Solution :
Given :
The angle of the first maximum with the center is given by :
[tex]$a=\tan^{-1}\left(\frac{0.488}{1.88}\right)$[/tex]
= 14.5°
The grating distance can be calculated as :
[tex]$d=\frac{1 \ cm}{5308 \text{ slits}}$[/tex]
= [tex]$1.88 \times 10^{-4} \ m$[/tex]
When the principal maxima yields at y = 0.488 m and the length from the wall 1.88 m. Thus the equation of the wavelength is :
[tex]$\lambda = g \times \frac{\sin a}{n}$[/tex] , where n = 1
[tex]$=1.88 \times 10^{-4} \times \sin (14.5)$[/tex]
[tex]$=4.70 \times 10^{-5} \ m$[/tex]
In an electric resistance of 20 ohms, if the current intensity passing through it
is doubled, its value becomes ........ ohms.
b. 20
d. 40
a. 10
c. 30
Answer:
a. 10 ohms.
Explanation:
Given;
first electrical resistance, r₁ = 20 ohms
let the first current through the circuit = I₁
let the second current through the circuit, I₂ = 2I₁ (since it is doubled)
then, the new value of the resistance after doubling the current = r₂
the current intensity is given as;
[tex]\frac{dI}{dt} = I = \frac{v}{r} \\\\I_1r_1 = I_2r_2\\\\r_2 = \frac{I_1r_1}{I_2} \\\\r_2 = \frac{I_1 \times 20}{2I_1 } \\\\r_2 = 10 \ ohms[/tex]
Therefore, the new value of the resistance is 10 ohms.
If you cut a permanent magnet into four pieces,
you will have what?
A) four temporary magnets
B) four smaller permanent magnets
C) two north poles and two south poles
D)four objects that are no longer magnets
you would have C) two north poles and two south poles
Phobos's Orbit. Phobos orbits Mars at a distance of 9,380 km from the center of the planet and has a period of 0.3189 days. Assume that Phobos's orbit is circular. Calculate the mass of Mars. Express your answer in units of kg. (Hint: Use the circular orbit velocity formula ; remember to use units of meters, kilograms, and seconds.) Please round the answer to four significant digits. m
Answer:
Explanation:
The relation between time period of moon in the orbit around a planet can be given by the following relation .
T² = 4 π² R³ / GM
G is gravitational constant , M is mass of the planet , R is radius of the orbit and T is time period of the moon .
Substituting the values in the equation
(.3189 x 24 x 60 x 60 s)² = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)
759.167 x 10⁶ = 8.25 x 10²⁰ x 39.43 / (6.67 x 10⁻¹¹ x M )
M = .06424 x 10²⁵
= 6.4 x 10²³ kg .
An object has one force acting on it. It is a 33- Newton force pointing downward. To create a net force of zero on the object, which force must be applied to it?
As soon as I see "Which...", I know that the last part of the question is the list of answer choices, but you decided not to let us see them.
The answer is: A 33-Newton force pointing upward.
Does the law of attraction actually have a basis in physics?
Answer:
Scientific theories are cited by proponents of the Law of Attraction as evidence in its favor. It, on the other hand, has no theoretical basis. A variety of scientists have questioned the promoters' abuse of scientific principles.
A 6.00 kg object at rest is suddenly broken apart into two fragments by an explosion. The fragment with mass 3.50 kg is moving 24.0m/s to the left. The other fragment is moving _______m/s to the right. Group of answer choices
Answer: 33.6 m/s
Explanation:
Given
The initial mass of the object is [tex]6\ kg[/tex]
It breaks into two fragments of 3.5 and 2.5 kg
3.5 kg part moves at 24 m/s towards left
Suppose 2.5 kg part moves with a speed of v towards the right
As the center of mass is at rest before the collision, it continues to remain at rest after the collision.
[tex]\therefore 6\times 0=3.5\times 24-2.5\times v\\\Rightarrow 3.5\times 24=2.5\times v\\\\\Rightarrow v=33.6\ m/s[/tex]
Therefore, the velocity of 2.5 kg mass is 33.6 m/s towards right.
Which refers to the density of the medium’s particles at the compression of a sound wave?
Answer:
Explanation:
Amplitude. the density of a mediums particles at the compression of the wave. Rarefaction. the part of a wave where the particles of the medium are farther apart.
