Matching the probability of falling BETWEEN the following z-scores will give: 10 Between -0.34 and 0.34 is A) 0.2662. 2)Between 2.6 and 3.14 is B) 0.0039. 3) Between -3.04 and -0.56 is C) 0.8661.
How to Match the probability of falling BETWEEN the following z-scores.To match the probability of falling between the given z-scores, we need to use a standard normal distribution table or a calculator with a built-in normal distribution function.
Between -0.34 and 0.34
Using the standard normal distribution table, the area between -0.34 and 0.34 is 0.2662. Therefore, the answer is A) 0.2662.
Between 2.6 and 3.14
Using the standard normal distribution table, the area between 2.6 and 3.14 is 0.0039. Therefore, the answer is B) 0.0039.
Between -3.04 and -0.56
Using the standard normal distribution table, the area between -3.04 and -0.56 is 0.8661. Therefore, the answer is C) 0.8661.
Between -1.17 and 2.23
Using the standard normal distribution table, the area between -1.17 and 2.23 is 0.2865. Therefore, the answer is D) 0.2865.
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What is the volume of 1 hemisphere created by cutting this sphere exactly in half?
Answer:
B. 1152π cm^3
Step-by-step explanation:
I'm 99.9% sure that this is correct!
I'm really really sorry if it's not! please tell me if I'm wrong!
Find the volume of the prism.
The volume is
cubic feet.
Answer: 8/125 or 0.064
Step-by-step explanation:
volume of a cube is w^3
(2/5)*(2/5)*(2/5)
8/125 or 0.064
Circle A has radius AB and Circle X has radius XY. Points A and X are distinct points. Complete the statements below describing how to prove that the circles are similar.
Translate the center of circle A onto point __ __.
Then dilate the image of circle A about its center by a scale factor of __ __.
Translate the center of circle A onto point X.Then dilate the image of circle A about its center by a scale factor of XY/AB.
What is circle?A circle is a geometric shape consisting of points in a plane that are equidistant from a fixed point called the center, forming a closed curve.
According to the given information :
To prove that circles A and X are similar, we can follow the steps below:
1) Translate the center of circle A onto point X. This can be done by moving the center of circle A to point X while keeping the radius AB the same.
2) Dilate the image of circle A about its center by a scale factor of XY/AB. This means that we multiply the radius of the image of circle A by XY/AB. The result is a new circle that is similar to circle A and has the same center as circle X.
To summarize, the statements to complete are:
Translate the center of circle A onto point X.
Then dilate the image of circle A about its cent er by a scale factor of XY/AB.
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Translate the center of circle A onto point X.Then dilate the image of circle A about its center by a scale factor of XY/AB.
What is circle?
A circle is a geometric shape consisting of points in a plane that are equidistant from a fixed point called the center, forming a closed curve.
According to the given information :
To prove that circles A and X are similar, we can follow the steps below:
1) Translate the center of circle A onto point X. This can be done by moving the center of circle A to point X while keeping the radius AB the same.
2) Dilate the image of circle A about its center by a scale factor of XY/AB. This means that we multiply the radius of the image of circle A by XY/AB. The result is a new circle that is similar to circle A and has the same center as circle X.
To summarize, the statements to complete are:
Translate the center of circle A onto point X.
Then dilate the image of circle A about its center by a scale factor of XY/AB.
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For the first half of a baseball season, a player had 90 hits out of 270 times at bat. The player's batting average was
90
270
≈ 0. 333. During the second half of the season, the player had 64 hits out of 276 times at bat. The player's batting average was
64
276
≈ 0. 232. (Round your answers to three decimal places. )
(a) What is the average (mean) of 0. 333 and 0. 232?
The issue inquires to discover the normal (cruel) of two values:
0.333 and 0.232. To do this, able to essentially include the two values together and partition them by 2. Including the two values gives us:
0.333 + 0.232 = 0.565
Separating by 2 gives us:
0.565 / 2 = 0.2825
So the normal of 0.333 and 0.232 is 0.2825.
In any case, the issue inquires to circular our answer to three decimal places, which suggests we have to be circular 0.2825 to the closest thousandth. The third decimal put maybe a 2, which implies we circular down. Hence, the ultimate reply is roughly 0.283, adjusted to three decimal places.
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convert this denary number 33 to a binary number
Answer: 100001
Step-by-step explanation: The trick for binary is that it only uses 1 & 0 for its number system. It goes by a system where you take 1 and multiply by 2, then you multiply 2 by 2, and so forth. So 33 has one 32, and one 1.
