Ann runs 800 meters without sandbags in 3 minutes. if she completes 800 meters with them in 2 more minutes. Ann's speed when jogging with sandbags is 160 m/min
Speed is defined as the rate at which an object's motion changes in relation to its distance. Since speed is a scalar quantity, the direction of the motion has no bearing on the speed.
It differs from velocity due to this. The rate of change of motion is measured in velocity in a certain direction. Velocity is a vector question, therefore. It's important to move in this way.
Distance to time ratios are used to calculate speed.
Therefore, in this scenario, Speed would travel without a sandbag.
800/3 = 266.66 m/min
Speed while travelling without the sandbag,
800/5 = 160 m/min.
Therefore, the speed while travelling with the sandbag is 160 m/min.
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While taking measurements using the uv-vis spectrometer, if the absorbance reading of a sample is more than _____, we will have to dilute the sample and collect a lower absorbance reading.
If a sample's absorbance reading is higher than 1.0 when being measured with a UV-vis spectrometer, it must be diluted in order to obtain a lower absorbance value.
The logarithm of light transmission (T) through a sample is known as absorbance. Transmission is the difference between the amount of light that passes through a sample and a blank in intensity (I) (Io). Thus, absorbance equals log (Io/I).
At an absorbance of 2, you are at 1%T, which denotes that the sample is blocking (absorbing) 99% of the light that is available. When you have an ABS of 3, you are at 0.1% T, which means that the sample is blocking (absorbing) 99.9% of the light that is available. These ranges fall outside of spectrometers' useful range.
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if you double your driving speed what happens to your stopping distance (the distance it takes to stop the car)?
If you double your driving speed, then the stopping distance will be four times the original.
What is the equation of motion?Equations of motion are equations that describe a physical system's behavior in terms of its motion as a function of time. Equations of motion, The three equations of the motion are,
v - u = atS = ut + 0.5(at²)v² - u² = 2aswhere
S is the distance,
u is the initial velocity,
v is the final velocity,
t is the time,
a is the acceleration.
Given that the car is traveling at a speed and is needed to be stopped, therefore, the car will deaccelerate. Also, the final velocity of the car will become 0. Therefore, we can write,
v² - u² = 2as
Substitute the values,
Final velocity, v = 0Initial velocity, u = uDistance covered, s = s₁Acceleration, a = -aTherefore, we can write,
v² - u² = 2as₁
(0)² - u² = 2(-a)s₁
-u² = -2as₁
u² = 2as₁
s₁ = u² / 2a
Now, if you double your driving speed. Therefore, we can write,
v² - u² = 2as
Substitute the values,
Final velocity, v = 0Initial velocity, u = 2uDistance covered, s = s₂Acceleration, a = -aTherefore, we can write,
v² - u² = 2as₂
(0)² - (2u)² = 2(-a)s₂
-4u² = -2as₂
4u² = 2as₂
s₂ = 4u² / 2a
Since u²/2a is equal to s₁, therefore, we can write,
s₂ = 4(u² / 2a)
s₂ = 4(s₁)
Hence, if you double your driving speed, then the stopping distance will be four times the original.
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A physics text has 544 sheets (1088 pages) and is 34.3 millimeters thick between the inside front cover and the inside back cover. what is the thickness of a single sheet?
The thickness of the single sheet of paper is 6.30 × 10-5 m
How do you define thickness?The thickness can be defined as the measure of the distance between the two surfaces of an object.
It is usually the smallest of three dimensions i.e., length, width, and thickness.
How do you physically obtain the thickness of a paper?In order to obtain the practical (not the theoretical) thickness of a sheet of paper, the best way would be using a micrometer, dial caliper, or a paper thickness gauge. There is digital as well as analog models of these instruments that can be used while measuring the thickness.
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At which location could another charge be placed so that the net force on it would be zero? another way to ask the same question: at which location, a->h, is the electric field zero?
Between a negative and positive charge along the line connecting the two charges, the electric field may be zero. if the two charges have the same size. When there is no longer any net force between the two charges, the third charge should be positioned between the two charges.
The internet pressure is the vector sum of all forces acting on an item.
