Look at each Lewis Dot Diagram for the following elements. How many electrons are needed to fill the outer shell?

Answer:

Mass to moles: mass/molar mass=mole

Moles to mass: moles x molar mass = mass

Moles to particles:1mole = 6.022x10^23 particles

Particles to moles: 1 particle =1/(6.022x10^23) mole

Explanation:

Question: Calculate the mass of magnesium chloride you would need to dissolve in 4dm³ of water to

make a 0.9g/dm³ solution.

Answer:

3.6 g

Explanation:

From the question,

Density of magnesium (D) = Mass of magnesium (m)/Volume of magnesium(V)

D = m/V............... Equation 1

Make m the subject of the equation

m = D×V............. Equation 2

Given: D = 0.9 g/dm³, v = 4 dm³

Substitute these values into equation 2

m = 0.9×4

m = 3.6 g.

Hence the mass of magnesium is 3.6 g.

Answer:

The plateaus or horizontal lines on the graph represent the transition between states of the sample. The first plateau represents the melting (or transition from solid to liquid) and the second plateau represents boiling (or transition from liquid to gas).

Explanation:

Answer:

HI and I-

Explanation:

Hello there!

In this case, according to the acid ionization of hydroiodic acid:

[tex]HI+H_2O\rightarrow I^-+H_3O^+[/tex]

Now, since the acid, HI, results in the conjugate base, I- and the base, H2O in the conjugate acid, H3O+, it is correct to assert that the acid-conjugate base pair is HI and I-

Best regards!

The acid-conjugate base pair in the reaction above is HI and I-. Details about conjugate base can be found below.

A conjugate base is the substance formed when an acid loses or donates its proton or hydrogen ion.

According to this question, the following reaction is given:

HI + H2O → H30+ + I-

The acid in this reaction is HI while the conjugate base is I-.

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One mole of NaOH = 40g NaOH

One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in water

One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in wateraccording to the given data,

One mole of NaOH = 40g NaOHso to prepare 1M NaOH we need to dissolve 40g NaOH in wateraccording to the given data,we have 6 moles of NaOH so we need 6 litres of Water olto prepare 1M Solution

Answer:

14.2 L H2S

Explanation:

Mole ratio

2 mol H2S:2 mol SO2

We are just looking for volume, so the required amount is the same as the produced amount as long as the mole ratio is balanced.

The balanced equation is: 2H2S + 3O2 → 2SO2 + 2H2O. Mole ratio 2 mol H2S:2 mol SO2.

Two factors can be used to identify stoichiometry problems:  the information provided in the problem and  he information that needs to be solved for, also known as the unknown.

The given and the unknown might both be reactants, could both be products, or could both be products with one of them acting as a reactant. Mole amounts can be used to express the substance quantities.

However, it is typical in a laboratory setting to calculate a substance's mass in grams to determine how much of it is present. A gaseous substance's volume can be used to express its quantity.

Therefore, The balanced equation is: 2H2S + 3O2 → 2SO2 + 2H2O. Mole ratio 2 mol H2S:2 mol SO2.

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A single proton has the charge of +1.

A neutron is neutral and has a charge of 0

A single electron has the charge of -1

Since the nucleus contains both protons and neutrons, with neutrons have charge of 0 and protons with +1, the total charge of the nucleus would be 25 * 1 which is +25.

Answer:

25+

Explanation:

25+  = the number of protons in the nucleus

Answer:

n = 0.223 mol.

Explanation:

Hello there!

In this case, according to the given information, it is possible for us to approach this problem via the ideal gas law, which involves the pressure, moles, temperature and volume of the gas:

[tex]PV=nRT\\\\[/tex]

Thus, by solving for moles we obtain:

[tex]n=\frac{PV}{RT}[/tex]

Therefore, we plug in the given volume, temperature (in Kelvins) and pressure to obtain:

[tex]n=\frac{0.9atm*8L}{0.08206\frac{atm*L}{mol*K}*(120+273)K} \\\\n=0.223mol[/tex]

Best regards!

It would be 2.515 yards. This is because to convert cm into yards, you would need to divide the length value by 91.44 so in your case, it would be 230÷ 91.44 which equals 2.51531.

Hope that helps!

Answer:

The volume at STP is 41.3mL

Explanation:

To solve this question we must find the volume using the combined gas law. The equation is:

P1V1 / T1 = P2V2 / T2

Where P is pressure, V volume and T absolute temperature of 1, initial state and 2, final state of the gas.

P1 = 718torr

V1 = 47.9mL

T1 = 26°C + 273.15 = 299.15K

P2 = 760torr at STP

V2 = ?

T2 = 273.15K at STP

Replacing:

718torr*47.9mL / 299.15K = 760torr*V2 / 273.15K

41.3mL = V2

Answer:

Liquid water  

Answer:

lol global warming is the gradual increase in the temperature of the earth and its atmosphere. this is do to the greenhouse effect caused by increased levels of carbon dioxide.

Explanation:

common knowledge

Answer:

143 parts I think probably not

Answer: The density of kerosene is [tex]2.7g/cm^3[/tex]

Explanation:

Density is defined as the mass contained per unit volume.

[tex]Density=\frac{mass}{Volume}[/tex]

Given : Mass of kerosene = mass of beaker with kerosene - mass of empty beaker = 60 g - 20 g = 40 g

Volume of kersone = [tex]15cm^3[/tex]

Putting in the values we get:

[tex]Density=\frac{40g}{15cm^3}[/tex]

[tex]Density=2.7g/cm^3[/tex]  

Thus the density of kerosene is [tex]2.7g/cm^3[/tex]

Answer:

3.33L

Explanation:

Answer:

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Answer:

uhh the Neutron i guess lol you didn't give any choices or explanation

Explanation:

Answer:

Explanation: b

Answer:

Deletion

Explanation:

A mutation refers to a change in the DNA sequence. This means that the original sequence of bases in the DNA has been altered permanently.

There are three types of DNA mutations;  base substitutions, deletions and insertions.

In the particular case of this question, the original is TTCGATA while the copy is TTGATA. If you look closely at the two, you will notice that the C has been omitted. This is an example of  deletion.

Answer:

Nerve or muscle damage in the eye might cause double vision. Each eye creates its own image of the environment. The brain combines the representations from each eye and perceives them as one clear picture. Damage to the muscles that move the eyes or the nerves that control eye movement can create a double image.

Explanation:

Answer:

True

Explanation:

Answer:

1.08827 x 10^3 g.

Explanation:

The equation for the reaction is:

2LiOH + CO2  ---->  Li2CO3 +  H2O

Using the molar masses:

CO2 = 12.011 + 2* 16 = 44.011.

LiOH = 6.94 + 1.008 + 16 = 23.948

S0 44.011 of CO2 reacts with  2*23.948 g of LiOH

1.00 *10^3 g CO2 reacts  with   2*23.948 * 1.00 *10^3 / 44.011

= 1088.27 g LiOH.

Explanation: the answer plant seeds

not skin

Answer:

Beryllium metal is relatively unreactive at room temperature, particularly in its massive form. Magnesium is more electropositive than the amphoteric beryllium and reacts more readily with most of the nonmetals.

Explanation:

When it comes to the ease with which a positive ion or cation of the metal can form, beryllium is less reactive than magnesium.

The chemical element magnesium has the atomic number 12 and the letter Mg as its symbol. It is a glossy, gray metal with a low melting point, high chemical reactivity, and a low density. It only naturally occurs in mixtures with other elements, just like the other alkaline earth metals, and it almost always has an oxidation state of +2.

At room temperature, beryllium metal is largely non-reactive, especially in its massive form. Magnesium interacts more quickly with the majority of nonmetals because it is more electropositive than amphoteric beryllium.

Due to the electron being removed being in the 3-level rather than the 2-level and being further away from the nucleus's attraction, the first ionization energy of magnesium is lower than that of beryllium.

Thus, When it comes to the ease with which a positive ion or cation of the metal can form, beryllium is less reactive than magnesium.

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Answer: The new pressure of the balloon is 108 kPa

Explanation:

The combined gas equation is,

[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

where,

[tex]P_1[/tex] = initial pressure of gas = 105 kPa

[tex]P_2[/tex] = final pressure of gas = ?

[tex]V_1[/tex] = initial volume of gas = 2510000 L

[tex]V_2[/tex] = final volume of gas = 2600000 L

[tex]T_1[/tex] = initial temperature of gas = [tex]122^0C=(122+273)K=395K[/tex]

[tex]T_2[/tex] = final temperature of gas = [tex]150^0C=(150+273)K=423K[/tex]

Now put all the given values in the above equation, we get:

[tex]\frac{105\times 2510000}{395}=\frac{P_2\times 2600000}{423}[/tex]

[tex]P_2=108kPa[/tex]

The new pressure of the balloon is 108 kPa