90%; n = 10; σ is unknown; population appears to be normally distributed
With 90% confidence, we can estimate that the true population mean lies between 13.96 and 16.04.
If the population appears to be normally distributed, and σ (population standard deviation) is unknown, we can use a t-distribution to calculate the confidence interval.
To find the confidence interval, we need to use the following formula
CI = X' ± t_(α/2, n-1) × (s/√n)
Where X' is the sample mean, t_(α/2, n-1) is the critical t-value based on the desired confidence level (α) and the sample size (n-1), s is the sample standard deviation, and √n is the square root of the sample size.
Given that we have a confidence level of 90%, α = 0.10, and we need to find the critical t-value for a two-tailed test with 10-1=9 degrees of freedom. Using a t-distribution table, we find that the critical t-value is approximately 1.833.
Assuming that we have a sample mean of X' = 15 and a sample standard deviation of s = 2, we can now calculate the confidence interval
CI = 15 ± 1.833 × (2/√10)
CI = 15 ± 1.04
CI = (13.96, 16.04)
Therefore, with 90% confidence, we can estimate that the true population mean lies between 13.96 and 16.04.
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in a recent basketball game, shenille attempted only three-point shots and two-point shots. she was successful on 20% of her three-point shots and 30% of her two-point shots. shenille attempted 30 shots. how many points did she score?(2013 amc 12a
The probability of a score for a recent basketball game, shenille attempted only three-point shots and two-point shots is 18 points in the game. The answer is Option B.
Let x be the number of three-point shots and y be the number of two-point shots attempted by Shenille.
Then, we have:
x + y = 30 (total number of shots attempted)
Let's solve for one of the variables. For example, we can solve for x by subtracting y from both sides of the equation:
x = 30 - y
Now, we can express Shenille's points in terms of x and y:
Points = 3x + 2y
Substituting x = 30 - y, we get:
Points = 3(30 - y) + 2y
Points = 90 - y
Shenille's success rate for three-point shots is 20%, so the number of successful three-point shots she made is 0.2x. Similarly, the number of successful two-point shots she made is 0.3y.
Total points scored = (0.2x)(3) + (0.3y)(2)
Substituting x = 30 - y, we get:
Total points scored = (0.2(30 - y))(3) + (0.3y)(2
Total points scored = 18 + 0.4y
Now we need to maximize the total points scored by Shenille. Since she attempted 30 shots in total, we have:
y = 30 - x
Substituting this into the equation for total points, we get:
Total points scored = 18 + 0.4(30 - x)
Total points scored = 30 - 0.4x
This is a linear function, which is maximized at its endpoint. The maximum value of this function occurs at x = 0, which means Shenille attempted all two-point shots. In this case, y = 30, and the total points scored would be:
Total points scored = 0 + 0.3(30)(2)
Total points scored = 18
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The question is -
In a recent basketball game, Shenille attempted only three-point shots and two-point shots. She was successful on 20% of her three-point shots and 30% of her two-point shots. Shenille attempted 30 shots. How many points did she score?
(A) 12
(B) 18
(C) 24
(D) 30
(E) 36
Answer questions 1 to 5.
The overall shapes of the distributions are symmetric and right skewed
The overall shape of the distributionIn statistics, a distribution is considered symmetric if the right and left halves of the distribution are mirror images of each other.
In this case, the overall shape of the distribution is symmetric
The mean absolute deviationFrom the dot plot, we have the following readings
0,3,4,5,5,6,6,7,7,8,8
Using a graphing tool, we have
Mean absolute deviation = 1.79
The overall shape of the distributionA right-skewed distribution is a type of probability distribution where the majority of the data values are clustered on the left side of the distribution, while a few large values extend out to the right side.
In this case, the overall shape of the distribution is right skewed
The true statement about the distribution
From the histogram, the true statement about the distribution is that the distribution has an outlier
The datapoints for the last question are not given
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Evaluate the expression when x = 7 (4x + 9) - 4(x - 1) + x use the answer choices in the diagram
Answer:
The answer is 20
Step-by-step explanation:
when x=7
(4x+9)-4(x-1)+x
(4(7)+9)-4(7-1)+7
28+9 -4(6)+7
37+7-24
44-24
=20
From a horizontal distance of 80.0 m, the angle to the top of a flagpole is 18°. Calculate the height of the flagpole to the nearest tenth of a meter.
