Answer:
7850 feet.sq
Step-by-step explanation:
the area of a cercle is:
A = r²*π where r is the radius
A= 50²*3.14 = 7850 ft²
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▹ Answer
0.25 = 1/4 because 25/100 = 1/4
▹ Step-by-Step Explanation
0.25 to a fraction → 25/100
25/100 = 1/4
Therefore, this statement is true. (0.25 = 1/4 because 25/100 = 1/4)
Hope this helps!
- CloutAnswers ❁
Brainliest is greatly appreciated!
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The length of a rectangle is 5M more than twice the width and the area of the rectangle is 63M to find the dimension of the rectangle
Answer:
width = 4.5 m
length = 14 m
Step-by-step explanation:
okay so first you right down that L = 5 + 2w
then as you know that Area = length * width so you replace the length with 5 + 2w
so it's A = (5 +2w) * w = 63
then 2 w^2 + 5w - 63 =0
so we solve for w which equals 4.5 after that you solve for length : 5+ 2*4.5 = 14
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 418 gram setting. It is believed that the machine is underfilling the bags. A 9 bag sample had a mean of 413 grams with a standard deviation of 20. A level of significance of 0.1 will be used. Assume the population distribution is approximately normal. Is there sufficient evidence to support the claim that the bags are underfilled?
Answer:
No. At a significance level of 0.1, there is not enough evidence to support the claim that the bags are underfilled (population mean significantly less than 418 g.)
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that the bags are underfilled (population mean significantly less than 418 g.)
Then, the null and alternative hypothesis are:
[tex]H_0: \mu=418\\\\H_a:\mu< 418[/tex]
The significance level is 0.1.
The sample has a size n=9.
The sample mean is M=413.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=20.
The estimated standard error of the mean is computed using the formula:
[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{20}{\sqrt{9}}=6.6667[/tex]
Then, we can calculate the t-statistic as:
[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{413-418}{6.6667}=\dfrac{-5}{6.6667}=-0.75[/tex]
The degrees of freedom for this sample size are:
[tex]df=n-1=9-1=8[/tex]
This test is a left-tailed test, with 8 degrees of freedom and t=-0.75, so the P-value for this test is calculated as (using a t-table):
[tex]\text{P-value}=P(t<-0.75)=0.237[/tex]
As the P-value (0.237) is bigger than the significance level (0.1), the effect is not significant.
The null hypothesis failed to be rejected.
At a significance level of 0.1, there is not enough evidence to support the claim that the bags are underfilled (population mean significantly less than 418 g.)
The following chart represents the record low temperatures recorded in Phoenix for April-November. Select the answer below that best describes the mean and the median of the data set (round answers to the nearest tenth). A graph titled Phoenix Low Temperatures has month on the x-axis and temperature (degrees Fahrenheit) on the y-axis. April, 32; May, 40; June, 50; July, 61; August, 60; September, 47; October, 34; November, 25. a. The mean is 43.5°F, and the median is 43.6°F. b. The mean is 60.5°F, and the median is 60.5°F. c. The mean is 60°F, and the median is 61°F. d. The mean is 43.6°F, and the median is 43.5°F.
Answer:
d. The mean is 43.6°F, and the median is 43.5°F.
Step-by-step explanation:
Hello!
The data corresponds to the low temperatures in Phoenix recorded for April to November.
April: 32ºF
May: 40ºF
June: 50ºF
July: 61ºF
August: 60ºF
September: 47ºF
October: 34ºF
November: 25ºF
Sample size: n= 8 months
The mean or average temperature of the low temperatures in Phoenix can be calculated as:
[tex]\frac{}{X}[/tex]= ∑X/n= (32+40+50+61+60+47+34+25)/8= 43.625ºF (≅ 43.6ºF)
The Median (Me) is the value that separates the data set in two halves, first you have to calculate its position:
PosMe= (n+1)/2= (8+1)/2= 4.5
The value that separates the sample in halves is between the 4th and the 5th observations, so first you have to order the data from least to greatest:
25; 32; 34; 40; 47; 50; 60; 61
The Median is between 40 and 47 ºF, so you have to calculate the average between these two values:
[tex]Me= \frac{(40+47)}{2} = 43.5[/tex] ºF
The correct option is D.
I hope this helps!
Answer:
it is d
Step-by-step explanation:
Refer to the Trowbridge Manufacturing example in Problem 2-35. The quality control inspection proce- dure is to select 6 items, and if there are 0 or 1 de- fective cases in the group of 6, the process is said to be in control. If the number of defects is more than 1, the process is out of control. Suppose that the true proportion of defective items is 0.15. What is the probability that there will be 0 or 1 defects in a sam- ple of 6 if the true proportion of defects is 0.15
Answer:
77.64% probability that there will be 0 or 1 defects in a sample of 6.
Step-by-step explanation:
For each item, there are only two possible outcomes. Either it is defective, or it is not. The probability of an item being defective is independent of other items. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The true proportion of defects is 0.15
This means that [tex]p = 0.15[/tex]
Sample of 6:
This means that [tex]n = 6[/tex]
What is the probability that there will be 0 or 1 defects in a sample of 6?
[tex]P(X \leq 1) = P(X = 0) + P(X = 1)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{6,0}.(0.15)^{0}.(0.85)^{6} = 0.3771[/tex]
[tex]P(X = 1) = C_{6,1}.(0.15)^{1}.(0.85)^{5} = 0.3993[/tex]
[tex]P(X \leq 1) = P(X = 0) + P(X = 1) = 0.3771 + 0.3993 = 0.7764[/tex]
77.64% probability that there will be 0 or 1 defects in a sample of 6.
A smaller square of side length 17 feet is cut out of a square board. What is the approximate area (shaded region) of the remaining board in square feet?
Answer:
The area of the remaining board is (x² - 289) sq. ft.
Step-by-step explanation:
Let the sides of the bigger square board be, x feet.
It is provided that a smaller square of side length 17 feet is cut out of the bigger square board.
The area of a square is:
[tex]Area=(side)^{2}[/tex]
Compute the area of the bigger square board as follows:
[tex]A_{b}=(side_{b})^{2}=x^{2}[/tex]
Compute the area of the smaller square board as follows:
[tex]A_{s}=(side_{s})^{2}=(17)^{2}=289[/tex]
Compute the area of the remaining board in square feet as follows:
[tex]\text{Remaining Area}=A_{b}-A_{s}[/tex]
[tex]=[x^{2}-289]\ \text{square ft.}[/tex]
Thus, the area of the remaining board is (x² - 289) sq. ft.
Suppose you have two six-sided dice where each side is equally likely to land face up when rolled.
Required:
a. What is the probability that you will roll doubles?
b. What is the probability that you will roll a sum of four?
c. Are these empirical or a theoretical probabilities?
i. Empirical
ii. Theoretical
Answer:a. ii.
A. Is Theoretical because there is no real way of knowing what you will roll.
Answer:
a. 0.17
b. 0.08
c. theoretical
Step-by-step explanation:
Please help with this
Answer:
C) 42
Step-by-step explanation:
The parallel lines divide the transversals proportionally.
x/35 = 30/25
x = 35(6/5) . . . . multiply by 35, reduce the fraction
x = 42
In a study of 205 adults, the average heart rate was 75 beats per minute. Assume the population of heart rates is known to be approximately normal, with a standard deviation of 8 beats per minute. What does a margin of error of 1.1 for the 95% confidence interval of the average beats per minute mean? There is a 95% chance that the population mean is between 67 and 83 beats per minute. There is a 95% chance that the population mean is between 73.9 and 76.1 beats per minute. There is a 5% chance that the population mean is less than 75 beats per minute. There is a 5% chance that the population mean is more than 75 beats per minute.
Answer:
There is a 95% chance that the population mean is between 73.9 and 76.1 beats per minute.
Step-by-step explanation:
i have the test
There is a 95% chance that the population mean is between 73.9 and 76.1 beats per minute.
Calculation of margin of error:Since
The average heart rate was 75 beats per minute.
The standard deviation is 8 beats per minute
And, there is the study of 205 adults
Now the following formula is to be used
Since
[tex]x \pm z \frac{\sigma}{\sqrt{n} }[/tex]
Here
z = 1.96 at 95% confidence interval
So,
[tex]= 75 \pm 1.96 \frac{8}{\sqrt{205} } \\\\= 75 - 1.96 \frac{8}{\sqrt{205} } , 75 + 1.96 \frac{8}{\sqrt{205} }[/tex]
= 73.9 ,76.1
Hence, the above statement should be true.
Learn more about standard deviation here: https://brainly.com/question/20529928
An interior angle of a regular polygon has a measure of 108°. What type of polygon is it?
