The total momentum after collision = 60 kgm/s
Explanation:[tex]\begin{gathered} \text{Mass of Matt, m}_m=\text{ 80kg} \\ \text{Mass of Trey, m}_t=\text{ 90 kg} \end{gathered}[/tex]Before the collision:
Matt was moving 3 m/s to the east and Trey was moving 2 m/s to the west
[tex]\begin{gathered} \text{Initial speed of Matt, u}_m=\text{ 3m/s} \\ \text{Initial speed of Trey, u}_t=\text{ -2m/s (Since it is an opposite direction)} \end{gathered}[/tex]According to the principle of momentum conservation:
The total momentum before collision = The total momentum after collision
[tex]\begin{gathered} \text{Total momentum before collision = m}_mu_m+m_tu_t \\ \text{Total momentum before collision = 80(3) + 90(-2)} \\ \text{Total momentum before collision = 240 - 180} \\ \text{Total momentum before collision = 60 kgm/s} \end{gathered}[/tex]Since the total momentum before collision = Total momentum after collision
The total momentum after collision = 60 kgm/s
If we wanted to convert 594300 into scientific notation how would we shift the decimal point
Answer: 5.943 x 10^5
Explanation:
The given expression is
594300
To convert it to scientific notation, we would place a decimal point between the first and second digits. We would count the number of digits to the right of the decimal point. This number would represent the exponent to which it would be raised.
Looking at the given value, the decimal point is between 5 and 9. Number of digits to the right is 5. Thus, in scientific notation, it becomes
5.943 x 10^5
A convex mirror with a radius of curvature of 0.450 m is placed above theaisles in a store. Determine the image distance and magnification of acardboard box on the floor 2.75 m below the mirror. Is the image virtual orreal? Is the image inverted or upright?
Given:
The radius of the curvature of the convex mirror is
[tex]R=0.450\text{ m}[/tex]The distance of the object is
[tex]u=-2.75\text{ m}[/tex]Required: image distance and the magnification
Explanation:
first, we find the focal length of the mirror by the relation is
[tex]f=\frac{R}{2}[/tex]plugging the values in the above, we get
[tex]\begin{gathered} f=\frac{0.450\text{ m}}{2} \\ f=0.22\text{5 m} \end{gathered}[/tex]the mirror formula is given by
[tex]\frac{1}{f}=\frac{1}{v}+\frac{1}{u}[/tex]Plugging all the values in the above relation, we get
[tex]\begin{gathered} \frac{1}{0.225\text{ m}}=\frac{1}{v}+\frac{1}{-2.75\text{ m}} \\ \frac{1}{v}=\frac{1}{0.225}+\frac{1}{2.75} \\ \frac{1}{v}=\frac{2.75+0.225}{2.75\times0.225} \\ \frac{1}{v}=\frac{2.975}{0.618} \\ v=0.21\text{ m} \end{gathered}[/tex]the distance of the image is 0.21 m. it will be formed behind the mirror.
now calculate the magnification. magnification is given by
[tex]m=-\frac{v}{u}[/tex]Plugging all the values in the above, we get
[tex]\begin{gathered} m=-\frac{0.21m}{-2.75\text{ m}} \\ m=0.076\text{ } \end{gathered}[/tex]The magnification is 0.076.
the image formed by the convex mirror is virtual, inverted, and erect.
A 5.0 n force is applied to a 3.0 kg ball to change its velocity from +9.0m/s to +3.0m/s. The impulse on the ball is ____ n s
Take into account that the impulse is given by:
[tex]I=m\Delta v=m(v-v_o)[/tex]where,
m: mas of the ball = 3.0kg
v: final speed = 3.0m/s
vo: initial speed = 9.0m/s
replace the previous values into the formula for I and simplify:
Hence, the impulse is -18 kg*m/s (it's negative due to the force is opposite to the motion of the ball)
A cube of Iron, 0.0800 m on a side,has a density of 7874 kg/m^3.What is its mass?Skip(Unit = kg)
ANSWER:
4.03 kilograms.
STEP-BY-STEP EXPLANATION:
We have that the density is given by the following formula:
[tex]\begin{gathered} d=\frac{m}{v} \\ \text{ we solve for m:} \\ m=d\cdot v \end{gathered}[/tex]We can calculate the raisin by multiplying the voulem by the density, we can calculate the volume since it is a cube, the volume of the cube is calculated like this:
[tex]\begin{gathered} v=s^3 \\ \text{ replacing} \\ v=(0.0800)^3 \\ v=0.000512 \end{gathered}[/tex]Now if we can calculate the mass, like this:
[tex]\begin{gathered} m=7874\cdot0.000512 \\ m=4.03\text{ kg} \end{gathered}[/tex]The mass of the iron cube is 4.03 kilograms.
A tennis ball with a velocity of 11.3 m/s to the right is thrown perpendicularly at a wall. After striking the wall, the ball rebounds in the opposite direction with a velocity of −9.71 m/s to the left. If the ball is in contact with the wall for 0.011 s, what is the average acceleration of the ball while it is in contact with the wall? Answer in units of m/s^2
The average acceleration of the ball while it is in contact with the wall for 0.011 s is 1910 m / s²
a = ( v - u ) / t
a = Acceleration
v = Final velocity
u = Initial velocity
t = Time
u = 11.3 m / s
v = - 9.71 m / s
t = 0.011 s
a = ( - 9.71 - 11.3 ) / 0.011
a = 21.01 / 0.011
a = 1910 m / s²
Average acceleration can be called as the rate of change in velocity with respect to the change in time. Here change in time is not mentioned because the time starts from 0.
Therefore, the average acceleration of the ball while it is in contact with the wall for 0.011 s is 1910 m / s²
To know more about Average acceleration
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Two charges separated a distance of 1.0 meter exert a 2.0-N force on each other. If the charges are pushed to a separation of 1/3 meter, the force on each charge will be?
ANSWER:
18 N
STEP-BY-STEP EXPLANATION:
Force between two charge particles is given by:
[tex]F=k\frac{q_1\cdot q_2}{d^2}[/tex]We can make the following relationship:
[tex]\begin{gathered} F_1=k\frac{q_1\cdot q_2}{d_1^2} \\ \\ F_2=k\frac{q_1\cdot q_2}{d_2^2} \\ \\ \frac{F_2}{F_1}=\frac{k\frac{q_1\cdot q_2}{d_2^2}}{k\frac{q_1\cdot q_2}{d_1^2}} \\ \\ \frac{F_2}{F_1}=\frac{d_2^2}{d_1^2} \\ \\ \frac{F_{2}}{F_{1}}=\left(\frac{d_1}{d_2}\right)^2 \end{gathered}[/tex]Therefore, we can establish the following:
[tex]\begin{gathered} \frac{F_2}{F_1}=\left(\frac{d_1}{d_2}\right)^2 \\ \\ \text{ We replacing:} \\ \\ \frac{F_2}{2}=\left(\frac{1}{\frac{1}{3}}\right)^2 \\ \\ F_2=2\cdot9 \\ \\ F_2=18\text{ N} \end{gathered}[/tex]Therefore, the force will now be 18 N at each charge.
If it takes you 0.25 seconds to go 14.75 m, what is your speed?
Use the speed formula to find the answer. Remember that if a distance d is traveled during a time interval t, then the speed s is given by:
[tex]s=\frac{d}{t}[/tex]Substitute d=14.75m and t=0.25s:
[tex]s=\frac{14.75m}{0.25s}=59\frac{m}{s}[/tex]Therefore, your speed is:
[tex]59\frac{m}{s}[/tex]What is deuterium?A.a hydrogen atom with 1 proton and 2 neuronsB.a hydrogen atom with 1 proton and 1 neutronC.a helium atom with 2 proton 1 neutronD. The stable and product of fusion
Deuterium is an isotop of hydrogen that contains one proton and one neutron. The most common isotops of hydrogen contain one proton and one electron and no neutrons.
Europa, a satellite of Jupiter, has an orbital diameter of 1.34 × 109m and a period of 3.55 days. What is the mass of Jupiter?
Given,
The orbital diameter is
[tex]d=1.34\times10^9m[/tex]The radius is
[tex]r=\frac{d}{2}=\frac{1.34\times10^9}{2}=0.67\times10^9m[/tex]The time period is T=3.55 days=3.55x86400 sec.
We know,
[tex]\begin{gathered} T=\frac{2\pi r^{\frac{3}{2}}}{\sqrt[\square]{GM}}^{}^{} \\ \Rightarrow3.55\times86400=\frac{2\pi\text{ (0.67}\times10^9)^{\frac{3}{2}}}{\sqrt[]{6.67\times10^{-11}\times M}} \\ \Rightarrow9.4\times10^{10}=\frac{1.18\times10^{28}}{6.67\times10^{-11}M} \\ \Rightarrow M=1.89\times10^{27}kg \end{gathered}[/tex]The answer is
[tex]1.89\times10^{27}kg[/tex]Can I please get this problem asap? I am unsure how to do it.
