Many reactions double their rates with every ten degrees rise in temperature. Assume that such a reaction takes place at 301 K and 311 K. What must its activation energy be for this statement to hold

Answers

Answer 1

Answer:

57.6 KJ/mol

Explanation:

We have that;

T1 = 301 K

T2= 311 K

k1 = k1

k2= 2k1

R = 8.314 JK-1

Ea= ?

So;

ln(k1/k2) = (-Ea/R) (1/T1 - 1/T2)

ln (k1/2k1) = -(Ea/8.314) (1/301 - 1/311)

ln(1/2) = -(Ea/8.314) (3.3 * 10^-3 - 3.2 * 10^-3)

-0.693 = -(Ea/8.314) 0.1 * 10^-3

-0.693/ 0.1  * 10^-3 = -(Ea/8.314)

-6930 =  -(Ea/8.314)

Ea = 6930 * 8.314

Ea = 57.6 KJ/mol


Related Questions

can you make energy with ionized particles? yes or no and how

Answers

Answer: Yes.

Explanation:
Atoms or molecules can acquire a positive or negative electrical charge when they gain or lose electrons. This process is called ionization.

Hope this helps.

Write a balanced equation describing the reduction of H2SeO4 by SO2 to produce selenium. (Use the lowest possible coefficients. Include states-of-matter under SATP conditions in your answer.)

Answers

Answer:

[tex]\mathbf{H_2SeO_{4(aq)} + 3SO_{2(aq)} + 2H_2O_{(l) } \to Se_{(s)} + 3H_2SO_{4(aq)} }[/tex]

Explanation:

We are to write a balanced equation from the information given above by including the states of their matter according to SATP conditions;

[tex]\mathbf{H_2SeO_{4(aq)} + 3SO_{2(aq)} + 2H_2O_{(l) } \to Se_{(s)} + 3H_2SO_{4(aq)} }[/tex]

From above;

The oxidizing agent is [tex]\mathbf{H_2SeO_{4(aq)} }[/tex]

The reducing agent is [tex]\mathbf{SO_{2(aq)} }[/tex]

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