James is competing in the shot put event for his tracJames is competing in the shot put event for his track team. His best attempt can be modeled using the quadratic function below,
h(x)= -0.05x^2+ x + 6
where x represents the horizontal distance, in feet, the shot traveled and h(x) represents the height, in feet, of the shot.
In this situation, the height of the shot starts to increase when
x = feet. (11 , 0, 10, or 6)
It continues to increase until
x = feet, (6, 20, 11, or 10)
and then the height decreases until
x = feet. (10, 20, 24, or 11)

The function h(t) = -16t^2 + 75 is a quadratic function, and the stick hits the ground at about 2.165 seconds

The function is given as:

h(t) = -16t^2 + 75

Next, we plot the graph of the function h(t)

From the graph of the function h(t) (see attachment), we have the following highlight:

t = -2.165 and t = 2.165 when h(t) = 0

Time cannot be negative.

So, we have:

t = 2.165

This means that the stick hits the ground at about 2.165 seconds

Read more about quadratic functions at:

https://brainly.com/question/8649555

Answer:

66°

Step-by-step explanation:

mJK = ( 6x - 45 )°

mJH = ( x + 20 )°

mJK = mJH

6x - 45 = x + 20

5x = 65

x = 13

mHK = ( x + 20 )° + ( 6x - 45 )°

mHK = 2 × 33° = 66 °

Answer:270

Step-by-step explanation:180/2=90

90*3=270

Hope this helps :)

Answer:

270

Step-by-step explanation:

You can do 180/2 and that gives you 90. Since we know 90:1, we can do 90x3. And that gives 270

Answer:

$ 80.73

Step-by-step explanation:

You can find the complete solution in the given attachment

Usando el concepto de seno, hay que la escalera debe formar un angulo de 41.8º con el suelo.

El seno de un angulo viene dada por el cambio vertical dividido por el cambio diagonal.

En este problema:

Por eso:

[tex]\sin{\alpha} = \frac{8}{12}[/tex]

[tex]\alpha = \sin^{-1}{\left(\frac{8}{12}\right)}[/tex]

[tex]\alpha = 41.8^\circ[/tex]

La escalera debe formar un angulo de 41.8º con el suelo.

Puede-se aprender más a cerca de el concepto de seno en https://brainly.com/question/24766917

#SPJ1

Answer:

The bench mark values might be 10/120 - 30/80

Step-by-step explanation

Answer:A

Step-by-step explanation: She will still care for people but spend lesser years qualifying

Answer: NURSE

Step-by-step explanation:

Answer:

2

5

YES

trinomial

Step-by-step explanation:

Given expression:  [tex]5x^2+3x+6[/tex]

The degree of the polynomial is the highest exponent = 2

The leading coefficient, is the coefficient (value) before the [tex]x^2[/tex] = 5

The constant in the polynomial is the value without a variable, i.e. 6 = YES

This expression can be called a trinomial expression since it is a polynomial with exactly three terms.

Expression given:-

So

Answer:

Step-by-step explanation:

The domain is the set of x-values in the ordered pairs.

So it is {0, 2, 5}

Yes it is a function as for each x value there is  1 y-value  (its a one-to-one function)

Answer:

0.8 meters

Step-by-step explanation:

1 decimeter is 0.1 meters

so,

[tex]\frac{1}{0.1} = \frac{8}{x}\\x = 8*0.1\\x = 0.8[/tex]

Answer:

Part A:

B. rhombus

Part B:

C. Opposite sides are parallel and congruent

Answer:

the answer is 4,500kgm/s2

Step-by-step explanation:

force= mass × acceleration

[tex]f = 1500 \times 3 \\ = 4500kgm {s}^{ - 2} [/tex]

Answer:

i³ = -i

Step-by-step explanation:

i³ can be rewritten as i² · i

i² = -1

-1 · i = -i

Hope this helps!

Answer:

3

Step-by-step explanation:

the absolute value function always returns a positive value , that is

| - a | = | a | = a

given

- 10 - | 5 - 12 | + 3 + | 5 + 12 |

= - 10 - | - 7 | + 3 + | 17 |

= - 10 - 7 + 3 + 17

= 3

Answer:

A customer purchased a furniture for Rs. 3390 with 13% VAT . Find the cost of the furniture without VAT?

Step-by-step explanation:

Angles XVW and XYZ are congruent, and so are angles VWX and XZY by the alternate interior angles theorem.

This means that triangle VWX is similar to triangle YZX.

So, since corresponding sides of similar triangles are proportional, VW/XY = WX / XZ.

120/8 = 15 = WX / 6.

So the width is 90 m.