Given:
Moment of intertia of first disk = 1.0 kg.m²
Spinning counterclockwise at = 20.0 rad/s
Rotational intertia of second disk = 4.0 kg.m²
Spinning clockwise at 15.0 rad/s
Let's find the angular velocity of the two disk system.
To find the angular velocity, apply the formula for angular momentum conserve:
[tex]I_1w_1-I_2w_2=(I_1+I_2)w[/tex]Rewrite the formula for angular velocity, w:
[tex]w=\frac{I_1w_1-I_2w_2}{I_1+I_2}[/tex]Where:
I₁ = 1.0 kg.m²
w₁ = 20.0 rad/s
I₂ = 4.0 kg.m²
w₂ = 15.0 rad/s
Input values into the equation and evaluate:
[tex]\begin{gathered} w=\frac{(1.0\times20.0)-(4.0\times15.0)}{1.0+4.0} \\ \\ w=\frac{20.0-60.0}{5.0} \\ \\ w=\frac{-40.0}{5.0} \\ \\ w=-8.0\text{ rad/s} \end{gathered}[/tex]Therefore, the angular velocity for the two disk system is 8.0 rad/s clockwise.
ANSWER:
8.0 rad/s clockwise.
what is the kinetic energy of a 1,719.44kg car that travels at 9.22 m/s?
Given data:
* The mass of the car is 1719.44 kg.
* The velocity of the car is 9.22 m/s.
Solution:
The kinetic energy of the car in terms of mass and velocity is,
[tex]K=\frac{1}{2}mv^2[/tex]where m is the mass of the car, v is the velocity of the car, and K is the kinetic energy,
Substituting the known values,
[tex]\begin{gathered} K=\frac{1}{2}\times1719.44\times(9.22)^2 \\ K=73083.42\text{ J} \\ K=73.08\times10^3\text{ J} \\ K=73.08\text{ kJ} \end{gathered}[/tex]Thus, the kinetic energy of the car is 73083.42 J or 73.08 kJ.
Which resistors in the circuit must always have the same current?B33cMDO A. C and DOB. A and DO C. A and BD. B and CPREVIOUSEXTD
Answer:
B. A and D
Explanation:
Two resistors have the same current if they are in series. It means that they are connected one after the other. On the other hand, they are in parallel when they are both connected to the source. For example:
Therefore, the resistors in series are A and D. So, they have the same current.
Then, the answer is:
B. A and D
A student is trying to determine if she can use Newton’s equations to calculate force in each of the situations shown in the table. Use what you know about predicting an object’s motion to choose the correct entry from each drop-down menu to complete the table.
In the first option, we have two masses, the gravitational constant and the distance between the masses, therefore we can calculate the force using Newton's law of universal gravitation.
In the second case, we only have the gravitational constant and no masses, therefore the force cannot be determined.
In the third case, we also don't have the masses, therefore the force cannot be determined.
The ACE towing company tows a disabled 1050-kg automobile off the road ata constant speed. If the tow line makes an angle of 10.0° with the vertical asshown, what is the tension in the line supporting the car?
Answer:
10,448.74 N
Explanation:
First, we know that the mass of the car is 1050 kg and the tow line makes an angle of 10.0° with the vertical and we want to know the tension in the line, so
The given
m = 1050 kg
θ = 10.0°
g = 9.8 m/s²
The unknown
T = ?
To write the formula, we need to draw a free body diagram as follows
They are moving at a constant speed, so there is no acceleration and the sum of the forces is equal to 0.
In the vertical direction, we have the following equation
[tex]\begin{gathered} T\cos\theta-mg=0 \\ T\cos\theta=mg \\ T=\frac{mg}{cos\theta} \end{gathered}[/tex]Therefore, the formula is
[tex]T=\frac{mg}{cos\theta}[/tex]Replacing the values, we get
[tex]T=\frac{(1050kg)(9.8\text{ m/s}^2)}{cos(10)}=10448.74\text{ N}[/tex]So, the answer is 10448.74 N
Question 11Not yetWavelength is determined by dividing a wave's speed by its frequency. If a wave has a frequency of 1 hertz and aspeed of 20 m/s, what is its wavelength?gi**76°F5)9:058/31
We have the next information
v=speed=20m/s
f=frequency=1 hz
we have the next formula
[tex]\lambda=\frac{v}{f}[/tex]we substitute the values
[tex]\lambda=\frac{20}{1}[/tex][tex]\lambda=20m[/tex]The wave length is 20m
What was the initial speed of a car if its speed is 40 m/s after 5 seconds of accelerating at -4 m/s²?A. 50 m/sB. 60 m/sC. 25 m/sD. 20 m/s
Explanation
The uniformly accelerated motion is a motion that is characterized for having a movement in a straight line and a constant acceleration and different of zero, to find the initial speed we can use the formula:
[tex]\begin{gathered} v_f=v_i+at \\ where\text{ v}_fis\text{ the final speed} \\ v_iis\text{ the initial speed} \\ a\text{ is the acceleration} \\ t\text{ is the time} \end{gathered}[/tex]so
Step 1
a)let
[tex]\begin{gathered} v_f=40\text{ }\frac{m}{s} \\ a=-4\frac{m}{s^2} \\ t=5\text{ s} \end{gathered}[/tex]b) now, replace in the formula and solve for vi
[tex]\begin{gathered} v_{f}=v_{i}+at \\ 40\text{ }\frac{m}{s}=v_i+(-4\frac{m}{s^2})(5) \\ 40=v_i-20 \\ add\text{ 20in both sides} \\ 40+20=v_i-20+20 \\ 60\text{ }\frac{m}{s}=v_i \end{gathered}[/tex]therefore, the answer is
B. 60 m/s
I hope this helps you
The period of a 440 Hz sound is
The period of a sound wave is given by the inverse of the frequency:
[tex]T=\frac{1}{f}[/tex]So, if the frequency is 440 Hz, the period is:
[tex]T=\frac{1}{440}=0.00227\text{ s}[/tex]Therefore the period is 0.00227 seconds.
I'm kind of confused on this question and #6 is just the continuation of the first question.
We are given that a marble is launched from a spring and we are asked to determine the initial speed as the marble leaves the spring. To do that we will consider the energy of the marble when it leaves the spring.
The spring has elastic potential energy due to its compression. The amount of energy is given by the following equation:
[tex]E_s=\frac{1}{2}ky^2[/tex]Where
[tex]\begin{gathered} k=\text{ constant of the spring} \\ y=\text{ compression} \\ E_s=\text{ energy of the spring} \end{gathered}[/tex]Now, all this energy is transferred to the marble and it is converted into kinetic energy of the marble. The kinetic energy is given by:
[tex]K=\frac{1}{2}mv^2[/tex]Where:
[tex]\begin{gathered} K=\text{ kinetic energy} \\ m=\text{ mass} \\ v=\text{ velocity} \end{gathered}[/tex]Due to conservation of energy, these quantities are equal, therefore:
[tex]E_s=K[/tex]Substituting the equations:
[tex]\frac{1}{2}ky^2=\frac{1}{2}mv^2[/tex]We can cancel out the 1/2:
[tex]ky^2=mv^2[/tex]Now we solve for "v", first by dividing both sides by the mass:
[tex]\frac{ky^2}{m}=v^2[/tex]Now we take the square root to both sides:
[tex]\sqrt{\frac{ky^2}{m}}=v[/tex]Simplifying we get:
[tex]y\sqrt[]{\frac{k}{m}}=v[/tex]Now. In the case of Neil, we have:
[tex]y_{\text{neil}}\sqrt[]{\frac{k_{neil}}{m}}=v_{\text{Neil}}[/tex]Now we substitute the corresponding values:
[tex](14\operatorname{cm})\sqrt[]{\frac{50.8\frac{N}{m}}{4.5g}}=v_{\text{Neil}}[/tex]Now we need to convert the 14 cm into meters. To do that we will use the following conversion factor:
[tex]100\operatorname{cm}=1m[/tex]Multiplying by the conversion factor we get:
[tex]14\operatorname{cm}\times\frac{1m}{100\operatorname{cm}}=0.14m[/tex]We also need to convert the 4.5 g into kg. To do that we will use the following conversion factor:
[tex]1000g=1\operatorname{kg}[/tex]Multiplying by the conversion factor we get:
[tex]4.5g\times\frac{1\operatorname{kg}}{1000g}=0.0045\operatorname{kg}[/tex]Now we substitute the new quantities:
[tex](0.14m)\sqrt[]{\frac{50.8\frac{N}{m}}{0.0045kg}}=v_{\text{Neil}}_{}[/tex]Now we solve the operations:
[tex]14.89\frac{m}{s}=v_{\text{Neil}}[/tex]Therefore, Neil's marble has an initial speed of 14.89 m/s. The same procedure is used to determine the initial speed of Gus's marble but substituting the corresponding spring constant and compression.