Answer:
Polygon is pentagon
Step-by-step explanation:
In a regular polygon each angle is equal.
In a regular polygon Each angle of polygon is given by (2n-4)90/n
where n is the number of sides of the polygon
given
An interior angle of a regular polygon has a measure of 108°.
(2n-4)90/n = 108
=> 180n - 360 = 108n
=> 180n-108n= 360
=> 72n = 360
=> n = 360/72 = 5
Thus, polygon has 5 sides
and we know that regular polygon which has 5 sides is called pentagon.
Thus, Polygon is pentagon
A rectangular park is 8 miles long and 6 miles wide. How long is a pedestrian route that runs diagonally across the park?
Hey there! :)
Answer:
10 miles.
Step-by-step explanation:
To solve for the diagonal side, we can simply visualize the sides of the rectangle as sides of a right triangle with the diagonal being the hypotenuse.
We can use the Pythagorean Theorem (a² + b² = c²), where:
a = length of short leg
b = length of long leg
c = length of the diagonal
Solve:
c² = a² + b²
c² = 6² + 8²
c² = 36 + 64
c² = 100
c = 10 miles. This is the length of the pedestrian route.
Answer:
10 milesSolution,
Hypotenuse (h) = R
Perpendicular (p) = 8 miles
Base (b) = 6 miles
Now,
Using Pythagoras theorem:
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
Plugging the values:
[tex] {r}^{2} = {(8)}^{2} + {(6)}^{2} [/tex]
Calculate:
[tex] {r}^{2} = 64 + 36[/tex]
[tex] {r}^{2} = 100[/tex]
[tex]r = \sqrt{100} [/tex]
[tex]r = 10 \: miles[/tex]
Length of route = 10 miles
Hope this helps...
Good luck on your assignment...
The trip is 375 miles and the train usually travels at a speed of 230mph. How long will it take them to travel.
Answer:
97.5 minutes or 1.63 hours
Step-by-step explanation:
1. Find the amount of time it takes to travel 1 mile
[tex]\frac{60}{230}[/tex] = 0.26 minutes
2. Multiply the distance by the time it takes to travel 1 mile
375 · 0.26 = 97.5 minutes
To convert to hours, divide by 60 because there are 60 minutes in 1 hour.
97.5 ÷ 60 = 1.63 hours
g a) What are some of the distinguishing properties of a normal Distribution? Discuss b) The sampling distribution of the sample means is the curve that describes how the sample means are distributed. True or False Explain c) The mean of sample means is the same as the population for a given sample of size n. True False Explain
Answer:
a) Check Explanation.
b) True. Check Explanation.
c) True. Check Explanation.
Step-by-step explanation:
a) A normal distribution is one which is characterized by four major properties.
- A normal distribution is symmetrical about the center of the distribution. That is, the variables spread out from the center in both directions in the same manner; the right side of the distribution is a mirror image of the left side of the distribution.
The center of a normal distribution is located at its peak, and 50% of the data lies above the mean, while 50% lies below.
- The mean, median and the mode are coincidental. The mean, median and mode of a normal distribution are all the same value.
- A normal distribution is unimodal, that is, has only one mode.
- The ends of the probability curve of a normal distribution never touch the x-axis, hence, it is said too be asymptotic.
b) The sampling distribution of sample means arises when random samples are drawn from the population distribution and their respective means are computed and put together to form a distribution. Hence, the curve of this sampling distribition of sample means will show how the sample means are distributed. Hence, this statement is true.
c) The Central Limit Theorem gives that if the samples are drawn randomly from a normal distribution and each sample size is considerable enough, the mean of the sampling distribution of sample means is approximately equal to the population mean. So, if the conditions stated are satisfied, then thos statement too, is true.
Hope this Helps!!!
Which expressions are equivalent to -3(2w+6)-4
Answer:
B is the answer
Step-by-step explanation:
-3(2w+6)-4
-6w-18-4
-6w-22
Answer:
B = 2(−3w + (−11)) is the answer.Step-by-step explanation:
-3(2w + 6) - 4
1. Distribute
= -3*2w = -6w
= -3 * 6 = -18
= -6w -18
2. Simplify like terms
= -18 - 4
= -22
3. Place variables and numbers together
= -6w - 22
-6w -22 is the answer.So, B is the answer.Explanation:
2 * -3w = -6w
2*-11 = -22
Place them together and you get the answer!
Find the remainder when f(x)=2x3−x2+x+1 is divided by 2x+1.
Step-by-step explanation:
it can be simply done by using remainder theorem.
You spend 6,380.00 a year for rent. This is 22% of your income. What is your income?
Answer: 29,000.00
Step-by-step explanation:
Let the income=x. 22%=0.22.
So 6380/x=0.22
x=6380/0.22=29,000.00
Jina wants to measure the width of a river. She marks off two right triangles, as shown in the figure. The base of the larger triangle has a length of 56m, and the base of the smaller triangle has a length of 26m. The height of the smaller triangle is 20.9m. How wide is the river? Round your answer to the nearest meter.
Answer:
width of a river = 45m
Step-by-step explanation:
ration and proportion
let x = width of a river
x 20.9 m
------ = --------
56 m 26 m
x = (20.9 * 56) / 26
x = 45 m
therefore the width of a river is 45 m
Use the Laplace transform to solve the given initial-value problem.
y' + 3y = f(t), y(0) = 0
where f(t) = t, 0 ≤ t < 1 0, t ≥ 1
Answer:
The solution to the given Initial - Value - Problem is [tex]y(t) = \frac{-1}{9} + \frac{1}{3}t + \frac{1}{9}e^{-3t} - [\frac{-1}{9} + \frac{1}{3}t - \frac{2}{9}e^{-3(t-1)}]u(t-1)[/tex]
Step-by-step explanation:
y' + 3y = f(t).................(1)
f(t) = t when 0 ≤ t < 1
f(t) = 0 when t ≥ 1
Step 1: Take the Laplace transform of the LHS of equation (1)
That is L(y' + 3y) = sY(s) + 3Y(s) = Y(s)[s + 3]..............(*)
Step 2: Get an expression for f(t)
For f(t) = t when 0 ≤ t < 1
f₁(t) = t (1 - u(t - 1)) ( there is a time shift of the unit step)
For f(t) = 0 when t ≥ 1
f₂(t) = 0(u(t-1))
f(t) = f₁(t) + f₂(t)
f(t) = t - t u(t-1)................(2)
Step 3: Taking the Laplace transform of equation (2)
[tex]F(s) = \frac{1}{s^2} - e^{-s} ( \frac{1}{s^2} + \frac{1}{s})[/tex]...............(**)
Step 4: Equating * and **
[tex]Y(s) [s + 3]=\frac{1}{s^2} - e^{-s} ( \frac{1}{s^2} + \frac{1}{s}) \\Y(s) = \frac{1}{s^2(s+3)} - e^{-s} ( \frac{1}{s^2(s+3)} + \frac{1}{s(s+3)})[/tex].......................(3)
Since y(t) is the solution we are looking for we need to find the Inverse Laplace Transform of equation (3) by first breaking every fraction into partial fraction:
[tex]\frac{1}{s^2 (s+3)} = \frac{-1}{9s} + \frac{1}{3s^2} + \frac{1}{9(s+3)}[/tex]
[tex]\frac{1}{s (s+3)} = \frac{1}{3s} + \frac{1}{3(s+3)}[/tex]
We can rewrite equation (3) by representing the fractions by their partial fractions.
[tex]Y(s) = \frac{-1}{9s} + \frac{1}{3s^2} + \frac{1}{9(s+3)} - e^{-s} [\frac{-1}{9s} + \frac{1}{3s^2} + \frac{1}{9(s+3)} + \frac{1}{3s} + \frac{1}{3(s+3)}]\\Y(s) = \frac{-1}{9s} + \frac{1}{3s^2} + \frac{1}{9(s+3)} - e^{-s}[\frac{2}{9s} + \frac{1}{3s^2} - \frac{2}{9(s+3)}][/tex]................(4)
step 5: Take the inverse Laplace transform of equation (4)
[tex]y(t) = \frac{-1}{9} + \frac{1}{3}t + \frac{1}{9}e^{-3t} - u(t-1)[\frac{2}{9} + \frac{1}{3}(t-1) - \frac{2}{9}e^{-3(t-1)}][/tex]
Simplifying the above equation:
[tex]y(t) = \frac{-1}{9} + \frac{1}{3}t + \frac{1}{9}e^{-3t} - [\frac{-1}{9} + \frac{1}{3}t - \frac{2}{9}e^{-3(t-1)}]u(t-1)[/tex]
The Laplace transform is use to solve the differential equation problem.
