Looking at the figure, the overall (SiO4) molecule, which forms the common mineral quartz, has a tetrahedral shape. It is probably a:
non-polar molecule
polar molecule

Answer:

Single-replacement reaction

Explanation:

Single-replacement reactions, aka. single-displacement reactions, involve one element/ion in a compound being replaced by another element/ion. In this case, aluminum is replacing the iron in the compound.

If you need help visualizing, the equation looks like this:

Fe₂O₃ + Al³⁺ --> Al₂O₃ + Fe³⁺

Answer:

D. Decreasing the temperature of the system

Explanation:

Correct option is C)

C

6

H

12

O

6

6x+12−12=0

C has oxidation number = 0

Sorry if my answers wrong.

Answer:

I don't know but I'm curious now

Answer:

Electronegativity

Explanation:

The ability of an atom to attract itself an electron pair shared with another atom in a chemical bond.

Answer:

C

Explanation:

The volume of the NaOH used is calculated as 14 mL.

The term stoichiometry has to do with the calculation of the amount of substance in a reaction using mass - mole or mass - volume relationship.

Here;

Number of  moles of CaCO3 = 0.205 g/100.1 = 0.00205 moles

Number of  moles of HCl = 2.00 M * 7/1000 L = 0.014 moles

2 moles of HCl reacts with 1 mole of CaCO3

x moles of HCl reacts with 0.00205 moles of CaCO3

x = 0.00205 moles * 2/1 = 0.0041 moles

Hence HCl is the excess reactant

Amount of excess HCl =  0.014 moles -  0.0041 moles = 0.0099 moles

Concentration of excess HCl reacted = 0.0099 moles/125 * 10^-3 = 0.0792 M

Using;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

VB = CAVANB/CBNA

VB = 0.0792 M * 10 mL * 1/ 0.058 M

VB = 14 mL

Missing parts;

A 0.205 g sample of caco3 (mr = 100.1 g/mol) is added to a flask along with 7.50 ml of 2.00 m hcl. caco3(aq) + 2hcl(aq) → cacl2(aq) + h2o(l) + co2(g) enough water is then added to make a 125.0 ml solution. a 10.00 ml aliquot of this solution is taken and titrated with 0.058 m naoh. naoh(aq) + hcl(aq) → h2o(l) + nacl(aq) how many ml of naoh are used?

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Answer:

• Information and media literacy

Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

Activity

Part A

Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil

War started? Base your

Explanation:

• Information and media literacy

Directions

Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write

brief evaluation of your work.

Activity

Part A

Now that you have analyzed the resources provided in the lesson, write your own response to the question, What is the main reason the US Civil

War started? Base your

Answer: =378.94000053g

Explanation:

I think that explains it

Answer:

A.

Explanation:

Answer:

Fe2O3

Explanation:

get the ratio for both Fe and O using relative atomic mass and the percent as the mass

Given the data from the question, the final temperature is 200 K, while pressure remains constant.

To obtain the correct answer to the question, we shall consider two conditions:

We shall determine the new pressure by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

Since temperature is constant, we have:

P₁V₁ = P₂V₂

3 × 1 = P₂ × 2

3 = P₂ × 2

Divide both side by 2

P₂ = 3 / 2

P₂ = 1.5 atm

We shall determine the new temperature by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

Since pressure is constant, we have:

V₁ / T₁ = V₂ / T₂

3 / 300 = 2 / T₂

1 / 100 = 2 / T₂

Cross multiply

T₂ = 100 × 2

T₂ = 200 K

SUMMARY

From the calculations made above, we can conclude that the correct answer is:

The final temperature is 200 K, while pressure remains constant.

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Answer:

b

Explanation:

The given molecule, cis-2-pentene, is an Alkene. The correct option is D. Alkene

Alkanes, Alkenes, and Alkynes are examples of simple hydrocarbons.

The given molecule is cis-2-pentene

Since the name of the molecule ends in "ene", the molecule is an Alkene.

