Kenny has 576 baseball cards. He would like
to put them in a blnder. Each binder page
holds 12 cards. 'How many pages does he
need for his baseball card binder?

Answer:

-1

Step-by-step explanation:

Using the formula to find gradient or slope:

m = (y2 - y1)/ (x2 - x1)

Using any two points from the graph: (-2, 0) (0, -2)

Substitute this into the equation to get the answer of -1.

Answer:

60% if this is an edge question

:)!!!!!!!!!!!!!!!!!!!

:)

<3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3 <3

Step-by-step explanation:

check the attached file

Answer:

Step-by-step explanation:

I thought of a 2 digit number. The digits of my number are different:  [XY]

Then I'm lost. Does "The unit digit of my number is the tens digit raised third power" mean that the X is raised to the third power?:

X^3

But then we need more information.  X could be 1, 2,3, or 4.  At 5 it becomes a three digit number.  All of the other option result in a two digit number with different digits, so all seem possible.  I don't know how to answer this without more information.

Answer:

You didn't ask a question.

Step-by-step explanation:

The volume of the box is the amount of space in it.

The dimension of the postcard is:

[tex]\mathbf{Length = 10}[/tex]

[tex]\mathbf{Width = 18}[/tex]

Let x represents the length of the cut.

So, the dimension of the box is:

[tex]\mathbf{Length = 10 -2x}[/tex]

[tex]\mathbf{Width = 18 -2x}[/tex]

[tex]\mathbf{Height = x}[/tex]

(a) The function that represents the volume of the box

This is calculated as:

[tex]\mathbf{V(x) = Length \times Width \times Height}[/tex]

So, we have:

[tex]\mathbf{V(x) = (10 - 2x) \times (18 - 2x) \times x}[/tex]

Expand

[tex]\mathbf{V(x) = 180x - 56x^2 + 4x^3}[/tex]

Hence, the volume function is: [tex]\mathbf{V(x) = 180x - 56x^2 + 4x^3}[/tex]

(b) The dimension that maximizes the volume

We have:

[tex]\mathbf{V(x) = 180x - 56x^2 + 4x^3}[/tex]

Differentiate

[tex]\mathbf{V'(x) = 180- 112x + 12x^2}[/tex]

Set to 0

[tex]\mathbf{180- 112x + 12x^2 = 0}[/tex]

Using a calculator, we have:

[tex]\mathbf{x = 7.3,2.1}[/tex]

The value x = 7.3 is greater than the dimension of the box.

So, we have:

[tex]\mathbf{x = 2.1}[/tex]

Recall that:

[tex]\mathbf{Length = 10 -2x}[/tex]

[tex]\mathbf{Width = 18 -2x}[/tex]

[tex]\mathbf{Height = x}[/tex]

So, we have:

[tex]\mathbf{Length = 10 -2 \times 2.1 = 5.8}[/tex]

[tex]\mathbf{Width = 18 -2 \times 2.1 = 13.8}[/tex]

[tex]\mathbf{Height = 2.1}[/tex]

Hence, the dimension that maximizes the volume is 5.8 by 13.8 by 2.1

(c) The maximum volume

This is calculated as the product of the dimension of the box

So, we have:

[tex]\mathbf{Volume = 5.8 \times 13.8 \times 2.1}[/tex]

[tex]\mathbf{Volume = 168.1}[/tex]

Hence, the maximum volume of the box is 168.1 cubic inches

Read more about volumes at:

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Step-by-step explanation:

50000÷10

=5000

Answer:

12 feet 9 inches

Step-by-step explanation:

There are 3 feet in a yard, and 12 inches in a foot. Multiply those together and you get 36 inches in a yard.

2 yards × 36 inches/yard = 72 inches

2 feet × 12 inches/foot = 24 inches

72 inches + 24 inches = 96 inches

------------

7 yards × 36 inches/yard = 252 inches

252 inches + 9 inches = 261 inches

==============

Add those together:

96 inches + 261 inches = 357 inches

Then to convert to feet again, you need to divide by 12 and find the remainder. I prefer to do it with a calculator like this, but you can do it however you prefer:

357 ÷ 12 = 29.75 feet (round down)

12 × 29 = 348 inches in 12 feet

Then find the remainder:

357 - 348 = 9 inches

12 feet 9 inches

Answer:0.216667

Step-by-step explanation: I figured out how many ft r in a yard the how many seconds r in a mi then went from there.

Answer:

x ÷ 4 ≤ 5

Step-by-step explanation:

[tex] \: \: \: \: \: \: \: \: [/tex]

[tex]m = 2[/tex]

Step-by-step explanation:

[tex]0 = 12 + 2(m - 8)[/tex]

[tex]0 = 12 + 2m - 16[/tex]

[tex]0 = - 4 + 2m[/tex]

[tex] - 2m = - 4[/tex]

[tex] = m = 2[/tex]

[tex] \: \: \: [/tex]

Answer:

m = 2

Step-by-step explanation:

0 = 12 + 2 ( m - 8 )

→ Expand the brackets

0 = 12 + 2m - 16

→ Add 16 to both sides

16 = 12 + 2m

→ Minus 12 from both sides

4 = 2m

→ Divide both sides by 2

2 = m

Answer:

for which one all ?

Step-by-step explanation:

because if so lemme know

No because for 5x10, you just add 10 5 times for 50. For 5x5x5, you multiply 5x5 and get 25 then multiply it again with the other 5 and get 125.

Answer:

No

Step-by-step explanation:

No, because 5 × 5 × 5 = 25 × 5 and that does not equal 10×5.

f(x)=(x+a)/b

or bf(x)=x+a

let f(x)=y

by=x+a

flip x and y

bx=y+a

or y=bx-a

or f^{-1}(x)=bx-a

also g(x) is inverse of f(x)

bx-a=cx-d

so b=c,a=d

again let g(x)=y

y=cx-d

flip x and y

x=cy-d

cy=x+d

y=(x+d)/c

or g^{-1}(x)=(x+d)/c

also f(x) is inverse of g(x)

so (x+a)/b=(x+d)/c

so a=d,b=c

so in either case a=d,b=c

take b=c=1

a=d=2

f(x)=(x+2)/1=x+2

g(x)=1x-2=x-2

so f(x) and g(x) are two parallel lines f(x) with y- intercept=1 and slope 0

g(x) with y-intercept -2 and slope 0

if we take b=c=2,a=d=3

f(x)=(x+3)/2=x/2+3/2

g(x)=2x-3

here f(x) is of slope 1/2 and y-intercept 3/2

g(x) is of slope 2 and y intercept -3

part 3.

f(f(x))=g((x+a)/b)=c[(x+a)/b]-d=(c/b)(x+a)-d

An inverse function or an anti function exists described as a function, which can change into another function. In other words, if any function “f” carries x to y then, the inverse of “f” will carry y to x.

Part 1: f(x) = (x+2) / 3 and g(x) = 3y-2.

Part 2: g(x) = 3x - 2, the inverse.

Part 3: g(f(x)) = x showing that f(x) and g(x) are mutual inverses.

An inverse function in mathematics exists function which "reverses" the another function.

TASK 1

Part 1

Let y = f(x) = (x + a) / b

x = g(y) = by-a = cy-d,

so c = b and d = a.

Let d = a = 2 and c = b = 3

f(x) = (x+2) / 3 and g(x) = 3y-2.

Part 2

y = f(x) = (x+2) / 3

3y = x+2  

x = 3y-2 = g(y)

so g(x) = 3x - 2, the inverse.

Part 3

g(f(x)) = 3

f(x)-2 = 3(x+2)/3-2 = x+2-2 = x,

so g(f(x)) = x showing that f(x) and g(x) exists mutual inverses.

x       -2  -1        0    1     2

f(x)    0    1/3   2/3   1    4/3

g(x)  -8   -5      -2    1      4

Part 4

The graph is given below.

TASK 2

Part 1

(a) Let a=1, b=2, c=3, d=6: [tex]$\sqrt{x}[/tex]+2+3=6 ; [tex]\sqrt{x}[/tex]-6=-5

(b) Let a=-1, b=2, c=3, d=4

(a) Multiply both sides by

[tex]$\sqrt{x}+6: x-36=-5(\sqrt{x}+6)=-5 \sqrt{x}-30[/tex]

[tex]$ x-36+30=-5 \sqrt{x }[/tex]

[tex]$ x-6=-5 \sqrt{x}$[/tex]

Square both sides:

[tex]$x^{2} -12 x+36=25 x ; x^{2} -37 x+36=0=(x-36)(x-1)$[/tex].

Part 2

(a) So x=36 or 1 (apparently).

Substitute x=36 in the original equation: 6+2+3=6, 11=6 is not true.

So x=36 is an extraneous solution.

substitute x=1: 1+2+3=6 is true, so x=1 exists the actual solution.

(b) [tex]$-\sqrt{x}+2+3=4 ;-\sqrt{x}=-1$[/tex]; multiply both sides by -1: [tex]$\sqrt{x}=1$[/tex]; square both sides: x=1.

Substitute x=1 in the original equation: -1+2+3=4 is true.

So x = 1 is the solution.

Part 3

(a) the act of squaring both sides resulted in creating an extraneous solution [tex]$\left((-5)^{2} =25=5^{2} \right)$[/tex].  

(b) the solution was simpler and there was no ambiguity.

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Answer:

-2, -1, 0, 1

Step-by-step explanation:

-2

-1

0

1

All the possible values of t in the inequality - 3 < t < 2 is,

t = - 2, - 1, 0, 1

Used the concept of inequality that states,

A relation by which we can compare two or more mathematical expressions is called an inequality.

Given that;

The inequality is,

- 3 < t < 2

Here the given inequality means all the values of t are lies between - 3 and 2.

That is,

t = - 2, - 1, 0, 1

Therefore, the value of t are t = - 2, - 1, 0, 1

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Answer:

B,D,E

Step-by-step explanation:

Answer:

15%

Step-by-step explanation:

24/160 = 0.15

0.15*100 = 15

Answer:

it is called rectangularization

Step-by-step explanation:

Answer:

1,23,098

Step-by-step explanation:

............

Answer:

D) the bridge is about 381.16 ft. above the river, and the length of the bridge above the arch is 1,792.58 ft

Answer:

b. 5

Step-by-step explanation:

Answer:

Step-by-step explanation:

Pythagorean theorem: base ² +altitude² = hypotenuse²

1) hypotenuse² = base² + altitude²

          x² = 6² + 3²

               = 36 + 9

               = 45

         x = √45

         x = 6.7 cm

4) base ² +altitude² = hypotenuse²

x ² + 3.7 ² =  4.2 ²

x ² + 13.69 = 17.64

             x ² = 17.64 - 13.69 = 3.95

             x = √3.95

            x = 1.99 cm

10)c ² = a ² + b ²

           = 3 ² +4 ²

         = 9 + 16

  c ² = 25

c = √25 = 5

11) a ² + b ² = c ²

9 ² +b² = 13 ²

81 + b² = 169

     b² = 169 - 81 = 88

b = 9.38

12) a² + b² = c²

12² + b² = 22²

  144 + b² = 484

           b² = 484 - 144 = 340

           b =√340 = 18.44

Answer:

I think the greater fraction is 27/5

Answer:

Step-by-step explanation:

what is greater: 19/5, 27/5, 10/3, 14/5​

fractions are divisions, we divide to see the greater

19/5= 3.8

27/5= 5.4

10/3= 3.33

14/5= 2.8

Answer:

  ∠FGH = ∠HGI = 29°

  ∠FGI = 58°

Step-by-step explanation:

GH is marked as an angle bisector, so we have ...

  ∠FGH = ∠HGI

  2x -9 = 3x -28

  19 = x . . . . . . . . . . . . add 28-2x to both sides

Of course, the angle FGH is the sum of its parts. Then the angle measures are  ...

  (2x -9)° = (2·19 -9)° = 29°

  ∠FGH = ∠HGI = 29°

  ∠FGI = 58°

Answer:

so subtract -2v to the left side add 5 to the right side so your left with

v = 15

Answer:

15 = v

Step-by-step explanation:

First start by grouping like terms,

=> - 5 - 10 = 2v - 3v

evaluate the LHS and RHS

=> - 15 = - v

Divide through by the coefficient of v, which in this case is - 1

=>

[tex] \frac{ - 15}{ - 1} = v[/tex]

Therefore, 15 = v