The solution for the given initial-value problem is,
[tex]y(t)=\dfrac{-1}{9}+\dfrac{-1}{3}t+\dfrac{1}{9}e^-3t-\left[\dfrac{-1}{9}+\dfrac{-1}{3}t+\dfrac{2}{9}e^{-3(t-1)}\right]u(t-1)[/tex]
Given:
The given initial value problem is [tex]y' + 3y = f(t)[/tex].
Consider the left hand side of the given equation.
[tex]y'+3y[/tex]
Take the Laplace transform.
[tex]L(y' + 3y) = sY(s) + 3Y(s) \\L(y' + 3y) = Y(s)[s + 3][/tex]
Consider the right hand side and get the expression for [tex]f(t)[/tex].
[tex]f(t) = t[/tex] when 0 ≤ t < 1
From time shift of the unit step
[tex]f_1(t) = t (1 - u(t - 1))[/tex]
For f(t) = 0 when t ≥ 1
Now,
[tex]f_2(t) = 0(u(t-1))f(t) = f_1(t) + f_2(t)f(t) = t - t u(t-1)[/tex]
Take the Laplace for above expression.
[tex]F(s)=\dfrac{1}{s^2}-e^{-s}\left(\dfrac{1}{s^2}+\dfrac{1}{s}\right)[/tex]
Now, the equate the above two equation.
[tex]Y(s)\left[s+3\right ]=\dfrac{1}{s^2}-e^{-s}\left(\dfrac{1}{s^2}+\dfrac{1}{s}\right)\\Y(s)=\dfrac {1}{(s^2(s+3))}-e^{-s}\left(\dfrac{1}{(s^2(s+3))}+\dfrac{1}{s(s+3)\right)}[/tex]
Find the inverse Laplace for the above equation.
[tex]\dfrac{1}{(s^2(s+3))}=\dfrac{-1}{9s}+\dfrac{1}{3s^2}+\dfrac{1}{9(s+3)}\\\dfrac{1}{(s(s+3))}=\dfrac{1}{3s}+\dfrac{1}{3(s+3)}[/tex]
Calculate the partial fraction of above equation.
[tex]Y(s)=\dfrac{-1}{9s}+\dfrac{1}{3s^2}+\dfrac{1}{9(s+3)}-e^{-s}\left[\dfrac{-1}{9s}+\dfrac{1}{3s^2}+\dfrac{1}{9(s+3)}+\dfrac{1}{3s}+\dfrac{1}{3(s+3)}\right]\\Y(s)=\dfrac{2}{9s}+\dfrac{1}{3s^2}+\dfrac{1}{9(s+3)}-e^{-s}\left[\dfrac{2}{9s}+\dfrac{1}{3s^2}-\dfrac{2}{9(s+3)}\right][/tex]
Take the inverse Laplace of the above equation.
[tex]y(t)=\dfrac{-1}{9}+\dfrac{-1}{3}t+\dfrac{1}{9}e^-3t-\left[\dfrac{-1}{9}+\dfrac{-1}{3}t+\dfrac{2}{9}e^{-3(t-1)}\right]u(t-1)[/tex]
Thus, the solution for the given initial-value problem is,
[tex]y(t)=\dfrac{-1}{9}+\dfrac{-1}{3}t+\dfrac{1}{9}e^-3t-\left[\dfrac{-1}{9}+\dfrac{-1}{3}t+\dfrac{2}{9}e^{-3(t-1)}\right]u(t-1)[/tex]
Learn more about what Laplace transformation is here:
https://brainly.com/question/14487937
Write an equation in slope-intercept form of the line that passes through the point (-6,-5) with slope 6.
Answer:
y=6x+31
Step-by-step explanation:
Since we are given a point and a slope, we can use the slope-intercept formula.
[tex]y-y_{1} =m(x-x_{1})[/tex]
where (x1,y1) is a point on the line and m is the slope.
The point given is (-6,-5) and the slope is 6.
x1= -6
y1= -5
m=6
[tex]y--5=6(x--6)[/tex]
A negative number subtracted from another number, or two negative signs, becomes a positive.
[tex]y+5=6(x+6)[/tex]
We want to find the equation of the line, which is y=mx+b (m is the slope and b is the y-intercept). Therefore, we must get y by itself on one side of the equation.
