lee mealone, a hermit pushes a 12.1 kg boulder into the wall of his cave at a speed of 4.43 m/s, the boulder is brought to a stop in 1.81 seconds. what was the magnitude of the impulse (in n*s) imparted to the boulder? (no or - signs.)

Answers

Answer 1

The magnitude of the impulse imparted to the boulder is 53.503 N*s.

How do we calculate?

We know that

Impulse = change in momentum = final momentum - initial momentum

initial momentum = mass * initial velocity

initial momentum = 12.1 kg * 4.43 m/s = 53.503 kg m/s

final momentum of the boulder using the formula:

final momentum = mass * final velocity

final momentum = 12.1 kg * 0 m/s = 0 kg m/s

In conclusion, the change in momentum of the boulder is:

change in momentum = final momentum - initial momentum = 0 kg m/s - 53.503 kg m/s = -53.503 kg m/s

The negative sign is an indication that the momentum of the boulder has decreased.

|Impulse| = |-53.503 kg m/s| = 53.503 N*s

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Related Questions

g what constant acceleration is required to increase the speed of a car from 20 mi/h to 52 mi/h in 3 seconds? (round your answer to two decimal places.)

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The constant acceleration required to increase the speed of the car from 20 mi/h to 52 mi/h in 3 seconds is 10.67 mi/h².

First, convert the initial and final velocities to feet per second (fps) to match the unit of acceleration:

20 mi/h = 29.33 fps52 mi/h = 76.27 fps

Then, use the formula:

a = (vf - vi) / t

where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time interval.

Substituting the values:

a = (76.27 - 29.33) / 3a = 15.98 fps²

Finally, convert the answer to miles per hour squared:

a = 15.98 * (3600/5280)²a ≈ 10.67 mi/h²

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the four strings of a bass guitar are 0.865 m long and are tuned to the notes g (98 hz), d (73.4 hz), a (55 hz), and e (41.2 hz). in one bass guitar, the g and d strings have a linear mass density of 5.8 g/m, and the a and e strings have a linear mass density of 26.8 g/m. what is the total force exerted by the strings on the neck?

Answers

The total force exerted by the strings on the neck is 3061 N

We must determine the tension in each string and add it together to determine the overall force the strings are applying on the neck.

The wave speed equation may be used to determine the tension in a string:

v = fλ

where v is the speed of the wave (which is the same as the speed of the string), f is the frequency of the note, and λ is the wavelength of the wave (which is twice the length of the string).

For the g and d strings:

λ = 2(0.865 m) = 1.73 m

v = fλ

v_g = (98 Hz)(1.73 m) = 169.5 m/s

v_d = (73.4 Hz)(1.73 m) = 127.0 m/s

The tension in each string can be found using the wave equation:

T = [tex]μv^2/λ[/tex]

where T is the tension in the string, μ is the linear mass density of the string (mass per unit length), and v and λ are the speed and wavelength of the wave on the string.

For the g and d strings:

[tex]T_g = (5.8 g/m)(169.5 m/s)^2/1.73 m = 320 N[/tex]

[tex]T_d = (5.8 g/m)(127.0 m/s)^2/1.73 m = 196 N[/tex]

For the a and e strings

λ = 2(0.865 m) = 1.73 mv = fλ

v_a = (55 Hz)(1.73 m) = 95.2 m/sv_e = (41.2 Hz)(1.73 m) = 71.2 m/s

[tex]T_a = (26.8 g/m)(95.2 m/s)^2/1.73 m = 1643 N[/tex]

[tex]T_e = (26.8 g/m)(71.2 m/s)^2/1.73 m = 902 N[/tex]

The total force exerted by the strings on the neck is:

F_total = T_g + T_d + T_a + T_e

F_total = 320 N + 196 N + 1643 N + 902 N

F_total = 3061 N

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if the merry-go-round starts at rest and acquires an angular speed of 0.5250 rev/s r e v / s in 5.00 s s , what is its mass?

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We can use the formula for Newton's second law (F = ma) to find the mass of the merry-go-round, given the force and assuming that it accelerates uniformly.

