Keith Rollag (2007) noticed that coworkers evaluate and treat "new" employees differently from other staff members. He was interested in how long a new employee is considered "new" in an organization. He surveyed four organizations ranging in size from 34 to 89 employees. He found that the "new" employee status was mostly reserved for the 30% of employees in the organization with the lowest tenure.
A) In this study, what was the real range of employees hired by each organization surveyed?
B) What was the cumulative percent of "new" employees with the lowest tenure?

Answers

Answer 1

Answer:

a) Real range of employees hired by each organization surveyed = 56

b) The cumulative percent of "new" employees with the lowest tenure =        30%

Step-by-step explanation:

a) Note: To get the real range of employees hired by each organization, you would do a head count from 34 to 89 employees. This means that this can be done mathematically by finding the difference between 34 and 89 and add the 1 to ensure that "34" is included.

Real range of employees hired by each organization surveyed = (89 - 34) + 1

Real range of employees hired by each organization surveyed = 56

b) It is clearly stated in the question that  the "new" employee status was mostly reserved for the 30% of employees in the organization with the lowest tenure.

Therefore, the cumulative percent of "new" employees with the lowest tenure = 30%


Related Questions

According to Brad, consumers claim to prefer the brand-name products better than the generics, but they can't even tell which is which. To test his theory, Brad gives each of 199 consumers two potato chips - one generic, and one brand-name - then asks them which one is the brand-name chip. 92 of the subjects correctly identified the brand-name chip.

Required:
a. At the 0.01 level of significance, is this significantly greater than the 50% that could be expected simply by chance?
b. Find the test statistic value.

Answers

Answer:

a. There is not enough evidence to support the claim that the proportion that correctly identifies the chip is significantly smaller than 50%.

b. Test statistic z=-1.001

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that the proportion that correctly identifies the chip is significantly smaller than 50%.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi=0.5\\\\H_a:\pi<0.5[/tex]

The significance level is 0.01.

The sample has a size n=199.

The sample proportion is p=0.462.

[tex]p=X/n=92/199=0.462[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.5*0.5}{199}}\\\\\\ \sigma_p=\sqrt{0.001256}=0.035[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.462-0.5+0.5/199}{0.035}=\dfrac{-0.035}{0.035}=-1.001[/tex]

This test is a left-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=P(z<-1.001)=0.16[/tex]

As the P-value (0.16) is greater than the significance level (0.01), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the proportion that correctly identifies the chip is significantly smaller than 50%.

solve for x
2x/3 + 2 = 16

Answers

Answer:

2x/3 + 2= 16

=21

Step-by-step explanation:

Standard form:

2

3

x − 14 = 0  

Factorization:

2

3 (x − 21) = 0  

Solutions:

x = 42

2

= 21

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