Answer :-

Step-by-step explanation:

Given :-

To Find :-

Solution :-

According to question,

↠ (x)(x + 2) = 528

↠ x² + 2x = 528

↠ x² + 2x - 528 = 0

↠ x² + 24x - 22x - 528 = 0

↠ x(x + 24) - 22 (x + 24) = 0

↠ (x + 24) (x - 22) = 0

↠ x = -24 or 22

Hence,

Value of two integers are 22 and 24

Step-by-step explanation:

It is given that, The product of 2 consecutive even integers is 528 and we have to find the value of each integers.

Now, As it is stated in the question that the product of 2 consecutive even integers is 528, So

[tex] \\ { \longrightarrow \qquad{ \pmb{ \sf { y(y + 2) = 528 }}}} \: \: \\ \\[/tex]

[tex]{ \longrightarrow \qquad{ \pmb{ \sf { {y}^{2} + 2y = 528 }}}} \: \: \\ \\[/tex]

Subtracting both sides by 528 we get :

[tex] \\ { \longrightarrow \qquad{ \pmb{ \sf { {y}^{2} + 2y - 528= 528 - 528 }}}} \: \: \\ \\[/tex]

[tex]{ \longrightarrow \qquad{ \pmb{ \sf { {y}^{2} + 2y - 528= 0 }}}} \: \: \\ \\[/tex]

We have to find two numbers such that,

[tex] \\ { \longrightarrow \qquad{ \pmb{ \sf { p + q= 24 }}}} \: \: \\ \\[/tex]

[tex]{ \longrightarrow \qquad{ \pmb{ \sf { p \times q= 528 }}}} \: \: \\ \\[/tex]

The two numbers are 24 and 22. So,

[tex] \\ { \longrightarrow \qquad{ \pmb{ \sf { {y}^{2} + (-22y) + 24y - 528= 0 }}}} \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \pmb{ \sf { {y}(y -22) + 24(y - 22)= 0 }}}} \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \pmb{ \sf { (y -22) (y + 24)= 0 }}}} \\ \\ [/tex]

[tex] \: [/tex]

So, The first consecutive even integer is 22.

Now,

[tex] \\ { \longrightarrow \qquad{ \pmb{ \sf {Second \: consecutive \: even \: integer=y \:+2 \: }}}} \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \pmb{ \sf {Second \: consecutive \: even \: integer=2 2+2 \: }}}} \\ \\ [/tex]

[tex]{ \longrightarrow \qquad{ \pmb{ \sf {Second \: consecutive \: even \: integer=24 }}}} \\ \\ [/tex]

Therefore,

Answer:

72 i think.

Step-by-step explanation:

Answer:

[tex]u^{2n+1}[/tex]

Step-by-step explanation:

Assuming you mean [tex]u^nu^{n+1}[/tex], then [tex]u^nu^{n+1}=u^{n+n+1}=u^{2n+1}[/tex].

Answer:

[tex]\Longrightarrow: \boxed{\sf{u^2^n+1}}[/tex]

Step-by-step explanation:

This equation can be solved simply by multiplying by the variable to isolate them on one side.

[tex]\Longrightarrow: \sf{u^n*u^n+1}[/tex]

[tex]\sf{u^n*u^n=u^2}\\\\\\\sf{= (u^2)^n}[/tex]

Solve.

[tex]\sf{\left(u^2\right)^n=u^{2n}=\boxed{\sf{u^{2n}+1}}[/tex]

Therefore, the final answer is [tex]\boxed{\sf{u^{2n}+1}}[/tex].

B.)

Step-by-step explanation:

area of a 10 inch pizza: A=pi * r^2 = 25 pi

area of a 14 inch pizza : A= 49 pi

the change : 49pi - 25pi = 24 pi or about 75.39822

Answer:

3

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

no image, but 6 + 2 + 2 + 6 = 16

Answer:

the one where it say it takes height

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

I got 100%

Answer:

I think the answer is 6/40

Step-by-step explanation:

Step-by-step explanation:

1.

a. true

b. false (the arc angles are relative to the center of the circle)

c. true (as the central angle of a circle is twice any inscribed angle subtended by the same arc)

d. true (but note that the arc angle of YE is again measured via the center of the circle and twice as large as the angle S)

2.

EGS is an isoceles triangle (that means both legs are equally long).

remember the extended Pythagoras for general triangles :

c² = a² + b² - 2ab×cos(C)

c being the side opposite of the angle C.

let's say c is our long baseline, since we have is opposite angle 124°, and a = b = GE = GS, we have

3.8² = a² + a² - 2aa×cos(124) = 2a² - 2a²×cos(124) =

= 2a²(1 - cos(124))

2a² = 3.8²/(1 - cos(124))

a² = 3.8²/(2(1 - cos(124)))

a = GS = sqrt(3.8²/(2(1 - cos(124)))) =

= 2.151883096... ≈ 2.2 cm

3.

circumference

16pi = 2pi×r

r = 8

area = pi×r² = pi×8² = 64pi

yes, the statement is true.

