Answer:
Yes i think its -96,
if thats what your asking
The probability that a women likes the color blue is 10%. The probability of being a women is 40%.What is the probability that a person likes the color blue given that they are a woman?
Answer:
The probability that a person likes the color blue given that they are a woman=0.25%
Step-by-step explanation:
We are given that
The probability that a women likes the color blue=10%=[tex]\frac{10}{100}=0.1[/tex]
The probability of being a women=40%=[tex]\frac{40}{100}=0.4[/tex]
We have to find the probability that a person likes the color blue given that they are a woman.
We know that
Conditional probability formula
[tex]P(A/B)=\frac{P(A\cap B)}{P(B)}[/tex]
The probability that a person likes the color blue given that they are a woman
=[tex]\frac{0.1}{0.4}[/tex]
[tex]=\frac{1}{4}=0.25[/tex]
Hence, the probability that a person likes the color blue given that they are a woman=0.25%
omg please help. make sure you put the product of A, the product of B, and the sum for C. it’s in the picture
Answer:
Product for A = 046
Product for B = 0230
Sum for C = 0.0276
Step-by-step explanation:
We need to multiply the terms and find the answers
First we multiply 2 with 0.23, then we multiply 1 with 0.23
0.23
x 0.12
-------------
046
0230
--------------
.0276
Since there are 2 numbers after decimal in 0.23 and same for 0.12, so we place the decimal so that there are 4 decimal places.
Counting of decimal will start from the units place.
So, Product for A = 046
Product for B = 0230
Sum for C = 0.0276
PLEASE HELP!!!!!
Which of the following is one of the standard forms of a hyperbola
centered at (h,k)?
Given:
Center of hyperbola is at (h,k).
To find:
The standard forms of a hyperbola.
Solution:
We know that, standard forms of a hyperbola are
1. For Horizontal hyperbola:
[tex]\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1[/tex]
2. For Vertical hyperbola:
[tex]\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1[/tex]
where, (h,k) is center of the hyperbola.
Therefore, the correct option is B.