First, distribute the 6. Multiply each term inside the parentheses by 6.
[tex]y+5=(6*x)+(6*6)[/tex]
[tex]y+5=6x+36[/tex]
Subtract 5 from both sides, because it is being added on to y.
[tex]y+5-5=6x+36-5[/tex]
[tex]y=6x+36-5[/tex]
[tex]y=6x+31[/tex]
The equation of the line is y=6x+31
1. Growth of Functions (11 points) (1) (4 points) Determine whether each of these functions is O(x 2 ). Proof is not required but it may be good to try to justify it (a) 100x + 1000 (b) 100x 2 + 1000
Answer:
See explanation
Step-by-step explanation:
To determine whether each of these functions is [tex]O(x^2)[/tex], we apply these theorems:
A polynomial is always O(the term containing the highest power of n)Any O(x) function is always [tex]O(x^2)[/tex].(a)Given the function: f(x)=100x+1000
The highest power of n is 1.
Therefore f(x) is O(x).
Since any O(x) function is always [tex]O(x^2)[/tex], 100x+1000 is [tex]O(x^2)[/tex].
[tex](b) f(x)=100x^ 2 + 1000[/tex]
The highest power of n is 2.
Therefore the function is [tex]O(x^2)[/tex].
Answer:
i think its 2000
Step-by-step explanation:
The dimensions of a closed rectangular box are measured as 96 cm, 58 cm, and 48 cm, respectively, with a possible error of 0.2 cm in each dimension. Use differentials to estimate the maximum error in calculating the surface area of the box.
Answer:
161.6 cm²Step-by-step explanation:
Surface Area of the rectangular box = 2(LW+LH+WH)
L is the length of the box
W is the width of the box
H is the height of the box
let dL, dW and dH be the possible error in the dimensions L, W and H respectively.
Since there is a possible error of 0.2cm in each dimension, then dL = dW = dH = 0.2cm
The surface Area of the rectangular box using the differentials is expressed as shown;
S = 2{(LdW+WdL)+(LdH+HdL)+(WdH+HdW)]
Also given L = 96cm W = 58cm and H = 48cm, on substituting this given values and the differential error, we will have;
S = 2{(96*0.2+58*0.2) + (96*0.2+48*0.2)+(58*0.2+48*0.2)}
S = 2{19.2+11.6+19.2+9.6+11.6+9.6}
S = 2(80.8)
S = 161.6 cm²
Hence, the surface area of the box is 161.6 cm²
The Westwood Warriors basketball team wants to score more points. To get better at scoring points the team is trying to improve its offensive strategies. Some opponents primarily use a zone defense, while others primarily use a man-to-man defense. When the Warriors play against teams that use a zone defense they score an average of 67 points per game with a standard deviation of 8 points per game. When they used a new offensive strategy against this defense, they scored 77 points. What is the Z-score of this value
Answer:
It is better for the warriors to use man-to-man defense.
Step-by-step explanation:
The complete question is: The Westwood Warriors basketball team wants to score more points. To get better at scoring points the team is trying to improve its offensive strategies. Some opponents primarily use a zone defense, while others primarily use a man-to-man defense. When the Warriors play against teams that use a zone defense they score an average of 67 points per game with a standard deviation of 8 points per game. When they play against teams that use a man-to-man defense they score an average of 62 points per game with a standard deviation of 5 points per game.
Since the Warriors started using their improved offensive strategies they have played two games with the following results.
Against the McNeil Mavericks
Maverick defense: zone
Warrior points: 77
Against the Round Rock Dragons
Dragon defense: man-to-man
Warrior points: 71
What is the Z-score of these values?
We are given that when the Warriors play against teams that use a zone defense they score an average of 67 points per game with a standard deviation of 8 points per game. When they play against teams that use a man-to-man defense they score an average of 62 points per game with a standard deviation of 5 points per game.
We have to find the z-scores.
Finding the z-score for the zone defense;Let X = points score by warriors when they use zone defense
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = mean score = 67 points
[tex]\sigma[/tex] = standard deviation = 8 points
It is stated that the Warriors scored 77 points when they used zone defense, so;
z-score for 77 = [tex]\frac{X-\mu}{\sigma}[/tex]
= [tex]\frac{77-67}{8}[/tex] = 1.25
Finding the z-score for the zone defense;Let X = points score by warriors when they use man-to-man defense
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = mean score = 62 points
[tex]\sigma[/tex] = standard deviation = 5 points
It is stated that the Warriors scored 71 points when they used man-to-man defense, so;
z-score for 71 = [tex]\frac{X-\mu}{\sigma}[/tex]
= [tex]\frac{71-62}{5}[/tex] = 1.8
So, it is better for the warriors to use man-to-man defense.
