Kennith blows up an AMG C 63 and it releases 530 kJ. How many kilocalories of energy are released?

Kennith Blows Up An AMG C 63 And It Releases 530 KJ. How Many Kilocalories Of Energy Are Released?

Answers

Answer 1

The amount of kilocalories of energy Kennith released after blowing up an AMG C 63 is 127 kcal.

How to determine energy?

To convert from kilojoules to kilocalories, multiply by 0.239. Therefore, the amount of kilocalories of energy released is 530 kJ × 0.239 = 127 kcal.

No, energy cannot be created. Energy can only be converted from one form to another. For example, when you burn a piece of wood, the chemical energy in the wood is converted into heat energy and light energy.

No, energy cannot be destroyed. Energy can only be converted from one form to another. For example, when you turn on a light switch, the electrical energy in the power grid is converted into light energy.

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Related Questions

Please Help!
About to fail my class for this

Answers

IUPAC (International Union of Pure and Applied Chemistry) naming is also known as systematic naming.

It is a set of rules and guidelines used to name chemical compounds systematically. It provides a standardized method for naming organic and inorganic compounds based on their molecular structure and composition.

The longest continuous carbon chain in the compound is identified as the parent chain.

The IUPAC name of the given compounds are:

2-methyl,2-hexene4-ethyl, 3,5-dimethyl nonane4-methyl, 2-heptene5-propyl decane2-methyl butane2-methyl, 2-pentene

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A chemist uses 0.25 L of 2.00 M H2SO4 to completely neutralize a 2.00 L of solution of NaOH. The balanced chemical equation of the reaction is given below.

2NaOH + H2SO4 Right arrow. Na2SO4 + 2H2O

What is the concentration of NaOH that is used?
0.063 M
0.25 M
0.50 M
1.0 M

Answers

The concentration of NaOH used is 0.125 M to neutralize 2.00 L of a solution of NaOH.

Given information.

Volume of H₂SO₄ = 0.25 L

Concentration of H₂SO₄= 2 M

Concentration of NaOH = 2 L

From the balanced chemical equation: 2 NaOH + H₂SO₄ → Na₂SO₄ + 2 H₂O

The stoichiometric ratio between NaOH and H₂SO₄ is 2:1. This means that for every 2 moles of NaOH, 1 mole of H₂SO₄ is required for complete neutralization.

Moles of H₂SO₄ = volume (in L) × concentration (in M)

= 0.25 L × 2.00 M

= 0.50 moles of H2SO4

According to the stoichiometry of the reaction, since the ratio between NaOH and H₂SO₄ is 2:1, the number of moles of NaOH used is half of the moles of H₂SO₄ used:

Moles of NaOH = 0.50 moles of H2SO4 / 2

= 0.25 moles of NaOH

The concentration of NaOH = Moles of NaOH / Volume of NaOH

= 0.25 moles / 2.00 L

= 0.125 M

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what was the original pressure in a rigid container if the new pressure is 82.5atm and the new temperature was raised from 44c to 67c

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The original pressure of a rigid container if the new pressure is 82.5atm and the new temperature was raised from 44°C to 67°C is 76.92 atm.

How to calculate pressure?

The pressure of a container can be calculated by using the following formula;

Pa/Ta = Pb/Tb

Where;

Pa and Ta = initial pressure and temperaturePb and Tb = final pressure and temperature

According to this question, the new pressure in a container is 82.5 atm and the new temperature was raised from 44°C to 67°C. The original pressure can be calculated as follows:

Pa/317 = 82.5/340

Pa = 317 × 0.243

Pa = 76.92 atm

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pls help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Alpha particles are the least penetrating type of radiation among the list.

Why are Alpha particles the least penetrating?

They are heavy and therefore move really slow because Alpha particles are made up of two protons and two neutrons that are bound together very tightly.

This is known to make Alpha particles very heavy and slow-moving, which means they can be stopped by a sheet of paper or even your skin.

Secondly, Alpha particles are positively charged. Alpha particles are positively charged, which means they are attracted to negatively charged electrons. This makes them more likely to interact with atoms and molecules, which can lead to damage.

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