Look at the graph. Which part of the line shows a time
when the object was not moving?

Answer:

A) antigens present on the invaders

Explanation:

Antigens are substances (usually proteins) on the surface of cells, viruses, fungi, or bacteria. Nonliving substances such as toxins, chemicals, drugs, and foreign particles (such as a splinter) can also be antigens. The immune system recognizes and destroys, or tries to destroy, substances that contain antigens

Answer:d

Explanation:

Answer:

706 L

Explanation:

P1V1 = P2 V2 3 atm 250.0 mL = 1 atm X

T1 T2 290 K 273 K

706 mL = X

magnets attract everything with metal inside of it

Answer: magnets attract everything with metal inside of it

Explanation:

The mass percentage of sugar in the sweet tea is 10%

From the question,

We are to determine the mass percentage of sugar in the sweet tea

[tex]Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{Mass\ of\ sugar\ in\ the\ solution}{Mass\ of\ the\ solution} \times 100\%[/tex]

Mass of sugar in the solution = 20 g

Mass of the solution = 20g + 180g = 200g

[tex]Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{20}{200} \times 100\%[/tex]

[tex]Mass\ percentage\ of\ sugar\ in\ the\ sweet\ tea = \frac{20}{2} \%[/tex]

∴ Mass percentage of sugar in the sweet tea = 10%

Hence, the mass percentage of sugar in the sweet tea is 10%

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The part of the chemical reaction that is the Brønsted-Lowry base is BrO.

Bronsted-Lowry definition of a base and acid is as follows:

According to this question, the following chemical reaction is given:

BrO + H2CO3 → HCO3 + BrOH

In the above reaction, BrO is the compound that accepts the hydrogen ion (H+) to become BrOH, hence, BrO is the Bronsted-Lowry base.

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Answer: the formula is NO

Answer:

Any substance that cannot be decomposed into simpler substances by ordinary chemical processes.

Another definition:

An element is the simplest pure substance which can neither be split nor built up from other simpler substances by chemical reaction

Answer:

About 0.53 g of carbon dioxide needs to be added.

Explanation:

Recall the ideal gas law:

[tex]\displaystyle PV = n RT[/tex]

To determine the amount of carbon dioxide we need, we need to solve for n:

[tex]\displaystyle n = \frac{PV}{RT}[/tex]

Recall that P, V, and T are in atm, L, and K, respectively. R is the universal gas constant.

Convert all values into the correct units:

Volume:

[tex]\displaystyle 250\text{ mL } \cdot \frac{1 \text{ L}}{1000 \text{ mL}} = 0.25 \text{ L}[/tex]

Temperature:

[tex]\displaystyle \begin{aligned} K & =( ^\circ C) + 273.15 \\ \\ & = (-24) + (273.15) \\ \\ & = 249 \text{ K}\end{aligned}[/tex]

And pressure:

[tex]\displaystyle 95 \text{ kPa} \cdot \frac{1.00 \text{ atm}}{101.3 \text{ kPa}} = 0.94 \text{ atm}[/tex]

Substitute and evaluate:

[tex]\displaystyle\begin{aligned} n & = \frac{\left(0.94 \text{ atm}\right)\left(0.25 \text{ L}\right)}{\left(\dfrac{0.08206 \text{ L-atm}}{\text{mol-K}}\right)\left(249\text{ K}\right)} \\ \\ & = 0.012 \text{ mol CO$_2$}\end{aligned}[/tex]

Convert moles to grams:

[tex]\displaystyle 0.012 \text{ mol CO$_2$} \cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} = 0.53 \text{ g CO$_2$}[/tex]

In conclusion, about 0.53 g of carbon dioxide needs to be added.

The enthalpy of this reaction is -296. 8 kJ/mol.

The equation of the reaction is;

S(s) + O2(g) -----> SO2(g)

Recall that the enthalpy of the reaction can be obtained from the formula;

ΔHrxn = ΔHf(products) - ΔHf(reactants)

We know that;

ΔHf S(s) = 0 KJ/mol

ΔHf O2(g) =  0 KJ/mol

ΔHf SO2(g) = -296. 8 kJ/mol

Hence;

ΔHrxn =  -296. 8 kJ/mol - [0 KJ/mol + 0 KJ/mol]

ΔHrxn = -296. 8 kJ/mol

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Using thermodynamics

[tex]\\ \sf\longmapsto Q=mc∆T[/tex]

[tex]\\ \sf\longmapsto Q=0.015(328)(4184)[/tex]

[tex]\\ \sf\longmapsto Q=20585.28J[/tex]

Answer:

SORRY IM LATE! at least i saw it.

Explanation:

Kingdom is Eucaryota

domain is eucarya

A wave with a smaller wavelength has UV radiation energy than one with a larger wavelength.

Uses of UV Rays

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Answer:

Explanation:

This is just a ratio question. Factor of increase = 27.2 / 3.20 = 8.50

Answer:

Ok the poprtion would look like this :  x                   23  

                                                          -----------   =     ----------

                                                            230                 100

Explanation:

So for the last fill in it could be 52.9 or 60

i hope i got it correct lol pretty sure i did

Answer:

In the Lewis structure for IF5 you'll need to put a total of 12 valence electrons on the Iodine atom in order to draw the Lewis structure. Remember that Iodine (I) can hold more than eight valence electrons. For the IF5 Lewis structure, calculate the total number of valence electrons for the IF5 molecule

Explanation:

I be knowing hope this helps

Answer:

1. the nail which is kept immersed in Sodium Chloride solution

2.

Explanation:

Explanation:

At the upper left is the atomic number, or number of protons. In the middle is the letter symbol for the element (e.g., H). Below is the relative atomic mass, as calculated for the isotopes found naturally on Earth. At the very bottom is the name of the element (e.g., hydrogen).

When 1-bromo propane is reacted with sodium metal, the propane and sodium bromide are formed.

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Explanation:

P1. V1/T1 = P2. V2/T2

Apply this

since here, P1 = P2

100 ml / 300 = V2/ 200

==> 100*200/300 = V2

===> V2 = 66.66 ml

Answer:

Pulley

Explanation:

You can't the piano up the stairs, you need to something to bring it up

To find the force,

 ⇒ must know the force's formula ⇒ F = MA

Let's consider the information given:

Let's solve:

  [tex]F=MA=0.025kg*5m/s^2=0.125N[/tex]

Thus the force is 0.125N

Answer: 0.125N

Hope that helps!

Answer:

Why does increasing the flow rate reduce the contribution of longitudinal diffusion to total plate height? Increasing the flow rate decreases the time the solute resides in the column, resulting in less diffusional broadening.

Explanation:

Br and As:

Bromine is more reactive as reactivity increases on moving from left to right in p-block

A graduated cylinder

_________________

o0o0o0o0o0o0o0o0o0

Answer:

1. gold and rust

2. carbon dioxide

3. sea water

4. carbon

Answer:

1. Gold and Iron

2. Helium

3. Seawater

4.Rust

Explanation: