Make a conditional relative frequency table for the columns of movie type. Determine which statement has the strongest association.


Do you prefer watching a comedy, a drama, or a thriller movie?
Comedy Drama Thriller Row Totals
Males 35 12 75 122
Females 46 65 18 129
Column Totals 81 77 93 251
Males prefer comedy movies.
Females prefer drama movies.
Males prefer thriller movies.
Females prefer thriller movies.

Answer: -628

Step-by-step explanation:

F(140) = 212 - 6(140)

F(140) = 212 - 840

F(140) = -628

Answer:

A  , B, and C

Step-by-step explanation:

i just did it

Answer:

3n-4= 44

3n=40

no u can solve

Answer:

17°

Step-by-step explanation:

3n - 5° + 90° + 44° = 180° { being linear pair }

3n + 129° = 180°

3n = 180° - 129°

3n = 51°

n = 51° / 3

n = 17°

Hope it will help :)

Answer:

128°

Step-by-step explanation:

180-52=128

Step-by-step explanation:

Using Pythagoras theorem

x=✓(35²-21²)=✓784=28 units

Answer:

Step-by-step explanation:

[tex]\tan22=h_1/200,\ \tan29=h_2/200

h_2+h_1=200(\tan29+\tan22)

H\approx 191.667ft

H\approx 191’ 8”

Answer:

3

Step-by-step explanation:

24 + 12 = ___(8+4)

36 = ___(12)

36/12 = 3

Answer:

Sophie has 12 feet more

Step-by-step explanation:

Answer:

If your polynomial is x^2+x-30, then your answer is (−5)(+6)

Answer:

16/3

Step-by-step explanation:

The value of the expression is 17.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

r + 4

When r = 13

r + 4

= 13 + 4

= 17

Thus,

The value is 17.

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Answer:

20/45

6/45

Step-by-step explanation:

A bag contains 1 green, 4 red, and 5 yellow balls. Two balls are selected at random. Find P( 1 red and 1 yellow) and P(2 red).

--------------------

# of red/yellow pairs: 4*5 = 20

# of random pairs: 10C2 = 45

P(1red & 1yellow) = 20/45

# of red pairs: 4C2 = 6

# of random pairs = 45

P(2 red) = 6/45

Answer:

168.75

Step-by-step explanation:

......

Answer:

168.75

Step-by-step explanation:

Answer:

4, ∛64, -∛64

explanation:

they all mean the same thing

The expression [tex]y^{3} = 64[/tex] can be written as :[tex]y= \sqrt[3]{64}[/tex] or y= 4

The correct option is (II) and (VI)

The cube root of a number is the factor that we multiply by itself three times to get that number.

We have given that:

[tex]y^{3} = 64[/tex]

 we can write it as:

[tex]y= \sqrt[3]{64}[/tex]

y = [tex]\sqrt{4*4*4}[/tex]

y= 4

The answer is : [tex]y^{3} = 64[/tex]

[tex]y= \sqrt[3]{64}[/tex] or y= 4

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Answer:

x=13 y=25

Step-by-step explanation:

Answer:

Step-by-step explanation:

ΔABC has AB = 2BC, hypotenuse is twice the leg

ΔBCD is isosceles right triangle

ΔMPN is isosceles right triangle (∠M = 45°)

ΔMKP is isosceles right triangle (∠M = 45°)

Answer:

Sample B: A random sample of 5 gallons of water from five different locations in the river

Step-by-step explanation:

Answer:

≈3.464

Step-by-step explanation:

1. the required 'x' belongs to the hypotenuse of the given triangle. It means, the formula of its length is:

x=4*cos30°=4*sin60°, note sin60°=cos30°=√3/2≈0.866.

2. according to the formula above the required length 'x' is:

x=4*0.866=3.464 (or 2√3)

Answer:

[tex]f(x) = \frac{6}{x^2} -8[/tex] or [tex]f(x) = -\frac{6}{x^2} + 4[/tex]

Step-by-step explanation:

Given

[tex](x,y) = (1,-2)[/tex] --- Point

[tex]\int\limits^6_2 {(1 + 144x^{-6})} \, dx[/tex]

The arc length of a function on interval [a,b]:  [tex]\int\limits^b_a {(1 + f'(x^2))} \, dx[/tex]

By comparison:

[tex]f'(x)^2 = 144x^{-6}[/tex]

[tex]f'(x)^2 = \frac{144}{x^6}[/tex]

Take square root of both sides

[tex]f'(x) =\± \sqrt{\frac{144}{x^6}}[/tex]

[tex]f'(x) = \±\frac{12}{x^3}[/tex]