When an item is in equilibrium, whether it is at rest or moving at a constant speed, there is no net force acting on it. A vector can only have magnitudes of zero when all of its components are zero.
In mechanics, the term "net force" refers to the vector sum of all forces acting on a particle or object. The internet pressure, which is a single pressure, replaces the influence of the real forces on the particle's motion. The net pressure is the sum of all forces acting on an item.
Newton's second regulation, which says that F = ma, wherein F represents the net force, can be used to compute the net force. The item's mass is given with the aid of m. Acceleration is a.
The internet force performing on an object is 0 whilst it is in equilibrium, whether it's far at rest or moving at a consistent pace.
handiest whilst all of a vector's components are 0 can a vector have magnitudes of zero. the general pressure acting on an item is referred to as the net force. while the forces are equal and cancel every different out, it will become zero. If there may be a internet force performing on an object, it's going to accelerate in that direction; but, except the object is shifting simple, this is not the same as the path of movement.
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the total resistance of any number of parallel resistances, all having the same value, is equal to the value of any one of the resistors divided by the total number of resistors.
The correct answer is true.
The algebraic sum of the inverses of the individual resistances is then the inverse of the equivalent resistance of two or more resistors linked in parallel.
The total or equivalent resistance, RT, is equal to half the value of one resistor if the two parallel resistances or impedances are equal and of the same value. That is equivalent to R/2, R/3, etc., for three parallel resistors of identical value.
The total resistance, RT, will always drop when more parallel resistors are added since the equivalent resistance is always smaller than the smallest resistor in the parallel network.
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Match the type of Entrepreneurship to the description that best fits.
Has an ideal, product or service for the business world
Start up their business due to their lifestyles such as sports hobbies or passions
Has to innovative ideas for social change, solutions, etc.
Has multiple startups do to new ideas.
1. Business Entrepreneur
2. Social Entrepreneur
3. Serial Entrepreneur
4. Lifestyle Entrepreneur
A business entrepreneur has a product or service for the business world, a Social one has ideas for social change, a Serial one has multiple startups and a Lifestyle one starts up their business due to their lifestyles.
A business entrepreneur starts new business with his own money. Some of the famous business entrepreneurs are Steve Jobs, Mark Zuckerberg and Bill Gates. A social entrepreneur develops solutions for social issues and directly addresses them. For example, microfinancing institutions provide banking services to low - income and unemployed people.
A serial entrepreneur can create ideas into successful businesses on a regular basis. They do not stop at one business. Elon Musk is a great example of a serial entrepreneur. A lifestyle entrepreneur creates business to change their lifestyle. A lifestyle entrepreneur does not necessarily make profits. Blogging and photography are some of the examples of lifestyle entrepreneurship.
Therefore,
1. Business Entrepreneur - Has an ideal, product or service for the business world
2. Social Entrepreneur - Has to innovative ideas for social change, solutions, etc.
3. Serial Entrepreneur - Has multiple startups do to new ideas.
4. Lifestyle Entrepreneur - Start up their business due to their lifestyles such as sports hobbies or passions
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Answer:
1. Business
2. Social
3. Serial
4. Lifestyle
Where will you store your carolina distance learning kit box when it is not in use, and why?
I will store carolina distance learning kit box in a refrigerator.
To increase their shelf life, they should be refrigerated as soon as they arrive. Keep the lyophilized cultures away from youngsters in a sealed, labeled plastic bag.
What is lyophilized cultures?Bacteria must be suspended in a medium that supports their viability during freezing, water removal, and subsequent storage if they are to be preserved by lyophilization.
The vials should be put within a freeze-dryer chamber, and the chamber should be vacuumed as directed by the manufacturer. Give the culture enough time to fully lyophilize (dry out).
Water is removed from a product after it has been frozen, and it is then placed in a vacuum, allowing the product to convert directly from solid to vapor without going through a liquid phase. This process is known as lyophilization or freeze drying.
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Recoil is noticeable if we throw a heavy ball while standing on roller skates. If instead we go through the motions of throwing the ball but hold onto it, our net recoil will be.
Answer:
we will feel unstable on the skates. Because the recoil force pushes us forward, and affect our balance
This system is now run in reverse as a refrigerator. how much heat does it extract from the cold reservoir when 900 j of work are done on the system? qc =
1500 j is extracted from the cold reservoir when 900 j of work are done on system .
We only need to think about total energy transmitted in terms of work and heat to find a solution to this issue. Essentially, the first law of thermodynamics conjugates this.
Evaluation :
The total work performed in the heat engine is if we consider the heat taken as positive and the heat released as negative.
[tex]W_{1}[/tex] = 2500 - 1000
[tex]W_{1}[/tex] = 1500 j
For the case of the engine pumps the Energy absorbed is
[tex]W_{2}[/tex] = 1500 j
In this way the ratio between the two would be
Ratio [tex]W_{1} /W_{2}[/tex] = 1
So it is reversible, because the state of efficiency of the body is totally efficient.
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Help me please, it's for physics and I really need help.
Answer:
4. y = 2.38333t - 26.55 is the answer.
A small cube of metal measures 16.8 mm on a side and weighs 35.9 g.what is the density of the metal in g/cm3?
Answer:
21.4 g/cm3
Explanation:
What is the magnetic field amplitude of an electromagnetic wave whose electric field amplitude is 50 v/m ?
The magnetic field amplitude of an electromagnetic wave 1.66[tex]10^{-7}[/tex]T
Magnetic field is the portion of space near a magnetic body or a current-carrying body in which the magnetic forces due to the body or current can be detected.
The relationship between the magnetic field amplitude of the electric field and the magnetic field in an electromagnetic wave is E=cB
where
E is the electric field amplitude
B is the magnetic field amplitude
c is the speed of light
For this electromagnetic wave, we have E=50v/m
So we can solve the formula to find B:
B=E/c = [tex]\frac{50v/m}{3*10^{8}m/s }[/tex]
=1.66[tex]10^{-7}[/tex]T
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a 1.7 μc charge and a 2.5 μc charge are 12.5 cm apart. find a point where the electric field is zero.
The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.
The electric field(E) due to a charge is given by the formula,
E = KQ/r^2
For a point where the electric field is zero, the magnitude of the field due to two charges should be equal so that they cancel each other
Hence, the field produced due to 1.7 uc at the point should be equal to the field produced by the 2.5 uc charge.
Let the distance of the point where the electric field is zero be x from the 1.7 uc.
So, the distance of the point where the field is zero will be (0.125 - x) from 2.5 uc.
K(1.7uc)/x^2 = K(2.5uc)/(0.125 - x)^2
Solving the above equation
x comes out to be 0.056 meters or 5.6 centimeters.
Hence, The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.
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The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.
The electric field(E) due to a charge is given by the formula,
E = KQ/r^2 equation 1
For a point where the electric field is zero, the magnitude of the field due to two charges should be equal so that they cancel each other
Hence, the field produced due to 1.7 uc at the point should be equal to the field produced by the 2.5 uc charge.
Let the distance of the point where the electric field is zero be x from the 1.7 uc.
So, the distance of the point where the field is zero will be (0.125 - x) from 2.5 uc.
Substitute the values of charges in equation1 and equate the equations for two different charges,
K(1.7uc)/x^2 = K(2.5uc)/(0.125 - x)^2
(1.7uc)(0.125 - x)^2 = (2.5uc) x^2
On simplifying the above equation
x = 0.056 meters or 5.6 centimeters.
Hence, the point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.
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a bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 6.3 cross times 10 to the power of 5 space m divided by s to the power of 2 space end exponent for 8.1 cross times 10 to the power of negative 4 end exponent space s. what is the bullet’s final velocity when it leaves the barrel, commonly known as the muzzle velocity?
The muzzle velocity of the bullet is 510.3 m/s.
What is muzzle velocity?The projectile's speed when it exits the gun's muzzle is known as muzzle velocity.
The quality (burn speed, expansion) and quantity of the propellant, the mass of the projectile, and the length of the barrel all affect the muzzle velocity of conventional firearms. While a slower burning propellant can use a heavier projectile, it requires a longer barrel to burn completely.
