Looking at the bank statement, what three items total that same amount?

Answers

Answer 1

The balance sheet, income statement, and cash flow statement each offer unique details with information that is all interconnected. Together the three statements give a comprehensive portrayal of the company's operating activities.


Related Questions

If the Earths atmosphere is air, then why doesn't the land fall? How is all the lava and water IN earth?

Answers

Answer:

Its stored in there

Explanation:

And air has little mass

A baby elephant trots in a straight line along a river. The horizontal position of the elephant in meters over
time is shown below.
Position
(meters)
15
12+
9+
6-
3+
+
4
+
16
8
12
20
24
-3+
-6+
Time
(seconds)
.92

Answers

Answer:

Displacement -6

Distance 24

Explanation:

Answer:

Explanation:

What is the displacement of the elephant between

0s

and

16s

displacement =9

distance traveled by the elephant between =9

Tarzan (who has mass 80.0 kg) is running across the jungle floor with speed 7.00 m/s as
shown in Figure 1. Tarzan grabs a large bunch of bananas (15.0 kg) and grabs a vine in an attempt to swing up to his monkey who is 3.00 m above him as in Figure 2.

i. What is Tarzan’s momentum before he grabs the bananas? [2 points]
ii. What is Tarzan’s speed just after he grabs the bananas? [4 points]
iii. Can Tarzan swing high enough to reach his monkey? Justify your answer. [2 points]

Answers

We are given:

Mass of Tarzan before swinging = 80 kg

Mass of Tarzan when swinging = 80 + 15 = 95 kg

Velocity of Tarzan = 7 m/s

The height of the rock Tarzan's monkey is sitting on = 3 m

__________________________________________________________

Momentum of Tarzan before swinging:

We know that:

Momentum = Mass*Velocity

Momentum = 80 * 7

Momentum = 560 kg m/s

__________________________________________________________

Speed of Tarzan after grabbing the bananas:

The momentum of Tarzan will remain the same but his mass will increase

So, Since Momentum = New Mass* velocity

560 = 95 * v                           [where v is the velocity of Tarzan]

v = 5.9 m/s

__________________________________________________________

Finding the Initial and Final KE and PE:

Here, KE = Kinetic Energy and PE = Potential Energy

Initial and Final KE:

We know that KE = 1/2*(mv²)

Initial KE:

Initial KE = 1/2*(mv²)          [where v is the velocity after picking the bananas]

Initial KE = 1/2*(95*5.9²)

Initial KE = 1653.5 Joules

Final KE:

Final KE = 1/2*(mv²)            

[where v is the velocity at the maximum point of the swing]

Since Tarzan will be at rest at the maximum point of the swing, v = 0 m/s

Final KE = 1/2*(95*0²)

Final KE = 0 Joules

Initial and Final PE:

We know that:

PE = mgh                

[where g is the acceleration due to gravity and h is the height]

Initial PE:

Since the height of Tarzan from the ground was 0 m at the beginning of the swing, h = 0

Initial PE = 95*10*0

Initial PE = 0 Joules

Final PE:

Let the maximum height of Tarzan be h m

Final PE = 95*10*h

Final PE = 950(h)

__________________________________________________________

Finding the maximum height Tarzan will reach:

Here, KE = Kinetic Energy and PE = Potential Energy

From the law of conservation of momentum, we know that:

Initial KE + Initial PE = Final KE + Final PE

Replacing the variables:

1653.5 + 0 = 0 + 950h

1653.5 = 950h

h = 1653.5/950         [dividing both sides by 950]

h = 1.74 m

Therefore, the maximum height reached by Tarzan is 1.74 m

but since his monkey is sitting 3 m high, he will NOT be able to reach his monkey

Two balls, one twice as massive as the other, are dropped from the roof of a building (freefall). Just before hitting the ground, the more massive ball has ______ the kinetic energy of the less massive ball. (Neglect air friction.)

Answers


KE= 1/2 mv^2

Kinetic Energy is equal to 1/2 x mass x velocity squared

The mass of the larger ball has TWICE
the kinetic energy. KE is directly proportional to the mass.

You push a manual lawn mower across the lawn at constant speed. What is the value of the coefficient of friction between the mower and the grass

Answers

Answer:

0.27

Explanation:

The question is incomplete. Here is the complete question:

You are pushing a 13.3 kg lawn mower across the lawn with a force of 200 N. What is the value of the coefficient of friction between the mower and the grass if the mower moves with a constant velocity? The force is applied downward at an angle of 65° with the horizontal.

According to Newton's second law of motion:

[tex]\sum F_x= ma_x\\F_{app} - F_f = ma_x\\[/tex]

[tex]F_f = \mu R\\[/tex]

[tex]F_{app} - \mu Rcos \theta = ma_x[/tex]

Fapp is the applied force = 200N

Ff is the frictional force

[tex]\mu[/tex] is the coefficient of friction between the mower and the grass

R is the reaction

m is the mass of the object

ax is the acceleration

Given

R = mg = 13.3*9.8

R = 130.34N

m = 13.3kg

ax  = 0m/s² (constant velocity)

Fapp = 200N

[tex]\theta = 65^0[/tex]

Substitute the given parameters into the formula and get the coefficient of friction as shown;

Recall that: [tex]F_f = \mu R\\[/tex]

[tex]\mu = \frac{F_f}{R}\\\mu = \frac{F_{x}cos65}{F_y+W} \\\mu =\frac{ 200cos65}{200sin65+13.3(9.8)}\\\mu = \frac{84.52}{181.26+130.34}\\\mu = \frac{84.52}{311.6}\\\mu = 0.27[/tex]

Hence the coefficient of friction between the mower and the grass is 0.27

Here's a quick story if a boy walks to the woods at night and slender man comes along what is most likely to happen put your answers in the comments.

Answers

Answer:

the boy would go missing

Answer: Slender man converts the boy to christianity

g A 240-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.600 rev/s in 2.00 s

Answers

Answer:

339.3 N

Explanation:

First, we start by converting the units.

1 rev/s = 2π rad/s, so

0.6 rev/s = 2π * 0.6 rad/s

0.6 rev/s = 1.2π rad/s

0.6 rev/s = 3.77 rad/s

Now we apply the equation of motion,

W(f) = w(o) + αt

3.77 = 0 + α * 2

3.77 = 2α

α = 3.77/2

α = 1.885 rad/s²

Torque = I * α

Torque = F * r

This means that

I * α = F * r, where I = 1/2mr²

Substituting for I, we have

1/2mr²α = F * r, making F the subject of formula, we have

F = 1/2mrα, then we substitute for the values

F = 1/2 * 240 * 1.5 * 1.885

F = 678.6 / 2

F = 339.3 N

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