Split:

[tex]f'(x) = \frac{12}{x^3}[/tex] or [tex]f'(x) = -\frac{12}{x^3}[/tex]

To solve fo f(x), we make use of:

[tex]f(x) = \int {f'(x) } \, dx[/tex]

For: [tex]f'(x) = \frac{12}{x^3}[/tex]

[tex]f(x) = \int {\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = \frac{12}{2x^2} + c[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = \frac{6}{1^2} + c[/tex]

[tex]-2 = \frac{6}{1} + c[/tex]

[tex]-2 = 6 + c[/tex]

Make c the subject

[tex]c = -2-6[/tex]

[tex]c = -8[/tex]

[tex]f(x) = \frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = \frac{6}{x^2} -8[/tex]

For: [tex]f'(x) = -\frac{12}{x^3}[/tex]

[tex]f(x) = \int {-\frac{12}{x^3} } \, dx[/tex]

Integrate:

[tex]f(x) = -\frac{12}{2x^2} + c[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex]

We understand that it passes through [tex](x,y) = (1,-2)[/tex].

So, we have:

[tex]-2 = -\frac{6}{1^2} + c[/tex]

[tex]-2 = -\frac{6}{1} + c[/tex]

[tex]-2 = -6 + c[/tex]

Make c the subject

[tex]c = -2+6[/tex]

[tex]c = 4[/tex]

[tex]f(x) = -\frac{6}{x^2} + c[/tex] becomes

[tex]f(x) = -\frac{6}{x^2} + 4[/tex]

You can use the formula for finding the arc length on specified interval on x axis.
The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

If the function is differentiable in the given interval, then we have:

[tex]s = \int_a^b\sqrt{(1 + (f'(x))^2)}\:dx[/tex]

where s denotes the length of the arc of the given function from x = a to x = b

Using the above formula, as we're already given the arc length, thus,

[tex]\int_a^b\sqrt{(1 + (f'(x))^2)}\:dx = \int_2^6\sqrt{(1 +144x^{-6})}\:dx[/tex]

This gives us

[tex]f'(x) = \pm \sqrt{144x^{-6}} = \pm 12x^{-3}[/tex]

Integrating both sides with respect to x, we get:

[tex]f(x) = \pm \int 12x^{-3}\\\\f(x) = \pm 6x^{-2} + c[/tex]

where c is constant of integration.

Since the curve passes through (1,-2), thus, putting f(x) = -2, x = 1, we get:

[tex]f(x) = \pm 6x^{-2} + c\\-2 = \pm 6 + c\\c = -2 \mp 6 = -8, or ,4[/tex]

c = -8 when we have [tex]f(x) = 6x^{-2} + c[/tex]

c = + 4 when we have [tex]f(x) = -6x^{-2} + c[/tex]

The curves whose arc length on the given interval is described are

[tex]f(x) = 6x^{-2} -8[/tex]

and

[tex]f(x) = -6x^{-2} + 4[/tex]

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Answer:

I love alegbra anyways

The ans is in the picture with the steps how i got it

(Hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

185.193 Cm, 5.7x5.7x5.7 is the volume

The volume of the Rubik's cube is 183.51 cubic centimeters.

To find the volume of a Rubik's cube, we can use the formula V = s ³, where V represents the volume and s represents the length of each edge.

In this case, the length of each edge is given as 5.7 centimeters.

Substituting this value into the formula, we have:

V = (5.7 cm) ³

Calculating the volume:

V = 5.7 cm * 5.7 cm * 5.7 cm

V = 32.49 * 5.7

V = 183.51 cm ³

Therefore, the volume of the Rubik's cube is 183.51 cubic centimeters.

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Answer:

10

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

We know that when x=0 y=5

B and D are the only ones that meet this criteria

we know that when x=2 y= 13 or so

D no longer works

it has to be B

Answer:

Question 13 is 27/2 (decimal form, 13.5, Mixed fraction 13 1/2)

Question 14 = 4

Step-by-step explanation:

hope this helped you:)

Hello!

[tex]\large\boxed{\frac{2\pi}{3} \text{ and } \frac{4\pi}{3}}[/tex]

2cosФ + 1 = 0

Begin by isolating for cosФ. Subtract both sides by -1:

2cosФ = -1

Divide both sides by 2:

cosФ = -1/2

Using the unit circle, we know that from [0, 2π), values that have a cosine of -1/2 are 2π/3 and 4π/3.

Therefore, the solutions of this equation are:

Ф = 2π/3 and 4π/3

Answer:

1.52%

Step-by-step explanation: