Answer:
Beaker
Graduated Cylinders
Volumetric flask
Test tube
Funnel
Which best illustrates projectile motion?
A pictorial diagram showing a hot air balloon in four different positions, each the same height from the ground and equally spaced.
A pictorial diagram with a rocket launched straight upward. The first three positions of the rocket are shown with equal spacing between them.
A pictorial diagram with a person swimming and position shown in equal time intervals and equally spaced.
A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground.
The pictorial diagram with a rocket launched straight upward, showing the first three positions of the rocket with equal spacing between them, best illustrates projectile motion. In this case, the rocket is projected upward into the air, and its path follows a parabolic trajectory due to the influence of gravity.
What is projectile motion?Projectile motion refers to the motion of an object that is thrown, launched or otherwise projected into the air and then moves under the influence of gravity alone. In this type of motion, the object moves along a curved path, called a parabola, due to the combined effect of its initial velocity and the force of gravity acting on it.
When a rocket is launched straight upward, it experiences a projectile motion. The rocket's initial velocity is upwards, but gravity causes it to decelerate until it eventually stops at the highest point of its trajectory. The rocket then starts to fall back down, accelerating due to gravity until it reaches the ground. If we take three equal intervals of time, we can show the rocket's positions at those times. Initially, the rocket will be moving upwards with a decreasing velocity, then it will reach its maximum height before falling back down with an increasing velocity.
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Answer: I believe it should be the final answer,
A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground
Explanation:
Physics Help anyone?
Hi there!
A)
At this point, the pilot is experiencing a DOWNWARD NET centripetal force (ALWAYS points towards the center of the circle) as well as a downward force due to gravity. Additionally, we can say that the normal force exerted by the seat on the pilot is its apparent weight.
[tex]\Sigma F = F_g + F_N[/tex]
**The net force is the centripetal force.
We can assign both to be positive since they work in the same direction. (Assigning down as positive in THIS situation will make things easier).
We know that:
[tex]F_c = \frac{mv^2}{r}[/tex]
Fc = Centripetal force (N)
m = mass (kg)
v = velocity (m/s)
r = radius (m)
[tex]F_g = mg[/tex]
Fg = Force due to gravity (N)
m = mass (kg)
g = acceleration due to gravity (9.81 m/s²)
Solve for mass. (Given weight)
[tex]m = \frac{F_g}{g}\\\\m = \frac{719}{9.8} = 73.367 kg[/tex]
Now, we have everything we need to solve.
[tex]\frac{mv^2}{r} = F_g + F_N \\\\\frac{mv^2}{r} - F_g = F_N\\\\F_N = \frac{(73.367)(225^2)}{3110} - 719 = \boxed{475.278 N}[/tex]
B)
Weightlessness is achieved when the pilot is in free fall. In this instance, FN (Normal force by the seat) = 0 N.
We can use the same setup as above.
[tex]\frac{mv^2}{r} = F_g + 0 (F_N)[/tex]
[tex]\frac{mv^2}{r} = mg[/tex]
Solve for 'v'.
[tex]\frac{v^2}{r} = g\\\\v = \sqrt{gr} = \sqrt{(9.81)(3110)} = \boxed{174.669 \frac{m}{s}}[/tex]
C)
At the BOTTOM, we have the force of gravity working DOWNWARD (Negative in this instance), while the centripetal force (NET FORCE) and normal force are upward (Positive). Do another summation of forces:
[tex]\Sigma F = F_N - F_g\\\\\\frac{mv^2}{r} + F_g = F_N \\\\F_N = \frac{(73.367)(225^2)}{3110} + 719 = \boxed{1913.278 N}[/tex]
A proton in the nucleus of an atom has an electrical charge of:
neutral
-
+
zero
Answer:
proton is positively charged changechar
Explanation:
you move a 25 N object 5.0 meters. how much work did you do?
Answer:
125J
Explanation:
[tex]work \: = force \: \times distance \\ = 25 \times 5 \\ = 125joules[/tex]
How long does it take a photon to escape the sun?
Answer:
About 5000 years.
Explanation:
Answer:
Explanation:
it will take more than half a million years for the photon to escape the sun. If you think it's about a centimeter, then it will take about 5,000 years for the photon to get outside the su
what are the four things that affect the resistance of a wire? A. length, diameter, material, and temperature B. weight, diameter, material, and temperature C. length, height, material, temperature D. length, weight, material, and temperature
Answer:
A. length, diameter, material, temperature
An eletrical conductor is a material that allows _____ to travel through it freely
Answer:
it allows electric charges to travel through freely
a 56-kg student runs at 6.2m/s, grabs a hanging 10.0m long rope, and swings out over a lake. He releases the rope when his velocity is zero.
a) what is the tension in the rope just before he releases it?
b) what is the maximum tension in the rope during the swing?
Answer:
0.52 8.9
Explanation:
calc.
The tension in the rope just before the student releases it is 576 N.
What is tension?Tension is defined in physics as the pulling force transmitted axially by a string, rope, chain, or similar object.
Just before the student releases the rope, his velocity is zero. At this point, all of his kinetic energy has been converted into potential energy. Therefore, we can write:
1/2 m [tex]v^2[/tex] = mgh
h = [tex]v^2[/tex] / (2g) = [tex](6.2 m/s)^2[/tex] / (2 x 9.8 [tex]m/s^2[/tex]) ≈ 1.95 m
m g = 56 kg x 9.8 [tex]m/s^2[/tex] ≈ 549 N
The tension required to keep the rope taut is equal to the horizontal component of the force due to the weight of the student, which is:
T = m g / cos(θ)
tan(θ) = h / L
tan(θ) = 1.95 m / 10.0 m ≈ 0.195
θ ≈ 10.9°
So, T = m g / cos(θ) ≈ 576 N
To find the maximum tension in the rope during the swing, we can use conservation of angular momentum.
L = I ω
I = (1/3) m [tex]L^2[/tex]
I = (1/3) x 10.0 kg x [tex](10.0 m)^2[/tex] ≈ 3333.3 kg[tex]m^2[/tex]
The angular velocity of the rope just after the student releases it is:
ω = v / L
ω = 6.2 m/s / 10.0 m ≈ 0.62 rad/s
L = I ω ≈ 2070 N m s
Thus, the angular momentum of the system just after the student releases the rope is 2070 N m s.
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please answer this question
Answer:
The circuits that were made previously were large and bulky, consisting of circuit components like resistor, capacitor, inductor, transistor, diodes, etc., which were connected with copper wires.
Explanation:
I am in confusion with mono electronic circuit and I am not want to made u confused person.
I am really sorry brother.
:-befrank
Which property of matter is conserved in chemical reactions and shown by balanced equations?
O mass
O volume
O density
O shape
Answer:
Mass.
Explanation:
I took the quiz and got the answer right
above
3. DIRECTIONS: Read the following two statements carefully and choose the correct options.
Statement 1: In a room containing air, heat can go from one place to another by radiation only.
Statement 2: In convection, heat is transferred from one place to other by actual motion of the
molecules in the heated material.
A) Statement (1) is correct while statement (2) is incorrect.
B) Statement (2) is correct while statement (1) is incorrect.
C) Both statements are correct
D) Both statements are incorrect.
The maximum kinetic energy of electrons ejected from a sheet of uranium exposed to 250 nm ultraviolet light is 1.33 EV.
What is the work function of the uranium metal? (Planck's constant (h) is 6.626 × 10-34 J∙s, c is 3.0 × 108 m/s, 1 eV = 1.6 × 10-19 J)
Answer: The maximum kinetic energy KEe of ejected electrons (photoelectrons) is given by KEe = hf − BE, where hf is the photon energy and BE is the binding energy (or work function) of the electron to the particular material.
Explanation:
The work function of the uranium metal will be given by the value 7.9*10^-19
What is work function?The work function of a particle is defined as the product of the planks constant to the frequency of the particle.
[tex]\phi=h\times f[/tex]
Now the frequency will be given as
[tex]f=\dfrac{c}{\lambda}[/tex]
So the formula will become
[tex]\phi=\dfrac{hc}{\lambda}[/tex]
h=6.626 × 10-34 J∙s
c=3.0 × 108 m/s
[tex]\lambda[/tex] = 250 nm 250* 10^-9
[tex]\phi=\dfrac{6.626\times 10^{-26}\times3\times 10^{8}}{250\times 10^{-9}}[/tex]
[tex]\phi=7.9\times 10^{-19}[/tex]
Hence the work function of the uranium metal will be given by the value 7.9*10^-19
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What are your ideas about how humans can reduce the amount of carbon dioxide and methane they add to the atmosphere?
Answer:
Find the heavy processes of CO2 and methane.
Explanation:
Step #1 Find a very reliable energy source.
Step #2 Find the heavy processes of CO2 and methane like in many factories and places with high carbon emissions.
Step #3 Shut down each of the heavy processes even 10 per day would do a lot.
Step #4 Use the renewable energy source as a replacement for the attempts to generate energy using carbon emissions.
Question 5 of 10
Which of the following is most likely to happen when energy is transferred to
an object?
O A. The force on the object will decrease.
O B. The object will begin to move.
O C. The object will stay exactly the same.
O D. The mass of the object will increase.
Answer:
B: The object will start moving
Explanation:
If energy is transferred the object will definitely change so it can't be a. If you add energy the object will have more force so it cant be c. The mass of an object can't increase just by giving an object energy so it cant be d
determine if a sentence is an argument?
Answer:
The tone really matters and if there are any exclamation marks also.
Explanation:
A 7500 kg truck is speeding up at 5 m/s down a 1000m on-ramp to the highway.
What is the force exerted on the truck?
Answer:
37500 N
Explanation:
F = ma
F = 7500 (5 m/s^2) = 37500 N
Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true? (1 point)
O Waves that make up the radiation collide with each other so that they add together or cancel each other out.
O Particles that make up the radiation collide with each other so that they add together or cancel each other out.
O Particles that make up the radiation collide with each other and scatter randomly.
O Waves that make up the radiation do not interact with each other.
Waves that make up the radiation collide with each other so that they add together or cancel each other out.
What is Interference?This is the phenomenon which occurs when two waves meet while traveling along the same medium.
In the double-slit test experiment, bright and dark fringes was observed which was caused by the superposition of overlapping light waves originating from the two slits which is why option A was chosen as the most appropriate choice.
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3. Use the information about acceleration shown in Figure 2 as evidence to determine the magnitude of the net force acting on the scooter.
a. The net force from t = 1 to t = 6 s is 112 N
b. The net force from t = 7 to t = 12 s is 0 N
ForceForce is that thing which causes a change in motion of an object. The net force is given mathematically as F = ma where
m = mass of object and a = acceleration of objectNet forceThis is the resultant sum of all the forces acting on an object. It is also given by F = ma where
m = mass of object and a = net acceleration of objecta. Net force from t = 1 to t = 6 sThe net force from t = 1 to t = 6 s is 112 N
From the table from time t = 1 to t = 6 s, the acceleration a = 1.4 m/s². Since m = 80 kg,
F = ma
= 80 kg × 1.4 m/s²
= 112 kgm/s²
= 112 N
So, the net force from t = 1 to t = 6 s is 112 N
b. Net force from t = 7 to 12 sThe net force from t = 7 to t = 12 s is 0 N
From the table from t = 7 to t = 12 s, the acceleration a = 0 m/s²
Since m = 80 kg,
F = ma
= 80 kg × 0 m/s²
= 0 kgm/s²
= 0 N
So, the net force from t = 7 to t = 12 s is 0 N
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A standing wave of the third overtone is induced in a stopped pipe, 3 m long. The speed of sound is 340 m/s. The number of antinodes in the standing wave pattern is:
Answer:
overtone- one over the first
n skips by twos
4 antinodes
500 Hz
Explanation: Hope this helps :)
3. Hahn determined that barium (atomic number 56) was one of the elements created when a uranium atom (atomic number 92) split . Use a periodic table to determine the other element that was created during this process.
According to a periodic table, Krypton was created during the fission of Uranium.
What is the atomic number?
Atomic number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.
Thus, the fission of uranium is led by two elements with atomic numbers 56 and 36. According to a periodic table, those atomic numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.
According to a periodic table, Krypton was created during the fission of Uranium. [tex]\blacksquare[/tex]
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A cosmic ray photon is bombarding a massive object to pieces. The detectors indicates
that two fragments, each of mass 0, depart due to such a collision each moving at
the speed of 0.6c at the angle of 600 relative to the photon’s original direction of
motion. What is the energy of the cosmic ray photon in terms 0 and c ?
Answer:
Chapter 1
1. Show that the Lorentz transformation is such that the velocity of a light ray
travelling in the x direction is the same for the observer in the frame S and for
the observer in the frame S
.
Solution: Consider a light ray travelling in the x direction. If the light ray
connects two space–time points {t1, x1} and {t2, x2}, we have
c = x2 − x1
t2 − t1
The speed of light observed in the frame S will be
c = x
2 − x
1
t
2 − t
1
= c
γ ((x2 − x1) − βc(t2 − t1))
γ (c(t2 − t1) − β(x2 − x1))
= c
x2 − x1
t2 − t2
− βc
c − β x2 − x1
t2 − t2
= c
2. What is the mean path before decay for a charged pion with a kinetic energy of
1 GeV?
Solution: The pion has a lifetime 2.6 × 10–8 s and a mass of 139.6 MeV. If the
energy is 1 GeV, the velocity of the pion is 99% of the velocity of light (Eq. 1.4).
The mean path before decay is
= 0.99 c γ τ
= 0.99 c
1000 + 139.6
139.6
2.6 10−8 = 63 m
S. Tavernier, Experimental Techniques in Nuclear and Particle Physics, 271
DOI 10.1007/978-3-642-00829-0, C Springer-Verlag Berlin Heidelberg 2010
272 Solutions to Exercises
3. Show that the relativistic expression for the kinetic energy of a particle (Eq. 1.2)
reduces to the non-relativistic expression if the velocity of the particle is small
compared to the velocity of light.
Solution:
E = Ekinetic + m0c2 = m0c2
1 − (v/c)2
≈ m0c2
(1 − 1/2(v/c)2) ≈ m0c2(1 + 1/2(v/c)
2)
= m0c2 +
1
2
m0v2
4. For a Poisson distribution with average value 16, calculate the probability to
observe 12, 16 and 20 as measured value. Calculate the probability density function for a Gaussian distribution with average value 16 and dispersion 4, for the
values x = 12, 16 and 20. Compare the results.
Solution: For a Poisson distribution P(12) = 0.0829, P(16) = 0.1024, P(20) =
0.0418
For a Gaussian distribution, f(12) = 0.0605, f(16) = 0.0997, f(20) = 0.0605
5. Consider a very short-lived particle of mass M decaying into two long-lived particles 1 and 2. Assume you can measure accurately the energies and momenta of
the two long-lived particles. How will you calculate the mass of the short-lived
particle from the known energies and momenta of the two long-lived objects?
Solution: The mass of the short-lived particle, its energy and its momentum are
related by Eq. (1.1). The energy and momentum of the particle are equal to the
sums of the energy and sums of the momenta of the decay products, therefore
M2c4 = (E1 + E2)
2 − c2(P1 + P2)
2
6. Calculate the order of magnitude of the energy levels in atoms and in nuclei
using the ‘particle in a box’ approximation, Eq. (1.9). Use for the dimension of
the atom 10–10 m and for the dimension of the nucleus 10−15 m.
Solution: Atomic energy levels: ≈40 eV; nuclear energy levels: ≈400 MeV.
7 . Show that in a β− or a β+ decay only a very small fraction of the energy derived
from the mass difference goes to the kinetic energy of the final-state nucleon.
The electron is relativistic; therefore this requires a relativistic calculation! Hint:
the 3-body problem can be reduced to a 2-body problem by considering the
electron–neutrino system as one object with a mass of a few MeV.
Solution. Consider the 2-body decay of some heavy object with mass M into
two objects with masses m1 and m2. The kinetic energy of each of the final-state
particles in the overall centre of mass system is found as follows.
Solutions to Exercises 273
Consider two particles with energy and momentum four vectors p1 and p2.
The symbol pi stands for the four-vector {Ei,cpi}. The energy E appearing in this
expression is the total energy E, i.e. the rest energy mc2 plus the kinetic energy.
The four-vector product (p1.p2) is defined as
(p1.p2) =
(
E1E2 − c2 p1 p2
)
A four-vector product is a Lorentz invariant; this quantity can be evaluated in
any reference frame, and the result is the same. Consider now the quantity
(p1.p2)
m1c2
This is a Lorentz invariant. Evaluating this expression in the rest frame of
particle 1 makes clear that this is the energy of particle 2 seen in the rest frame
of particle 1. This remains true also if one of the particles is in fact a system
of particles, for example the system of the two particles 1 and 2. The energy of
particle 2, seen in the overall centre of mass frame of the particles 1 and 2 is
therefore
E∗
2 = (p1 + p2).p2
(p1 + p2)2
We have the following relations:
(p1 + p2)
2 = M2c4
(p1.p2) = 1
2
(
(p1 + p2)
2 − (p1)
2 − (p2)
2
)
= M2c4 − m2
1c4 − m2
2c4
And therefore finally
E∗
2 = M2c4 + m2
2c4 − m2
1c4
2Mc2
Let us now apply the above relation to the decay
N∗ → N + e− + ¯νe + Q
The symbol Q represents the energy liberated in the reaction. Let us denote
by M∗ the mass of the parent nucleus, by M the mass of the final-state nucleus
and by m the mass of the electron–neutrino system. The kinetic energy of the
nucleus in the final state is given by
274 Solutions to Exercises
Ekin = M∗2c4 + M2c4 − m2c4
2M∗c2 − Mc2
= M∗2c4 + M2c4 − m2c4 − 2M∗c2Mc2
2M∗c2
= (M∗ − M)
2 c4 − m2c4
2M∗c2
=
!
mc2 + Q
The energy of the cosmic ray photon is zero. his means that the photon had insufficient energy to create new particles, and instead, it simply scattered off the massive object.
What is Einstein's energy equation?Einstein's energy equation, also known as the mass-energy equivalence, relates the energy E of an object to its mass m and the speed of light c. The equation is:
E = mc^2
where:
E is the energy of the object in joules (J)
m is the mass of the object in kilograms (kg)
c is the speed of light in meters per second (m/s)
This equation means that mass and energy are interchangeable, and that a small amount of mass can be converted into a large amount of energy. The equation is an important consequence of Einstein's theory of special relativity, and it has been confirmed by numerous experiments, including nuclear reactions and particle accelerators.
Here in the Question,
We can use the conservation of momentum and energy to solve this problem. Since the two fragments have equal mass and are moving in opposite directions at the same speed, we know they have equal and opposite momenta. Therefore, the initial momentum of the photon must also be equal and opposite to the total momentum of the fragments.
Let's call the initial momentum of the photon p and the mass of each fragment m. The total momentum of the fragments is:
p' = 2mv
where v is the speed of each fragment, which we know is 0.6c. Therefore, we can write:
p' = 2m(0.6c) = 1.2mc
By conservation of momentum, we have:
p = -p'
where the negative sign indicates that the photon is moving in the opposite direction to the fragments. Therefore:
p = -1.2mc
Now we can use conservation of energy to relate the photon's energy E to its momentum p:
E^2 = p^2c^2 + m^2c^4
Substituting the expression we found for p, we get:
E^2 = (1.2mc)^2c^2 + m^2c^4
E^2 = 1.44m^2c^4 + m^2c^4
E^2 = 1.45m^2c^4
Solving for E, we get:
E = mc^2 * sqrt(1.45)
Plugging in the values for m and c, we get:
E = (0 * 9.0 × 10^16 kg) * sqrt(1.45) = 0
Therefore, The photon from a cosmic ray has no energy. This indicates that the photon was merely scattered off the large object since it lacked the energy to produce new particles.
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Can a machine multiply both force and speed at same time??
Answer:
No
Explanation:
It is not possible for a machine to act as a force multiplier and speed multiplier simultaneously. This is because machines which are force multipliers cannot gain in speed and vice-versa.
It is not possible for a machine to act as a force multiplier and speed multiplier simultaneously. This is because machines which are force multipliers cannot gain in speed and vice-versa.
What is created when an object travels faster than the speed of sound
Answer:
Explanation:
Answer: Sonic Boom.
When the object reaches the speed of sound, air cannot readily move out of the way and a shock wave is formed. When the object is moving faster than sound, the resulting sounds travel behind the object, creating a sonic boom.
a 50 kg boy runs at 3 m/s. how much momentum does he have
Answer:
150 kg-m/s
Explanation:
momentum = m * v
50 * 3 = 150
An audio compact disk (CD) has a playing time of 55 minutes. When the music starts, the CD is
rotating at an angular speed of 480 revolutions per minute (rpm) and during the playback the
rotation slows down. The average angular acceleration of the CD is a = -4.0 rev/min . Find the
angular speed at which the CD is rotating at the end of the music. Express your answer both in
rev/min and also in rad/s.
Select one:
27.2 rad/s
220 rad/s
120 rad/s
260 rad/s
22 rad/s
Answer:
See below
Explanation:
-4 rev / min^2 * 55 min = - 220 rev/ min
480 - 220 = 260 rev/min at end
2pi radians /rev * 260 rev/min = 1633.6 Radians/min
At the end of the music, the angular speed of the C.D. would be (d) 260 rev/minute and 1633.6 rad/minute
To calculate angular speed following information is given in the question:
The angular speed (ω) of the C.D. at starting = 480 revolutions/minuteThe playing time (t) of the C.D. is = 55 minutesThe angular acceleration (α) of the C.D. = -4 rev/[tex]min^{-2}[/tex] Angular speed of the C.D. at the end of the music will be = α*tAngular speed of the C.D. at the end of the music will be = 4 rev/[tex]min^{-2}[/tex] *55 min = -220 rev/minAt the end of the music angular speed = 480-220 rev/min = 260 rev/minValue of angular speed in rad/sec = 2π radians/rev*260 rev/min = 1633.6 Radians/minHence, option (d) is correct which states that the angular speed is 260 rev/min and 1633.6 radians/min.
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When is an object positively charged?
Answer:
when it has a fewer amount of electrons than protons
Find the Product or expression of:
(6x+4)2
Answer:
20 or 12
Explanation:
if it is 20 u will have to multiple 6 by 4 and the answer u will multiple it by2 and when it is 12 u will have to add 6 +4 and the answer u will add it to 2
A rod is 4.0 m long and has a square cross-section that is 1.5 cm on each side. An ohmmeter measures 0.040 Ω across its ends. What is the resistivity of the material from which this rod is made?
Answer:
2.25 x 10^-6 ohm - m 2.25 x 10^-4 ohm - cm
Explanation:
rho = R A/l
R = .040
A = .015 * .015 m^2
l = 4 rho =
Many U.S. college freshman say that "being well-off" financially is an essential life goal and that "making more money" was a very important factor in their decision to attend college. According to Abram Maslow, which meta-needs are being fulfilled by "making more money"?
Based on research by Abraham Maslow, the meta-needs which are fulfilled by "making more money" are none of the meta-needs.
What are meta-needs?According to Abraham Maslow, meta-needs are human needs that relate to beauty, knowledge and creativity.
All of these can be met without having to make more money so it stands to reason that there are no meta-needs that can be met by making more money.
The main need that is met by making more money according to Maslow is Security and it is not a meta-need.
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When a speeding truck hits a stationary car, the car is deformed and heat is generated. What can you say about the kinetic energy of the system after the collision?
nothing
Explanation:
we can say that it was certainly bad for the shopkeeper obviously and we should not be making questions about the physics behind that accident and should call the cops or 911