4.

a half-circle has 180°.

the arc angel AD is a full half-circle (because AD is a diameter), so it is 180°.

the angle ACB is the arc angle AB = 40°. so, the arc angle BD must be the rest of the 180° = 180 - 40 = 140°.

5.

diameter = 50 ft.

so, the radius or distance from the center to the circle arc is 50/2 = 25 ft.

the length of a chord is

c = 2×sqrt(r² - d²)

with r being the radius, d being the distance of the chord from the center.

40 = 2×sqrt(25² - d²)

20 = sqrt(625 - d²)

400 = 625 - d²

-225 = -d²

225 = d²

d = 15 cm

so, the distance of the chord from the center is 15 cm.

6.

the arc angles RE and TS are equal. that means the arc lengths of RE and TS are equal.

and that means the arc lengths of RS and ET are equal. the chords between 2 points on a circle must have the same length, when the arc lengths between these 2 points are the same.

7.

they are equally long.

as we saw in 5., the length of a chord depends on the radius of the circle and the distance of the chord from the center.

since both chords are in the same circle (with the same radius), and they both have the same distance from the center, they can only be equally long, as there is no other element to name them different.

8.

the angle NPE is half of the angle NAE (= the arc angle NE).

the arc angle NE = 63×2 = 126°

the angle PET is half of the angle PAT (= the arc angle PT).

the arc angle PT = 19×2 = 38°

the arcs NP and ET cover the rest of the whole circle circumference (360°).

so, arc angle NP + arc angle ET = 360 - 38 - 126 = 196°

but arc angles NP and ET must be equal (as per the problem definition).

therefore, 2 equal arc angles = 196°

1 arc angle = NP = 196/2 = 98°

Answer:

0 ≤ y ≤ 7

Step-by-step explanation:

Hey there! :)

Please see an explanation for better understanding, and let me know if you have any questions!

Range in Function means set of all y-values. We know by the graph that y-value is a vertical value while x-value is horizontal value. From the graph, we have y-axis which is vertical line and x-axis which is horizontal line.

For this question, I would like you to focus on y-value instead, at best, only. That is because we are finding the range, as said above that range is the set of all y-values.

To find the range in graph, first, you must understand that range starts from minimum point/value to maximum point/value. Therefore, we will have to find y-values for both points and combine the interval.

From the graph, we see that there are two points given which are (-6,0) and (9,7). Since (-6,0) is the minimum point because below y = 0, there exists no values. On the other hand, (9,7) is our maximum point because above y = 7, there exists no values.

Focus only y-values, for both points, we have y = 0 and y = 7. Since range is minimum < y < maximum - for opened dots of both points or minimum ≤ y ≤ maximum - for closed dots for both points.

In case if you don’t know what opened dots and closed dots are. Opened dots are white dots while closed dots are colored dots, usually dark ones.

Thus, from the y-values of both point, our range is 0 ≤ y ≤ 7

Answer:

[A] 20%

[B] 400%

Step-by-step explanation:

Part A:

To Find: Percentage

= Price in 1985/price in 2003

Thus,

$62000×100%=6200000÷310000=20%

Part B:

To FInd: Percentage increase

= (Price in 2003-price in 1985)/price in 1985

Thus,

$248000×100=$24800000÷62000=400%

[RevyBreeze]

Given Equation :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad {x}^{2} + 9x - 22 = 0 \:}}} \\ \\[/tex]

To Find :

Solution :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad {x}^{2} + 9x - 22 = 0 \:}}} \\ \\[/tex]

We are to find two numbers such that,

[tex]\\ {\longrightarrow \pmb{\sf {\qquad p + q = 9 \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad p \times q = 22 \:}}} \\ \\[/tex]

The two numbers are 2 and 11, so

[tex]\\ {\longrightarrow \pmb{\sf {\qquad {x}^{2} + ( - 2x) + 11x - 22 = 0 \:}}} \\ \\[/tex]

Finding common factors :

[tex]{\longrightarrow \pmb{\sf {\qquad {x} (x - 2) + 11(x - 2) = 0 \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad (x - 2)(x + 11) = 0 \:}}} \\ \\[/tex]

Whether, the value of x is :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad (x - 2) = 0 \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = 2 \:}}} \\ \\[/tex]

Or, Whether the value of x is :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad (x + 11) = 0 \:}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = - \: 11 \:}}} \\ \\[/tex]

So,

Answer:

A) –11

D) 2

Step-by-step explanation:

Got it right on edge!