Match it, I’m not sure which category they go in

aswer: protactinium-234 is more dang erous than uranium

There can be emissions of radiations like gamma radiation. There can be emission of particles too like alpha particle. Therefore protactinium-234 is more dangerous than uranium-234.

Nuclear decay is process in which the radioactive element releases particles or radiations. Alpha particles is ⁴₂He. Alpha particle is nothing but helium particle.  Protactinium-234 and uranium-234 are radioactive element.

If we were sitting near a gram of protactinium-234 and a gram of uranium-234, both solid materials then protactinium-234 is more dangerous than uranium-234. The half-life of protactinium-234 is smaller than that of uranium-234. So, protactinium-234 is more active than uranium-234 and hence more harmful than uranium-234.

Therefore, protactinium-234 is more dangerous than uranium-234.

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Answer: I believe it's C

Hope this helped<3

Can you please make my answer brainly

Answer:

B. The limiting reactant determines the maximum amount of product that can be formed.

Answer:

[tex]\mathbf{a \ strong \ base \ such \ as\ LiOH \ or \ NaOH.}[/tex]

Explanation:

In the condensation reactions of carbonyl compounds, it is essential to establish the order of events in advance to minimize or suppress the possibilities of self-condensation and the occurrence of cross-condensation, which unfortunately are an obvious threat in these reactions.

Self-condensation:

Any carbonyl compound that has one or more alpha hydrogens, on the carbons adjacent to the carbonyl group, runs the risk of undergoing a self-condensation reaction if the corresponding rigor is not carried out.

Cross-condensation:

Ideally, in the condensation reactions of carbonyl compounds, one of the reacting molecules should quickly enolise, while the other preferably should not have Hα, to ensure that no other by-products are formed.

[tex]\text{To achieve this process;}[/tex] [tex]\text{A self-aldol or crossed aldol requires a strong base such as LiOH or NaOH.}[/tex]

Answer:

(8.3×40)+(8.3×71)

921.3grames

Answer:

[tex]\Large \boxed{\sf 921.3 \ g}[/tex]

Explanation:

Use formula

[tex]\displaystyle moles=\frac{mass}{M_r}[/tex]

[tex]M_r=40+35.5 \times 2 = 111[/tex]

Solve for mass

[tex]mass=8.3 \times 111=921.3[/tex]

Answer:

3.45E24

Explanation:

calculator I'm not that great at math but I'm good at science but that isn't really science but it's aix between it tho

[tex]\huge\underline\mathbb\pink{ANSWER\::}\\\\[/tex]

_BaS + _PtF2 → _BaF2 + _Pts

Barium Sulfide + Platinum(II) Fluoride = Barium Fluoride + Platinum(II) Sulfide.

=> 1 BaS + 1 PtF2 → 1 BaF2 + 1 PtS

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Answer:

Electrostatic smoke precipitators work by forcing dirty flue gas (the gas escaping from a smokestack) past two electrodes (electrical terminals), which take the form of metal wires, bars, or plates inside a pipe or smokestack

Explanation:

Answer:

Option B.

Explanation:

First we convert 9.90 g of Pb(NO₃)₂ into moles, using its molar mass:

Then we convert moles of Pb(NO₃)₂ into moles of PbO, using the stoichiometric coefficients:

Now we convert 0.0299 mol PbO into grams, using its molar mass:

So 6.67 g is the theoretical yield. With that in mind we calculate the percent yield:

So the correct answer is option B.

Answer:

yes correct salt hardens soap

This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained

Answer:

the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

Explanation:

Given the data in the question;

thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

concentration high pressure side C[tex]_A[/tex] = 2.4

concentration low pressure side C[tex]_B[/tex] = 0.6 kg

from the question, we calculate the concentration gradient

dc/dx = (C[tex]_A[/tex] -  C[tex]_B[/tex])/dt

so we substitute

dc/dx = (2.4 - 0.6) / ( - 5 × 10⁻³ )

dc/dx = -360

now, mass of hydrogen per hour that diffuse through a pd sheet

M = -∝AT(dc/dx)

where time t is 1 hour ( 3600 sec )

we substitute

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per one hour

Therefore, the number of kilograms of hydrogen that pass per hour through is 2.592 × 10⁻³ kg

The number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500°C is 2.592 × 10⁻³ kg.

Purification: It refers to the process of removing impurities or contaminants from a substance in order to make it cleaner, purer, or more refined. It also involves the elimination or reduction of unwanted substances or components that may be present in the original material.

According to the question, given data is:

Thickness of sheet t = 5 mm

Area A = 0.20 m²

Temperature T = 500°C

Diffusion coefficient ∝ = 1.0 × 10⁻⁸ m²/s

Concentration high pressure side [tex]C_A[/tex] = 2.4

Concentration low pressure side[tex]C_B[/tex]= 0.6 kg

from the question, we calculate the concentration gradient,

[tex]dc/dx = (C _A- C_B)/dt[/tex]

so, we substitute the values,

[tex]dc/dx[/tex] = (2.4 - 0.6)/ ( - 5 × 10⁻³)

[tex]dc/dx = -360[/tex]

Now, mass of hydrogen per hour that diffuse through a Palladium sheet,

M = -∝[tex]AT(dc/dx)[/tex]

where time t is 1 hour (3600 sec)

We substitute,

M = -(1.0 × 10⁻⁸) × 0.20 × 3600 (-360)

M = 0.002592

M = 2.592 × 10⁻³ kg per hour.