1. 24.7 meters
2. 76.1 meters
3. 26.0 meters
4. 25.3 meters
Answer:
The figure is omitted--please sketch it to confirm my answer.
Set your calculator to degree mode.
Let h be the height of the flagpole.
[tex] \tan(18) = \frac{h}{80} [/tex]
[tex]h = 80 \tan(18) = 25.994[/tex]
The height of the flagpole is approximately 26.0 meters. #3 is correct.
Need the answer to question 15
An equation in slope-intercept form for the perpendicular bisector of the segment with endpoints H (-3, 2) and K (7, -5) is y = -0.7x - 0.1.
How to determine an equation of this line?In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):
y - y₁ = m(x - x₁)
Where:
m represent the slope.x and y represent the points.First of all, we would determine the slope of this line;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (-5 - 2)/(7 + 3)
Slope (m) = -7/10
Slope (m) = -0.7.
At data point (-3, 2) and a slope of -7/10, a linear equation in slope-intercept form for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 2 = -7/10(x + 3)
y - 2 = -7x/10 - 21/10
y = -7x/10 - 21/10 + 2
y = -0.7x - 0.1
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James decided to share rocks collection. He gave 13 to Bill, 18 to lill, and 15 to mark. He had 32 left. How many rocks did he have to start with
James started with 78 rocks, as he gave away 46 rocks and had 32 rocks left.
The problem states that James gave away 13 rocks to Bill, 18 rocks to Lill, and 15 rocks to Mark. Therefore, the total number of rocks he gave away is the sum of these three amounts
13 + 18 + 15 = 46
This means that James had 46 fewer rocks after giving them away. The problem also states that he had 32 rocks left after giving some away. We can use this information to figure out how many rocks he started with by adding the number of rocks he had left to the number he gave away
46 + 32 = 78
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A pistol is accidently discharged vertically in the air. The height, h, of the bullet at time t seconds is recorded in the table below. Using an equation to model the data, find the height of the pistol after 10 seconds.
t (sec)
0
1
2
3
4
h (ft)
3
187
339
459
547
The height of the pistol after 10 seconds is 783 feet.
How to find the height of the pistol after 10 seconds.We can use the method of finite differences to find the degree of the polynomial function that models the data. The first differences are:
3, 18, 37, 56, 72
The second differences are:
15, 19, 19, 16
Since the second differences are constant, we know that the function that models the data is a quadratic function of the form:
h(t) = at² + bt + c
where a, b, and c are constants to be determined.
To find a, we can use the fact that the coefficient of t² in the quadratic function is equal to half of the second difference. Thus, we have:
a = 1/2(15) = 7.5
To find b, we can use the fact that the coefficient of t in the quadratic function is equal to the first difference minus twice the coefficient of t². Thus, we have:
b = 18 - 2(7.5) = 3
To find c, we can use the fact that the constant term in the quadratic function is equal to the value of h(0). Thus, we have:
c = h(0) = 3
Therefore, the equation that models the data is:
h(t) = 7.5t² + 3t + 3
To find the height of the pistol after 10 seconds, we can substitute t = 10 into the equation:
h(10) = 7.5(10)² + 3(10) + 3
h(10) = 750 + 30 + 3
h(10) = 783
Thus, the height of the pistol after 10 seconds is 783 feet.
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Gemma can't type 350 words in five minutes how many words can she type in 3/4 of an hour
Answer:
Gemma can type 3150 words in 3/4hr
Step-by-step explanation:
350 word------>five minutes
x words------->3/4hr
convert 3/4hr-minutes
3/4×60=45minutes
x word =350×45/5
x word=3,150 words
armer abe has a budget of $300 to build a rectangular pen to protect his rambunctious sheep. he decides that three sides of the pen will be constructed with chain-link fence, which costs only $1 per foot. farmer abe decides that the fourth side of the pen will be made with sturdier fence, which costs $5 per foot. find the dimensions of the largest area the pen can enclose.
Let x be the length of the pen and y be the width of the pen.
The total cost of the pen is given by:
Cost = 3x + 5y = 300
3x + 5y = 300
3x = 300 - 5y
x = (300 - 5y)/3
The area of the pen is given by:
Area = xy = (300 - 5y)/3 * y
three machines, a, b, c produce a large number of identical products. 60% of the products come from machine a, 30% from b and 10% from c. historical records indicate that 10% of the parts produced by machine a are defective, compared with 30% for machine b and 40% for machine c. what is the probability that a randomly chosen part is defective?
