Magnesium, Mg, reacts with hydrochloric acid, HCl, to produce hydrogen gas, Hy, and
magnesium chloride, MgCl2. If 0.750 mol of hydrogen gas is produced, how many moles
of magnesium chloride are also produced?

Answer:

Explanation:

The compound shown is Carbon Dioxide and is as a result of a covalent bond between Carbon and Oxygen where carbon is sharing two electrons each with the oxygen atoms.

The O is the atomic symbol for Oxygen and the C is the symbol for Carbon. Carbon Dioxide then has the atomic symbol of CO₂ to show the relative number of atoms of each element in it.

Answer:

See Explanation

Explanation:

The colour of many transition metal complexes stem from transitions of electrons between energy levels. These transitions are governed by the spin selection rules and the colour is determined by the magnitude of crystal field splitting.

According to the spin selection rules, transitions in which ΔS = 0 are forbidden. Hence, a Mn^2+high spin compound is expected to be colourless. However, contrary to the spin selection rules Mn^2+high spin compounds do exhibit transitions in which the intensity is only about one-hundredth of the intensity of the spin allowed transitions. Thus many Mn^2+  high spin compounds such as Mn(NO3)2 are very pale pink or off white.

Note also that the crystal field stabilization energy of Mn^2+ which is a d^5 low spin ion is zero hence the very pale colour observed.

K4[Mn(CN)6] is deep blue as a result of charge transfer. Also, the compound exhibits an observed crystal field stabilization energy because it is a d^5 low spin compound hence the observed colour. Its low spin nature is because the cyanide ion is a strong field ligand hence it causes a greater magnitude of crystal filed splitting.

The following compounds are colourless;

Zn(NO3)2

CdSO4

AgClO3

One thing that is common to all the compounds listed above is that they are all d^10 compounds. This means that they all possess completely filled d-orbitals hence they are colourless.

Answer: 2.23 is the difference.

Explanation: Sodium has an electronegativity of 0.93 and Chlorine has an electronegativity of 3.16, so when Sodium and Chlorine form an ionic bond, in which the chlorine takes an electron away from sodium, forming the sodium cation, Na+, and the chloride anion, Cl-.

Answer:

Are a form of fat in which all or most of the fatty acid chains are single bonds. Glycerol and fatty acids are the two types of smaller molecules that make up fat.

hope it helps...

Answer:

hot spring

Explanation:

The mineral water in hot springs can also help reduce stress by relaxing tense muscles. Meanwhile as your body temperature rises in the bath, and then cools once you exit can also help you relax and fall into a deeper sleep.

Answer:

kc = [G]² / [E] [F], kc = [1.30M]² / [0.60M] [0.80M]

Explanation:

The reaction is:

E + F ⇄ 2G

The equilibrium constant, kc, must be written as the ratio of the molar concentrations of products over reactants. Each concentration powered to its coefficient.

For the reaction of the problem, kc is:

Replacing the given concentrations:

Answer:

b. The splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.

Explanation:

The spectrochemical series is an arrangement of ligands in increasing order of their magnitude of crystal field splitting.

Ligands that occurs towards the right in the series are called strong field ligands and they tend to cause a greater magnitude of crystal field splitting. Ligands that occur towards the left hand side in the series are called weak field ligands and they tend to cause a lesser magnitude of crystal field splitting.

Since Cl^- is a weak field ligand, it causes a lesser magnitude of d orbital splitting compared to ethylenediammine (en) which causes a greater magnitude of d orbital splitting.

Hence; the splitting of the d-orbitals is smaller in the [Ni(Cl)6]4- complex than in the [Ni(en)3]2+ complex.

Answer:

0.040M RbOH

Explanation:

The reaction of Rb with water is:

2Rb + 2H₂O → 2RbOH + H₂

As 2 moles of rubidium produce 2 moles of rubidium hydroxide, we need to find the moles of rubidium added. With these moles and the volume we can find molar concentration of RbOH as follows:

Moles Rb = Moles RbOH -Molar mass Rb = 85.4678g)

8.5g * (1mol / 85.4678g) = 0.099 moles RbOH

As 1dm³ = 1L, the volume in liters is 2.5L

That means molarity is:

0.099 moles RbOH / 2.5L =

Answer:

This really depends on what you belive in honestly, as a christian i belive a supreme being created all but school says something happend with bacteria and evolution or something lol. If this was a serious question and you need an answer for school just search up the evolution theory

Explanation:

Answer:

a) (I) and (iii) only

Explanation:

Because different plastics have different size.

Explanation:

Charge flow occurs in solution by ions carrying positive or negative charges. Oxidation always occurs at the Anode and Reduction always at the Cathode. Electron flow through the metal is from the anode to the cathode.

Explanation:

For a Galvanic - Voltaic Cell, electron flow is from the anode to the cathode. The following diagram gives reactions at electrodes and direction

Answer:

Reaction type: Single displacement

Reactant: Magnesium

Product: Dihydrogen - H2

Given

Mass of NO - 824 g

Molar mass of NO - 30.01g/mol

No of moles of NO = Given mass/Molar mass

No of moles of NO = 824/30.01= 27.45 mole

Hence 27.5 moles of NO are formed!