Apply the kinematics equation,
v=u+at
Here v is the final velocity, u is the initial velocity, a is the acceleration and t is the time interval during which a body is under acceleration.
The muzzle velocity of a bullet is the velocity with which the bullet leaves contact with the barrel of the gun.
The muzzle velocity or the final velocity of the bullet will be
v=u+at
v=0+(6.3×[tex]10^{5}[/tex])(8.1×[tex]10^{-4}[/tex])
=50.3 m/s
Therefore, the muzzle velocity of the bullet is 510.3 m/s.
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at highway speeds, a particular automobile is capable of an acceleration of 1.6 m/s2. at this rate, how long does it take to accelerate from 80 km/h to 110 km/h?
By using uniform motion, the time taken to accelerate is 5.21 second.
We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.
From the question above, we know that
vo = 80 km/h = 80 x 1000/3600 m/s = 22.22 m/s
vt = 110 km/h = 110 x 1000/3600 m/s = 30.56 m/s
a = 1.6 m/s²
By using first equation, we can calculate the time taken
vt = vo + a . t
30.56 = 22.22 + 1.6 . t
1.6t = 8.34
t = 5.21 second
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If the astronaut throws the tool with a force of 16. 0 n , what is the magnitude of the acceleration a of the astronaut during the throw? assume that the total mass of the astronaut after she throws the tool is 80. 0 kg.
The magnitude of the acceleration attained by the tool will be [tex]0.2\frac{m}{s^{2} }[/tex]
It is given that the force is acting upon a tool that attains an acceleration. The tool has a certain mass. We know that Force is calculated by the product of mass and acceleration of the object which gives us the following equation: => F = m*a, where F = Force, m = Mass of the object, and a = acceleration attained by the object.
Sp, F = 16N, M = 80 kg, and acceleration = a
Putting these values into the Formula to calculate Force we get :
=> F = ma => 16 = 80*a => a = 16/80
=> a = 0.2
Hence, we get Acceleration a = [tex]0.2\frac{m}{s^{2} }[/tex]
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What fraction of the entire electromagnetic spectrum is spanned by visible light?.
Visible light covers a tiny fraction of the electromagnetic spectrum
Electromagnetic Spectrum is the range of all electromagnetic frequencies, including radio waves, microwaves, infrared waves, visible light, ultraviolet light, x-rays and gamma rayVisible Light is the part of the electromagnetic spectrum that consists of waves detectable by the human eyeRadio waves are longest wavelengths and lowest frequenciesMicrowaves are EM waves with higher frequncies than radio, but lower than infrared; used for radar, cell phones, cooking.gamma rays are Electromagnetic waves with the shortest wavelengths and highest frequencies.Ultraviolet are waves that are part of the electromagnetic spectrum and can't be seen by the eyes; they have a higher frequncy than visible light but a lower frequency than x-raysTo know more about electromagnetic spectrum visit : https://brainly.com/question/23727978
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the nec requires that when a suspended ceiling grid is used to support lay-in type lighting fixtures, .
The nec requires a suspended ceiling grid is used to support lay-in type lighting fixtures - the grid be securely fastened together
Does the NEC deal with spill lighting fixtures or mild pollution?
The national electrical Code does now not deal with the difficulty of "spill lights" or "light pollutants" from one belongings to some other because undesirable illumination isn't a(n) ____________________ trouble.
What have to lighting fixtures intended for set up in wet locations be marked with?
A luminaire installed in a bath, in which it's miles in near proximity to steam and water splash ought to be a humid- or wet-location luminaire and marked “suitable for Damp locations” or “appropriate for moist places.”
What article of the NEC defines outlet and receptacle?
210-21(b) Receptacles A “Receptacle,” as described in Article one hundred, is a contact device hooked up at an outlet for the connection of an attachment plug. The words “receptacle” and “receptacles” appear quite often within the country national electrical Code (NEC).