The angular acceleration of the merry-go-round can be found using the formula:

angular acceleration = (final angular speed - initial angular speed) / time

angular acceleration = [tex](0.5250 rev/s - 0 rev/s) / 5.00 s = 0.105 rev/s^2[/tex]

Then, using the formula for torque (τ = Iα) and the moment of inertia of a solid disk (I = 0.5MR^2), we can find the torque exerted on the merry-go-round. Assuming that the torque comes from a person pushing on the edge of the disk, we can estimate the force exerted as F = τ / R, where R is the radius of the disk.

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T/F : Staleness and burnout are not associated with overtraining.

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False. Staleness and burnout are often associated with overtraining, which occurs when an individual exceeds their capacity to recover from intense physical training or activity.

Overtraining can lead to physical and psychological symptoms, including decreased performance, fatigue, irritability, and decreased motivation. It is important for individuals to listen to their bodies and take rest and recovery periods to prevent overtraining and associated symptoms.

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what type of galaxy is m82 based on its appearance in the visible-light view? view available hint(s)for part a what type of galaxy is m82 based on its appearance in the visible-light view? irregular spiral elliptical

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Based on its appearance in the visible-light view, M82 is classified as an irregular galaxy.

A galaxy is a vast collection of stars, gas, dust, and dark matter that are held together by gravity. Galaxies come in many different shapes and sizes, and they can contain anywhere from a few million to hundreds of billions of stars.

Based on its appearance in the visible-light view, M82 is an irregular galaxy. It has a distorted, asymmetric shape and lacks the clear spiral or elliptical structure that defines those types of galaxies. Its irregular shape suggests that it has experienced some kind of disturbance or interaction with other galaxies in the past.

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A proton accelerates from rest in a uniform electric field of 691 N/C. At some time later, it’s speed is 2. 30 x 10^6 m/s. (a) What is the magnitude of its acceleration? (b) How long does it take the proton to reach this speed

(c) How far has it moved in this time interval?

(d) What is its kinetic energy at the later time?

Mass of proton: 1. 6726x10^-27

Fundamental charge:

1. 602 x10^-19

Answers

The proton experiences an acceleration of [tex]$6.60\times10^{10} \text{m/s}^2$[/tex] in a uniform electric field of 691 N/C, and it takes [tex]$3.48\times10^{-5}$[/tex] s to reach a velocity of [tex]$2.30\times10^{6}$[/tex] m/s. During this time, the proton travels a distance of [tex]$4.36\times10^{-10}$[/tex] m and has a kinetic energy of [tex]$3.07\times10^{-12}$[/tex] J.

(a) The magnitude of the acceleration experienced by the proton can be determined by using the equation for the force on a charged particle in an electric field, which is F = qE, where F is the force, q is the charge of the particle, and E is the electric field strength. For a proton, the charge is equal to the fundamental charge, which is [tex]$1.602\times10^{-19} \text{C}$[/tex]. Therefore, the force on the proton is [tex]$F = (1.602\times10^{-19} \text{C})(691 \text{N/C}) = 1.106\times10^{-16} \text{N}$[/tex]

The acceleration of the proton can be determined using the equation F = ma, where m is the mass of the proton. Thus, [tex]$a = F/m = \dfrac{1.106\times10^{-16} \text{N}}{1.6726\times10^{-27} \text{kg}} = 6.60\times10^{10} \text{m/s}^2$[/tex].

(b) To find the time it takes for the proton to reach the given speed, we can use the kinematic equation v = u + at, where u is the initial velocity (which is 0 m/s), v is the final velocity ([tex]$2.30\times10^{6} \text{m/s}$[/tex]), a is the acceleration ([tex]$6.60\times10^{10} \text{m/s}^2$[/tex]), and t is the time. Rearranging this equation gives [tex]$t = \dfrac{v-u}{a} = \dfrac{2.30\times10^{6} \text{m/s}}{6.60\times10^{10} \text{m/s}^2} = 3.48\times10^{-5} \text{s}$[/tex].

(c) The distance the proton has moved in this time interval can be calculated using the kinematic equation [tex]$s = ut + \dfrac{1}{2}at^2$[/tex], where s is the distance traveled. Substituting the known values, we get [tex]$s = \dfrac{1}{2}(6.60\times10^{10} \text{m/s}^2)(3.48\times10^{-5} \text{s})^2 = 4.36\times10^{-10} \text{m}$[/tex]

(d) The kinetic energy of the proton can be calculated using the equation [tex]$KE = \dfrac{1}{2}mv^2$[/tex], where KE is the kinetic energy, m is the mass of the proton, and v is the velocity of the proton. Substituting the known values, we get [tex]$KE = \dfrac{1}{2}(1.6726\times10^{-27} \text{kg})(2.30\times10^{6} \text{m/s})^2 = 3.07\times10^{-12} \text{J}$[/tex].