Which of the following equation is equivalent toY=2x+3? A. Y - 3 = 2(x-1) B. Y - 2x=3 C. Y - 3 = 2(x+1) D. Y + 2x = 3
Answer:
the answer is b
Step-by-step explanation:
Find the value of s(t(-3)):
s(x) = - 3x-2
t(x) = 5x - 4
Please helppp!
Answer:
(-3x-2/x) multiply by (-15x+12/x) so It's (A)
Hope this helped you!!
Step-by-step explanation:
The product of an irrational number and a rational number is irrational. Sometimes True Always True Never True
Answer:
Always true
Step-by-step explanation:
If you can't express the number as a ratio of integers, multiplying or dividing it by integers will not make it so you can.
If π is irrational, 2π is also irrational.
It is always true that the product of a rational and an irrational number is irrational.
Answer:
all ways true
Step-by-step explanation:
A market research company conducted a survey to find the level of affluence in a city. They defined the category "affluence" for people earning $100,000 or more annually. Out of 267 persons who replied to their survey, 32 are considered affluent. What is the 95% confidence interval for this population proportion? Answer choices are rounded to the hundredths place
Answer:
A 95% confidence interval for this population proportion is [0.081, 0.159].
Step-by-step explanation:
We are given that a market research company conducted a survey to find the level of affluence in a city.
Out of 267 persons who replied to their survey, 32 are considered affluent.
Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;
P.Q. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of people who are considered affluent = [tex]\frac{32}{267}[/tex] = 0.12
n = sample of persons = 267
p = population proportion
Here for constructing a 95% confidence interval we have used One-sample z-test for proportions.
So, 95% confidence interval for the population proportion, p is ;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level
of significance are -1.96 & 1.96}
P(-1.96 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 1.96) = 0.95
P( [tex]-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95
P( [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95
95% confidence interval for p = [ [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] , [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ]
= [ [tex]0.12-1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } }[/tex] , [tex]0.12+1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } }[/tex] ]
= [0.081, 0.159]
Therefore, a 95% confidence interval for this population proportion is [0.081, 0.159].
Answer:
0.08 to 0.16
Step-by-step explanation:
Which of the following values are in the range of the function graphed below? check all that apply.
A. 0
B. -4
C. 2
D. 1
E. -1
F. 4
Answer:
1
Step-by-step explanation:
The range is the output values
The only output value is y=1
The range is 1
A class of 30 music students includes 13 who play the piano, 15 who play the guitar, and 9 who play both the piano and the guitar. How many students in the class play neither instrument?
Answer: 2
Step-by-step explanation:
As given, out of 30 students, 15 play guitar and 13 play piano, thats 28.
Among these, 9 play both the guitar and the piano.
That means, only 2 remaining students play neither instrument. (30-15-13)
what is 3/5 of 1800
Answer:
1080
Step-by-step explanation:
first do 3 times 1800, because they are both the numerators. Then divide that number, which is 5400, by the denominator: 5. You will get 1080.
The Nutty Professor sells cashes for $6.00 per pound and Brazil nuts for $5.30 per pound. How much of
each type should be used to make a 35 pound mixture that sells for $5.64 per pound?
Answer:
17 pound of cashew and 18 pound of Brazil nutsStep-by-step explanation:
Let X be the amount of cashews that the nutty professor will mix.
Since, the total weight of the nuts should be 35 lbs
The amount of Brazil nuts = 35 - X
Now,
[tex]6x + 5.30(35 - x) = 5.64(35)[/tex]
[tex]600x + 530(35 - x) = 564 \times 35[/tex]
[tex]600x + 18550 - 530x = 19740[/tex]
[tex]70x = 19740 - 18550[/tex]
[tex]70x = 1190[/tex]
[tex]x = \frac{1190}{70} [/tex]
[tex]x = 17[/tex]
Again,
[tex] 35 - x[/tex]
[tex]35 - 17[/tex]
[tex]18[/tex]
17 pounds of cashew and 18 pounds of Brazil nuts.
Hope this helps...
Good luck on your assignment...