The probability that a randomly chosen part is defective is 0.16, or 16%.
The probability that a randomly chosen part is defective, we need to use the law of total probability.
Let [tex]$D$[/tex] be the event that a part is defective and let [tex]$M_i$[/tex] be the event that the part came from machine [tex]$i$[/tex], for [tex]$i = A, B, C$[/tex].
Then we have:
[tex]$P(D) = P(D|M_A)P(M_A) + P(D|M_B)P(M_B) + P(D|M_C)P(M_C)$[/tex]
60% of the products come from machine A, 30% from machine B, and 10% from machine C.
Therefore:
[tex]$P(M_A) = 0.6$[/tex]
[tex]$P(M_B) = 0.3$[/tex]
[tex]$P(M_C) = 0.1$[/tex]
The probability of a part being defective is 10% if it comes from machine A, 30% if it comes from machine B, and 40% if it comes from machine C.
Therefore:
[tex]$P(D|M_A) = 0.1$[/tex]
[tex]$P(D|M_B) = 0.3$[/tex]
[tex]$P(D|M_C) = 0.4$[/tex]
Substituting these values into the law of total probability, we get:
[tex]$P(D) = 0.1 \cdot 0.6 + 0.3 \cdot 0.3 + 0.4 \cdot 0.1 = 0.16$[/tex]
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As a nurse working in a hospital one of the jobs is to give appropriate doses of medicine
before surgery so the patient doesn't wake up during surgery. 4cc of this particular medicine is
meant for a 180lb man, what would be the correct dosage for a 145 lb. woman?
Answer:
the correct dosage of the medicine for a 145 lb. woman would be approximately 3.22 cc
Step-by-step explanation:
To calculate the correct dosage of the medicine for a 145 lb. woman, we can use the following formula:
dosage = (weight of patient / weight of reference patient) x reference dosage
where the weight of the reference patient is 180 lb. and the reference dosage is 4 cc.
Plugging in the given values, we get:
dosage = (145 / 180) x 4
= 3.22 cc (rounded to two decimal places)
Therefore, the correct dosage of the medicine for a 145 lb. woman would be approximately 3.22 cc. However, it's important to note that dosages of medications should only be determined by a qualified medical professional based on a number of factors, including the patient's weight, medical history, and current condition.
a slide caliper has 32 divisions per inch and a vernier of 8 divisions per major division. for this instrument the smallest resolution and uncertainty are:
The smallest resolution for this instrument is 1/256 inches.
This is also the instrument's uncertainty, as it represents the smallest measurable increment.
Let's first understand the terms mentioned:
Slide caliper:
A measuring instrument with a main scale and a vernier scale for taking precise measurements.
Divisions per inch:
The number of equal divisions on the main scale in one inch.
Vernier:
A short auxiliary scale that slides along the main scale, allowing for more precise readings.
Divisions per major division:
The number of equal divisions on the vernier scale that correspond to one division on the main scale.
Now, let's determine the smallest resolution and uncertainty for this instrument.
Calculate the main scale resolution
Main scale resolution = 1 inch / 32 divisions per inch = 1/32 inches
Calculate the vernier scale resolution
Vernier scale resolution = Main scale resolution / Vernier divisions per major division = (1/32 inches) / 8 = 1/256 inches.
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Solve the following problem. Be sure to show all the steps (V. E. S. T. ) and work in order to receive full credit.
The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.
Please help due tomorrow
The three numbers are 4, 8, and 14.
Let's use variables to represent the three numbers
Let x be the first number.
Then the second number is twice the first, so it is 2x.
The third number is 6 more than the second, so it is 2x + 6.
We know that the sum of the three numbers is 26, so we can write an equation:
x + 2x + (2x + 6) = 26
Now we can solve for x
5x + 6 = 26
5x = 20
x = 4
So the first number is 4.
To find the second number, we can use the equation we wrote earlier:
2x = 2(4) = 8
So the second number is 8.
To find the third number, we can use the other equation we wrote earlier
2x + 6 = 2(4) + 6 = 14
So the third number is 14.
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6. ____ tales and _____ tales
folk tales are storues with no known creator. they were originally passed down from one generation to another by word of mouth.
fairytales were often created to teach children behavior in an entertaining way.
what is the blank fictions/nonfictions?
