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1) To find the relative maxima of a function, we need to perform the first derivative test. It tells us whether the function has a local maximum, minimum r neither.
[tex]\begin{gathered} f^{\prime}(x)=\frac{d}{dx}\mleft(8x^3-3x^2\mright) \\ f^{\prime}(x)=\frac{d}{dx}\mleft(8x^3\mright)-\frac{d}{dx}\mleft(3x^2\mright) \\ f^{\prime}(x)=24x^2-6x \end{gathered}[/tex]2) Let's find the points equating the first derivative to zero and solving it for x:
[tex]\begin{gathered} 24x^2-6x=0 \\ x_{}=\frac{-\left(-6\right)\pm\:6}{2\cdot\:24},\Rightarrow x_1=\frac{1}{4},x_2=0 \\ f^{\prime}(x)>0 \\ 24x^2-6x>0 \\ \frac{24x^2}{6}-\frac{6x}{6}>\frac{0}{6} \\ 4x^2-x>0 \\ x\mleft(4x-1\mright)>0 \\ x<0\quad \mathrm{or}\quad \: x>\frac{1}{4} \\ f^{\prime}(x)<0 \\ 24x^2-6x<0 \\ 4x^2-x<0 \\ x\mleft(4x-1\mright)<0 \\ 0Now, we can write out the intervals, and combine them with the domain of this function since it is a polynomial one that has no discontinuities:[tex]\mathrm{Increasing}\colon-\infty\: 3) Finally, we need to plug the x-values we've just found into the original function to get their corresponding y-values:[tex]\begin{gathered} f(x)=8x^3-3x^2 \\ f(0)=8(0)^3-3(0)^2 \\ f(0)=0 \\ \mathrm{Maximum}\mleft(0,0\mright) \\ x=\frac{1}{4} \\ f(\frac{1}{4})=8\mleft(\frac{1}{4}\mright)^3-3\mleft(\frac{1}{4}\mright)^2 \\ \mathrm{Minimum}\mleft(\frac{1}{4},-\frac{1}{16}\mright) \end{gathered}[/tex]4) Finally, for the inflection points. We need to perform the 2nd derivative test:
[tex]\begin{gathered} f^{\doubleprime}(x)=\frac{d^2}{dx^2}\mleft(8x^3-3x^2\mright) \\ f\: ^{\prime\prime}\mleft(x\mright)=\frac{d}{dx}\mleft(24x^2-6x\mright) \\ f\: ^{\prime\prime}(x)=48x-6 \\ 48x-6=0 \\ 48x=6 \\ x=\frac{6}{48}=\frac{1}{8} \end{gathered}[/tex]Now, let's plug this x value into the original function to get the y-corresponding value:
[tex]\begin{gathered} f(x)=8x^3-3x^2 \\ f(\frac{1}{8})=8(\frac{1}{8})^3-3(\frac{1}{8})^2 \\ f(\frac{1}{8})=-\frac{1}{32} \\ Inflection\: Point\colon(\frac{1}{8},-\frac{1}{32}) \end{gathered}[/tex]Related Questions
When should the Empirical Rule be used?
Answers
The empirical formula should be used after calculating the standard deviation and collecting the exact data needed for a forecast.
Explanations:What is the empirical rule?The empirical rule is a term used in statistics also known as the 68–95–99.7 rule. This rule is majorly used in forecasting the final outcome of events.
The empirical rule can be used to therefore determine a rough estimate of the outcome of the impending data to be collected and analyzed. This is done after calculating the standard deviation and collecting the exact data needed.
68–95–99.7 rule,
The population of Somewhere, USA was estimated to be 658,100 in 2003, with an expected increase of 5% per year. At the percent ofincrease given, what was the expected population in 2004? Round your answer to the nearest whole number.
Answers
To solve for the expected population in 2004:
[tex]\begin{gathered} \text{Estimated population for 2003=658100} \\ \text{rate = 5 \%} \\ nu\text{mber of year = 1} \end{gathered}[/tex]Using compound interest formular to solve for the expected popupation:
Expected population = Amount
[tex]\begin{gathered} A=p(1+\frac{r}{100})^n \\ A\text{ = 658100 (1+}\frac{5}{100})^1 \\ A=658100\text{ (1+0.05)} \\ A=658100(1.05) \\ A=691005 \end{gathered}[/tex]Hence the expected population in 2004 = 691,005
What is the distance from the ball to the base of the building? Round to the nearest foot.*
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Given:
[tex]\theta=37^{\circ}\text{ ; height of the building is }60\text{ ft}[/tex][tex]\begin{gathered} \tan 37^{\circ}=\frac{Height\text{ of the building}}{\text{Distance between the ball and foot of the building}} \\ 0.7536=\frac{60}{\text{Distance between the ball and foot of the building}} \\ \text{Distance between the ball and foot of the building}=\frac{60}{0.7536} \\ =80\text{ feet} \end{gathered}[/tex]80 feet is the final answer.
what property tells us that m
Answers
Reflexive Property
1) For this assertion m∠GHK ≅ m∠GHK we have the Reflexive Property, which states that the same segment or geometric entity has the same measure.
"A quantity is congruent to itself"
m∠GHK ≅ m∠GHK
a =a
Fill in the blanks. (6x)^2 = _x^_
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Step-by-step explanation:
[tex](6x) {}^{2} = -x { }^{?} - [/tex]The Terrell Middle School wants to plant a community garden. They plan togrow and harvest vegetables, which will then be sold to raise funds for futuregardening.1. The science teacher, Ms. Maeda, wants the school to start composting.She borrows $392 from a school fund for supplies to make thecompost bins.Part AStudents plan to pay back half the debt now through fundraising,and the rest after the harvest. Write and solve an equation to representthe debt they will repay through fundraising. Use a negative integer toshow debt.
Answers
Total money $392
half of $392 is 196
one half would be paid through fundraising
The debt would be the other half
[tex]\begin{gathered} The\text{ debt} \\ x=\frac{-1}{2}(392) \\ x=-196\text{ dollars} \end{gathered}[/tex]THE FINAL ANSWER
x=-196 dollars
Triangle A is rotated 90° about the origin. Which triangle shows the image?
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Rotation 90° about the origin.
First, choose a point from triangle A.
For example: (-2,2)
For any point (x,y) rotated 90° =(-y,x)
So:
(-2,2) becames = (-2,-2)
Triangle D
Ms. Wong sold 28 cars. She sold 8 fewer cars that 3/4 as many cass as Mr. Diaz. Which equation can be used to find the number of cars that Mr. Diaz sold,c?
Answers
The equation that we can be used to find the number of cars that Mr. Diaz sold is [tex]\frac{3}{4}x[/tex]−[tex]8=28[/tex].
Ms Wong sold cars = 28.
She sold [tex]8[/tex] fewer cars that is 3/4 as many cars as Mr. Diaz.
Let Mr. Diaz sold [tex]x[/tex] cars.
Cars is 3/4 as many cars as Mr. Diaz so the term [tex]3/4x[/tex].
She sold 8 fewer cars.
Now from the statement the Ms Wong sold cars [tex]\frac{3}{4}x[/tex]−[tex]8[/tex].
As it is given that Ms Wong sold 28 cars.
So the equation must be
[tex]\frac{3}{4}x[/tex]−[tex]8=28[/tex]
So equation that we can be used to find the number of cars that Mr. Diaz sold is [tex]\frac{3}{4}x[/tex]−[tex]8=28[/tex].
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Evaluate( - 4) ^ 3/2
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Answer: 8i
I need help with a math question. Ilinked it below
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EXPLANATION:
We are given a dot plot as shown which indicates the ages of members of an intermediate swim class.
The dot plot indicates a cluster to the right for the values;
[tex]11yrs-14yrs[/tex]This indicates that a reasonable amount of the members are within that age range.
For this reason, it is not likely that Mira will be able to convince her mother.
This is because Mira's age (13 years old) is within the area where the data are clustered.
Therefore;
ANSWER:
(1) The data are clustered between 11 and 14 years old
(2) It is not likely that she will be able to convince her mother
(3) Mira's age is within the area where the data are clustered.
The function f(x) = 6x represents the number of lightbulbs f(x) that are needed for x chandeliers. How many lightbulbs are needed for 7 chandeliers? Show your work
Answers
There are a total of 42 lightbulbs needed for 7 chandeliers
How to determine the number of lightbulbs needed?From the question, the equation of the function is given as
f(x) = 6x
Where
x represents the number of chandeliersf(x) represents the number of lightbulbs
For 7 chandeliers, we have
x = 7
Substitute x = 7 in f(x) = 6x
So, we have
f(7) = 6 x 7
Evaluate the product
f(7) = 42
Hence, the number of lightbulbs needed for 7 chandeliers is 42
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The number of lightbulbs needed for 7 chandeliers would be; 42
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
From the given problem, the equation of the function is;
f(x) = 6x
Where
x be the number of chandeliers and f(x) represents the number of lightbulbs.