Answer:

most rocks are a mixture of minerals

Answer: 6.04 g

Explanation: In STP conditions, amoint of substance

n = V / Vm = 4.23 l / 22.41 l/mol = 0.188755 mol

Molar mass M(O2) = 32 g/mol  and

mass m = nM

Answer:

78.8%

Explanation:

The equation of the reaction is;

2 Al(s) + Fe2O3(aq) ------> Al2O3(aq) + 2Fe(s)

Number of moles in 20g of Al= 20g/27 g/mol = 0.74 moles

From the reaction equation;

2 moles of Al yields 2 moles of Fe

0.74 moles of Al yields 0.74 moles of Fe

Hence;

Mass of Fe produced = 0.74 moles of Fe * 56 g/mol

Mass of Fe produced = 41.44 g of Fe (This is the theoretical yield of Fe)

percent yield = actual yield/ theoretical yield  * 100

actual yield = 32.67 grams of iron

percent yield = 32.67 g/41.44 g * 100

percent yield = 78.8%

Answer:

Explanation:

harmless

...............

Answer:

acid rain is a problem associated with the use of fossil fuels

Answer:

The reaction will proceed to the right to attain the equilibrium.

Explanation:

Step 1: Write the balanced equation

2 N₂(g) + 3 H₂(g) = 2 NH₃(g)

Step 2: Calculate the reaction quotient

The reaction quotient (Qc) is calculated in the same way as the equilibrium constant (Kc) but it uses the concentrations at any time.

Qc = [NH₃]² / [N₂]² × [H₂]³

Qc = 8.00² / 1.50² × 1.00³ = 28.4

Since Qc ≠ Kc, the reaction is not at equilibrium.

Since Qc < Kc, the reaction will proceed to the right to attain the equilibrium.

Answer:

1.765x10²⁵ molecules

Explanation:

First we convert 7.328 moles of propane (C₃H₈) into moles of H₂O, using the stoichiometric coefficients of the balanced reaction:

Then we convert 29.312 moles of H₂O into molecules, using Avogadro's number:

Answer: The concentration of hydrogen ions for this solution is [tex]1.99 \times 10^{-3}[/tex].

Explanation:

Given: pOH = 11.30

The relation between pH and pOH is as follows.

pH + pOH = 14

pH + 11.30 = 14

pH = 14 - 11.30

= 2.7

Also, pH is the negative logarithm of concentration of hydrogen ions.

[tex]pH = - log [H^{+}][/tex]

Substitute the values into above formula as follows.

[tex]pH = -log [H^{+}]\\2.7 = -log [H^{+}]\\conc. of H^{+} = 1.99 \times 10^{-3}[/tex]

Thus, we can conclude that the concentration of hydrogen ions for this solution is [tex]1.99 \times 10^{-3}[/tex].

Answer:

[tex]n_{N_2}=6.41mol[/tex]

Explanation:

¡Hola!

En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:

[tex]PV=nRT\\\\n=\frac{RT}{PV} \\\\n=\frac{0.08206\frac{atm*L}{mol*K}*(50.0+273.15)K}{740/760atm*4.25L}\\\\n=6.41mol[/tex]

Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):

[tex]n_2=\frac{6.41mol*8.50L}{4.25L}\\\\n_2=12.82mol[/tex]

Quiere decir que las moles de N2(g) que se agregaron son:

[tex]n_{N_2}=12.81mol-6.41mol\\\\n_{N_2}=6.41mol[/tex]

¡Saludos!

Answer:

0.001 M OH-

Explanation:

[OH-] = 10^-pOH, so

pOH + pH = 14 and 14 - pH = pOH

14 - 11 = 3

[OH⁻] = 10⁻³ ; [OH-] = 0.001 M OH-

Answer:

55.0 g

Explanation:

Step 1: Write the balanced equation for the production of oxygen

2 CO₂(g)⇒ 2 CO(g) + O₂(g)

Step 2: Calculate the mass of oxygen produced over a 2 hour period

The MOXIE produces 10.0 g of oxygen per hour.

2 h × 10.0 g/1 h = 20.0 g

Step 3: Calculate the moles corresponding to 20.0 g of O₂

The molar mass of O₂ is 32.00 g/mol.

20.0 g × 1 mol/32.00 g = 0.625 mol

Step 4: Calculate the number of moles of CO₂ needed to produce 0.625 moles of O₂

The molar ratio of CO₂ to O₂ is 2:1. The moles of CO₂ needed are 2/1 × 0.625 mol = 1.25 mol

Step 5: Calculate the mass corresponding to 1.25 moles of CO₂

The molar mass of CO₂ is 44.01 g/mol.

1.25 mol × 44.01 g/mol = 55.0 g

Answer:

increase the voltage of the power source to create a higher current.

Explanation:

Using a battery with more voltage will also cause more current to pass through the wire which will increase the power of the electromagnet.

Answer:

Salinization is the increase of salt concentration in soil and is, in most cases, caused by dissolved salts in the water supply. This supply of water can be caused by flooding of the land by seawater, seepage of seawater or brackish groundwater through the soil from below.

Explanation: