Look at the system of equations shown in the graph. What is the solution to the system?
Answers
Solution
A solution to a system of linear equations is the point of intersection of both lines when graphed.
Parallel lines do not ever cross so there are zero solutions.
However, there could be a chance that there is a solution because often, the equation of two lines that look parallel are actually the same line, in which case the system will produce an infinite number of solutions.
The way to be sure is just to pick an x value randomly and put it in both equations and see if the answers are equal. If it is really two parallel lines, they will not be equal otherwise, they will be equal.
Hence from the graph, we will first get the equation for both lines
Line 1
[tex]\begin{gathered} y_2=-4 \\ y_1=2 \\ x_2=0 \\ x_1=-2 \\ \text{Hence the equation of the line is given as} \\ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)_{} \end{gathered}[/tex][tex]\begin{gathered} y\text{ -(2)=}\frac{-4-(2)_{}}{0-(-2)}(x-(-2)) \\ y-2=\frac{-6}{2}(x+2) \\ y-2\text{ = -3x}-6 \\ y\text{ = -3x -}6+2 \\ y\text{ = -3x-4} \end{gathered}[/tex]For line 2
[tex]\begin{gathered} y_1=4 \\ y_2=\text{ 1} \\ x_2=0 \\ x_1=-1 \\ \text{The equation of the line is} \\ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ \text{After susbstitution} \\ y\text{ -4=}\frac{1-4}{0-(-1)}(x-(-1)) \\ y-4\text{ = }\frac{-3}{1}(x+1) \\ y-4=-3x-3 \\ y\text{ = -3x-3+4} \\ y\text{ = -3x+1} \end{gathered}[/tex]So picking a random value of x= -1
we will have
[tex]\begin{gathered} \text{Line 1} \\ y\text{ = -3(-1)-4} \\ y=3-4 \\ y\text{ = -1} \\ \text{Line 2} \\ y\text{ = -3(-1)+1} \\ y=\text{ 3+1} \\ y\text{ =4} \end{gathered}[/tex]Since both values of y using a constant random value of x gives us different answers, the lines, therefore, are not images of each other and the system has no solution.
Final answer------ No solution
Related Questions
writw the equation of the root 8, 1/-2
Answers
Concept
To write an equation for given roots, let x variable represent the solutions
Therefore,
x = 8 and x = -1/2
x - 8 = 0 and x + 1/2 = 0
x - 8 and x + 1/2 are factors.
[tex]\text{Next, multiply the two factors, then equate it to zero.}[/tex]Next, multiply the two roots to find the equation.
[tex]\begin{gathered} (x\text{ - 8) x (x + }\frac{1}{2}\text{ ) = 0} \\ x^2\text{ + }\frac{1}{2}x\text{ }-\text{ 8x - 8 }\times\text{ }\frac{1}{2}\text{ = 0} \\ x^2\text{ + }\frac{1}{2}x\text{ - 8x - }\frac{8}{2}\text{ = 0} \\ x^2\text{ - }\frac{7}{2}x\text{ - 4 = 0} \end{gathered}[/tex]Final answer
[tex]x^2\text{ - }\frac{7}{2}x\text{ - 4 = 0}[/tex]Solving Systems by Substitution Day 11. 4x+2y=8y=-2x+4Word bank: (5,-2) (5,5) (2,6) NO SOLUTION INFINITE SOLUTIONS (11, 13) (-2,-6) (0,0) (2.-6) (6,2)
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We have to solve the system of equations
[tex]\begin{gathered} 4x+2y=8 \\ y=-2x+4 \end{gathered}[/tex]by substitution.
This method requieres to solve one of the equations for one of the variables and then plugging this value in the other equation. Since in this case the second equation is already solve for y, we plug this value in the first equation to get an equation of only the x variable.
[tex]\begin{gathered} 4x+2(-2x+4)=8 \\ 4x-4x+8=8 \\ 8=8 \end{gathered}[/tex]Since this equation is always true, no matter the value of x, the system of equations has an infinite number of solutions.
what is the volume of a basketball with a radius of 4.5 inches?
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Since the basketball-shaped sphere, then
Its volume = The volume of the sphere
The volume of the sphere is
[tex]V=\frac{4}{3}\pi r^3[/tex]r is the radius of it
Since the radius of the basketball is 4.5 inches, then
• r = 3.5
Substitute in the rule above
[tex]\begin{gathered} V=\frac{4}{3}\pi(4.5)^3 \\ V=121.5\pi in^3 \end{gathered}[/tex]The volume of the basketball is 121.5 pi in^3
We can use pi = 3.14 or 22/7
The volume of the basketball is 381.8571429 in^3
Given m 0 n, find the value of x and y. (2y+2) (9x-7)° (4x-8)
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Find angles between parallel lines
Angles opposed by line diagonal
m and n are parallel
Then 180° = (9x-7)° + ( 4x -8)° =
Isolate x
9x + 4x = 180 +7 + 8
13 x = 195
x = 195/13 = 15
Now to find y
Apply principle
Two lines are parallel ,if alternate internal angles are equal ( congruents)
Then this means m,n are parallel and
9x - 7 = 2y + 2
replace x= 15
Isolate y
2y = 9x - 7 - 2 = 9•(15) - 7 - 2 = 9•(15) -9 = 9•(14) = 126
y = 126/2 = 63
2n ≤ 128 :this is the whole equation
Answers
The question asks to solve for n
We can get this by dividing both sides by 2
We have this as;
[tex]\begin{gathered} 2n\leq\text{ 128} \\ n\text{ }\leq\frac{128}{2} \\ \\ n\text{ }\leq\text{ 64} \end{gathered}[/tex]The half life of a radioactive element is 100 years. How long does it take for 20 grams of it to be reducedto 5 grams?
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The half-life period represents the amount of time needed for the substance to decay to half the initial mass.
Since 5 grams is one-fourth of the initial 20 grams, it will need 2 half-life periods (one-half times one-half is one-fourth) so the 20 grams decay into 5 grams.
If one half-life period is 100 years, so it will take 200 years to reduce from 20 grams to 5 grams.
The bus comes to a stop near your house every morning at a random time between 6:45 and 6:50. You arrive at the bus stop at a random time between 6;40 and 6:45 every morning and wait until the bus comes. What is the probability that you will wait less than 4 minutes for the bus to arrive?
Answers
What we have here is an example of a geometric probability.
This is the probability that an event will occur within the given area of a figure. That is the ratio of the desired area (required outcomes) to the total area (all possible outcomes).
We shall sketch a graph for the sake of simplicity, as follows;
What we now have is a graph showing the arrival,time of the bus on the vertical axis and, your own arrival time on the horizontal axis.
Next we would shade the area which indicates your waiting time.
Note that the experiment ia aimed at a waiting time of less than 4 minutes.
Therefore, if you arrived at 6:40, a less than 4 minutes waiting time would be between 6:41 and 6:45 (and nothing beyond that).
The area of the shaded region shall be;
[tex]\begin{gathered} \text{Area of triangle}=\frac{1}{2}b\times h \\ b=4\text{ units} \\ h=4\text{ units} \\ \text{Area}=\frac{1}{2}\times4\times4 \\ \text{Area}=\frac{1}{2}\times16 \\ \text{Area}=8\text{ units} \end{gathered}[/tex]The area of the entire region both shaded and unshaded (all posible outcomes) shall be:
[tex]\begin{gathered} \text{Area of a square}=l\times w \\ l=5\text{ units} \\ w=5\text{ units} \\ \text{Area}=5\times5 \\ \text{Area}=25units^2 \end{gathered}[/tex]ANSWER:
The probability that you will wait less than 4 minutes for the bu to arrive is;
[tex]\begin{gathered} P\lbrack E\rbrack=\frac{\text{area of shaded region}}{area\text{ of entire region}} \\ P\lbrack E\rbrack=\frac{8}{25} \end{gathered}[/tex]The probability is 8/25
OR
The probability is 0.32 (expressed as a decimal)
solve proportion using the multiplication property of equality 3/4=x/5
Answers
Question:
solve proportion using the multiplication property of equality
3/4=x/5.
Solution:
Remember that when you divide or multiply both sides of an equation by the same quantity, you still have equality. This principle is called the multiplication property of equality. So, applying this property we have
[tex]\frac{3}{4}\text{ = }\frac{x}{5}[/tex]if we multiply both sides of the equation by 4/3 we obtain the equivalent:
[tex]\frac{3}{4}\text{ . }\frac{4}{3}\text{= }\frac{x}{5}\text{ . }\frac{4}{3}[/tex]this is equivalent to:
[tex]1\text{= }x\text{ . }\frac{4}{15}[/tex]now, if we multiply both sides of the equation by 15/4 we obtain the equivalent:
[tex]1.\frac{15}{4}\text{= }x\text{ . }\frac{4}{15}\text{.}\frac{15}{4}[/tex]this is equivalent to:
[tex]\frac{15}{4}\text{= }x\text{ . }1[/tex]that is:
[tex]\frac{15}{4}\text{= }x[/tex]Then, we can conclude that the solution is:
[tex]x=\frac{15}{4}[/tex]
Given ABC has interior angle measures with:
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For this exercise it is important to remember the de sum of the interior angles of a triangle is 180 degrees.
For this case, you have the triangle ABC, and according to the information given in the exercise:
[tex]\begin{gathered} \angle A=3x-15 \\ \angle B=x+5 \\ \angle C=x-10 \end{gathered}[/tex]Knowing the above, you can set up the following equation:
[tex](3x-15)+(x+5)+(x-10)=180[/tex]Now you must solve for "x":
[tex]\begin{gathered} 3x-15+x+5+x-10=180 \\ 5x-20=180 \\ 5x=180+20 \\ 5x=200 \\ \\ x=\frac{200}{5} \\ \\ x=40 \end{gathered}[/tex]Now, substitute the value of "x" into this equation:
[tex]\angle A=3x-15[/tex]Evaluating, you get that the measure of the angle A is:
[tex]\angle A=3(40)-15=105\degree[/tex]The answer is:
[tex]\angle A=105\degree[/tex]could you help with the problemfactor find the gcm greatest common monomial[tex]16x2y2 - 8xy2 - 4y2[/tex]
Answers
Factor the following;
[tex]\begin{gathered} 16x^2y^2-8xy^2-4y^2 \\ \text{The greatest common factor in all parts of the expression is } \\ 4y^2 \\ \text{Therefore, we have;} \\ 4y^2(4x^2-2x-1) \end{gathered}[/tex]1.4.8Danielle tests the following conjecture.If two angles share a common vertex, then they are adjacent.Her work is shown to the right. What error does Danielle make?Choose the correct answer below.
Answers
Explanation:
The diagram drawn shows two angles that share a common side and a common vertex.
Danielle only mentioned two angles share a common vertex in her conjecture.
Hence, the statement is false as there are angles which share a common vertex and they are not adjacent angles. These angles are called vertical angles.
Adjacent angles have both a common vertex and side.
Hence, Danielle ony gave an example of angles that share a vertex
f(x) = V2 - 1 and h(x) = x² + 5Answer three questions about these functions.What is the value of f(h(2))?f(h(2)) =What is the value of h(f (16))?h(f(16)) =Based only on the previous compositions, is it possible that f and h are inverses?Choose 1 answer:YesBNo
Answers
Given:
[tex]\begin{gathered} f(x)=\sqrt[]{x}-1 \\ h(x)=x^2+5 \end{gathered}[/tex]To find: f(h(2))
So, we get,
[tex]\begin{gathered} f(h(2))=f(2^2+5) \\ =f(9) \\ =\sqrt[]{9}-1 \\ =3-1 \\ =2 \end{gathered}[/tex]Hence, the answer is, f(h(2))=2.
To find: h(f(16))
So, we get
[tex]\begin{gathered} h(f(16))=h(\sqrt[]{16}-1) \\ =h(3) \\ =3^2+5 \\ =14 \end{gathered}[/tex]Hence, the answer is, h(f(16))=14.
Since, h(f(16))=14
And, f and h are not inverses.
A rectangular room is four times as long as it is wide, and its perimeter is 70 meters.
Find the width of the room.
Answers
Step-by-step explanation:
length = 4×width
2×length + 2×width = 70
so, we use the first equation in the second :
2×(4×width) + 2× width = 70
8×width + 2×width = 70
10×width = 70
width = 7 meters
length = 4×width = 4×7 = 28 meters
which of the following values are in the range of the function graphed below? check all that apply A. -1B. 1C.-2D. 2E. -6
Answers
The range of the function is the values of the y coordinates of the graph.
In the given options, the y coordinates of the graph are -1, -2 and -6.
Therefore, options A, C and E are correct.
describe the end behavior of each function f(x)=x^3-4x^2+5
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Solution:
The determine the end behavior of the function below
[tex]f(x)=x^3-4x^2+5[/tex]We will use the image of the function below
The end behavior of a function f describes the behavior of the graph of the function at the "ends" of the x-axis. In other words, the end behavior of a function describes the trend of the graph if we look to the right end of the x-axis (as x approaches +∞ ) and to the left end of the x-axis (as x approaches −∞ ).
Step 1:
From looking at the graph above, we can see that
Since the leading term of the polynomial (the term in the polynomial which contains the highest power of the variable) is x3, the degree is 3, i.e. odd, and the leading coefficient is 1, i.e. positive.
The domain of the function is given below as
[tex]-\inftyTherefore,The end behavior of the function above is
[tex]\begin{gathered} x\rightarrow+\infty,f(x)\rightarrow+\infty,\text{and} \\ x\rightarrow-\infty,f(x)\rightarrow-\infty \end{gathered}[/tex]QuestionDetermine the value(s) for which the rational expressionlist them separated by a comma, e.g. n = 2,3.-3n + 12is undefined. If there's more than one value,84n2 + 76n +16
Answers
A rational expression is defined for all real numbers except the zeros of the denominator.
Then, find the zeros of the denominator to find the values for which the given rational expression is undefined:
[tex]84n^2+76n+16=0[/tex]Use quadratic formula:
[tex]\begin{gathered} ax^2+bx+c=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}[/tex][tex]\begin{gathered} n=\frac{-76\pm\sqrt[]{76^2-4(84)(16)}}{2(84)} \\ \\ n=\frac{-76\pm\sqrt[]{5776-5376}}{168} \\ \\ n=\frac{-76\pm\sqrt[]{400}}{168} \\ \\ n=\frac{-76\pm20}{168} \\ \\ n_1=\frac{-76+20}{168}=\frac{-56}{168}=-\frac{1}{3} \\ \\ n_2=\frac{-76-20}{168}=\frac{-96}{168}=-\frac{4}{7} \end{gathered}[/tex]Then, the given rational expression is undefined for:n= -1/3 , -4/7Last question for tonight! Can anybody help me out with it? I don't need a huge explanation just the answer and a brief explanation on how you got it :)
Answers
We have a direct variation between x and y.
We can write this as:
[tex]y=k\cdot x[/tex]where k is a constant.
Knowing one point of the relation, like (-2,-8) we can calculate k as:
[tex]k=\frac{y}{x}=\frac{-8}{-2}=4[/tex]Then, if we have the point (x,36), we have to calculate the value of x.
As we know that y = 36 and k = 4, we can find x as:
[tex]\begin{gathered} y=k\cdot x \\ x=\frac{y}{k}=\frac{36}{4}=9 \end{gathered}[/tex]Answer: the missing value is x = 9
Write the rate as a unit rate. 60 feet climbed in 15 minutes. ANS. ___________ ft/min
Answers
SOLUTION
The rate is in ft/min.
So this is calculated thus:
[tex]\begin{gathered} \frac{60feet}{15\min } \\ \\ 4ft\text{/min} \end{gathered}[/tex]The accurate scale diagram shows a telephone mast and a box. Find an estimate for the real height, in metres, of the telephone mast. telephone mast +2.5 m box
Answers
The estimate for the real height of the telephone mast is of 9 meters, using proportions.
What is a proportion?A proportion is a fraction of a total amount, and equations are built with these fractions and estimates to find the desired measures in the problem using basic arithmetic operations such as multiplication and division.
In this problem, the telephone box and the mast are similar figures, hence their side lengths are proportional.
The, the following proportional relationship is established:
10.8 cm / 1.8 cm = x / 1.5 cm.
The left side of the relationship can be simplified, as follows:
6 = x / 1.5 cm.
Then the estimate is found applying cross multiplication, as follows:
x = 6 x 1.5 cm = 9.5 cm².
Missing InformationThe diagram is given by the image at the end of the answer.
More can be learned about proportions at https://brainly.com/question/24372153
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A survey went out asking consumersabout their shopping habits. Theresults showed that 165 people weremore likely to go to a store if they hada coupon. This represents 66% of thetotal number of people who took thesurvey.How many people took the survey?25
Answers
We know that 165 people represent a proportion of 0.66 of the people surveyed (66%).
Then, if N is the number of people surveyed, we can write:
[tex]\begin{gathered} 0.66\cdot N=165 \\ N=\frac{165}{0.66}=250 \end{gathered}[/tex]Answer: 250 persons took the survey.
The question asks select all the sequences of transformations that could take figure P to figure Q choices:A a single clock wise rotation B two clockwise rotations of 90 degrees C A single clockwise rotations of 180 degrees.D a transition 5 units to the right and then a reflection over the x axis.E a reflection over the x axis the a diffrent reflexion over the y axis
Answers
C. A single clockwise rotations of 180 degrees.
Explanations:First, let us find the coordinates of the vertices of figure P and that of the corresponding vertices of Q
Figure P Figure Q
(-4, 3) (4, -3)
(-4, 1) (4, -1)
(-1, 1) (1, -1)
By careful observation of the coordinates of P and Q, we would see that:
(x, y) in P is transformed to (-x, -y) in Q
Note that:
When an object of coordinates (x, y) is transformed to an image of coordinates (-x, -y), the type of transformation done is a clockwise rotation of 180 degrees
find the distance between (14,-6) and (12,8)
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For explanation purposes I'll call Point A (14,-6) and Point B (12,8) the given points.
To calculate the distance between both points you have to calculate the distance between each coordinate over the x and y axis.
Then apply the Phytagoras theorem to calculate its length.
I'll sketch the points:
x-axis
[tex]base=d_{AB}=x_A-x_B=14-12=2[/tex]y-axis
[tex]heigth=d_{AB}=y_B-y_A=8-(-6)=8+6=14[/tex]Now according to the Phythagoras theorem, the sum of the squared base and the squared heigth of a triangle is equal to the squared hypotenuse:
[tex]a^2+b^2=c^2[/tex]For this triangle:
[tex]\begin{gathered} 2^2+14^2=c^2 \\ c^2=200 \\ c=\sqrt[]{200}=10\sqrt[]{2}=14.14 \end{gathered}[/tex]The distance between both points is 14.14 units.
Brandon says 4 x 800 is greater than 8 x 4,000. Renee says 4 x 800 is less than 8 X 4,000.A. Without calculating the answer, explain how to use place-value strategies or the Associative Property to find which is greater
Answers
We have two multiplications:
4*800
And
8*4000
We have that 8 is higher than 4, and 4000 is higher than 800. This means that the second one is greather, which means that Renee is correct
you would probably use calculus to determine the area for which of the following shapes, I think it’s A
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To determine the area of shape A we need to use calculus.
This comes from the fact that this is a curved figure. The other options don't need calculus since we can divide them in polygons from which we know how to determine the area.
Write all classifications that apply to the real number 4.O rational, integer, whole numberOnatural number, terminating decimalrational, integer, whole number, natural number, terminating decimalO terminating decimal, integer, rational
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EXPLANATION
The classificationts that apply to the real number 4 are the following:
Rational, integer, whole number
A polygon has the following coordinates: A(6,-7), B(1,-7), C(1,-4), D(3,-2), E(7,-2), F(7,-4). Find the length of BC. A. 5 units B. 2 units C. 4 units D. 3 units
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The formula to find the distance between two points A(x₁,y₁) and B(x₂,y₂) is:
[tex]D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]In this case, we have:
[tex]\begin{gathered} B(x_1,y_1)=(1,-7) \\ C(x_2,y_2)=(1,-4) \end{gathered}[/tex][tex]\begin{gathered} D=\sqrt[]{(1-1)^2+(-4-(-7))^2} \\ D=\sqrt[]{(0)^2+(-4+7)^2} \\ D=\sqrt[]{3^2} \\ D=3 \end{gathered}[/tex]Therefore, the length of segment BC is 3 units.
write the slope intercept form of the equation given the point (2, 9) and a slope of 1/2
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Given a point and a slope, use slope point form to find the intercept slope form.
[tex]\begin{gathered} y-9=\frac{1}{2}(x-2) \\ y-9=\frac{1}{2}x-1 \\ y=\frac{1}{2}x-1+9 \\ y=\frac{1}{2}x+8 \end{gathered}[/tex]Enter the correct answer in the box. Simplify the expression [tex]x - 4 |5.x 7 \8[/tex]
Answers
Question
[tex]x^{\frac{-4}{5}}.x^{\frac{7}{8}}[/tex]Apply multiplication law of exponent.