Hence, the given molecule, cis-2-pentene, is an Alkene. The correct option is D. Alkene

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Answer: Alkene

Explanation: just took tha test

That is correct! It is a positive ion!

Answer: The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?

Explanation:

Answer:

Explanation:

Whenever you see molar masses in gas law questions, more often than not density will be involved. This question is no different. To solve this, however, we will first need to play with the combined ideal gas equation PV=nRT to make it work for density and molar mass. The derivation is simple but for the sake of time and space, I will skip it. Hence, just take my word for it that you will end up with the equation:M=dRTPM = molar mass (g/mol)d = density (g/L)R = Ideal Gas Constant (≈0.0821atm⋅Lmol⋅K) T = Temperature (In Kelvin) P = Pressure (atm)As an aside, note that because calculations with this equation involve molar mass, this is the only variation of the ideal gas law in which the identity of the gas plays a role in your calculations. Just something to take note of. Back to the problem: Now, looking back at what we're given, we will need to make some unit conversions to ensure everything matches the dimensions required by the equation:T=35oC+273.15= 308.15 KV=300mL⋅1000mL1L= 0.300 LP=789mmHg⋅1atm760mmHg= 1.038 atmSo, we have almost everything we need to simply plug into the equation. The last thing we need is density. How do we find density? Notice we're given the mass of the sample (0.622 g). All we need to do is divide this by volume, and we have density:d=0.622g0.300L= 2.073 g/LNow, we can plug in everything. When you punch the numbers into your calculator, however, make sure you use the stored values you got from the actual conversions, and not the rounded ones. This will help you ensure accuracy.M=dRTP=(2.073)(0.0821)(308.15)1.038= 51 g/molRounded to 2 significant figuresNow if you were asked to identify which element this is based on your calculation, your best bet would probably be Vandium (molar mass 50.94 g/mol). Hope that helped :) 

Answer:

294 moles of P

Explanation:

For every 1 mol of P4O10 contains 4 mol of P

so;

73.5 mol P4O10 × 4 mol P

1 mol P4O10

= 73.5 × 4

= 294 moles of P

73.5 mol of [tex]P_4O_{10}[/tex] contains 294 moles of P. In 1 mole of [tex]P_4O_{10}[/tex], there are 4 moles of P.

The International System of Units (SI) uses the mole (abbreviated as mol) as its basic unit to measure the amount of a substance. It is mostly used in chemistry and is defined as the volume of a substance that contains exactly 12 grammes of pure carbon-12 in terms of atoms (or equivalent amounts of molecules, ions, or particles). The fundamental notion that atoms combine in whole-number ratios to form compounds serves as the foundation for the concept of the mole. It makes it simple for scientists to convert between a substance's mass and the quantity of atoms or molecules it contains.

In 1 mole of [tex]P_4O_{10}[/tex], there are 4 moles of P.

=4 × 73.5 moles of P.

= 294 moles of P

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#SPJ6

Answer:

independent- test variable

manipulated - outcome variable; if needed, there could be changes.

Explanation:

knowledge

For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as

pH=3.95

Generally, the equation for the Hendersons equation   is mathematically given as

pH=pKa+log(SALT)/(ACID)

Where

moles of  (NaCOOH)=100*0.05/1000

moles of  (NaCOOH)=0.05moles

and  formic acid

moles of formic acid=100*0.05/1000

moles of  formic acid=0.05moles

Therefore

pKa=-logka

pKa=1.4*10*3.77

pH=3.77+log{0.06/0.04}

pH=3.95

In conclusion, the pH is

pH=3.95

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Answer:

An anionic single replacement reaction.

Explanation:

Hope this helps!!!

Answer:

Substitution or Displacement maybe?

Answer:

vibration of particles...........

Considering the definition of volume percentage, the mass/volume percent in this solution is 26.5%.

Mass/volume percent is a measure of concentration that indicates the number of grams of solute in each 100 mL of solution.

In other words, the volume percent of a component in the solution is defined as the ratio of the mass of solute that is present in a solution, relative to the volume of the solution, as a whole.

