It describes the physical and social elements common to this work. Note that common contexts are listed toward the top, and less common contexts are listed toward the bottom. According to O*NET, what are common work contexts for Reporters and Correspondents? Check all that apply.

Answer:

Hello your question has some missing part below is the missing part

Estimate The matching time for the Finish cut

answer:  79.588 seconds

Explanation:

Calculate the matching time for the Finish cut

Diameter of workpiece before cutting = 100 mm

hence

Diameter of workpiece before Finishing cut ( same as after rough cut )

D2 = D1 - 2 * d  = 100 - (2 * 12) = 76mm

step 1 : determine spindle speed

V = [tex]\frac{\pi D_{2}N_{s} }{60}[/tex]  -------- ( 1 ).  where : D2 = 76 mm , Ns = ? , V = 1.5  ( input values into equation 1 )

therefore Ns = 376.94 rpm

Finally : Determine the matching time

T = [tex]\frac{L + A}{Ft * Ns}[/tex] ---- ( 2 ) . where : Ft = 0.1  mm , Ns = 376.94 rpm, L = 50 mm , A = 0 ( input values into equation 2 )

note : A = allowance length ( not given ) , ft = feed rate

T = 50  / ( 0.1 * 376.94 )

   = 1.3265 minutes ≈ 79.588 seconds

Answer:

A voltage divider is a simple series resistor circuit. It's output voltage is a fixed fraction of its input voltage. The divide-down ratio is determined by two resistors.

Answer:

hello your question lacks some information attached below is the complete question with the required information

answer : 81.63 mm

Explanation:

settlement of the surface due to compression of the clay ( new consolidated )

= 81.63 mm

attached below is a detailed solution to the given problem

Answer:

a) 23.89 < -25.84 Ω

b) 31.38 < 25.84 A

c) 0.9323 leading

Explanation:

A) Calculate the load Impedance

current on load side = 0.75 p.u

power factor angle = 25.84

[tex]I_{load}[/tex] = 0.75 < 25.84°

attached below is the remaining part of the solution

B) Find the input current on the primary side in real units

load current in primary = 31.38 < 25.84 A

C) find the input power factor

power factor = 0.9323 leading

attached below is the detailed solution

Answer:

preguntas a parte o no???????

Answer:

The heat flow in 24 hours through the refrigerator door is approximately 1,608.57 BTU

Explanation:

The given parameters are;

The duration of the heat transfer, t = 24 hours = 86,400 seconds

The area of the refrigerator door, A = 30.0" × 58.0" = 1,740 in.² = 1.122578 m²

The material of the insulator in the door = Cellulose fiber

The thickness of the insulator in the door, d = 2.0" = 0.0508 m

The temperature inside the fridge = 38° F = 276.4833 K

The temperature of the room = 78°F = 298.7056 K

The thermal conductivity of cellulose fiber = 0.040 W/(m·K)

By Fourier's law, the heat flow through a by conduction material is given by the following formula;

[tex]\dfrac{Q}{t} = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d}[/tex]

[tex]Q = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d} \times t[/tex]

Therefore, we have;

[tex]Q = \dfrac{0.04 \times 1.122578 \times (298.7056 - 276.4833 ) }{0.0508} \times 86,400 =1,697,131.73522[/tex]

The heat flow in 24 hours through the refrigerator door, Q = 1,697,131.73522 J = 1,608.5705140685 BTU

Explanation:

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