[tex]\begin{gathered} \text{Multiplication law of exponent } \\ X^m.^{}X^{n\text{ }}=X^{m+n} \end{gathered}[/tex][tex]\begin{gathered} X^{\frac{-4}{5}\text{ }}.X^{\frac{7}{8}} \\ =X^{\frac{-4}{5}\text{ + }\frac{7}{8}} \\ =X^{\frac{-4\text{ x 8 + 5 x 7}}{40}} \\ =X^{\frac{-32\text{ + 35}}{40}} \\ =X^{\frac{3}{40}} \end{gathered}[/tex]I need help with this math problem because I am having a hard time understanding the problem and finding the answer. Can u help me
Answers
Answer:
[tex]h(x)=\frac{x+1}{5x+7},Domain=All\text{ }Real\text{ }numbers,\text{ }except\text{ }x=-\frac{3}{2}\text{ }and\text{ }x=-\frac{7}{5}[/tex][tex]h^{-1}(x)=\frac{1-7x}{5x-1},Domain=All\text{ }Real\text{ }numbers,\text{ }except\text{ }x=\frac{1}{5}[/tex]
Explanation:
The notation for composition of functions is:
[tex](f\circ g)(x)=f(g(x))[/tex]In this case:
[tex]\begin{cases}f(x)={\frac{x}{x+2}} \\ g(x)={\frac{x+1}{2x+3}}\end{cases}[/tex]To do the composition, we replace the x in the f(x) with the function g(x):
[tex](f\circ g)(x)=f(g(x))=\frac{g(x)}{g(x)+3}=\frac{\frac{x+1}{2x+3}}{\frac{x+1}{2x+3}+2}[/tex]And solve:
[tex]=\frac{\frac{x+1}{2x+3}}{\frac{x+1}{2x+3}+2}=\frac{\frac{x+1}{2x+3}}{\frac{x+1}{2x+3}+\frac{2(2x+3)}{2x+3}}=\frac{\frac{x+1}{2x+3}}{\frac{5x+7}{2x+3}}=\frac{(x+1)(2x+3)}{(2x+3)(5x+7)}[/tex]Here, we can calcualte the domain. The function is not defined when teh denominator is 0, thus:
[tex]2x+3=0\Rightarrow x=-\frac{3}{2}[/tex][tex]5x+7=0\Rightarrow x=-\frac{7}{5}[/tex]Since the function can't be evaluated when x = -3/2, we can cancel the terms (2x+3) in the numerator and denominator:
[tex]\frac{(x+1)(2x+3)}{(2x+3)(5x+7)}=\frac{x+1}{5x+7}[/tex]Thus:
[tex]\begin{equation*} h(x)=\frac{x+1}{5x+7},Domain=All\text{ }Real\text{ }numbers,\text{ }except\text{ }x=-\frac{3}{2}\text{ }and\text{ }x=-\frac{7}{5} \end{equation*}[/tex]Now, to find the inverse of the function, we first switch the variables:
[tex]y=\frac{x+1}{5x+7}\Rightarrow x=\frac{y+1}{5y+7}[/tex]And solve for y:
[tex]\begin{gathered} \begin{equation*} x=\frac{y+1}{5y+7} \end{equation*} \\ . \\ x(5y+7)=y+1 \\ . \\ 5xy+7x=y+1 \\ . \\ 5xy-y=1-7x \\ . \\ y(5x-1)=1-7x \\ . \\ y=\frac{1-7x}{5x-1}\Rightarrow h^{-1}(x)=\frac{1-7x}{5x-1} \end{gathered}[/tex]And since the denominator can't be 0:
[tex]5x-1=0\Rightarrow x=\frac{1}{5}[/tex]Thus:
[tex]\begin{equation*} h^{-1}(x)=\frac{1-7x}{5x-1},Domain=All\text{ }Real\text{ }numbers,\text{ }except\text{ }x=\frac{1}{5} \end{equation*}[/tex]The point A (3, 2) is rotated 270 counterclockwise about the origin and is then reflected over the y-axis. What is the ordered pair for point A
Answers
the point is A(3,2)
when we rotate a point (x, y) 270 degrees about the origin counterclockwise
then
(x, y ) becomes (y,-x)
so the point A will be (2, -3) after the rotation,
now we reflect it over y axis, x will replaced by -x
so the point A will be
(-2, -3)
thus, the answer is (-2, -3)