Laney left a nail in water for two weeks, and the nail became rusted from sitting in the water.
What kind of change occurred?
A
decomposition change
B
chemical change
С
physical change
D
change of state

Answer:

partB: n=2N205

partc:17.20

Answer:

Hydrogen is the limiting reactant.

Explanation:

Hello!

In this case, for the identification of the limiting reactant, it is necessary to compute the yielded moles of ammonia via both hydrogen and nitrogen in agreement to the 3:2 and 1:2 mole ratios respectively:

[tex]n_{NH_3}^{by\ H_2}=5molH_2*\frac{2molNH_3}{3molH_2}=3.33molNH_3\\\\n_{NH_3}^{by\ N_2}=2molN_2*\frac{2molNH_3}{1molN_2}=4molNH_3[/tex]

Thus, since hydrogen yields the fewest moles of ammonia we infer it is the limiting reactant.

Best regards!

Answer:

B

Explanation:

Answer:

B

Explanation:

Edge 2022

Answer:

C2H2

Explanation:

The given question is incomplete. The complete question is:

Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced

Answer: 60.0 g of glucose

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

a) moles of [tex]CO_2[/tex]

[tex]\text{Number of moles}=\frac{88.0g}{44g/mol}=2.0moles[/tex]

b) moles of [tex]H_2O[/tex]

[tex]\text{Number of moles}=\frac{64.0g}{18g/mol}=3.5moles[/tex]

[tex]6CO_2+6H_2O\rightarrow C_{6}H_{12}O_6+6O_2[/tex]

According to stoichiometry :

6 moles of [tex]CO_2[/tex] require = 6 moles of [tex]H_2O[/tex]

Thus 2.0 moles of [tex]CO_2[/tex] require=[tex]\frac{6}{6}\times 2.0=2.0moles[/tex]  of [tex]H_2O[/tex]

Thus [tex]CO_2[/tex] is the limiting reagent as it limits the formation of product.

As 6 moles of [tex]CO_2[/tex] give =  1 moles of glucose

Thus 2.0 moles of [tex]CO_2[/tex] give =[tex]\frac{1}{6}\times 2.0=0.33moles[/tex]  of glucose

Mass of glucose = [tex]moles\times {\text {Molar mass}}=0.33moles\times 180g/mol=60g[/tex]

Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water  

In green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis produces 60.0 g of glucose.

To calculate the moles, we use the equation:

Mole fraction is a unit of concentration, described to be same to the range of moles of a element divided via way of means of the entire range of moles of a solution.

Thus it is well explained.

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Answer:

Sep 23, 2019 — It's in everyone's benefit if physicians participate in research. By Mukesh K. Jain, Tadataka Yamada and Robert Lefkowitz. Drs. Jain, Yamada ...

Explanation:

Answer:

d is right hope this helps:)

Answer:

The fourth one is correct ( D/ number 4).

Answer:

[tex]\boxed{\bold { \Large { \boxed {0.28 \ kg}}}}[/tex]

Explanation:

Use kinetic energy formula

[tex]\sf \displaystyle K.E=\frac{1}{2} mv^2[/tex]

Solve for m

[tex]\displaystyle 125=\frac{1}{2} m \times 30^2[/tex]

[tex]m=0.2777..[/tex]

A man has a kinetic energy of 125J when he runs at 30m/s.  0.2777  is the mass of the man.

Kinetic energy is the energy of motion, observable as the movement of an object, particle, or set of particles.

Use kinetic energy formula:

Given data:

K.E = 125J

V = 30m/s

K.E = [tex]\frac{1}{2} mv^2[/tex]

Solve for m

125J = [tex]\frac{1}{2} \;m \;{30m/s}^2[/tex]

m = 0.2777

Hence,  0.2777 is the mass of the man.

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This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained

Answer:

the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

Explanation:

Given the data in the question;

thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

concentration high pressure side C[tex]_A[/tex] = 2.4

concentration low pressure side C[tex]_B[/tex] = 0.6 kg

from the question, we calculate the concentration gradient

dc/dx = (C[tex]_A[/tex] -  C[tex]_B[/tex])/dt

so we substitute

dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )

dc/dx = -360

now, mass of hydrogen per hour that diffuse through a pd sheet

M = -∝AT(dc/dx)

where time t is 1 hour ( 3600 sec )

we substitute

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per one hour

Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.

Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.

According to the question, given data is:

Thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

Concentration high pressure side [tex]C_A[/tex] = 2.4

Concentration low pressure side[tex]C_B[/tex]= 0.6 kg

from the question, we calculate the concentration gradient,

[tex]dc/dx = (C _A- C_B)/dt[/tex]

so, we substitute the values,

[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)

[tex]dc/dx = -360[/tex]

Now, mass of hydrogen per hour that diffuse through a Palladium sheet,

M = -∝[tex]AT(dc/dx)[/tex]

where time t is 1 hour (3600 sec)

We substitute,

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per hour.

Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.

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This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.

Answer:

Nucleus

Explanation:

they originate in the nucleus

Answer:

B

Explanation:

The statement "Some of the mass is converted into energy during this process" describes the total mass of the nucleus formed in the

fusion reaction.

So B is correct option.

The nuclear reaction in which two or more atomic nuclei are combined to form one or more different atomic nuclei and subatomic particle by releasing or absorbing energy.

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Answer: i could be incorrect but im pretty sure the answer is, Gas surface with no rings.

Explanation:

s-s-s-science!

Answer:

Gas surface with no rings.

Explanation:

the answer is 375 joules

Answer:

12.6 g of H₂O can be produced in the combustion

Explanation:

This excersise involves an easy combustion reaction:

2C₄H₁₀  +  13O₂  →   8CO₂  +  10H₂O

First step: calculate moles of reactants in order to find out the limiting.

23 g . 1mol / 58g = 0.396 moles of butane

29.1 g . 1mol /32g = 0.909 moles of O₂

2 moles of butane react to 13 moles of oxygen

Then, 0.396 moles of butane may react to (0.396 . 13) / 2 = 2.574 moles

Certainly we do not have enough oxygen, so O₂ becomes the limiting reactant

13 moles of O₂ can produce 10 moles of water

Then 0.909 moles may produce (0.909 . 10) /13 = 0.699 moles H₂O

We convert moles to mass → 0.699 mol . 18 g/mol = 12.6 g

Answer:

i think answer is B negative effects and benefits

Answer:

The balanced equation is given below:

SiO2 + 4HF —> SiF4 + 2H2O

The coefficients are 1, 4, 1, 2

Explanation:

The equation for the reaction is given below:

SiO2 + HF —> SiF4 + H2O

The above equation can be balance by as follow:

There are 4 atoms of F on the right side and 1 atom on the left side. It can be balance by putting 4 in front of HF as shown below:

SiO2 + 4HF —> SiF4 + H2O

Therefore are 4 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 2 in front of H2O as shown below:

SiO2 + 4HF —> SiF4 + 2H2O

Now the equation is balanced.

Explanation:

A balanced equation obey the law of conservation of mass. According to this law, the mass can neither be created nor be destroyed. Here the balanced equation for the given reaction is 2KClO₃ → 2KCl + 3O₂.

A chemical equation in which the number of atoms of reactants and products are equal on both sides of the equation is defined as the balanced chemical equation. The coefficients are the numbers that are used to balance a chemical equation.

The substances which appear on the left hand side of the equation are called the reactants whereas those which appear on the right hand side are called the products. The coefficients are essential to balance a equation.

The given equation can be balanced as follows:

2KClO₃ → 2KCl + 3O₂

Here the coefficients are 2, 2 and 3.

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Answer:

120.366 g/mol

Explanation:

Answer:

(8.3×40)+(8.3×71)

921.3grames

Answer:

[tex]\Large \boxed{\sf 921.3 \ g}[/tex]

Explanation:

Use formula

[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]

[tex]M_r=40+35.5 \times 2 = 111[/tex]

Solve for mass

[tex]mass=8.3 \times 111=921.3[/tex]

The third picture has only one type of combination of atoms so it represents a pure compound. Therefore, option (c) is correct.

A pure compound is a compound that contains two or more elements combined chemically in a fixed ratio. These compounds can be broken down into separate or simple elements by chemical methods.

A pure compound is formed when elements are joined together by chemical bonds. Compounds such as water, crystals, and baking soda as pure.  

Water is a compound formed by the combination of oxygen and hydrogen in a fixed ratio. A pure substance is a substance that has only one kind of atom or molecule having a constant composition.

The first picture represents pure substance and the 2nd and 4th pictures represent mixed compounds. Therefore, the third picture represents a pure compound.

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Answer:

huh

Explanation:

I like ribs too eat lamfoaoa

Answer:

I believe it would be D, to enhance the survival rate.

Explanation:

Answer:

D

Explanation:

to enhance the survival

Answer:

It is 98 degrees C.

Explanation:

Answer:

D.

the father parent shares his genetic information with the mother during sexual intercourse( the sperm and egg)

Answer: Ammonia Ice

Explanation: Like Jupiter, Saturn boasts layers of clouds. The upper layers of clouds are made up of ammonia ice. Traveling toward the core, clouds of water ice form, with bands of ammonium hydrosulfide ice intermixed. The lower layers of Saturn see higher temperatures and pressures.