Answer:
Step-by-step explanation:
The summary of the given data includes;
sample size for the first school [tex]n_1[/tex] = 42
sample size for the second school [tex]n_2[/tex] = 34
so 16 out of 42 i.e [tex]x_1[/tex] = 16 and 18 out of 34 i.e [tex]x_2[/tex] = 18 have ear infection.
the proportion of students with ear infection Is as follows:
[tex]\hat p_1 = \dfrac{16}{42}[/tex] = 0.38095
[tex]\hat p_2 = \dfrac{18}{34}[/tex] = 0.5294
Since this is a two tailed test , the null and the alternative hypothesis can be computed as :
[tex]H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0[/tex]
level of significance ∝ = 0.05,
Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.
The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.
[tex]\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}[/tex]
[tex]\bar p = \dfrac{16 +18}{42 +34}[/tex]
[tex]\bar p = \dfrac{34}{76}[/tex]
[tex]\bar p = 0.447368[/tex]
[tex]\bar p + \bar q = 1 \\ \\ \bar q = 1 -\bar p \\ \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632[/tex]
The pooled standard error can be computed by using the formula:
[tex]S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} + \dfrac{\bar p \bar p}{n_2} }[/tex]
[tex]S.E = \sqrt{ \dfrac{ 0.447368 * 0.552632}{ 42} + \dfrac{ 0.447368 * 0.447368}{34} }[/tex]
[tex]S.E = \sqrt{ \dfrac{ 0.2472298726}{ 42} + \dfrac{ 0.2001381274}{34} }[/tex]
[tex]S.E = \sqrt{ 0.01177284105}[/tex]
[tex]S.E = 0.1085[/tex]
The test statistics is ;
[tex]z = \dfrac{\hat p_1 - \hat p_2}{S.E}[/tex]
[tex]z = \dfrac{0.38095- 0.5294}{0.1085}[/tex]
[tex]z = \dfrac{-0.14845}{0.1085}[/tex]
z = - 1.368
Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.
Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools
Suppose that BC financial aid alots a textbook stipend by claiming that the average textbook at BC bookstore costs $ $ 93.29. You want to test this claim.Required:a. The null and alternative hypothesis in symbols would be: _______b. The null hypothesis in words would be: 1. The average price of textbooks in a sample is S 96.28 2. The proportion of all textbooks from the store that are less than 96.28 is equal to 50% 3. The average of price of all textbooks from the store is less than $96.28. 4. The average of price of all textbooks from the store is greater than $96.28. 'The average price of all textbooks from the store is S 96.28
Answer:
H₀: μ = 93.29 vs. Hₐ: μ ≠ 93.29.
Step-by-step explanation:
In this case we need to test whether the claim made by BC financial aid is true or not.
Claim: The average textbook at BC bookstore costs $93.29.
A null hypothesis is a sort of hypothesis used in statistics that intends that no statistical significance exists in a set of given observations.
It is a hypothesis of no difference.
It is typically the hypothesis a scientist or experimenter will attempt to refute or discard. It is denoted by H₀.
Whereas, the alternate hypothesis is the contradicting statement to the null hypothesis.
The alternate hypothesis describes direction of the hypothesis test, i.e. if the test is left tailed, right tailed or two tailed.
It is also known as the research hypothesis and is denoted by Hₐ.
The hypothesis to test this claim can be defined as follows:
H₀: The average textbook at BC bookstore costs $93.29, i.e. μ = 93.29.
Hₐ: The average textbook at BC bookstore costs different than $93.29, i.e. μ ≠ 93.29.
Diabetic patients have normally distributed cholesterol with mean 200 and standard deviation=10.
Find the percentage of patients whose cholesterol is between 198 mg/dL and
207 mg/dL ?
Answer:
The percentage of patients whose cholesterol is between 198 mg/dL and 207 mg/dL is 33.73%
Step-by-step explanation:
To calculate this proportion, we follow the probability route, using the z-score statistics
Mathematically;
z-score = (x-mean)/SD
from the question, mean = 200 and SD = 10
So for 198
z-score = (198-200)/10 = -2/10 = -0.2
For 207
z-score = (207-200)/10 = 7/10 = 0.7
So the probability we want to calculate is;
P(-0.2<z<0.7)
Mathematically this can be calculated as;
P(z<0.7) - P(z<-0.2)
We can calculate the required probability using the standard normal distribution table
P(-0.2<x<0.7) = 0.3373 from the standard distribution table
So it is this 0.3373 that we now convert to percentage and that is 33.73%
A job can be done by 30 men in 15 days. How long would it take 10 men to do the same job?