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maxwell's equations are a complete description of electric and magnetic fields. how many equations are there?

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Maxwell's equations are a complete description of electric and magnetic fields. There are four equations in Maxwell's equations. These four equations are:

1. Gauss's Law for Electric Fields: Describes the relationship between electric charges and the electric field produced by them.
2. Gauss's Law for Magnetic Fields: States that there are no magnetic monopoles, and the magnetic field lines are always closed loops.
3. Faraday's Law of Electromagnetic Induction: Describes the induced electromotive force (EMF) in a closed circuit produced by a changing magnetic field.
4. Ampere's Law with Maxwell's Addition: Relates the magnetic field around a closed loop to the electric current passing through the loop and the rate of change of the electric field.

These four equations collectively provide a comprehensive description of electric and magnetic fields and their interactions.

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write a paragraph describing your evaluation of the experiment and describing how to modify an experiment. plssss Science 8 B - Unit 5, Lesson 9: Non-Contact Forces Portfolio 3

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Contact pressure occurs due to the contact between two distinctive objects. Non-contact pressure happens due to either appeal or repulsion between two objects such that there is no contact between these objects. There is no area linked with the contact force.

What are the distinct kinds of non-contact forces describe?

A non-contact pressure is any force applied to an object via another body without any contact. For example, magnetic force, gravitational pressure and electrostatic force.

Force utilized through direct touching an object is called contact force. Like me pushing a wall i.e. muscular pressure or frictional pressure etc.

A force that can purpose or change the movement of an object by means of touching it is referred to as Contact Force. For example, muscular force,frictional force,spring force,tension force,air resistance pressure etc.

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help please!!!!!!!!!!! ​

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The circled vector on the diagram below represents the tension on the rope.

The option C is correct

What is  tension?

Tension is described as  the force transmitted through a string, rope, cable or wire when it is pulled tight by forces acting from opposite ends.

T = mg + ma

We know that the force of tension is calculated using the formula T = mg + ma.

In other terms, the pulling force that runs the length of a flexible connector, such a rope or cable, is known as tension. It is always pointed away from the force-applying object and along the length of the connector.

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Where do I place the right ones

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Cause: Human population grows worldwide.

Effect: Fossil fuels burn, cities become more industrialized, glaciers melt, climates change, and rain falls in unusual amounts.

What is global warming?

Global warming refers to the long-term increase in Earth's average surface temperature, primarily due to the increasing levels of greenhouse gases, such as carbon dioxide, in the atmosphere. These gases trap heat from the sun, preventing it from radiating back into space and causing the Earth's temperature to rise.

Global warming has a range of potential impacts, including rising sea levels, more frequent and severe heat waves, changes in precipitation patterns, and more intense storms. It is considered one of the most significant and pressing environmental challenges facing the planet today.

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Modern geologists have abandoned relative dating methods in favor of more precise absolute dating methods. True/False

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False. Here is a step-by-step explanation:

1) Relative dating methods and absolute dating methods are two types of techniques used by geologists to determine the age of rocks and fossils.

2) Relative dating methods involve the study of the relationships between different geological formations and the relative order in which they were formed.

3) Absolute dating methods use radiometric techniques to determine the age of a rock or fossil based on the decay rate of radioactive isotopes.

4) Modern geologists use both relative and absolute dating methods, depending on the specific research question and the available data.

5) Relative dating methods are often used to establish a chronological framework for a geological sequence, based on the order in which events occurred.

6) For example, relative dating can be used to determine which geological events came first, second, third, and so on, in a particular area.

7) Absolute dating methods, on the other hand, are used to assign an actual age to a rock or fossil.

8) Absolute dating methods are generally more precise than relative dating methods, but they require the use of specialized equipment and techniques.

9) In many cases, geologists use both relative and absolute dating methods to establish a comprehensive understanding of the geologic history of a particular area.

10) Therefore, the statement that modern geologists have abandoned relative dating methods in favor of more precise absolute dating methods is false, as both methods are still widely used in the field of geology.

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A 55 kg skater is gliding along the ice at a velocity of 8 m/s to the right while holding a 3 kg ball. The skater throws the ball at a velocity of 4 m/s to the right. What will be the skaters velocity after throwing the ball?

