematical statement that shows that two expressions are equal. It consists of two sides, the left-hand side (LHS) and the right-hand side (RHS), separated by an equals sign (=). The expressions on both sides of the equals sign must have the same value for the equation to be true. Equations can involve a wide range of mathematical operations such as addition, subtraction, multiplication, division, exponents, and roots. They are used to solve problems in various fields such as physics, engineering, economics, and many others.

Here,

To find the total revenue generated by the company, we need to multiply the number of new cars sold by the average price per car. We can do this as follows:

Total revenue = number of new cars sold x average price per car

Total revenue = 2.3 million x $21,000

To multiply these two numbers, we can use the distributive property:

Total revenue = (2.3 x 10⁶) x ($21,000)

Total revenue = 2.3 x $21 x 10⁶

Multiplying 2.3 by 21 gives us 48.3, which we can write in scientific notation as 4.83 x 10¹. We can then add the exponents to get:

Total revenue = 4.83 x 10¹ x 10⁶

Total revenue = 4.83 x 10⁷

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The missing angles of the diagram are:

∠1 = 118°

∠2 = 62°

∠3 = 118°

∠4 = 30°

∠5 = 32°

∠6 = 118°

∠7 = 30°

∠8 = 118°

Supplementary angles are defined as two angles that sum up to 180 degrees. Thus:

∠1 + 62° = 180°

∠1 = 180 - 62

∠1 = 118°

Now, opposite angles are congruent and ∠2 is an opposite angle to 62°. Thus: ∠2 = 62°.

Similarly: ∠3 = 118° because it is congruent to ∠1

Alternate angles are congruent and ∠5 is an alternate angle to 32°. Thus:

∠5 = 32°

Sum of angle 4 and 5 is a corresponding angle to ∠2 . Thus:

∠4 + ∠5 = 62

∠4 + 32 = 62

∠4 = 30°

This is an alternate angle to ∠7 and as such ∠7 = 30°

Sum of angles on a straight line is 180 degrees and as such:

∠8 = 180 - (30 + 32)

∠8 = 118° = ∠6 because they are alternate angles

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In the given triangle the 3 trigonometric ratios are:

(A) Sinθ = 3/5, (B) Cosθ = 4/5, and (Tanθ = 3/4)

The trigonometric functions in mathematics are real functions that connect the right-angled triangle's angle to the ratios of its two side lengths.

They are extensively employed in all fields of geometry-related study, including geodesy, solid mechanics, celestial mechanics, and many others.

In general, arcsine, arccosine, tangent, cotangent, secant, and cosecant functions are used to express the inverses of sine, cosine, tangent, cotangent, secant, and cosecant functions.

So, according to t the given triangle, the 3 trigonometric ratios would be:

Sinθ = B/H

Sinθ = 27/45

Sinθ = 3/5

Cosθ = P/H

Cosθ = 36/45

Cosθ = 4/5

Tanθ = B/P

Tanθ = 27/36

Tanθ = 3/4

Therefore, in the given triangle the 3 trigonometric ratios are:

(A) Sinθ = 3/5, (B) Cosθ = 4/5, and (Tanθ = 3/4)

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Answer: This situation involves choosing a group of 5 players out of a total of 12 players, where the order in which the players are chosen does not matter. Therefore, this is an example of a combination problem.

The number of ways to choose a group of 5 players out of 12 is given by the formula for combinations:

n C r = n! / (r! * (n-r)!)

where n is the total number of players, r is the number of players being chosen, and "!" represents the factorial operation.

In this case, we have n = 12 and r = 5, so the number of different choices of starters is:

12 C 5 = 12! / (5! * (12-5)!)

= 792

Therefore, there are 792 different choices of starters that the coach can make from the team of 12 players.

Step-by-step explanation:

The section for piano will have 60 degrees in the circle graph.

To find out how many degrees the section for piano will have in the circle graph, we first need to find the fraction of the circle that the piano represents.

The total degrees in a circle is 360 degrees. We can use the given fraction of piano (1/6) and multiply it by 360 degrees to find out the degrees of the section for piano.

Degrees for piano = (Fraction of piano) × 360

Degrees for piano = (1/6) × 360

Now, multiply the fraction by 360:

Degrees for piano = 60

So, the section for piano will have 60 degrees in the circle graph.

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→ 60° ( btw, ° means degrees )

— if a WHOLE circle is 360° and the piano is 1/6 of the circle, then all you have to do is multiply 1/6 by 360° which gives you 60 OR 60°

HEY- you look hungry, eat up !! →

Answer:

The value of x is 2.

Step-by-step explanation:

5(2x -1) + 3(x -3) = -(4x - 6) + 2(13 -3x)

Expand both sides of the equation to remove parenthesis

10x - 5 + 3x - 9 = -4x + 6 + 26 - 6x

Transpose all terms with x as the coefficient on the left side of the equation and transpose the constants to the right.

10x + 3x + 4x + 6x = 6 + 26 + 5 + 9

Simplify

23x = 46

Divide both sides of the equation by 23

23x/23 = 46/23

x = 2

The width of the shower caddy is 8 inches.

What is Volume?

Volume is a measure of the total amount of material that an object contains. In mathematical terms, volume is calculated by multiplying the length, width, and height of an object.

We can use the formula for the volume of a rectangular prism, which is V = lwh, where l is the length, w is the width, and h is the height.

We know that the volume of the caddy is 420 cubic inches, the length is 10.5 inches, and the height is 5 inches. Let's substitute these values into the formula and solve for the width:

420 = 10.5w × 5

Divide both sides by 52.5:

8 = w

Therefore, the width of the shower caddy is 8 inches.

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The measure of the unknown side from the given triangle is 14.48.

The given triangle is a right triangle with the following sides;

Hypotenuse = 15

Adjacent = x

Acute angle = 52 degrees

We are to determine the measure of the unknown side using trigonometry identity

Cos 15 = Adjacent/Hypotenuse

Cos 15 = x/15

x = 15cos15

x = 15(0.9659)

x = 14.48

Hence the measure of the unknown side is 14.48

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Answer:

[tex]\large\boxed{\tt x \approx 95.6}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to solve for x by using \underline{Trigonometric Identities}.}[/tex]

[tex]\large\underline{\textsf{What are Trigonometric Identities?}}[/tex]

[tex]\boxed{\begin{minipage}{20 em} \\ \underline{\textsf{\large Trigonometric Identities;}} \\ \\ \textsf{Trigonometric Identities are trigonometric ratios determined with what's given in order to find a missing value. For a Right Triangle, the Trigonometric Identities are Sine, Cosine, and Tangent. These are used to find missing sides.} \\ \\ \tt Sine = \tt $ \tt \frac{Opposite}{Hypotenuse} \\ \\ Cosine = \frac{Adjacent}{Hypotenuse} \\ \\ Tangent = \frac{Opposite}{Adjacent} \end{minipage}}[/tex]

[tex]\textsf{We should determine whether Sine, Cosine, or Tangent will actually help us}[/tex]

[tex]\textsf{determine x. We are given a Right Triangle that has 1 15}^{\circ} \ \textsf{angle, and a side with}[/tex]

[tex]\textsf{a length of 99. Because this side is opposite of the right angle, this side is called}[/tex]

[tex]\textsf{the \underline{Hypotenuse}.}[/tex]

[tex]\textsf{The side labeled x is \underline{Adjacent}, which means that it's touching the given angle.}[/tex]

[tex]\textsf{Using what was given to us, we should use Cosine since we are asked for the}[/tex]

[tex]\textsf{Adjacent Angle when given the Hypotenuse.}[/tex]

[tex]\large\underline{\textsf{Solving;}}[/tex]

[tex]\textsf{Remember that;}[/tex]

[tex]\tt \cos(15^{\circ}) =\frac{Adjacent}{Hypotenuse}[/tex]

[tex]\textsf{We're given;}[/tex]

[tex]\tt \cos(15^{\circ}) =\frac{x}{99}[/tex]

[tex]\textsf{To find the value of x, we first should remove the fraction using cancellation.}[/tex]

[tex]\textsf{We are able to use the \underline{Multiplication Property of Equality} to prove that the}[/tex]

[tex]\textsf{equation remains equal.}[/tex]

[tex]\underline{\textsf{Multiply both expressions by 99;}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) =\not{99} \frac{x}{\not{99}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) =x[/tex]

[tex]\underline{\textsf{Evaluate;}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) \approx \boxed{\tt 95.6}[/tex]

[tex]\large\boxed{\tt x \approx 95.6}[/tex]

Step-by-step explanation:

Again, using similar triangle ratios

7.2 m  is to 2.4 m  

     as   AB is to  12.0 m

7.2 / 2.4  = AB/12.0    Multiply both sides of the equation by 12

12 *   7.2 / 2.4   = AB = 36.0 meters

The justifications for 2 and 3 are;

Addition property of equality and

Multiplication property of equality

1. x/2 - 9 = -4 given

Add 9 to both sides

2. x/2 = -13 (Addition property of equality)

cross product

3.x = -26 (Multiplication property of equality)

Therefore, x/2 - 9 = -4 where x Is -26 is justified by addition and multiplication property of equality.

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Answer:966%

Step-by-step explanation:

To convert a decimal to a percent, we need to multiply the decimal by 100 and add a percent sign. So, to convert 9.66 to a percent, we do the following:

9.66 × 100% = 966%

Therefore, 9.66 is equivalent to 966% as a percent.

Answer: you divide by 100 and you get your answer

Step-by-step explanation:

9.66 ÷ 100 = 0.0966