Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 17. g of hexane is mixed with 101. g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Be sure your answer has the correct number of significant digits.

Answers

Answer 1

Answer:

52g of carbon dioxide

Explanation:

Liquid hexane + gaseous oxygen --> Carbon dioxide + gaseous water

The balance chemical equation is given as;

C6H12 + 9O2 --> 6CO2 + 6H2O

From the stochiometry of the reaction;

1 mol of hexane (86g) would consume 9 mol of oxygen (144g) to form 4 mol of carbon dioxide (264g)

The limiting reactant in this equation is hexane as it would run out before oxygen. This means hexane determines how much of the carbon dioxide is formed.

86g of hexane = 264g of crbon dioxide

17g of hexane = xg of carbon dioxide

x = 17 * 264 / 86 =  52g of carbon dioxide


Related Questions


Which of the following best describes the change in Antarctic temperature from about 440,000 years ago to about 340,000 years ago?
A
The temperature increases by about 10 S
B
The temperature decreases by about 8°C.
С
The temperature increases by about 12°C and then decreases by about 12°C.
D
The temperature decreases by about 10°C and then increases by about 12°C.

Answers

Answer: С . The temperature increases by about 12°C and then decreases by about 12°C.

Explanation:

Temperatures around the world have been on the rise since the Industrial revolution as humans clog the planet with Carbon Dioxide and other pollutants. This had led to a rise in temperatures that has seen ice levels fall and sea levels rise around the world.

Temperature fluctuations on the other hand are not a new thing. Studies show that in Antarctica temperatures from about 440,000 years ago to about 340,000 years ago increased by 12°C and then decreased by about 12°C.

Answer:

  C.  The temperature increases by about 12°C and then decreases by about 12°C.

Explanation:

The attached shows ice core data that indicates the time period of interest was about the period of one full cycle of climate change. Temperature went up, then went down again to about its original level. The range of change was on the order of 12 °C.

What is the percent yield for the reaction below when
705.0 g SO2 and 80.0 g 02 produce 586.0 g S03?
2802(g) + O2(g) → 2503(9)

Answers

Answer:

Percent yield of reaction is 150%.

Explanation:

Given data:

Percent yield = ?

Actual yield of SO₃ = 586.0 g

Mass of SO₂ = 705.0 g

Mass of O₂ = 80.0 g

Solution:

Chemical equation:

2SO₂ + O₂      →     2SO₃

Number of moles of SO₂:

Number of moles = mass/ molar mass

Number of moles = 586.0 g/ 64.1 g/mol

Number of moles = 9.1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 80.0 g/ 32g/mol

Number of moles = 2.5 mol

Now we will compare the mole of SO₃ with O₂ and SO₂.

                      SO₂          :          SO₃

                        2             :            2

                     9.1              :           9.1

                       O₂            :          SO₃

                        1              :            2

                     2.5             :           2×2.5 = 5

The number of moles of SO₃ produced by oxygen are less it will limiting reactant.

Theoretical yield of SO₃:

Mass = number of moles × molar mass

Mass = 5 mol × 80.1 g/mol

Mass = 400.5 g

Percent yield of reaction:

Percent yield = actual yield / theoretical yield  × 100

Percent yield = 586.0 g/ 400.5 g× 100

Percent yield = 1.5× 100

Percent yield = 150%

A hypothesis must be testable. Which hypothesis is testable? *

Ablue is the best color.
BSummer is nicer than fall.
CDogs are better than cats.
DA beagle can jump higher than a Persian cat.

Answers

the answer is D because can be tested the others ones is opinion

please mark me as brainliest

Fill in the blank... spelling counts.

Speed is the ______ something travels divided by the _____ It takes to travel that dinstance.

Answers

Answer:

[tex]speed = \frac{distance}{time}[/tex]

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