Answer:
45 days
Step-by-step explanation:
Based on the giving information, 30*15/10.
Reduce the fraction by canceling the greatest common factor: 3*15 = 45
Describe the transformation in the given image.
1
2.
Rotation
3
Dilation
Reflection
4
Translation
Answer:
C
Step-by-step explanation:
It's a clear reflection transformation
Evaluate. log (down)2 256 . Write a conclusion statement.
[tex] \Large{ \boxed{ \bf{ \color{blue}{Solution:}}}}[/tex]
By using the fact that,
When,
[tex] \large{ \sf{ {a}^{x} =b}}[/tex]
Then, With logarithm base a of a number b:
[tex] \large{ \sf{ log_{a}(b) = x}}[/tex]
☃️So, Let's solve ths question....
To FinD:
[tex] \large{ \sf{log_{2}(256) }}[/tex]
Let it be x,
[tex] \large{ \sf{ \longrightarrow{ log_{2}(256) = x}}}[/tex]
Proceeding further,
[tex] \large{ \sf{ \longrightarrow \: {2}^{x} = 256}}[/tex]
[tex] \large{ \sf{ \longrightarrow \: {2}^{x} = {2}^{8} }}[/tex]
Then, We have same base 2, So
[tex] \large{ \sf{ \longrightarrow \: x = 8}}[/tex]
Or,
➙ log₂(256) = log₁₀(256) / log₁₀(2)
➙ log₂(256) = 2.40823996531 / 0.301029995664
➙ log₂(256) = 8
☕️ Hence, solved !!
━━━━━━━━━━━━━━━━━━━━
Answer:
256
Step-by-step explanation:
log 256 can most easily be found by rewriting 256 as a power of 2:
2
2^5 * 2^3 = 32*8 = 256, so 2^ (5 + 3) = 2^8.
Then we have:
log 256
2 2 = 256
Alternatively, write:
log (down)2 256 = log (down)2 2^8 = 2*8 = 256
Note that your "log (down)^2 and the function y = 2^x are inverse functions that effectively cancel one another.
whats is 5% in words?
Here are a few ways 5% could be written in words:
-five percent
-five thousandths (0.05)
Hope this helps! :)
Answer:
0.05
Step-by-step explanation:
Assuming you mean as a decimal...
5/100 = 0.05
ALTERNATIVELY
5% = Five Percent
0.05 = Five Thousandths, Zero Point Zero Five
Solve four and two fifths plus two and two thirds
I NEED this answered within the next 30 minutes! Please it is simple. There is an error in this. What is it?
Answer:
(a). x = 80°
(b). x = 7.2 units
Step-by-step explanation:
Angle formed between the tangents from a point outside the circle measure the half of the difference of intercepted arcs.
(a). Here the intercepted arcs are,
Measure of major arc = 360° - 100°
= 260°
Measure of minor arc = 100°
x° = [tex]\frac{1}{2}[m(\text{Major arc})-m(\text{Minor arc})][/tex]
= [tex]\frac{1}{2}(260-100)[/tex]
x = 80°
(b). If a secant and tangent are drawn form a point outside the circle, then square of the measure of tangent is equal to the product of the measures of the secant segment and and its external segment.
x² = 4(4 + 9)
x² = 4 × 13
x² = 52
x = √52
x = 7.211 ≈ 7.2 units
If a plane can climb at 2,400 feet per minute, how many minutes are needed to climb to 60,000 feet?
If a plane can climb at 2,400 feet per minute, how many minutes are needed to climb to 60,000 feet?
Answer:
25 is the amount needed to climb to 60,000 feet
Determine whether the statement is true or false. If it is false, rewrite it as a true statement. A sampling distribution is normal only if the population is normal. Choose the correct answer below. A. The statement is false. A sampling distribution is normal only if n30. B. The statement is false. A sampling distribution is normal if either n30 or the population is normal. C. The statement is true. D. The statement is false. A sampling distribution is never normal.
The statement is false. A sampling distribution is normal if either n > 30 or the population is normal.
==========================================
Explanation:
If the underlying population is normally distributed, then so is the sample distribution (such as the distribution of sample means, aka xbar distribution).
Even if the population isn't normally distributed, the xbar distribution is approximately normal if n > 30 due to the central limit theorem. Some textbooks may use a higher value than 30, but after some threshold is met is when the xbar distribution is effectively "normal".
Choice A is close, but is missing the part about the population being normal. If we know the population is normal, then n > 30 doesn't have to be required.
Write 36 143/1000 as a decimal number.
Answer:
36.143
Step-by-step explanation:
143/1000=0.143
36+0.143=36.143
area to the right of z=0.72
I don’t have a graphing calculator and I couldn’t find one online. I’m completely clueless on this one.
Answer:
Desmos could come in handy
An asset's book value is $43,200 on January 1, Year 6. The asset is being depreciated $600 per month using the straight-line
method. Assuming the asset is sold on July 1, Year 7 for $29,400, the company should record:
Assuming the asset is sold on July 1, Year 7 for $29,400, the company should record the asset's value as equal to $32,400.
The book value of the asset on January 1, Year 6 was $43,200.The asset is being depreciated at $600 per month using the straight-line method.The asset was sold on July 1, Year 7 for $29,400.The amount of time elapsed until the asset is sold is 18 months.The time elapsed can be considered as the "x-coordinate".The asset's value can be considered as the "y-coordinate".The rate of depreciation can be considered as the slope of the line.The equation formed from the given data is given below :(y-y1) = m(x-x1)y-43,200 = (-600)(18)y = 43,200-10,800y = 32,400To learn more about equations, visit :
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What is the slope of the line y = 2x – 5
Answer:
2
Step-by-step explanation:
produces a straight line
Hello! :)
y=2x-5 is written in slope-intercept form (y=mx+b)
m is the slope, and b is the y-intercept.
So the slope of this line is 2. Hope it helps. Please ask if you have any query.
~An excited gal
[tex]MagicalNature[/tex] here to help
A math teacher needs to choose 6 students from a class of 30 to go to the library. How many different groups can she select?
No if groups=No of students/no of students in each groups
[tex]\\ \sf\longmapsto \dfrac{30}{6}[/tex]
[tex]\\ \sf\longmapsto 5groups[/tex]
In a survey of 15000 students of different schools, 40% of them were found to have tuition before the see examination. Among them 50% studied only mathematics ,30% only science and 10% studied others subject. how many student studied mathematics as well as science.
Answer: 600 students.
Step-by-step explanation:
Ok, we start with 15,000 students.
40% of them had tuition, so the actual number of them that had tuition is:
15,000*0.40 = 6,000.
Now we want to find the number of students that studied math and science.
50% only studied math,
30% only studied science
10% studied other subjects.
So 50% + 30% + 10% did NOT studied both math and science
90% is the percentage that did not study math and mathematics as well as science, then the other 10% did.
Then, out of the 6,000 students that had tuition, 10% studied math and science, the total number is:
6,000*0.10 = 600
which graph shows a reflection across the line Y = X
Answer:
B
Step-by-step explanation:
"A" is not a reflection, it looks like a translation.
"C" is not a reflection, it is a rotation.
So, B is a reflection.
Answer:
[tex]\large \boxed{\mathrm{Graph \ C}}[/tex]
Step-by-step explanation:
The reflection is across the line y = x.
All options show reflection. Option C shows reflection across the line y = x.
In the reflection, the points on the triangle will also be reflected.
Point S is reflected across the line y=x, the reflected point is S’.
Point R is reflected across the line y=x, the reflected point is R’.
Point Q is reflected across the line y=x, the reflected point is Q’.
2. Write the equation of the line in point-slope form.
(-1,3) and (2,9)
Answer:
y - 9 = 2 (x - 2)
Step-by-step explanation:
y2 - y1 / x2 - x1 9 - 3 / 2 - (-1) 6/3 = 2
y - 9 = 2 (x - 2)
What is the reciprocal of 0.025 (not -0.025)
Answer:
1000/25 or 40
Step-by-step explanation:
~ A reciprocal is the fraction's reverse
For example 2/3=3/2
.025 is also 25/1000
The reverse of 25/1000 is 1000/25
Simplified into 40 wholes
1000/25 is the reciprocal of 0.025
What is Fraction?A fraction represents a part of a whole.
Given,
Decimal value is 0.025
Zero point zero two five.
Firstly let us convert this to the fraction form.
When twenty five is divided by thousand we get 0.025
25/1000=0.025
So the fraction is 25/1000.
Now we need to find the reciprocal of fraction 25/1000.
Reciprocal means the numerator changes to denominator and denominator changes to numerator.
So 25/1000 reciprocal is 1000/25
Hence, 1000/25 is the reciprocal of 0.025
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(21x-3)+21=23x+6 solve
Answer:
False
Step-by-step explanation:
You Cnat solve it
Answer:
you cannot solve it
Step-by-step explanation:
false
Question 1 (5 points)
The line segment AB with endpoints A(-3, 6) and B(9, 12) is dilated with a scale
factor 2/3 about the origin. Find the endpoints of the dilated line segment.
OA) (-2, 4), (6,8)
B) (2, 4). (6,8)
OC) (4, -2), (6,8)
OD) (-2,4), (8,6)
Answer: A) (-2, 4), (6,8)
Step-by-step explanation:
When a point (x,y) is dilated by a scale factor of k , then the new points is given by (kx,ky).
Given: The line segment AB with endpoints A(-3, 6) and B(9, 12) is dilated with a scale factor [tex]\dfrac23[/tex] about the origin.
Let A' and B' b the endpoints of the dilated line segment.
Then, [tex]A'(\dfrac{2}{3}(-3), \dfrac23(6))=A'(-2,4)[/tex]
[tex]B'(\dfrac{2}{3}(9), \dfrac23(12))=B'(6,8)[/tex]
Hence, the correct option is A) (-2, 4), (6,8)
A bike wheel. A bike wheel is 26 inches in diameter. What is the bike wheel's diameter in millimeters (1 inch = 25.4 millimeters)?
Answer:
The answer is 660.4 millimetersStep-by-step explanation:
Diameter = 26 inches
From the question
1 inch = 25.4 mm
To find it's equivalent in millimeters multiply 26 inches by 25.4 millimeters and divide by 1 inch
so we have 26 inches as
[tex] \frac{26 \: inches \times 25.4mm}{1 \: inch} [/tex]
Simplify
We have
26 × 25.4 mm
We have the final answer as
660.4 millimetersHope this helps you
Answer: B.) 26 inches (25.4 millimeters/ 1 inch)
Step-by-step explanation: i hope this helps :)
URGENT, PLEASE HELP! (4/5) -50 POINTS- ! please no wrong answers for the points.! A) y = -3x + 2 B) y = -x + 2 C) y = 3x + 2 D) y = x + 1
Answer:
D y= x+1
Step-by-step explanation:
The line has a positive slope since it goes up from left to right
We can eliminate A and B
3 is a fairly steep slope for line C
Lets check with point x=7
y = 3*7 +2 = 21+2 = 23
Way too steep
Lets check 2
y = 3*2+2 = 6+2 = 8
Still above the points
Checking D
y = x+1
x=7
y = 7+1 =8 A little high
x=2
y = 2+1 =3 A little low but much better than C
Answer:
[tex]\huge \boxed{y=x+1}[/tex]
Step-by-step explanation:
Using a graph,
we can see the line y=x+1 is best fit for the data.
602/100 into a decimal describe plz
Answer:
6.02
six point zero two
Step-by-step explanation:
Answer:
602 / 100= 6,02
Step-by-step explanation:
602 to divide 100 = 6,02
Complete each equation with a number that makes it true. 5⋅______=15 4⋅______=32 6⋅______=9 12⋅______=3
Answer: blank 1: 3 Blank 2: 8 blank 3: 1.5 blank 4: 0.25
Step-by-step explanation:
5 times 8=15
4 times 8=32
6 times 1.5=9
12 times 0.25=3
The complete equation is
5⋅____3__=15
4⋅___8___=32
6⋅___1.5___=9
12⋅__0.25____=3
What is Multiplication?Multiplication is an operation that represents the basic idea of repeated addition of the same number. The numbers that are multiplied are called the factors and the result that is obtained after the multiplication of two or more numbers is known as the product of those numbers. Multiplication is used to simplify the task of repeated addition of the same number.