For 7 chandeliers, x = 7
Now Substitute x = 7 in f(x) = 6x
Therefore, f(7) = 6 x 7
Evaluate the product;
f(7) = 42
Hence, the number of lightbulbs needed for 7 chandeliers would be; 42
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What is the volume of the right triangular prism below? a 1600cm 800cm 400cm 160cm
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The formula for determining the volume of a triangular prism is expressed as
Volume = area of triangular face * height of prism
The fotmula for finding the area of the triangular face is
Area = 1/2 * base * height
Looking at the diagram,
base = 8 cm
height = 10 cm
Area of triangular face = 1/2 * 8 * 10 = 40 cm^2
height of prism = 20 cm
Volume of prism = 40 * 20 = 800 cm^3
Option B is correct
Graph the inequality
y<= -(2/3)|x-3|+4
Please show how
Answers
We have the following inequality
[tex]y\leq-\frac{2}{3}\lvert x+3\rvert+4[/tex]We must graph this inequality, In order to understand this I will explain term by term
But first, we must remember that in mathematics, the absolute value or modulus of a real number x, denoted by |x|, is the non-negative value of x regardless of the sign, positive or negative. This must be taken into account for the |x+3| term.
That is to say that the value will always be assumed by its magnitude and we will tend to have the same behavior on both the negative and positive x-axis.
Taking this into account and that the slope is -2/3 the graph would look like this:
Now, we must remember two rules of function translation, these are as follows:
y = f(x) original funtion
y = f(x+c) it is moved horizontally "c" units to the left
y = f(x)+c it moves vertically "c" units upwards
So taking into account these rules our graph is shifted 3 units to the left and 4 units upwards.
In conclusion, this graph looks like this:
help meeeeeeeeee pleaseee !!!!!
Answers
The composition of functions g(x) and f(x) evaluated in x = 5 is:
(g o f)(5) = 6
How to evaluate the composition?
Here we have two functions f(x) and g(x), and we want to find the composition evaluated in x = 5, this is:
(g o f)(5) = g( f(5) )
So first we need to evaluate f(x) in x = 5, and then g(x) in f(5).
f(5) = 5² - 6*5 + 2 = 25 - 30 + 2 = -3
Then we have:
(g o f)(5) = g( f(5) ) = g(-3)
Evaluating g(x) in x = -3 gives:
g(-3) = -2*(-3) = 6
Then the composition is:
(g o f)(5) = 6
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10(6 + 4) ÷ (2³-7)² =
Answers
Answer:
100
Explanation:
Given the expression
[tex]10\mleft(6+4\mright)\div(2^3-7)^2[/tex]First, we evaluate the bracket and exponents.
[tex]=10\mleft(10\mright)\div(8-7)^2[/tex]This then gives us:
[tex]\begin{gathered} 100\div(1)^2 \\ =100\div1 \\ =100 \end{gathered}[/tex]I have attached the question
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The following are the primary factors that the Cvp analysis employs to determine if the sales price per unit and variable costs per unit are impacted
Describe CVP Analysis?This is the term used to describe the cost-volume-profit analysis, which is used to determine how changes in cost and volume might directly affect operating costs.With this in mind, it is clear that the primary component that businesses utilize in their CVP analyses to ensure that their operational costs don't fluctuate arbitrary is cost changes. Profit = revenue - costs is the fundamental CVP formula. Naturally, you must understand how to calculate your revenue in order to use this formula:(Retail price * Units Sold)Additionally, you must understand how to calculate your costs: fixed costs plus (unit variable cost x number of units). Y = a + bx is the cost volume formula. Y = Total expense = Total fixed expense (that is, a cost that does not vary in proportion to activity)B is the variable cost per unit of activity; this cost does vary in relation to activity. Contribution/Sales is the P/V ratio. It is employed to gauge the company's profitability. The surplus of sales over variable costs is known as contribution. In essence, the P/V ratio is utilized to assess the level of contribution provided at various sales volumes.To learn more about Cpv analysis refer
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Find all the solutions and if there is an extraneous solution, identify them and explain why they are extraneous.
