Jane cloaked in to world on Tuesday at 7:30 am and went to her lunch at 11:30 am. She returned from her lunch break at 12:30 pm and clocked out of work for the day at 4:00pm. How many hours did she work on Tuesday?

Answers

Answer 1

Answer:

7 hours 30 minutes

Step-by-step explanation:

Jane clocks into work at 7:30 and goes to lunch at 11:30. (4 hours)

4 hours so far.

takes 1 hour break and returns for 12:30.

She finishes at 4. Time from 12:30 to 4 is (3h30)

3h30 + 4 = 7h30m

Check yourself ^


Related Questions

A fish tank has 12 angelfish .out of every 8 fish 3 are angelfish. how many fish are in the tank?

Answers

12 fishes are in the tank

A fish tank has 12 angelfish .out of every 8 fish 3 are angelfish. how many fish are in the tank?

Answer:

Step-by-step explanation:

12angelfish(8fish/3angelfish)=32 fish

answer please quick its due

Answers

Answer:

a

Step-by-step explanation:

A, B, C and D form the vertices of a parallelogram
AD = 10.3cm, AB = 15.5cm and BAD = 63°
Find the area of the parallelogram. Round to 1 DP

The diagram is not drawn accurately.​

Answers

AB=8.7 cm. Work out the length of BC. ... 1. Adi. Diagram NOT accurately drawn. POR is a triangle. Angle Q = 90° ... Give your answer correct to 1 decimal place. ton o. Ady ... Ad. POR is a right-angled triangle. PR = 12 cm. OR = 4.5 cm. Angle PRO = 90°. ... AB= 7 cm. BC = 12 cm. Angle BAD= 65°. Calculate the length of AC.

find the area of the shaded region under the
standard normal curve. If convenient, use technology to find the area

Answers

Answer

The area of the shaded region under the standard normal curve is 0.4834.

Step-by-step explanation:

A random variable X is said to have a normal distribution with mean, µ and variance σ².

Then , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z  N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Compute the area under the curve between -2.13 and 0 as follows:

                           

Thus, the area of the shaded region under the standard normal curve is 0.4834.

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