is burning trash a physical change or chemical change?

Answer:

Hooke's law describes the elastic properties of materials only in the range in which the force and displacement are proportional. Hooke's law states that the applied force F equals a constant k times the displacement or change in length x, or F = kx. the maximum extent to which a solid may be stretched without permanent alteration of size or shape, is called elastic limit

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Answer:

40*C

Explanation:

Answer:

Rain water carries sediment and then these accumulate on the bottom of ponds, lakes and wetlands. This accumulation build up over time and eventually, the water disappears (because they sink into the ground) and the area once covered with water becomes land.

Answer:

The angle the boat must be pointed upstream is 69⁰

Explanation:

Check the image uploaded for the diagram;

Given;

speed of the boat on still water, = 4.6 km/h

speed of the boat on a river with current, = 1.8 km/h

The angle the boat must be pointed upstream is calculated as follows

[tex]tan(\theta) = \frac{4.6}{1.8} \\\\tan(\theta) = 2.556\\\\\theta = tan^{-1}(2.556)\\\\\theta = 68.63^0\\\\\theta = 69^0[/tex]

Answer:

As long as there is rain, a rainbow is possible. Rain is possible on a sunny day, and is known as a sunshower.The rainbow can be observed in a sunny day if the water droplets are present in air and the sun rays pass through it reaches the eye of the observer. In this situation, the observer can see a rainbow.

or

If you happened to look up at the sky this past weekend, you might have noticed a rare and beautiful sight: iridescent rainbow clouds, but not a drop of rain in sight. This phenomenon is known, fittingly, as cloud iridescence or irisation. The effect is not unlike seeing a rainbow painted on the clouds.

Answer:

Cellular respiration takes place in the cells of all organisms. It occurs in autotrophs such as plants as well as heterotrophs such as animals. Cellular respiration begins in the cytoplasm of cells. It is completed in mitochondria

Explanation:

Cellular respiration takes place in the cells of all organisms. It happening in autotrophs such as plantas as well as heterotrophs such as animals. Cellular respiration starts in the cytoplasm of cells.

It is finished in mitochondria.

Answer: [tex]1.102\ J[/tex]

Explanation:

Given

Mass [tex]m=1.3\ kg[/tex]

Spring constant [tex]k=58\ N/m[/tex]

Compression in the spring [tex]x=19.5\ cm\ or\ 0.195\ m[/tex]

When the mass leaves the spring, the elastic potential energy of spring is being converted into kinetic energy of mass i.e.

[tex]\Rightarrow \dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}\cdot 58\cdot (0.195)^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}mv^2=1.102\ J[/tex]

The kinetic energy of the mass is 1.102 J.

Answer:

773.25 Hz

Explanation:

Concept : In an open organ pipe in fundamental mode of vibration

wave length of wave λ = 2L

where L  is length of  the pipe

frequency   = velocity of sound / λ

Given values: fundamental frequency = 288 Hz

fluid is air. velocity of sound = 340 m/s

⇒ 288 = 340/2L

⇒L = 59.02 cm

The point to be noted is if the pipe is filled with helium initially at the same temperature, there would be change in the sound velocity .Then,  frequency of note produced will also be changed .

We know that velocity of sound is inversely proportional to  square root of molar mass of gas

velocity of sound in air / velocity of sound in helium = Square root of (Molar mass of Helium/ molar mass of air)

[tex]\frac{V_a}{V_{He}} = \sqrt{\frac{4}{28.8} } \\\frac{340}{V_{He}} =0.3725\\V_{He} =912.5 m/s[/tex]

Now, frequency  = velocity of sound / λ

= 912.75 / (2 x 0.5902)

= 773.25 Hz

Answer:

Explanation:

Let after time t , Tina catches up David .

Distance travelled by them are equal ,

Distance travelled by Tina

s = ut + 1/2 a t²

= .5 x 2.10 t²

= 1.05 t²

Distance travelled by David

= 30 t ( because of uniform velocity )

1.05 t² = 30t

t = 28.57 s

Distance travelled by Tina

= 1/2 a t²

= .5 x 2.10 x 28.57²

= 857 m approx.