Therefore, the number of kilograms of hydrogen that pass per hour through a palladium sheet is approximately 2.592 × 10⁻³ kg.

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This question is incomplete, the complete question is;

The purification of hydrogen gas by diffusion through a palladium sheet was discussed in Section 5.3. Compute the number of kilograms of hydrogen that pass per hour through a 5-mm-thick sheet of palladium having an area of 0.20 m² at 500C.

Assume a diffusion coefficient of 1.0 × 10⁻⁸ m²/s, that the concentrations at the high- and low-pressure sides of the plate are 2.4 and 0.6 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.

Answer: Molar mass of [tex]NH_3[/tex] is 17.00 g and moles in 50.0 grams is 2.94.

Explanation:

Molar mass is defined as the mass in grams of 1 mole of a substance.

S.I Unit of Molar mass is gram per mole and it is represented as g/mol.

Atomic Mass of Nitrogen (N) = 14.00 g

Atomic Mass of Hydrogen (H) = 1.00 g

Molar mass of [tex]NH_3[/tex] = 1(14.00)+3(1.00) g = 17.00 g

According to avogadro's law, 1 mole of every substance contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles and weigh equal to its molecular mass.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

[tex]\text{Number of moles of }NH_3==\frac{50.0g}{17.00g/mol}=2.94moles[/tex]

Answer:

i think answer is B negative effects and benefits

A scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.

Bacterial pollution refers to the uncontrolled proliferation of bacteria in the surrounding environment and ecosystems.

In conclusion, a scientist that carelessly pours cultures of living microbes down the drain represents a type of bacterial pollution.

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Answer:

MgS + KI = K2S + MgI2

Answer:

Promethium

Pm 61

Discovered by Jacob .A. Marinsky

Answer:

3224 kJ/mol

Explanation:

The combustion of benzoic acid occurs as follows:

C₇H₆O₂ + 13/2O₂ → 7CO₂ + 3H₂O + dE

The change in temperature in the reaction is the change due the energy released, that is:

3.256K * (10.134kJ / K) = 33.00kJ are released when 1.250g reacts

To find the heat released per mole we have to find the moles of benzoic acid:

Moles benzoic acid -Molar mass: 122.12g/mol-:

1.250g * (1mol / 122.12g) = 0.0102 moles

The dE combustion per mole of benzoic acid is:

33.00kJ / 0.0102moles =

3224 kJ/mol

Answer:

partB: n=2N205

partc:17.20

Answer:

Explanation:

It processes the environment and sends out signals.

Explanation:

It is represented using the ideal gas equation , or PV = nRT, where P is the pressure in atmospheres, V is the volume in liters, n represents the quantity of particles in the container, T represents the temperature in Kelvin, and R is the ideal gas constant equal to 0.0821 liters atmospheres per moles Kelvin.

Answer:

B

Explanation:

Answer:

B

Explanation:

Edge 2022

Answer:

It is 98 degrees C.

Explanation:

Answer:

3 moles of NH₄Cl

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

NH₃(g) + HCl(g) → NH₄Cl(s) ΔH = –176 kJ

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Finally, we shall determine the number of mole of NH₄Cl produced when the change in enthalphy (ΔH) is –528 kJ. This can be obtained as follow:

From the balanced equation above,

1 mole of NH₄Cl where obtained when the change in enthalphy (ΔH) was –176 kJ.

Therefore, Xmol of NH₄Cl will be obtained when the change in enthalphy (ΔH) is –528 kJ i.e

Xmol of NH₄Cl = –528 / –176

Xmol of NH₄Cl = 3 moles

Thus, 3 moles of NH₄Cl where obtained from the reaction.

Answer:

A Brønsted-Lowry acid is any species that can donate a proton (H +) to another molecule. A Brønsted-Lowry base is any species that can accept a proton from another molecule. In short, a Brønsted-Lowry acid is a proton donor (PD), while a Brønsted-Lowry base is a proton acceptor (PA).

Answer:

20. ²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He

21. ⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca

Explanation:

20. ²⁴¹₉₅Am —> __ + ⁴₂He

Let ⁿₘX be the unknown.

Thus, the equation becomes:

²⁴¹₉₅Am —> ⁿₘX + ⁴₂He

Next, we shall determine n, m and X. This can be obtained as follow:

241 = n + 4

Collect like terms

n = 241 – 4

n = 237

95 = m + 2

Collect like terms

m = 95 – 2

m = 93

Thus,

ⁿₘX => ²³⁷₉₃X => ²³⁷₉₃Np

Therefore, the complete equation is:

²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He

21. __ —> ⁰₋₁β + ⁴²₂₀Ca

Let ʸₓZ be the unknown.

Thus, the equation becomes:

ʸₓZ —> ⁰₋₁β + ⁴²₂₀Ca

Next, we shall determine y, x and Z. This can be obtained as follow:

y = 0 + 42

y = 42

x = –1 + 20

x = 19

Thus,

ʸₓZ => ⁴²₁₉Z => ⁴²₁₉K

Therefore, the complete equation is:

⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca

Answer:

stress

Explanation:

people cn get stressed and not want to do work