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100 points pls help
With what will a car hit a tree if the car has a mass of 3,000 kg acceleration of m/s^2
What force would be needed to make 10kg bowling ball acceleration of 3m/s^2
What would be the mass of a truck if it is accelerating at a rate of 5m/s^2 and hits a parked car with a force of 14000 N
What is the acceleration of a softball if it has a mass of 0.50 kg and hits the catcher's glove with a force of 25 N
How much does a suitcase weigh if has a mass of 22.5 kg
What would the mass of a rock falling from the sky if it hits the ground with the force of 147N
Find the acceleration of the stacks of books pictured if the stack has a total mass 1.5 kg
A kg model airplane is traveling at a speed 33m/s.
The operator than increases the speed up to 45 m/s in seconds
How much force did the engine need in order to make this change.
Answer:
According to Newton's second law of motion, the acceleration of a body is directly proportional to the force acting on the body and inversely proportional to its mass. The formula for this law is
a
=
F
m
, from which we get the formula
F
=
m
a
. When mass is in kg and acceleration is in
m/s/s
or
m/s
2
, the unit of force is
kgm/s
2
, which is read as kiligram-meter per second squared. This unit is replaced with an N in honor of Isaac Newton. Your problem can be solved as follows:
Known/Unknown:
m
=
3000kg
a
=
2m/s
2
Equation:
F
=
m
a
Solution:
F
=
m
a
=
3000kg
x
2m/s
2
=
6000kgm/s
2
=
6000N
Explanation:
ikikikiki
Answer:
6000
Explanation:
If of work is done on a system, and of heat leave the system, what is the net change in internal energy?
W is the system's overall work product. When the system performs more work than it does for itself, W is positive. The first law of thermodynamics, U=QW, relates the change in the system's internal energy, U, to heat and work.
The internal energy of a system drops when it interacts with its environment. The internal energy of a system grows when work is done on it. Particles accelerate and pick up kinetic energy when energy is applied to increase the temperature. Potential energy is raised when a substance melts or boils because energy is expended in severing the connections holding the particles together.
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an analysis of the advantages and limitations of vacuum tubes in terms of performance and reliability
Vacuum tubes enjoy numerous upper hands over semiconductor gadgets in applications between 300 MHz and 300 GHz.
What is a vacuum tube?A vacuum tube, electron tube, valve (English use), or cylinder (North America), is a gadget that controls electric flow stream in a high vacuum between terminals to which an electric potential distinction has been applied.
The sort known as a thermionic cylinder or thermionic valve uses thermionic emanation of electrons from a hot cathode for basic electronic capabilities like sign intensification and current correction. Non-thermionic sorts, for example, a vacuum phototube, notwithstanding, accomplish electron outflow through the photoelectric impact, and are utilized for such purposes as the discovery of light powers. In the two sorts, the electrons are advanced from the cathode to the anode by the electric field in the cylinder. Sound power speaker utilizing tubes, in activity. Red-orange sparkle is from warmed fibers. Delineation addressing a crude triode vacuum tube and the polarities of the run of the mill dc working possibilities. Not shown are the impedances (resistors or inductors) that would be remembered for series with the C and B voltage sources.
Every group of vacuum tubes (triodes, tetrodes, and their subordinates including magnetrons, klystrons, crossed field speakers, voyaging wave tubes and gyrotrons) have their own qualities as far as working recurrence, quick data transmission, top power, mean power, gain (enhancers), electrical proficiency, linearity, dependability and lifetime. This makes it simpler to choose the most reasonable vacuum tube for a given application.
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Where on the x-axis can a third positive charge be placed so that the net electric force on it is zero?
A third positive charge [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex] can be placed on the x-axis so that the net electric force on it is zero.
whilst -factor charges are in touch, there may be
[tex]F = k \frac{q_{1}q_{2} }{ r^{2} }[/tex]
Where
[tex]k = 9 * 10^{9} Nm^{2}C^{-1}[/tex] = the coulomb constant.
The charges' magnitudes are [tex]q_{1}[/tex] and [tex]q_{2}[/tex].
r is the separation of the charges.
Let,
The third charge equals Q at, x equals x from the source.
because there is no net force acting on the third charge.
Hence,
[tex]f_{1} + f_{2} = 0[/tex]
⇒ [tex]k\frac{(2q)Q}{x^{2} }-k\frac{qQ}{(2a-x)^{2} } = 0[/tex]
⇒ [tex]\frac{2}{x^{2} } - \frac{1}{(2a-x)^{2} } = 0[/tex]
⇒ [tex]\frac{2}{x^{2} } = \frac{1}{(2a-x)^{2} }[/tex]
⇒ [tex]\frac{\sqrt{2} }{x} = \frac{1}{2a-x}[/tex]
⇒ [tex]2\sqrt{2}a - \sqrt{2} = x[/tex]
⇒ [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex]
handiest when forces resulting from previous prices cancel every different out will the pressure on a third fee be 0.
at the same time as the pressure between identical costs is repulsive and is interpreted as high-quality, the pressure between two opposing expenses is attracted and is interpreted as bad.
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a train of length 200m passes over a bridge of length 600m how long does it take to cross the bridge with a uniform speed of 36kmph?
80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.
Given data,
length of bridge = 600m
length of train = 200m
Length of bridge + Length of train is the total distance travelled by train to cross the bridge.
So, 600+200 = 800m = 0.8km
Now, applying the formula for time,
[tex]time =\frac{distance}{speed}[/tex]
[tex]time = \frac{0.8}{36}[/tex]
time = 0.022hours
time in seconds= 0.022×60×60
time in seconds= 1.33×60
time in seconds= 80seconds
Therefore, 80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.
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Assuming that this sound was emitted as a spherical wave, what was the power emitted by the burper during his record burp?
1.15.42 Loudness of sound is the power emitted by the burper during his record burp.
What is the most audible burp ever recorded?Decibels: 112.4
Neville Sharp (Australia) has broken the record for the loudest male burp, which had stood for over a decade.' On July 29, 2021, Neville's mighty burp was measured at 112.4 decibels (db.) in Darwin, Northern Territory, Australia. That is louder than a typical electric drill or trombone.Paul Hunn set the Guinness World Record for the loudest burp on August 23, 2009, at Butlins Bognor Regis in the United Kingdom. At a distance of one meter, this is louder than a jackhammer.At 0 degrees Celsius, a sound of 194 dB has a pressure deviation of 101.325 kPa, which is ambient pressure at sea level. At 194 dB, the waves are effectively creating a complete vacuum between themselves.To learn more about power emitted by the burper refer to
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A ball hits a wall going 10 m/s, and bounces off going 8 m/s. the coefficient of restitution is?
A ball hits a wall going 10 m/s, and bounces off going 8 m/s. the coefficient of restitution is
the coefficient of restitution is 0.8.Given that
A ball hits a wall going 10 m/s, and bounces off going 8 m/s.To find
the coefficient of restitutionSo according the question
We have
The initial velocity of approach towards the wall isu = 10 m/s.
The final velocity of separation from the wall after the collision isv = 7 m/s.
Now, We have to find the coefficient of restitution
We know that,
[tex]n = \frac{velocity \;\;of \; \;separation}{velocity \;of \;approach}[/tex]
So,
[tex]n = \frac{8}{10}[/tex]
n = 0.8
The coefficient of restitution is 0.8.
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Can atomic theory be eliminated
Answer: Atoms cannot be created nor destroyed, and they are indestructible; they cannot be broken into smaller parts. This was based on the Law of Conservation
Explanation: hope this helps you a little!!
If the speed of a car with a turbo engine can be modeled as a function of time using the parabolic equation s(t) = 2t, how many seconds will it take the car to exceed the 65 mph?
The car will take 32.5 seconds to exceed the 65mph.
What is turbo engine?The speed of a car with a turbo engine can be modeled as a function of time using the parabolic equation
s(t) = 2t
We need to find the time taken by the car to exceed the 65 mph.
Put s(t) = 65 mph
65 = 2t
t = 32.5 seconds
The additional compressed air is then forced into the combustion chamber by a turbine that is powered by the exhaust gas of the turbocharged engine. On the other hand, a supercharged engine employs a mechanically-driven process. This kind of charger is often driven by a crankshaft-mounted belt.
In terms of performance and efficiency, a turbocharged engine is superior to a standard engine. The power output of a smaller capacity turbo engine is equivalent to that of a bigger capacity NA engine.
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you are on the management team of a company that is considering purchasing a tanker truck. the truck you want has a volume of 28,000 liters and an empty mass/weight of 15,500 kg. however, the route you wish to travel has a bridge with a weight limit of 25 tons. if you purchase the truck and fill it to capacity with a liquid whose density is 0.90 kg/l, what will the mass of the truck be?
For getting the mass of the truck, we have to just multiply the volume with the liquid density given and then add up the empty truck mass with it.
What is liquid density?A liquid's density is a gauge of how heavy it is relative to the amount being measured or in simpler terms, the density of any kind of liquid is a measure of how much heavy it is for the amount measured.
Any kind of liquid that weighs heavier is termed denser if you weigh two liquids with similar volumes or amounts. A substance which is less dense than water will float if it is gently put on the water's surface.
Just like any kind of solid, the density of a liquid will be equal to the mass of the liquid divided by its volume. i.e., D = m/v.
Mass of the truck = (Volume x liquid density) + empty mass of the truck
= (28,000 x 0.90) + 15,500 kg
= 25,200 + 15,500
= 40,700 kg
Thus the mass of tge truck can be calculated as 40,700 kg.
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if you shout into the grand canyon, your voice travels at the speed of sound (340 m/s) to the bottom of the canyon and back, and you hear an echo. how deep is the grand canyon at a spot where you can hear your echo 5.2 seconds after you shout? [hint: think about the path the sound has to travel for you to hear your own echo.]
The Grand Canyon is 884 m deep from the spot where I heard the echo
The formula for uniformly rectilinear motion (URM) and procedure we will use to solve this exercise is:
v = x /t
Where:
x = distancet = timev = velocityInformation about the problem:
t(echo) = 5.2 sv= 340 m/sx = ?Notice that the echo is a sound that is produced when its wave hits an object (Grand Canyon) and returns to the place where it was emitted (person), that is to say that to calculate the time in which the echo arrived effectively to the bottom of the canyon we must divide it by 2.
t(canyon's bottom) = t(echo)/2
t(canyon's bottom) = 5.2 s/2
t(canyon's bottom) = 2.6 s
Applying the velocity formula, and isolating the distance, we get:
v = x /t(canyon's bottom)
x = v * t(canyon's bottom)
x = 340 m/s * 2.6 s
x = 884 m
What is velocity?It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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a radar station detects an airplane approaching directly from the east. at first observation, the range to the plane is 385.0 m at 41.0 °
An airplane flying directly toward it from the east is spotted by a radar station. The distance to the plane at initial observation is 385.0 m at 41.0 °. 302.26m is the displacement.
What is displacement?Displacement is defined as a shift in an object's position. It is a vector quantity with direction and magnitude. An arrow pointing from the starting location to the finishing position is used to represent it. For instance, if an object moves from position A to position B, its position changes. The term used to describe this change in an object's position is displacement.
The instantaneous velocity of the item is the rate at which the displacement changes as a function of time when studying the motions of objects across time. Therefore, the instantaneous speed is different from the velocity, or the rate at which the distance traveled along a particular path changes over time. The temporal rate of change can also be used to define the velocity. The velocity of P (for example, a point representing the position of a passenger walking on the train) may be referred to as a relative velocity as opposed to an absolute velocity, which is computed with respect to a point which is considered to be "fixed in the space," if one takes into consideration a moving initial position or, equivalently, a moving origin (e.g., an initial position or the origin which is fixed to a train wagon, which in turn moves on its rail track) (such as, for instance, a point fixed on the floor of the train station).
Therefore,
d1= 385.0m
∅ = 41°
and ∅=124° , d2= 795.0m
r1= d1sin∅j+d2cos∅i
=385sin41°j+795cos41°i
=252.59j+599.98i
|r1|= [tex]\sqrt{63801.70+359976.00} ( r=\sqrt{a^{2}+b^{2} }[/tex] if |r| = ai+bj)
=650.98m
similar for r2,
=d1sin124°j+d2cos124°i
=319.16j+(-444..40)i
|r2|=[tex]\sqrt{101863.10+19749.36}[/tex]
=348.72m
so displacement |r2-r1| = 302.26m
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