Answers
ANSWER
Solution: b = 3
It is extraneous
EXPLANATION
We want to solve the equation given and to see if there are any extraneous solutions.
We have:
[tex]\begin{gathered} \frac{7}{b\text{ + 3}}\text{ + }\frac{5}{b\text{ - 3}}\text{ = }\frac{10b}{b^2\text{ - 9}} \\ \Rightarrow\text{ }\frac{7}{b\text{ + 3}}\text{ + }\frac{5}{b\text{ - 3}}\text{ = }\frac{10b}{(b\text{ + 3)(b - 3)}} \\ \text{Multiply both sides by (b + 3)(b - 3):} \\ \Rightarrow\text{ }\frac{7(b+3)(b\text{ - 3)}}{b\text{ + 3}}\text{ + }\frac{5(b\text{ + 3)(b - 3)}}{b\text{ - 3}}\text{ = }\frac{10b(b\text{ + 3)(b - 3)}}{(b\text{ + 3)(b - 3)}} \\ 7(b\text{ - 3) + 5(b + 3) = 10b} \\ 7b\text{ - 21 + 5b + 15 = 10b} \\ \text{Collect like terms:} \\ 7b\text{ + 5b - 10b = 21 - 15} \\ 2b\text{ = 6} \\ Divide\text{ both sides by 2:} \\ b\text{ = }\frac{6}{2} \\ b\text{ = 3} \end{gathered}[/tex]That is the solution to the equation.
To find if the solution is extraneous, we will insert the value of b = 3 into the original equation.
That is:
[tex]\begin{gathered} \Rightarrow\text{ }\frac{7}{3\text{ + 3}}\text{ + }\frac{5}{3\text{ - 3}}\text{ = }\frac{10(3)}{(3\text{ + 3)(3 - 3)}} \\ \frac{7}{6}\text{ + }\frac{5}{0}\text{ = }\frac{30}{(6)(0)} \\ \frac{7}{6}\text{ + }\frac{5}{0}\text{ = }\frac{30}{0} \end{gathered}[/tex]An extraneous solution is a solution that derives from solving a rational equation but does not exactly satisfy the original equation, that is, it is invalid for the equation.
By inserting b = 3 into the equation, we see that the equation is undefined.
Therefore, since b = 3 is a solution, but it does not satisfy the equation, it is an extraneous solution.
Which of the following are a qualitative catecorical variables
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A qualitative variable, also called a categorical variable, is a variable that isn’t numerical. It describes data that fits into categories.
From the given options below, the arrival status of a train ( early, on time, late, canceled) and a person's blood type are the only qualitative variables.
Hence, Option 3 and Option 5 are the correct answers.
I need help with this quadratic function… I thought I knew the answer, but obviously I don’t
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Let us start with the following quadratic function:
[tex]f(x)=x^2-x-12[/tex]the X-intercepts are the collection of values to X which makes f(x) = 0, and it can be calculated by the Bhaskara formula:
[tex]x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]where the values a, b, and c are given by:
[tex]f(x)=ax^2+bx+c[/tex]Substituting the values from the proposed equation, we have:
[tex]\begin{gathered} x_{1,2}=\frac{1\pm\sqrt{1^2-4*1*(-12)}}{2*1} \\ x_{1,2}=\frac{1\pm\sqrt{1+48}}{2}=\frac{1\pm\sqrt{49}}{2} \\ x_{1,2}=\frac{1\pm7}{2} \\ \\ x_1=\frac{1+7}{2}=\frac{8}{2}=4 \\ x_2=\frac{1-7}{2}=-\frac{6}{2}=-3 \end{gathered}[/tex]From the above-developed solution, we are able to conclude that the solution for the first box is:
(-3,0) ,(4,0)Now, the y-intercept, is just the value of y when x = 0, which can be calculated as follows:
[tex]\begin{gathered} f(0)=0^2-0-12=-12 \\ f(0)=-12 \end{gathered}[/tex]From this, we are able to conclude that the solution for the second box is:
(0, -12)Now, the vertex is the value of minimum, or maximum, in the quadratic equation, and use to be calculated as follows:
[tex]\begin{gathered} Vertex \\ x=-\frac{b}{2a} \\ y=\frac{4ac-b^2}{2a} \end{gathered}[/tex]substituting the values, we have:
[tex]\begin{gathered} x=-\frac{-1}{2*1}=\frac{1}{2} \\ y=\frac{4*1*(-12)-(-1)^2}{4*1}=\frac{-48-1}{4}=\frac{-49}{4} \end{gathered}[/tex]which means that the solution for the thirst box is:
(1/2, -49/4) (just as in the photo)Now, the line of symmetry equation of a quadratic function is a vertical line that passes through the vertex, which was calculated to be in the point: (1/2, -49,4).
Because this is a vertical line, it is represented as follows:
[tex]x=\frac{1}{2}[/tex]fredrico has earned scores of 7.2, 8.4, and 8.4 on his first 3 dives he has one dive left what score must he get on his last dive to have an average of at least 7.4 on all four dives
Answers
For Fredrico to make an average of at least 7.4 on all four dives, he must get at least 5.6 in his last dive.
What is the average?The average is the mean of the total scores that Fredrico scored in his dives.
The average can be computed by dividing the total scores by the number of dives.
The average is the quotient of the division operation of the total scores and the number of dives.
The total score based on an average of 7.4 = 29.6
The total scores obtained = 24 (7.2 + 8.4 + 8.4)
The remaining score to obtain to get the average of 7.4 = 5.6 (29.6 - 24)
Thus, Fredrico needs an additional 5.6 score in the last dive to make the average.
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Fredrico needs to score at least 5.6 on his final dive in order to achieve an average of at least 7.4 on all four dives.
Let's assume the required score would be x on his final dive
Mean = ∑x/n
The average represents the mean of all of Fredrico's dive-related scores.
Here, n = 4
Sum of Observations (∑x) = 7.2 + 8.4 + 8.4 + x
∑x = x + 24
Mean = ∑x/n
Substitute the values in the above formula,
⇒ 7.4 = (x + 24) / 4
Apply the cross-multiplication operation in the above equation,
⇒ 7.4 × 4= (x + 24)
⇒ 29.6 = x + 24
⇒ x = 29.6 - 24
Apply the subtraction operation to get
⇒ x = 5.4
Therefore, Fredrico needs to score at least 5.6 on his final dive
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How many times in the parabola does a line intersect?
Answers
The line can intersect the parabola at one or two points.
See the example below.
The black line intersects the parabola at (1, -1)
The blue line intersects the parabola at two points: (0, 0) and (4, 8).
(Combining Equation)What is the result of subtracting the second equation from the first ?-2x + y = 0 -7x + 3y = 2
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We are given the following two equations
[tex]\begin{gathered} -2x+y=0\quad eq.1 \\ -7x+3y=2\quad eq.2 \end{gathered}[/tex]Let us subtract the second equation from the first equation.
Therefore, the result of subtracting the second equation from the first is
[tex]5x-2y=-2[/tex]I want to know how to determine whether the x or r in cos A = -2/5 is negative so when im using cos A's values in the x^2+y^2=r^2 equation I dont use the wrong number
Answers
INFORMATION:
STEP BY STEP EXPLANATION:
ANSWER:
I really need help solving this problem from my trigonometry prepbook
Answers
The terminal ray of 145° lies in II Quadrant.
The terminal ray of -83° lies in IV Quadrant.
The terminal ray of -636 lies in I Quadrant.
The terminal ray of 442 lies in I Quadrant.
Hayley's rectangular bedroom is 6 meters by 5 meters. What is the diagonal distance from one corner to the opposite corner? If necessary, round to the nearest tenth.
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Hayley's rectangular bedroom is 6 meters by 5 meters. What is the diagonal distance from one corner to the opposite corner? If necessary, round to the nearest tenth.
Apply the Pythagorean Theorem
c^2=a^2+b^2
we have
a=6 m
b=5 m
c^2=6^2+5^2
c^2=36+25
c^2=61
square root c=7.8 m
answer is 7.8 metersO EQUATIONS AND INEQUALITIESSolving a decimal word problem using a linear equation with th.
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Given:
[tex]PlanA=0.16\text{ for each minutes of calls}[/tex][tex]PlanB=25\text{ monthly fee plus 0.12 for each minute of calls}[/tex]To Determine: The numbers of calls for the which the two plans are equal
Solution
Let x be the number of minutes of calls for which the two plans are equal
The cost of plan A is
[tex]C_{ost\text{ of plan A}}=0.16x[/tex]The cost of plan B
[tex]C_{ost\text{ of plan B}}=25+0.12x[/tex]If the cost for the two plans are equal, then
[tex]0.16x=25+0.12x[/tex]Solve for x
[tex]\begin{gathered} 0.16x-0.12x=25 \\ 0.04x=25 \\ x=\frac{25}{0.04} \\ x=625 \end{gathered}[/tex]Hence, the number of minutes of calls for which two plans are equal is 625 minutes
When the polynomial mx^3 - 3x^2 +nx +2 is divided by x+3, the remainder is -4. When it is divided by x-2, the remainder is -4. Determine the value of m and n.
Answers
Answer:
[tex]\begin{gathered} m\text{ =-2} \\ n\text{ =11} \end{gathered}[/tex]Explanation:
Here, we want to find the value of m and n
If we substituted a supposed root into the parent polynomial, the value after evaluation is the remainder. If the remainder is zero, then the value substituted is a root.
for x+ 3
x + 3 = 0
x = -3
Substitute this into the first equation as follows:
[tex]\begin{gathered} m(-3)^3-3(-3)^2-3(n)+\text{ 2 = -4} \\ -27m\text{ -27-3n+ 2 = -4} \\ -27m\text{ -3n = -4}+27-2 \\ -27m-3n\text{ = 21} \\ -9m\text{ - n = 7} \end{gathered}[/tex]We do this for the second value as follows:
x-2 = 0
x = 2
Substitute this value into the polynomial:
[tex]\begin{gathered} m(2)^3-3(2)^2+2(n)\text{ + 2 = -4} \\ 8m\text{ - 12 +2n + 2 = -4} \\ 8m\text{ + 2n = -4-2+12} \\ 8m\text{ + 2n = 6} \\ 4m\text{ + n = 3} \end{gathered}[/tex]Now, we have two equations so solve simultaneously:
[tex]\begin{gathered} -9m-n\text{ = 7} \\ 4m\text{ + n = 3} \end{gathered}[/tex]Add both equations:
[tex]\begin{gathered} -5m\text{ = 10} \\ m\text{ =-}\frac{10}{5} \\ m\text{ = -2} \end{gathered}[/tex]To get the value of n, we simply susbstitute the value of m into any of the two equations. Let us use the second one:
[tex]\begin{gathered} 4m\text{ +n = 3} \\ 4(-2)\text{ + n = 3} \\ -8\text{ + n = 3} \\ n\text{ = 8 + 3} \\ n\text{ = 11} \end{gathered}[/tex]A park has several rows of trees. Each row has 5 trees. How many trees could be in the park?
Answers
Answer: so lets say x =the exact amount of rows
so each row has 5 tree's
then a is the answer
its an equation of x·5=a
so that would be a unknown number of trees so you assume that there is more than 1 row because there is several rows so its a incomplete question
Step-by-step explanation:
On a circle of radius 9 feet, what angle would subtend an arc of length 7 feet?
_____ degrees
Answers
The angle subtend an arc length of 7 feet is 44.56°
Given,
Radius of a circle = 9 feet
Arc length of a circle = 7 feet
Arc length :
The distance between two places along a segment of a curve is known as the arc length.
Formula for arc length:
AL = 2πr (C/360)
Where,
r is the radius of the circle
C is the central angle in degrees
Now,
AL = 2πr (C/360)
7 = 2 × π × 9 (C/360)
7 = 18 π (C/360)
7/18π = C/360
C = (7 × 360) / (18 × π)
C = (7 × 20) / π
C = 140 / π
C = 44.56°
That is,
The angle subtend an arc length of 7 feet is 44.56°
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Jenny originally bought her car for $42,000. Four years later, she sold it to a used car salesman for $14,000. What is the ratio for the amount she sold it for to the amount that it depreciated?
Answers
SOLUTION
The amout that Jenny sold the car for is $14,000
The amout that the car depriciated will be
$42,000 - $14,000 = $28,000
The ratio for the amount she sold it for to the amount that it depreciated becomes
[tex]\begin{gathered} \frac{14,000}{28,000} \\ \\ =\text{ }\frac{1}{2} \\ \\ =\text{ 1 : 2} \end{gathered}[/tex]