Answer: amplitude
Explanation:
A uniform rod of length 80cm rotated in the xy plane about a frictionless pin passing through one end (as shown in figure). If the angular
velocity of the rod is 4rad/s, find the linear velocity (in m/s) of its mid-point C
Rod
Pin
С
Select one:
O a. 0.5
O b. 1.6
O c. 1.3
O d. 0.8
Answer:
Linear velocity (in m/s) = 1.6 m/s
Explanation:
Given:
Length of rotational plane = 80 cm
Angular velocity of the rod = 4rad/s
Find:
Linear velocity (in m/s)
Computation:
Radius from mid point C = Length of rotational plane / 2
Radius from mid point C = 80 / 2
Radius from mid point C = 40 cm
Radius from mid point C = 0.4 m
Linear velocity (in m/s) = Angular velocity of the rod x Radius from mid point C
Linear velocity (in m/s) = 0.4 x 4
Linear velocity (in m/s) = 1.6 m/s
An open cart is rolling to the left on a horizontal surface. A package slides down a chute and lands in the cart. Which quantity or quantities have the same value just before and just after the package lands in the cart
Answer: the horizontal component of total momentum
Explanation:
Since the open cart is rolling to the left on the horizontal surface, the quantity that has the same value just before and just after the package lands in the cart is the horizontal component of total momentum.
Momentum, is the product of the mass of a particle and the velocity of the particle. The change of momentum depends on the force which acts on it. The addition of the the individual momenta is the total momentum.
Un corredor hace los 400 metros lisos en 50 seg. Calcula la velocidad en la carrera.
Answer:
8 meters/second
Explanation:
Rate x Time = Distance
R x T = D
R x 50sec = 400meters
R x 50sec/50sec = 400meters/50sec
R = 8meters/sec
A system is in liquid-vapor mixture of 0.5 kg of saturated water vapor and 0.5 kg
of saturated liquid. Calculate the quality.
Answer:
x = 0.5 = 50%
Explanation:
The quality of a water liquid-vapor mixture can be defined as the fraction of water vapor present in the water liquid-vapor mixture. Therefore, it can be calculated by the use of the following formula:
[tex]x = \frac{m_{vap}}{m}[/tex]
where,
x = quality = ?
m_vap = mass of saturated water vapor = 0.5 kg
m = total mass = mass of saturated vapor + mass of saturated liquid
m = 0.5 kg + 0.5 kg = 1 kg
Therefore,
[tex]x = \frac{0.5\ kg}{1\ kg}[/tex]
x = 0.5 = 50%
A gondola can carry 20 skiers, with a total mass of up to 2250 kg. The gondola ascends at a constant speed from the base of a mountain, at 2150 m, to the summit at 3345 m. (a) How much work does the motor do in moving a full gondola up the mountain
Answer:
[tex]$2.63\times 10^{7} \ J$[/tex]
Explanation:
Given :
Total mass that a gondola can carry, m = 2250 kg
Displacement, s = 3345 - 2150
= 1195 m
Gravitational force, F = mg
= 2250 x 9.8
= 22050 N
Therefore the work done by the motor in moving the full gondola up the mountain,
W = F x s
= 22050 x 1195
= [tex]$2.63\times 10^{7}$[/tex] J
a 4 kg block is moving at 12 m/s on a horizontal frictionless surface. a constant force is applied such that the block slows with an acceleration of 3 m/s^2. how much work must this force do to stop the block?
a. -576 J
b. -360 J
c. -288 J
d. 360 J
e. 576 J
walk me through this please. NO LINKS.
Answer:
Is there a picture?
Explanation:
The bands on Jupiter are ultimately caused by...
the Coriolis effect.
its magnetic fields.
precession.
the Great Red Spot.
Explain what you understand by Millennial Generation
Answer:
refers to the generation of people born between the early 1980s and 1990s
You drop a 10 kg bowling ball off a 2 story building, what is the force generated by
the bowling ball when it hits the ground
Answer:i
Explanation:
A solid, uniform sphere of mass 2.0 kg and radius 1.8 m rolls from rest without slipping down an inclined plane of height 7.5 m. What is the angular velocity of the sphere at the bottom of the inclined plane
Answer:
[tex]w^2=5.5rads/s[/tex]
Explanation:
From the question we are told that:
Mass [tex]m=2.0kg[/tex]
Radius [tex]r=1.8m[/tex]
Height [tex]h=7.5m[/tex]
Generally the equation for Potential energy is mathematically given by
Potential energy=Kinetic energy+Rotational energy
[tex]mgh=\frac{1}{2}mv^2+\frac{1}{2}Iw^2[/tex]
Since there is no slipping
[tex]v=rw[/tex]
Therefore
[tex]mgh=\frac{1}{2}mr^2w^2+\frac{1}{2}Iw^2[/tex]
Where
[tex]I=\frac{1}{2}mr^2[/tex]
[tex]l=3.24m[/tex]
[tex]2*9.81*7.5=\frac{1}{2}(2)(1.8)^2w^2+\frac{1}{2}(3.24)w^2\\\\[/tex]
[tex]147.15=3.24w^2+1.62w^2[/tex]
[tex]w^2=\frac{147.15}{4.86}[/tex]
[tex]w^2=\sqrt{\frac{147.15}{4.86}}[/tex]
[tex]w^2=5.5rads/s[/tex]
а)
In figure below, assume that a 20-mm-diameter rivet joins the plates that are each 110 mm
wide. The allowable stresses are 120 MPa for bearing in the plate material and 60 MPa for
shearing of rivet. Find the followings. Express your final answer in N/mm².
110 mm
20-mm
P
(1) Determine the minimum thickness of each plate and largest average tensile stress in the
plates.
(6 marks)
Image of the plate is missing, so i have attached it.
Answer:
A) t = 7.854 mm
B) σ = 26.67 MPa
Explanation:
A) From shearing of rivet, formula for pressure is;
P = τ•A_rivets
Where;
τ is allowable stress
A_rivets is Area of rivet
We are given:
τ = 60 MPa
Diameter; d = 20 mm
A_rivets = πd²/4 = π × 20²/4 = 100π
Thus;
P = 60 × 100π
P = 6000π N
From bearing of plate material, we can calculate pressure as;
P = σ_b•A_b
We are given;
σ_b = 120 MPa
A_b is area of plate = 20t
Where t is the thickness
Thus;
6000π = 120 × 20t
t = 6000π/(120 × 20)
t = 7.854 mm
B) Largest average tensile stress is given by the formula;
σ = P/A
Where A = 110t - 20t
A = 90t
A = 90 × 7.854
Thus;
σ = 6000π/(90 × 7.854)
σ = 26.67 MPa
If the height is 10m, what is the potential energy? Asuming that the mass is 10
[tex]\huge{\textit{\sf{{\color{m}{Answer}}{\color{b}{࿐}}}}}[/tex]
we know,
[tex] \boxed{potential \: energy = mgh}[/tex]
So,
[tex]\longmapsto10 \times 9.8 \times 10[/tex]
[tex]\longmapsto980 \: joules[/tex]
What is the frequency of microwaves of wavelength 3 cm?
Give your answer to the
nearest GHz and without units.
Answer:
10 GHz
Explanation:
Applying,
v = λf.................... Equation 1
Where v = speed of microwave, λ = wavelength, f = frequency.
make f the subject of the equation
f = v/λ................ Equation 2
Note: Microwave is an electromagnetic wave, and all electromagnetic wave have the same speed, which is 3×10⁸ m/s
From the question,
Given: λ = 3 cm = 0.03 m
Constant; v = 3×10⁸ m/s
Substitute these values into equation 2
f = 3×10⁸/(0.03)
f = 10¹⁰ Hz
f = (10¹⁰/10⁹) GHz
f = 10 GHz
An object
moves through space with balanced forces acting on it. Which statement
best describes the speed and direction of the object as long as the forces acting on it
remain balanced?
Pls answer number 4 and an explanation
Answer: G the speed and direction of the object will remain constant.
Definition of waves
Answer:
A wave can be described as a disturbance that travels through a medium from one location to another location.
Explanation:
Select the correct answer from each drop-down menu.
After World War II, political leaders from various countries discussed ways to strengthen individual-as well as
economies. They began promoting
to boost production and exports,
Answer: I think it’s Global for the 1st one
And free trade for the 2nd one
Explanation:
The correct answer is: "After World War II, political leaders from various countries discussed ways to strengthen individual economies." They began promoting economic policies to boost production and exports.
What happened after World War II?After World War II, many countries were left with weakened economies and infrastructure, and there was a need for economic recovery and growth. To achieve this, political leaders from different countries came together to discuss ways to strengthen their individual economies and also promote international economic cooperation. One of the ways they did this was by promoting economic policies that aimed to boost production and exports. This involved policies that encouraged businesses to increase their output and create more jobs, as well as policies that made it easier for countries to trade with each other.
Hence, after World War II, political leaders from various countries discussed ways to strengthen their individual economies. They began promoting economic policies to boost production and exports.
Learn more about World War II's aftermath here.
https://brainly.com/question/27327667
#SPJ5
a particle covers 10m distance in 2sec. if final velocity is 8m/s, find initial velocity
Answer:
vi =2
Explanation:
Δx = 1/2 (vi + vf) t
10 = 1/2 ( vi + 8 ) 2
10 = vi + 8
10-8 = vi
vi = 2 m/s
vi= initial velocity
vf= final velocity
Δx= distance
t= time
The planets and the asteroid belt orbit the Sun in __________. Multiple Choice a spherical distribution, whereas the Oort cloud of comets orbits in a plane planes, whereas the Oort cloud of comets has a spherical distribution orbits nearly identical to the Oort cloud of comets planes tilted at an angle to the plane of the Oort cloud of comets a spherical distribution similar to that of the Oort cloud of comets
Answer:
planes, whereas the Oort cloud of comets has a spherical distribution.
Explanation:
A planet can be defined as a large celestial body having sufficient mass to allow for self-gravity and make it assume a nearly circular shape (hydrostatic equilibrium), revolves in an orbit around the Sun in the solar system and has a cleared neighborhood.
Basically, the planets are divided into two (2) main categories and these includes;
I. Outer planets: these planets are beyond the asteroid belt and comprises of jupiter, saturn, uranus and neptune, from left to right of the solar system.
II. Inner planets: these planets are the closest to the sun and comprises of mercury, venus, earth and mars.
These outer planets are made mostly of gases (hydrogen and helium) causing them to be less dense than the solid inner planets. These gases are generally known to be less dense in terms of physical properties.
Oort cloud is also referred to as Opik and it typically comprises of icy pieces of planetesimals (space debris) that spherically surrounds the sun at distances ranging from about 3000 to 100,000 AU.
Hence, the planets and the asteroid belt orbit the Sun in planes, whereas the Oort cloud of comets has a spherical distribution.
DESCRIBE THE REQUIREMENTS OF AN INTERNET CONNECTION?
please tell me the answer
Answer: The basic requirements for connecting to the Internet are a computer device, a working Internet line, and the right modem for that Internet line. In addition, software programs such as Internet browsers, email clients, Usenet clients, and other special applications are needed in order to access the Internet.
Explanation: brainleist pls :)
If I have a sphere rolling on a table with an initial velocity and then it falls off the edge of the table, from this point on it is taken as if my initial velocity were zero, or it starts from the initial velocity that I had before in the table?
Answer:
The initial velocity after leaving the table is the same as it was before leaving the table (nothing is present to produce discontinuties in the velocity).
Before leaving the table the vertical velocity was zero and is zero when it leaves the table.
The horizontal velocity is constant with no forces present to change the velocity.
What is the term for the force that holds protons and neutrons together in the nucleus of
an atom?
a electromagnetism
b. gravity
c. the strong force
d the weak force
A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms. Two hours later, the numbers of the two atoms are equal. The half-life of A is 0.77 hours. What is the half-life of B in hours?
Answer:
Explanation:
Initially no of atoms of A = N₀(A)
Initially no of atoms of B = N₀(B)
5 X N₀(A) = N₀(B)
N = N₀ [tex]e^{-\lambda t}[/tex]
N is no of atoms after time t , λ is decay constant and t is time .
For A
N(A) = N(A)₀ [tex]e^{-\lambda_1 t}[/tex]
For B
N(B) = N(B)₀ [tex]e^{-\lambda_2 t}[/tex]
N(A) = N(B) , for t = 2 h
N(A)₀ [tex]e^{-\lambda_1 t}[/tex] = N(B)₀ [tex]e^{-\lambda_2 t}[/tex]
N(A)₀ [tex]e^{-\lambda_1 t}[/tex] = 5 x N₀(A) [tex]e^{-\lambda_2 t}[/tex]
[tex]e^{-\lambda_1 t}[/tex] = 5 [tex]e^{-\lambda_2 t}[/tex]
[tex]e^{\lambda_2 t}[/tex] = 5 [tex]e^{\lambda_1 t}[/tex]
half life = .693 / λ
For A
.77 = .693 / λ₁
λ₁ = .9 h⁻¹
[tex]e^{\lambda_2 t}[/tex] = 5 [tex]e^{\lambda_1 t}[/tex]
Putting t = 2 h , λ₁ = .9 h⁻¹
[tex]e^{\lambda_2\times 2}[/tex] = 5 [tex]e^{.9\times 2}[/tex]
[tex]e^{\lambda_2\times 2}[/tex] = 30.25
2 x λ₂ = 3.41
λ₂ = 1.7047
Half life of B = .693 / 1.7047
= .4065 hours .
= .41 hours .
The instrument measuring the temperature change between inspired cool air and expired warm air is called?
Answer:
It's called a Spirometer