The complete statement is folk tales and fairy tales
Both folk tales and fairy tales are types of fiction because they are imaginative stories that are not based on factual events or characters.
Explaining fictions and nonfictions?Folk tales
Folk tales are stories with no known creator. They were originally passed down from one generation to another by word of mouth. Folk tales are a type of traditional literature that is deeply rooted in the culture of a particular region or community.
They often feature supernatural elements, and their origins can be traced back many centuries.
Because they were passed down orally, different versions of the same tale may have developed in different regions, with variations in characters, plot, and theme.
Fairy tales
Fairy tales were often created to teach children behavior in an entertaining way. Fairy tales are a type of story that typically features magical creatures or events and often have a moral or lesson to teach. They were originally intended for both adults and children and were used as a way to teach moral values, societal norms, and important life lessons in an entertaining way.
The fairy tale genre has evolved over time, and modern fairy tales may have different themes and messages than traditional ones.
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HELP ASAPPPPPP Kendra is filling cone-shaped baskets, each with a height of 20 inches and a radius of 6 inches to use as
table decorations.
In terms of , what is the exact volume of each cone-shaped basket?
The exact volume of each cone-shaped basket is (240/π) cubic inches.
The formula for the volume of a cone is,
V = (1/3)πr^2h
Where,
V is the volume of the cone
π is the mathematical constant pi (approximately 3.14159)
r is the radius of the base of the cone
h is the height of the cone
In this case, the height of the cone-shaped basket is 20 inches and the radius is 6 inches. So, substituting these values into the formula,
V = (1/3)π(6^2)(20)
V = (1/3)π(36)(20)
V = (1/3)π(720)
V = (240/π) cubic inches
Hence, volume is (240/π) cubic inches.
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call a positive integer kinda-prime if it has a prime number of positive integer divisors. if there are $168$ prime numbers less than $1000$, how many kinda-prime positive integers are there less than $1000$?
There are 173 kinda-prime positive integer less than 1000.
To find the number of kinda-prime positive integer less than 1000, we'll follow these steps:
1. Understand the definition of a kinda-prime number: A positive integer is kinda-prime if it has a prime number of positive integer divisors.
2. Determine the number of prime numbers less than 1000: There are 168 prime numbers less than 1000, as given.
3. Determine the possible prime number of divisors: Since 168 is not too large, we only need to consider 2 and 3 as possible prime numbers of divisors for a kinda-prime number.
4. Analyze the cases:
Case 1: Kinda-prime numbers with 2 divisors (prime numbers)
All prime numbers have exactly 2 divisors (1 and itself). Thus, all 168 prime numbers less than 1000 are kinda-prime.
Case 2: Kinda-prime numbers with 3 divisors
Let N be a kinda-prime number with 3 divisors. Then, N = p^2 for some prime number p. To find the suitable prime numbers p, we need[tex]p^2 < 1000[/tex]. The prime numbers that meet this condition are 2, 3, 5, 7, and 11 (since 13^2 = 169 > 1000). Therefore, there are 5 additional kinda-prime numbers ([tex]2^2, 3^2, 5^2, 7^2, and 11^2[/tex]).
5. Add the total number of kinda-prime numbers from both cases: 168 + 5 = 173.
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[tex]$(\pi(1000)-1)+11=\boxed{177}$[/tex] "kind a-prime" positive integers less than $1000$.
Let [tex]$n$[/tex] be a positive integer with[tex]$k$[/tex] positive integer divisors.
If [tex]$k$[/tex] is prime, then.
[tex]$n$[/tex] is a "kind a-prime" integer.
[tex]$k$[/tex] must be of the form.
[tex]$k=p$[/tex] or [tex]$k=p^2$[/tex] for some prime [tex]$p$[/tex].
If [tex]$k=p$[/tex], then [tex]$n$[/tex] must be of the form.
[tex]$p^{p-1}$[/tex] for some prime [tex]$p$[/tex]. Since [tex]$p < 1000$[/tex], there are.
[tex]$\pi(1000)$[/tex]possible values of [tex]$p$[/tex].
[tex]$p=2$[/tex] gives [tex]$2^1$[/tex], which is not prime, so we have to subtract.
[tex]$1$[/tex] from [tex]$\pi(1000)$[/tex] to get the number of possible.
[tex]$p$[/tex].
[tex]$\pi(1000)-1$[/tex] values of [tex]$p$[/tex] that give a "kind a-prime" integer of this form.
If [tex]$k=p^2$[/tex], then [tex]$n$[/tex] must be of the form.
[tex]$p^{p^2-1}$[/tex] for some prime[tex]$p$[/tex].
There are.
[tex]$\pi(31)=11$[/tex] primes less than [tex]$31$[/tex], and each of them gives a different "kind a-prime" integer of this form.
Since [tex]$31^5 > 1000$[/tex], no primes larger than [tex]$31$[/tex]can be used to form a "kind a-prime" integer of this form.
[tex]$11$[/tex] possible values of [tex]$p$[/tex] that give a "kind a-prime" integer of this form.
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Given the following code fragment, which of the following expressions is always true?
int x;
scanf("%d", &x);
A) if( x = 1)
B) if( x < 3)
C) if( x == 1)
D) if((x/3) > 1)
If the expressions given, only C) if( x == 1) is always true.
In the given code fragment, the value of x is read from the user using the scanf() function. The value of x can be any integer value, depending on what the user enters. After the value of x is read, the program checks the value of x using a conditional statement (if statement) and executes the code inside the if statement only if the condition is true.
Expression A) if( x = 1) assigns the value 1 to x and then checks if x is true. This means that the condition is always true, because the assignment operation (=) returns the assigned value (in this case, 1), which is a non-zero value and therefore considered true in C programming.
Expression B) if( x < 3) checks if x is less than 3. This expression is not always true, as x can be any value greater than or equal to 3, in which case the condition would be false.
Expression C) if( x == 1) checks if x is equal to 1. This expression is always true if the user enters the value 1 for x.
Expression D) if((x/3) > 1) checks if the integer division of x by 3 is greater than 1. This expression is not always true, as x can be any value less than or equal to 3, in which case the result of the integer division by 3 would be 1 or less, in which case the condition would be false.
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the only expression that is always true in this code fragment is option C) if( x == 1).
The expression that is always true in this code fragment is option C) if( x == 1).
Option A) if( x = 1) is not always true because it is an assignment statement instead of a comparison statement. It assigns the value 1 to x instead of checking if x is equal to 1.
Option B) if( x < 3) is also not always true because x could be any number less than 3.
Option D) if((x/3) > 1) is not always true because x could be any number less than or equal to 3, in which case the expression would evaluate to false.
Therefore, the only expression that is always true in this code fragment is option C) if( x == 1).
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What is the slope of the line?
-2
-1
1
2
Answer: positive 2
Step-by-step explanation:
What is the argument of z = StartFraction 1 Over 16 EndFraction minus StartFraction StartRoot 3 EndRoot Over 16 EndFraction i?
To find the argument of the complex number z = 1/16 - (sqrt(3)/16)i, we need to find the angle that the complex number forms with the positive real axis in the complex plane.
We can start by finding the magnitude of z, which is the distance between the origin and the point representing z in the complex plane:
|z| = sqrt( (1/16)^2 + (sqrt(3)/16)^2 )
= sqrt(1/256 + 3/256)
= sqrt(4/256)
= 1/4
Next, we can find the argument of z using the formula:
arg(z) = tan^(-1)(Im(z)/Re(z))
where Im(z) is the imaginary part of z, and Re(z) is the real part of z.
In this case, we have:
Re(z) = 1/16
Im(z) = -(sqrt(3)/16)
Therefore, we get:
arg(z) = tan^(-1)(Im(z)/Re(z))
= tan^(-1)(-(sqrt(3)/16)/(1/16))
= tan^(-1)(-sqrt(3))
= -60° (in degrees)
So, the argument of z is -60 degrees (or -π/3 radians).
Answer:
A
Step-by-step explanation:
A rectangular plece of paper with length 28 cm and width 14 cm has two semicircles cut out of it, as shown below. Find the area of the paper that remains. Use the value 3.14 for 1, and do not round your answer. G ✓6 14 cm 0 00 H cm X 2023 McGraw Hill LLC As Rights Reserve
The area of the paper remains is 238.14 cm².
What is area?Area is the region bounded by a plane shape.
To calculate the area of the paper that remains, we use the formula below.
Formula:
Area of the paper that remains(A) = Area of the rectangle(LW)-Area of the two semi circles [π(W/2)²]A = LW- [π(W/2)²]................ Equation 1Where:
L = Length of the rectangleW = Width of the rectangle = Diameter of the semi circleFrom the diagram in the question,
Given:
L = 28 cmW = 14 cmSubstitute these values into equation 1
A = (28×14)-[3.14(14/2)²A = 392-153.86A = 238.14 cm²Hence, the area is 238.14 cm².
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a plumber works twice as fast as his apprentice. after the plumber has worked alone for 3 hours, his apprentice joins him and working together they complete the job 4 hours later. how many hours would it have taken the plumber to do the entire job by himself?
If after the plumber has worked alone for 3 hours, his apprentice joins him and working together they complete the job 4 hours later, it would take the plumber 9 hours to do the entire job by himself.
Let's start by assigning some b to represent the rate at which each person works. Let's say that the plumber's rate is P (in units of job per hour) and the apprentice's rate is A (also in units of job per hour). Since the plumber works twice as fast as the apprentice, we can write:
P = 2A
Next, let's think about how much work can be done in a certain amount of time. If the plumber works alone for 3 hours, he completes 3P units of work. When the apprentice joins him, they work together for another 4 hours to complete the entire job, which is a total of 7 hours of work. So, the amount of work done in those 4 hours is:
4(P + A)
We also know that the total amount of work is 1 (since it's one complete job). Putting this all together, we can write an equation:
3P + 4(P + A) = 1
We can simplify this to:
7P + 4A = 1
But we also know that P = 2A, so we can substitute that in:
7(2A) + 4A = 1
Simplifying this, we get:
18A = 1
So, A = 1/18. This means that the apprentice can complete 1/18 of the job in one hour. Since the plumber works twice as fast, he can complete 2/18 of the job (or 1/9) in one hour.
To find out how long it would take the plumber to do the entire job by himself, we can use the formula:
Time = Work / Rate
The entire job is 1, and the plumber's rate is 1/9. So:
Time = 1 / (1/9) = 9 hours
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HELP PLS EXPLAIN THISSSSS
Plugging in the values given into the expression, and simplifying, we would have our answer as: B. [tex]\frac{9}{25}[/tex]
How to Evaluate an Expression?To evaluate an expression, follow these steps:Identify the variables and constants in the expression.Substitute the given values for each variable in the expression.Simplify the expression until there are no more operations left.Given that, a = 5 and k = -2, substitute the values into the expression given and simplify:
[tex](\frac{3^2(5^{-2})}{3(5^{-1})} )^{-2}[/tex]
Simplify:
[tex](\frac{9 * \frac{1}{25} }{3* \frac{1}{5} } )^{-2}[/tex]
[tex](\frac{\frac{9}{25} }{\frac{3}{5} } )^{-2}\\\\(\frac{9}{25} * \frac{5}{3} } )^{-2}\\\\(\frac{3}{5} )^{-2}\\\\ = \frac{9}{25}[/tex]
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If r=0.5 m, A = ???
(Use the r key.)
The calculated value of the angular velocity of the object is 2 rad/s.
Calculating the angular velocityThe angular velocity, denoted by the Greek letter omega (ω), represents the rate of change of the angle with respect to time.
For an object moving in a circular path, the angular velocity is related to the linear speed and the radius of the circle by the equation:
ω = v/r
where v is the linear speed and r is the radius.
In this case, the radius is 0.5m and the speed is 1ms−1. Thus, the angular velocity is:
ω = v/r = 1/0.5 = 2 radians per second (rad/s)
Therefore, the angular velocity of the object is 2 rad/s.
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Complete question
An object moves in a circular path of radius 0.5m with a speed of 1ms−1. What is its angular velocity (A)?
If r = 0.5 m, A = ???
The volume of a cylinder is given by the formula v - pi^h, where r is the radius of the cylinder and h is the height.
Which expression represents the volume of this cylinder?
The expression that represents the volume of the cylinder is:
V = π[tex]r^{2}[/tex]h
What is cylinder?
A cylinder is a three-dimensional geometric shape that consists of two parallel circular bases of the same size and shape, and a curved lateral surface connecting the bases. The cylinder can be thought of as a tube or a can. The lateral surface of the cylinder is formed by "unrolling" a rectangular shape along the circumference of the base.
There appears to be a typographical error in the given formula for the volume of a cylinder. The correct formula is:
V = π[tex]r^{2}[/tex]h
where V is the volume of the cylinder, r is the radius of the circular base, and h is the height of the cylinder.
Using this formula, the expression that represents the volume of the cylinder is:
V = π[tex]r^{2}[/tex]h
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