Multiplication Formula
The multiplication formula is expressed as, Multiplicand × Multiplier = Product; where:
Multiplicand: The first number (factor).Multiplier: The second number (factor).Product: The final result after multiplying the multiplicand and multiplier.Multiplication symbol: '×' (which connects the entire expression)5 * 3=154 * 8=326 * 1.5=912 * 0.25=3Learn more about multiplication here:
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The formula for the area of a square is s2, where s is the side length of the square. What is the area of a square with a side length of 6 centimeters? Do not include units in your answer.
Answer:
36
Step-by-step explanation:
formula of area for square:
A=s^2
s=6
A=6^2
A=36
Answer:
36
Step-by-step explanation:
I got it right
What is the 25th term in the following arithmetic sequence? -7, -2, 3, 8, ...
Answer:
108.
Step-by-step explanation:
-7, -2, 3, 8 is an arithmetic sequence with a1 (first term) = -7 and common difference (d) = 5.
The 24th term = a1 + (24 - 1)d
= -7 + 23 * 5
= -7 + 115
= 108.
What is the solution to this equation? 2x + 4 = 16
Answer:
x=6
Step-by-step explanation:
2x+4=16
2x+4-4=16-6
2x=12
x=6
Proof:
2x+4=16
2(6)+4=16
12+4=16
16=16
Hope this helps ;) ❤❤❤
Answer:
find out what x is and it is 6 it is 6 because 2 times 6 is 12 and 12 plus 4 is 16
Step-by-step explanation:
Will mark the brainliest
And thank you:)
[tex]\sf{\implies Range = Highest \: - lowest }[/tex]
→ Range of Lewistown = 74 - 64
→ Range of Lewistown = 10 .
→ Range of Hamersville = 71 - 55
→ Range of Hamersville = 16 .
☆ Range of Hamersville - Range of Lewistown
→ 16 - 10
→ 6
Answer → The range for Hamersville is 6 more than the range for Lewistown .
(a) Use appropriate algebra and Theorem to find the given inverse Laplace transform. (Write your answer as a function of t.)
L−1 {3s − 10/ s2 + 25}
(b) Use the Laplace transform to solve the given initial-value problem.
y' + 3y = e6t, y(0) = 2
(a) Expand the given expression as
[tex]\dfrac{3s-10}{s^2+25}=3\cdot\dfrac s{s^2+25}-2\cdot\dfrac5{s^2+25}[/tex]
You should recognize the Laplace transform of sine and cosine:
[tex]L[\cos(at)]=\dfrac s{s^2+a^2}[/tex]
[tex]L[\sin(at)]=\dfrac a{s^2+a^2}[/tex]
So we have
[tex]L^{-1}\left[\dfrac{3s-10}{s^2+25}\right]=3\cos(5t)-2\sin(5t)[/tex]
(b) Take the Laplace transform of both sides:
[tex]y'(t)+3y(t)=e^{6t}\implies (sY(s)-y(0))+3Y(s)=\dfrac1{s-6}[/tex]
Solve for [tex]Y(s)[/tex]:
[tex](s+3)Y(s)-2=\dfrac1{s-6}\implies Y(s)=\dfrac{2s-11}{(s-6)(s+3)}[/tex]
Decompose the right side into partial fractions:
[tex]\dfrac{2s-11}{(s-6)(s+3)}=\dfrac{\theta_1}{s-6}+\dfrac{\theta_2}{s+3}[/tex]
[tex]2s-11=\theta_1(s+3)+\theta_2(s-6)[/tex]
[tex]2s-11=(\theta_1+\theta_2)s+(3\theta_1-6\theta_2)[/tex]
[tex]\begin{cases}\theta_1+\theta_2=2\\3\theta_1-6\theta_2=-11\end{cases}\implies\theta_1=\dfrac19,\theta_2=\dfrac{17}9[/tex]
So we have
[tex]Y(s)=\dfrac19\cdot\dfrac1{s-6}+\dfrac{17}9\cdot\dfrac1{s+3}[/tex]
and taking the inverse transforms of both sides gives
[tex]y(t)=\dfrac19e^{6t}+\dfrac{17}9e^{-3t}[/tex]