Answers

Answer:

Speed of Skater = 8.16 m/s

Explanation:

Using kinetic energy:

[tex]M_{t} = M_{skater} + m_{ball}\\\frac{1}{2}M_{t}V_{i}^2 = \frac{1}{2}*M*V_{s} ^2+\frac{1}{2}*m*V_{b}^2\\ M_{t}V_{i}^2 = M_{s}*V_{s} ^2+m_{b}*V_{b}^2\\M_{t}V_{i}^2-m_{b}*V_{b}^2 = M_{s}*V_{s} ^2\\(M_{t}V_{i}^2-m_{b}*V_{b}^2)/M_{s} = V_{s} ^2\\V_{s} = \sqrt{\frac{(M_{t}V_{i}^2-m_{b}*V_{b}^2)}{M_{s}} } \\[/tex]

This gives the skater a velocity of 8.16 m/s after throwing the ball

a person on a rotating stool with arms closer to the chest rotates at an angular speed of 7.5 rad/s. on stretching out the arms, the angular speed decreases to 5 rad/s. by what factor does the moment of inertia change?

Answers

The factor by which the moment of inertia changed is equal to the ratio of the angular speed squared, i.e. (7.5 rad/s)2 / (5 rad/s)2.

The moment of inertia (I) is an important physical quantity which describes the rotational inertia of an object. It is a measure of an object's resistance to change in its angular motion.

A rotating object's moment of inertia is influenced by the distribution of its mass. Stretching out one's arms causes a change in the moment of inertia because it alters the mass distribution of the person seated on a revolving stool.

The change in the moment of inertia (ΔI) is equal to the difference between the original moment of inertia (I1) and the new moment of inertia (I2).

ΔI = I1 - I2

Given that the angular speed of the person decreased from 7.5 rad/s to 5 rad/s, we can calculate the change in the moment of inertia:

ΔI = (7.5 rad/s)2 / I1 - (5 rad/s)2 / I2

Thus, the factor by which the moment of inertia changed is given by:

Factor = I2 / I1 = (7.5 rad/s)2 / I1 / (5 rad/s)2 / I2

Therefore, the factor by which the moment of inertia changed is equal to the ratio of the angular speeds squared.

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which one is not one of the functions of the screen pack and breaker plate at the die end of the extruder barrel?

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Increasing the pressure inside the extruder barrel is not a function of the screen pack and breaker plate.

The screen pack and breaker plate have several functions, including:
1. Filtering out contaminants and impurities from the molten plastic.
2. Creating uniform melt flow.
3. Reducing pressure fluctuations.
However, they do not serve to increase the pressure inside the extruder barrel.

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A bowling ball has a surface area of about 232 square inches. Find the radius of the bowling ball.

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The radius of the bowling ball is approximately 7.65 inches.

We can use the formula for the surface area of a sphere to find the radius of the bowling ball:

Surface area of a sphere = 4πr²

where r is the radius of the sphere.

In this problem, we are given the surface area of a bowling ball, which is 232 square inches. We can use this information and the formula for surface area of a sphere to solve for the radius of the ball. Plugging this value into the formula, we get:

232 = 4πr²

Dividing both sides by 4π, we get:

r² = 58.5

Taking the square root of both sides, we get:

r ≈ 7.65 inches

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a tank is 10 m long, 4 m wide, 4 m high, and contains kerosene with density 820 kg/m3 to a depth of 3.5 m. (use 9.8 m/s2 for the acceleration due to gravity.) (a) find the hydrostatic pressure (in pa) on the bottom of the tank. incorrect: your answer is incorrect. pa (b) find the hydrostatic force (in n) on the bottom of the tank. n (c) find the hydrostatic force (in n) on one end of the tank. n

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(a) The hydrostatic pressure is 28,490 Pa.

(b) At the bottom the force is 1,139,600 N.

(c)  At the end the force is 1,621,200 N.

What is(a) The hydrostatic pressure (in pa) on the bottom of the tank(b) The hydrostatic force (in n) on the bottom of the tank. (c) The hydrostatic force (in n) on one end of the tank.

(a) To find the hydrostatic pressure on the bottom of the tank, we can use the formula:

P = ρgh

where P is the pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the height of the liquid column.

The height of the liquid column is 3.5 m, and the density of kerosene is 820 kg/m3. The acceleration due to gravity is 9.8 m/s2. Therefore, we have:

P = 820 kg/m3 * 9.8 m/s2 * 3.5 m = 28,490 Pa

So the hydrostatic pressure on the bottom of the tank is 28,490 Pa.

(b) To find the hydrostatic force on the bottom of the tank, we can use the formula:

F = PA

where F is the force, P is the pressure, and A is the area. The area of the bottom of the tank is:

A = 10 m * 4 m = 40 m2

Using the pressure we found in part (a), we have:

F = 28,490 Pa * 40 m2 = 1,139,600 N

So the hydrostatic force on the bottom of the tank is 1,139,600 N.

(c) To find the hydrostatic force on one end of the tank, we need to first find the pressure on that end. The pressure on any point of the tank is given by:

P = ρgh

where h is the vertical distance from the point to the surface of the liquid.

The pressure on one end of the tank will depend on the distance of that end from the surface of the liquid. Let's assume that the end we are interested in is at the same level as the surface of the liquid. Then the pressure on that end is simply the atmospheric pressure, which we will assume is 101,325 Pa.

The area of one end of the tank is:

A = 4 m * 4 m = 16 m2

Using the pressure we found and the area of the end, we have:

F = 101,325 Pa * 16 m2 = 1,621,200 N

So the hydrostatic force on one end of the tank is 1,621,200 N.

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wo astronauts are at rest in outer space, one 19.7 m from the space shuttle and the other 39.4 m from the shuttle. using a 121.0-w laser, the astronaut located 39.4 m away from the shuttle decides to propel the other astronaut toward the space shuttle. he focuses the laser on a piece of totally reflecting fabric on her space suit. if her total mass with equipment is 117.0 kg, how long will it take her to reach the space shuttle?

Answers

This is a very large amount of time, approximately [tex]3.6 x 10^5[/tex] years, which is not feasible for the astronauts.

We can use the conservation of momentum to solve this problem. Initially, the system (two astronauts and the laser) is at rest, so the total momentum is zero. When the laser is fired and the astronaut is propelled towards the shuttle, she gains some momentum in the direction of the shuttle, and the system as a whole gains an equal and opposite momentum.

First, we need to find the momentum gained by the astronaut. We can use the formula for the momentum of a photon:

p = h / λ

where p is the momentum, h is the Planck constant, and λ is the wavelength of the laser light. We are given the power of the laser (121.0 W), but we also need to know the energy of each photon. We can use the formula:

E = hc / λ

where E is the energy of a photon, c is the speed of light, and λ is the wavelength of the laser light. Rearranging this formula, we get:

λ = hc / E

Substituting the values and converting to SI units, we get:

[tex]λ = (6.626 x 10^-34 J s)(3.00 x 10^8 m/s) / (6.63 x 10^-19 J) = 3.13 x 10^-7 m[/tex]

Using this wavelength, we can find the momentum gained by the astronaut:

[tex]p = h / λ = (6.626 x 10^-34 J s) / (3.13 x 10^-7 m) = 2.12 x 10^-27 kg m/s[/tex]

This is the momentum gained by the astronaut in one photon.

To find the time it takes for the astronaut to reach the shuttle, we can use the impulse-momentum theorem:FΔt = Δp

where F is the force exerted by the laser, Δt is the time for which the force is applied, and Δp is the change in momentum of the astronaut. We can rearrange this formula to solve for Δt:

Δt = Δp / FThe force exerted by the laser can be found by dividing the power by the speed of light:

[tex]F = P / c = 121.0 W / 3.00 x 10^8 m/s = 4.03 x 10^-7 N[/tex]

Substituting the values, we get:

[tex]Δt = Δp / F = (2.12 x 10^-27 kg m/s) / (4.03 x 10^-7 N) = 5.27 x 10^-21 s[/tex]

This is the time it takes for the astronaut to gain the momentum needed to reach the shuttle. However, this time does not include the time it takes for the astronaut to travel the distance to the shuttle. We can use the average velocity of the astronaut to find this time:

v_avg = Δx / Δtwhere Δx is the distance to the shuttle. Substituting the values, we get:

[tex]v_avg = (39.4 m - 19.7 m) / (5.27 x 10^-21 s) = 3.80 x 10^22 m/s[/tex]

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after the switch s is closed, what will be the current in the circuit at the instant that the capacitors have lost 80.0% of their initial stored energy?