The volume percentage of a solution is determined by the following expression:

[tex]mass/volume percent=\frac{mass of solute}{volume of solution}100[/tex]

In this case, you know:

Replacing in the definition of mass/volume percent:

[tex]mass/volume percent=\frac{22 g}{83 mL}100[/tex]

Solving:

mass/volume percent= 26.5 %

Finally, the mass/volume percent in this solution is 26.5%.

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Answer:

otherwise you will be bord and have nothing to do

Explanation:

The mass, in grams, of lead that will be produced from the illustrated reaction would be 71.47 grams

From the balanced equation of the reaction:

Pb(NO3)2 + 2NaCl ---> PbCl2 + 2NaNo3

Mole ratio of Pb(NO3)2 and NaCl = 1:2

Mole of 15.3 g NaCl = 15.3/58.4

 = 0.257 moles

Mole of 60.8 g PbCl(NO3)2 = 60.8/331.2

  = 0.184 moles

Thus, NaCl is limiting.

Mole ratio of NaCl to PbCl2 = 1:1

Mas of 0.257 moles PbCl2 = 0.257 x 278.1

 = 71.47 grams

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This question provides us –

__________________________________________

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 39.0983 \times 35.453 [/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf 74.5513[/tex]

Using formula –

[tex]\qquad[/tex] [tex]\purple{\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ W\times 1000}{MV}}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ 47 \times 1000}{74.5513\times 375}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{47000}{27956.7375}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf Molarity _{(Solution)} = \cancel{\dfrac{47000}{27956.7375}}[/tex]

[tex]\qquad[/tex] [tex] \twoheadrightarrow\bf Molarity _{(Solution)} = 1.68117M [/tex]

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf Molarity _{(Solution)} = 1.7M} [/tex]

___________________________________________

Answer:

2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)

Explanation:

I used powers ³,²,²

So change them to be down

Answer: A light year is a measure of distance, for example, there is a big comet 5 light years away, it takes 5 years for light to get to the comet, and just like the galaxy, it would take 25,000 years for light to reach the center of the galaxy.

Answer:It’s important to know WHY. Great explanations are what makes Brainly awesomeExplain everything. Imagine that the person who was asking, knows nothing at all so you need to start from the very beginningAlways include the steps and/or background required to get to the final answer. Let’s help other people understand and solve future problems on their ownShow all the calculation if it is a numerical question.

Explanation:

Answer: 2.24 grams of Pb

Explanation:

Step 1

Balanced chemical reaction;

2PbS + 3O2 → 2Pb + 2SO3

Step 2

Moles of both PbS and O2

Moles = mass / molar mass

Moles of PbS = 2.54 g / 239.3 g/mol = 0.0108 moles

Moles of O2 = 1.88 / 32 g/mol = 0.0588 moles

Step 3

Finding the limiting reactant.

Limiting reactant, is that reactant which is completely used in the reaction;

If we assume that PbS is the limiting reactant;

We have 0.0588 moles of O2. This needs ( 0.0588 * 2) / 3 = 0.0392 moles of PbS to fully react. But we have only 0.0108 moles of PbS available. That means that the PbS will be completely consumed hence the limiting reactant

If we assume O2 is the limiting reactant;

We have 0.0108 moles of PbS. That needs ( 0.0108 * 3) / 2 = 0.0162 moles of O2. But we have 0.0588 moles of O2 which is in excess further confirming that PbS is the limiting reactant since it will be depleted in the reaction.

Step 4

Moles of lead

For this step we apply the mole ratios with the limiting reactant;

Mole ratio of PbS : Pb = 2 : 2 = 1 : 1

Therefore;

Moles of Pb = (0.0108 moles  * 1 ) 1

Moles of Pb =0.0108 moles

Step 5

Mass of Pb

Mass = moles * molar mass

Mass of Pb =0.0108 moles * 207.2 g/mol

Mass of Pb = 2.24 grams