Answer: [tex]857\ m[/tex]

Explanation:

Given

Speed of David car [tex]v=30\ m/s[/tex]

Tina begins to accelerate [tex]2.1\ m/s^2[/tex] after David pass the tina

Suppose it took t time for tina to catch David

Distance traveled by David in t time

[tex]\Rightarrow s_d=30\times t[/tex]

Using the equation of motion to get the distance of Tina is

[tex]s_t=ut+\dfrac{1}{2}at^2\\\\s_t=0+\dfrac{1}{2}\times 2.1t^2[/tex]

now, [tex]s_d=s_t[/tex]

[tex]30t=\dfrac{2.1}{2}t^2\\\\\Rightarrow 2.1t^2-60t=0\\\Rightarrow t(2.1t-60)=0\\\Rightarrow t=0,28.57\ s[/tex]

Neglecting [tex]t=0[/tex]

Distance traveled by tina in [tex]28.57\ s[/tex] is

[tex]s_t=\dfrac{1}{2}\times 2.1\times (28.57)^2\\\\s_t=857.057\approx 857\ m[/tex]

Answer:

the frequency of the oscillation is 1.5 Hz

Explanation:

Given;

mass of the spring, m = 1500 kg

extention of the spring, x = 5 mm = 5 x 10⁻³ m

mass of the driver = 68 kg

The weight of the driver is calculated as;

F = mg

F = 68 x 9.8 = 666.4 N

The spring constant, k, is calculated as;

k = F/m

k = (666.4 N) / (5 x 10⁻³ m)

k = 133,280 N/m

The angular speed of the spring is calculated;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{133280}{1500} } = 9.426 \ rad/s[/tex]

The frequency of the oscillation is calculated as;

ω = 2πf

f = ω / 2π

f = (9.426) / (2π)

f = 1.5 Hz

Therefore, the frequency of the oscillation is 1.5 Hz

This question is incomplete, the complete question  is;

Write the differential equation that governs the motion of the damped mass-spring system, and find the solution that satisfies the initial conditions specified. Units are mks; γ is the damping coefficient, with units of kg/sec

m = 0.2, γ = 1.6 and k = 4

Initial displacement is 1 and initial velocity is -2

x" + _____ x' ____x = 0

x(t) =

Answer:

the solution that satisfies the initial conditions specified is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

Explanation:

Given the data in the question ;

m = 0.2, γ = 1.6, k = 4

x(0) = 1, x'(0) = -2

Now, the differential equation that governs the motions of spring mass system is;

mx" + γx' + kx = 0

so we substitute

0.2x" + 1.6x' + 4x = 0

divide through by 0.2

x" + 8x' + 20x = 0

hence, characteristics equation will be;

m² + 8m + 20 = 0

we find m using; x = [ -b±√(b² - 4ac) ] / 2a

m = [ -8 ± √((8)² - 4(1 × 20 )) ] / 2(1)

m = [ -8 ± √( 64 - 80 ) ] / 2

m = [ -8 ± √-16 ) ] / 2

m = ( -8 ± 4i ) / 2

m = -4 ± 2i

Hence, the general solution of the differential equation is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

From the initial conditions;

c₁ = 1, c₂ = 1

the solution that satisfies the initial conditions specified is;

x(t) = [tex]c_1e^{-4t}cos(2t)[/tex] + [tex]c_2e^{-4t}sin(2t)[/tex]

Answer:

C) the heat removed from the inside to the work done to remove the heat.

Explanation:

Refrigerator is a heat engine working in reverse direction . Heat from cold source is taken out , some work is done to remove them and total heat and work energy is thrown into outside surrounding .

If q heat is taken out and W is work done to get this heat out .

coefficient of performance ( COP ) = q / W .

Hence C ) is the right choice .

Answer:

r = 6.6 x 10³ m = 6600 m

Explanation:

The potential at a distance from a charged sphere can be given as follows:

[tex]V = \frac{kq}{r}\\\\r = \frac{kq}{V}[/tex]

where,

r = distance = ?

k = Colomb Constant = 9 x 10⁹ Nm²/C²

q = charge on sphere = 3.3 C

V = potential = 4.5 MV = 4.5 x 10⁶ V

Therefore,

[tex]r = \frac{(9\ x\ 10^9\ Nm^2/C^2)(3.3\ C)}{4.5\ x\ 10^6\ V}[/tex]

r = 6.6 x 10³ m = 6600 m

Answer:

the wavelength of the sound in seawater is 90.1 m.

Explanation:

Given;

frequency of the sound, f = 17 Hz

speed of the sound in seawater, v = 1531 m/s

The wavelength of the wave is calculated as follows;

v = fλ

λ = v / f

where;

λ is the wavelength of the sound

λ = 1531 / 17

λ = 90.1 m

Therefore, the wavelength of the sound in seawater is 90.1 m.

Answer:

D)parallel circuit

Explanation:

the components are placed parallel from eachother

Answer:

Option C. 4 Hz

Explanation:

To know the correct answer to the question given above, it is important we know the definition of frequency.

Frequency can simply be defined as the number of complete oscillations or circles made in one second.

Considering the diagram given above, the wave passes through the medium over a period of one second.

Thus, we can obtain the frequency by simply counting the numbers of complete circles made during the period.

From the diagram given above,

The number of circles = 4

Thus,

The frequency is 4 Hz

Answer:

2633.7 s

Explanation:

From the question,

Heat lost by the water heater = Heat gained by the water

Applying,

P = cm(t₂-t₁)/t.................. Equation 1

Where P = power of the heat, c = specific heat capacity of water, m = mass of water, t₁ = initial temperature, t₂ = final temperature, t = time

make t the subject of the equation

t = cm(t₂-t₁)/P.............. Equation 2

From the question,

Given: c = 4190 J/kgK, P = 3.5 kW = 3500 W, m = 40 kg, t₁ = 20°C, t₂ = 75°C

Substitute these values into equation 2

t = 4190×40(75-20)/3500

t = 9218000/3500

t = 2633.7 s

The relative error in this weight measurement as percentage is

is the ratio of the absolute error of a measurement to the measurement being taken. In other words, this type of error is relative to the size of the item being measured.

Therefore,

[tex]\% relative error = \frac{smallest division}{mass of apples}*100\\\\\% relative error = \frac{2.1g}{1900}*100\\\\\% relative error = 0.1105\%[/tex]

For more information on relative error, visit

https://brainly.com/question/64815

Answer:

The relative error in this weight measurement is approximately 0.1105 %.

Explanation:

We know that,
Relative Error is the ratio of the absolute error of a measurement to the actual measurement . It can be mathematically represented as,

Relative Error  = (Measured Value - Actual Value)  / Actual Value * 100

In this case, the actual weight is 1.9 kg, and the smallest division of the spring scale is 2.1 g.

Actual Weight = 1.9  * 1000  = 1900  (As 1 kg = 1000g)

We know that the absolute error will be equal to the smallest division hence,

Measured Value - Actual Value = 2.1 g

By replacing this in the general formula we get,

Relative Error = (Measured Value - Actual Value) / Actual Value * 100

= [tex]\frac{2.1}{1900} *100[/tex] %

= [tex]\frac{2.1}{19}[/tex] %

≈ 0.1105 %

Therefore, the relative error in this weight measurement is approximately 0.1105 %.

For more information on relative error, visit

brainly.com/question/64815

Answer:

As objects move around over time, the energy associated with them—e.g., kinetic, gravitational potential, heat—might change forms, but if energy is conserved, then the total will remain the same. Conservation of energy applies only to isolated systems.

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Answer:

     λ = 5.75 10⁻⁷ mm

Explanation:

This is a slit interference exercise, we analyze each wavelength separately                    

            λ = 657 nm                                     indicate that the third dark pattern

          a sin θ = (m + ½) lam

          a sin θ = (3 + ½) 657 10⁻⁹

          a sin θ = 2299.5 10⁻⁹ nm

for the other wavelength in the same place we have m = 4 bright

          a sin θ = m lam

we substitute

           2299.5 10⁻⁹ = 4 λ

           λ = [tex]\frac{2299.5 \ 10^9 }{ 4}[/tex]

           λ = 5.75 10⁻⁷ mm

Answer:

The answer is "[tex]4659.2 \times 10^{-24} \ N[/tex]"

Explanation:

The magnetic field at ehe mid point of the coils is,

[tex]\to B=\frac{\mu_0 i R^2}{(R^2+x^2)^{\frac{3}{2}}}\\\\[/tex]

Here, i is the current through the loop, R is the radius of the loop and x is the distance of the midpoint from the loop.

[tex]\to B=\frac{(4\pi\times 10^{-7})(2.80\ A) (\frac{0.35}{2})^2}{( (\frac{0.35}{2})^2+ (\frac{0.24}{2})^2)^{\frac{3}{2}}}\\\\[/tex]

       [tex]=\frac{(12.56 \times 10^{-7})(2.80\ A) \times 0.030625}{( 0.030625+ 0.0144)^{\frac{3}{2}}}\\\\=\frac{ 1.07702 \times 10^{-7} }{0.0095538976}\\\\=112.730955 \times 10^{-7}\\\\=1.12\times 10^{-5}\ \ T\\[/tex]

Calculating the force experienced through the protons:

[tex]F=qvB=(1.6 \times 10^{-19}) (2600)(1.12 \times 10^{-5})= 4659.2 \times 10^{-24}\ N[/tex]

Answer:

The number of particles in state E0 over the number of particles in state E1  will reduce

Explanation:

E0 represents the ground level state when all the particles have same energy level.

E1 represents excited state in which only a few particle reaches

E0 and E1 get further apart  means that the energy difference between the two level increases.

Thus, the number of particles in state E0 over the number of particles in state E1  will reduce.

Answer:

ook soooooo

Explanation:

Answer:

[tex](a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

[tex](b)\ F_{No} = 771.125N[/tex]

Explanation:

Given

[tex]d_D = 6000ft[/tex] ---- Altitude of container in Denver

[tex]A = 0.0155m^2[/tex] -- Surface Area of the container lid

[tex]P_D = 79000Pa[/tex] --- Air pressure in Denver

[tex]P_{No} = 100250Pa[/tex] --- Air pressure in New Orleans

See comment for complete question

Solving (a): The expression for [tex]F_{No[/tex]

Force is calculated as:

[tex]F = \triangle P * A[/tex]

The force in New Orleans is:

[tex]F_{No} = \triangle P * A[/tex]

Since the inside pressure is half the pressure at sea level, then:

[tex]\triangle P = P_{No} - \frac{P_{area}}{2}[/tex]

Where

[tex]P_{area} = 101000Pa[/tex] --- Standard Pressure

Recall that:

[tex]F_{No} = \triangle P * A[/tex]

This gives:

[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

Solving (b): The value of [tex]F_{No[/tex]

In (a), we have:

[tex]F_{No} = [P_{No} - \frac{P_{area}}{2}]* A[/tex]

Where

[tex]A = 0.0155m^2[/tex]

[tex]P_{No} = 100250Pa[/tex]

[tex]P_{area} = 101000Pa[/tex]

So, we have:

[tex]F_{No} = [100250 - \frac{101000}{2}] * 0.0155[/tex]

[tex]F_{No} = [100250 - 50500] * 0.0155[/tex]

[tex]F_{No} = 49750* 0.0155[/tex]

[tex]F_{No} = 771.125N[/tex]

Answer:

B

Explanation:

Answer:To explian the exact calculation of this pruduct we must not try!