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After switch S is closed, the capacitors in the circuit start to discharge.

The initial stored energy in the capacitors is given by [tex]1/2*C*V^2[/tex],

where C is the capacitance of the capacitors and V is the initial voltage across them.

As the capacitors discharge, the voltage across them decreases and so does the stored energy.

When the capacitors have lost 80.0% of their initial stored energy, the voltage across them will be 0.447 times the initial voltage.

At this point, the current in the circuit can be calculated using Ohm's law, which states that the current is equal to the voltage divided by the total resistance of the circuit.

Therefore, the current in the circuit at this point can be calculated as I = V/R, where V is the voltage across the capacitors and R is the total resistance of the circuit.

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if the electrical power is eliminated, which fires become class a or class b and may be extinguished appropriately?

Answers

When electrical power is eliminated, fires that were initially caused by an electrical fault may change classification depending on the materials and substances involved in the fire.

Class A fires involve ordinary combustibles such as wood, paper, cloth, and plastics. If an electrical fire involves any of these materials, it will become a Class A fire and can be extinguished using water or an appropriate Class A fire extinguisher.

Class B fires involve flammable liquids and gases such as gasoline, oil, and propane. If an electrical fire involves any of these materials, it will become a Class B fire and can be extinguished using a Class B fire extinguisher, such as a dry chemical extinguisher or a carbon dioxide extinguisher.

It's important to note that extinguishing an electrical fire with water can be dangerous as water conducts electricity and can cause electrocution. Therefore, it's important to first cut off the power source before attempting to extinguish an electrical fire.

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if the total mechanical energy e of the particle is -8 j, what are the minimum and maximum positions of the particle?

Answers

To determine the minimum and maximum positions of the particle, we need to know more information about the system. However, we can use the principle of conservation of energy to make some observations.

Since the total mechanical energy of the particle is negative, we know that the particle must be in a state of potential energy greater than its kinetic energy. This means that the particle could be at the top of a hill, for example, where it has a large potential energy but a small kinetic energy. Alternatively, the particle could be in a region of space where there is a large attractive force acting on it, such as a gravitational or electric field, which could also contribute to a negative total mechanical energy. Without more information, it is not possible to determine the exact minimum and maximum positions of the particle. Conservation of energy is a fundamental law of physics stating that energy cannot be created or destroyed, only transformed from one form to another or transferred from one object to another.

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Assuming that the particle is subject to conservative forces, the total mechanical energy E of the particle is the sum of its kinetic energy and potential energy. Mathematically,

E = K + U

where K is the kinetic energy of the particle, and U is its potential energy.

Since the total mechanical energy E of the particle is given as -8 J, we have:

E = -8 J

Let's assume that the potential energy U has a minimum value of Umin and a maximum value of Umax.

Then we can write:

E = K + Umin (at the minimum position)

E = K + Umax (at the maximum position)

Subtracting the first equation from the second equation, we get:

E = (K + Umax) - (K + Umin)

E = Umax - Umin

Substituting the value of E, we get:

-8 J = Umax - Umin

This means that the difference between the maximum potential energy and the minimum potential energy is 8 J.

Since potential energy is a relative quantity, we can choose any point as a reference and assign it a potential energy of zero.

Let's assume that the minimum potential energy occurs at this reference point.

Then we can say:

Umin = 0 J

Umax = 8 J

Substituting these values in the equations for E, we get:

-8 J = K + 0 J (at the minimum position)

-8 J = K + 8 J (at the maximum position)

Solving for K, we get:

K = -8 J (at the minimum position)

K = -16 J (at the maximum position)

Since kinetic energy is always non-negative, the second equation is not physically possible. Therefore, the particle cannot reach the position where its kinetic energy is -16 J.

Therefore, the minimum position of the particle is the point where its kinetic energy is -8 J, and the maximum position is the point where its potential energy is 8 J.

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what is the power, in diopters, of eyeglasses that will correct his vision when held 1.50 cm from his eyes?

Answers

To calculate the power, in diopters, of eyeglasses that will correct vision when held 1.50 cm from the eyes, you need to know the individual's refractive error in diopters.

Refractive error refers to the degree of near sightedness (myopia), farsightedness (hyperopia), or astigmatism that an individual has. This value is typically measured by an optometrist or ophthalmologist using a phoropter.

Once the refractive error is known, the power of the corrective eyeglasses can be determined by dividing the refractive error by the distance (in meters) between the glasses and the eyes. In this case, since the glasses are held 1.50 cm from the eyes, the distance in meters would be 0.015 meters.

For example, if the individual has a refractive error of -2.00 diopters, the power of the corrective eyeglasses when held 1.50 cm from the eyes would be -2.00 / 0.015 = -133.33 diopters.

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when a fan is turned off, its angular speed decreases from 10 rad/s to 4.4 rad/s in 2.50 s. what is the magnitude of the average angular acceleration of the fan? a. 0.86 rad/s2 b. 2.24 rad/s2 c. 0.37 rad/s2 d. 11.0 rad/s2 e. 1.20 rad/s2

Answers

The magnitude of the average angular acceleration of the fan is 2.24 rad/s2 . So the correct answer is option: b.

The average angular acceleration can be calculated using the formula:

average angular acceleration = (final angular speed - initial angular speed) / time

Plugging in the given values, we get:

average angular acceleration = (4.4 rad/s - 10 rad/s) / 2.50 s

average angular acceleration = -2.56 rad/s2

Note that the negative sign indicates that the angular acceleration is in the opposite direction to the initial angular velocity.

|average angular acceleration| = 2.56 rad/s2 ≈ 2.24 rad/s2 .

Therefore, the correct answer is (b).

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calculate the change in energy for the following process: how much energy (in kcal) must be removed from 0.811 kg of water to cool it from 91 oc to 15 oc?

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The amount of energy that must be removed from 0.811 kg of water to cool it from 91°C to 15°C is approximately 61.636 kcal.

To calculate the change in energy for this process, we will use the specific heat capacity of water and the equation:

[tex]Q = m . c .[/tex]ΔT

where:
Q = change in energy (in kcal).
m = mass of water (in kg).
c = specific heat capacity of water (in kcal/kg°C).
ΔT = change in temperature (in °C).

The specific heat capacity of water is approximately 1 kcal/kg°C.

First, we need to determine the change in temperature (ΔT). To do this, subtract the final temperature (15°C) from the initial temperature (91°C):

Δ[tex]T = 91^{O}C - 15^{O}C = 76^{O}C[/tex]
Now, plug in the values into the equation:
[tex]Q = m . c .[/tex]ΔT
[tex]Q = (0.811 kg) . (1 kcal/kg°C) . (76°C)\\Q = (0.811 kg) . ( 76 kcal/°C)\\Q = 61.636 kcal\\[/tex]

Therefore, 61.636 kcal of energy must be removed from 0.811 kg of water to cool it from 91°C to 15°C.

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a barbell consists of two massive balls connected by a low-mass rod. the barbell slides across a low-friction icy surface, spinning as it moves, as shown in the diagram. the mass m of each ball is 0.9 kg. the distance d between the centers of the balls is 0.45 m. the speed v of the center of mass of the barbell is 0.37 m/s, and the barbell makes one complete revolution in 6 seconds. what is the translational kinetic energy of the barbell? ktrans

Answers

The translational kinetic energy of the barbell is approximately 0.12321 J (Joules).

To calculate the translational kinetic energy (K_trans) of the barbell, you can use the formula:

K_trans = (1/2) * M * V^2

Here, M represents the total mass of the barbell and V represents the speed of the center of mass.

Given that the mass (m) of each ball is 0.9 kg, the total mass (M) of the barbell would be:

M = 2 * m = 2 * 0.9 kg = 1.8 kg

The speed (V) of the center of mass of the barbell is given as 0.37 m/s.

Now, you can calculate the translational kinetic energy:

K_trans = (1/2) * 1.8 kg * (0.37 m/s)^2
K_trans = 0.9 kg * 0.1369 m^2/s^2
K_trans ≈ 0.12321 kg*m^2/s^2



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How much heat does it take to raise the temperature of 5.0 kg of plastic from 15°C to 75°C? The specific heat of plastic is 2.60 kJ/(kg × °C).

Answers

where

m is the mass

c is the specific heat capacity

ΔT is the change in temperature

In your problem,

m=2.5 kg

c=2.60 kJ⋅°C-1kg-1

Δ

∴ q=2.5kg×2.60 kJ⋅°C-1⋅kg-1×60°C=390 kJ

If 5.4 J of work is done in raising a 178 g apple, how far is it lifted? Assume
9 = 9.81 m/s?.
Answer in units of m. Answer in units of m.

Answers

Answer: The apple is lifted approximately 0.1232 m (rounded to four decimal places).

Explanation: To find the distance the apple is lifted, we can use the formula for work: work = force x distance.

The force required to lift the apple is equal to the weight of the apple, which can be calculated using the formula:

weight = mass x acceleration due to gravity.

we have work = weight x distance, 5.4 J = (0.178 kg x 9.81 m/s^2) x distance.

Solving for distance, we get a distance ≈ of 0.1232 m (rounded to four decimal places).

Here is an article on work, force, and distance in physics: https://byjus.com/physics/work-energy-power/#:~:text=The%20work%20done%20by%20a,only%20magnitude%20and%20no%20direction.

select the best answer: electricity flows in a circle. it flows from the outlet to the electric device and back to the outlet. if something gets in the way of this flow, what is it called?

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When something gets in the way of the flow of electricity in a circuit, it is called resistance.

Resistance can come in many forms, such as a faulty wire, a broken switch, or a damaged component in the device being powered.

When resistance occurs, the flow of electricity is impeded, which can result in a number of issues such as a loss of power, damage to the device, or even a fire. It is important to identify and resolve any resistance in a circuit as soon as possible to ensure safe and efficient operation.

Resistance can be measured in units called ohms, and there are many tools available for testing and diagnosing resistance issues in electrical circuits.

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009 (part 1 of 2) 10.0 points A gas expands from I to F in the figure. The energy added to the gas by heat is 402 J when the gas goes from I to F along the diagonal path. 0 1 2 3 4 0 1 2 3 4 b b b b I A B F V (liters) P (atm) What is the change in internal energy of the gas? Answer in units of J. 010 (part 2 of 2) 10.0 points How much energy must be added to the gas by heat for the indirect path IAF to give the 2 same change in internal energy? Answer in units of J.

Answers

In the illustration, a gas from I to F. The energy contributed to the gas through heat is 474 J when the gas moves along the diagonal line from I to F.

In physics, what is heat?

In thermodynamics, heat is energy that, in some way besides through labor or the movement of matter, spontaneously flows between a system and the surroundings. Heat transfers naturally from a warmer to a cooler body when an appropriate physical pathway is present.

What category does heat fit into?

Based on this, heat is divided into two categories: hot and cold. We encounter heat energy everywhere, including in icebergs, earthquakes, and our own bodies. There is heat energy in all matter. Heat energy is the only thing that results from the movement of microscopic particles called as atoms, atoms, or ions in fluids, solids, and gases.

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what is wrong when i turn my amana electric stove on for 350 degrees and it beeps and a f3 something shows up

Answers

The F3 error code on an Amana electric stove usually indicates an issue with the oven temperature sensor.

What does the F3 error code and beeping indicate on my Amana electric stove set to 350 degrees?

When you turn on your Amana electric stove to 350 degrees and it beeps while displaying an F3 error code, it usually indicates an issue with the oven temperature sensor. The F3 error code means that the control board has detected an open circuit in the temperature sensor circuit or that the temperature sensor is reading a temperature outside of its normal range. This can lead to inaccurate temperature readings, which may prevent the oven from heating up or cause it to overheat. You may need to replace the temperature sensor or have it checked by a professional technician to resolve the issue.

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when measuring the pendulum period, should the interface measure the time between two adjacent blocks of the photogate? or is some other measurement logic used? why?

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When measuring the pendulum period, the interface should measure the time between two adjacent blocks of the photogate. This method is used because it accurately captures the time taken for the pendulum to complete one full oscillation.

The photogate is an optical device that detects the interruption of a light beam by the pendulum bob. As the pendulum swings, it passes through the photogate and blocks the light, triggering a timing event. When the pendulum returns and blocks the light again, another timing event is triggered.

Measuring the time between these two adjacent blocks allows the interface to determine the time taken for one complete oscillation (from one extreme to the other and back). This method is reliable and precise, as it directly measures the time it takes for the pendulum to cover its full path, which is the definition of its period.

Other measurement techniques, such as recording the time of multiple oscillations and dividing by the number of cycles, can also be used. However, using the time between adjacent blocks of the photogate provides a more direct and accurate measurement of the pendulum period.

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