A 1-kilogram coconut falls out of a tree from a height of 12 meters.
Determine the coconut's potential and kinetic energy at each point
shown in the picture. Its speed is zero at point A.
A
3m
B
3m
с
3m
D
3m
E
Which of the following diagrams illustrates diffraction of a sound wave around a wall?A.B.C.D.
ANSWER:
STEP-BY-STEP EXPLANATION:
Sound is a wave that can't go through walls, but it can engulf them, because when the sound comes closer and hits the wall, we would get a doppler effect equal to the sound you hear when the sound source is moving towards you. This means that the sound waves reaching you have a shorter wavelength and a higher frequency.
Therefore, the correct answer is diagram D.
D. O8356.675 JE. 5056.506 J2. A bullet of mass 0.0555 kg is fired from a12 m tall building horizontally with a speedof 600 m/s. Calculate its mechanical energyjust after it is fired. (1 point)A. O 4399.788 JB. O 7576.232 JC. 2900.974 JD. O9996.527 JE. O 11970.179 J4
Given:
The mass of the bullet is m = 0.0555 kg
The height of the building is h = 12 m
The speed of the bullet is v = 600 m/s
To find the mechanical energy just after it fired.
Explanation:
Mechanical energy is the sum of potential energy and kinetic energy.
The potential energy of the bullet can be calculated by the formula
[tex]P.E.\text{ = mgh}[/tex]Here, g = 9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the potential energy will be
[tex]\begin{gathered} P.E.\text{ = 0.0555}\times9.8\times12 \\ =6.5268\text{ J} \end{gathered}[/tex]The kinetic energy can be calculated as
[tex]\begin{gathered} K.E.\text{ = }\frac{1}{2}mv^2 \\ =\frac{1}{2}\times0.0555\times(600)^2 \\ =\text{ 9990 J} \end{gathered}[/tex]Thus, the mechanical energy will be
[tex]\begin{gathered} E=P.E.+K.E. \\ =6.5268+9990 \\ =9996.5268\text{ J} \\ =9996.527\text{ J} \end{gathered}[/tex]Hence, the correct option is D
Gamma rays require _____ to be stopped.Question 13 options:paperglassaluminumlead
Gamma rays have so much penetrating power. They can easily penetrate obstacles . The penetrative power of gamma rays needs dense material like lead to stop it .
MS . madero sells tables . She charges $26 per square foot of the table stop and charges a fixed fee of $75 . Which equation could be used to find the area x , in square feet , of the tablestop of a table Ms. madero sells for $244 .
Given:
Charge per square foot of table stop = $26
Fixed charge = $75
Cost of table = $244
Let's write an equation that could be used to find the area x, in square feet of a tablestop.
Use the slope-intercept form:
y = mx + b
Let y represent cost of the table = $244
Let b represent the fixed fee = $75
Let m represent the charge per square foot = $26
Therefore, we have the equation:
244 = 26x + 75
The equation that could be used to find the area x, in square feet of thr tablestop of a table is:
26x + 75 = 244
ANSWER:
26x + 75 = 244
On a hot summer night (32°C), you are listening to a rock group in a stadium 350 m away. A friend of yours is sitting in an air-conditioned house across the country, listening to the broadcast on the radio. If the signal travels 30,000 km up to a satellite that retransmits it, who hears the concert first (speed of signal = 3.00 x 108 m/s)?
In ou case we have
[tex]\text{Temp}=331.4+(0.606\cdot32)=350.8\text{ m/s}[/tex]Then for the case of the friend
[tex]\text{Friend}=300,000,000\text{ m/s}[/tex]Therefore the person who hears the concert first is your friend
ANSWER
Your friend
A converging lens has a focal length of 0.36 m. If an object is placed at 0.21 m from the lens, where will its image be located?
ANSWER
[tex]0.504\text{ }m\text{ in front of the lens}[/tex]EXPLANATION
We want to determine the position where the image will be formed.
To do this, we apply the formula:
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]where f = focal length
u = distance of the object from the lens
v = distance of the image from the lens
Solving for v, we have the position that the image is formed:
[tex]\begin{gathered} \frac{1}{0.36}=\frac{1}{0.21}+\frac{1}{v} \\ \frac{1}{0.36}=\frac{v+0.21}{0.21v} \\ 0.21v=0.36(v+0.21) \\ 0.21v=0.36v+0.0756 \\ 0.21v-0.36v=0.0756 \\ -0.15v=0.0756 \\ v=\frac{0.0756}{-0.15} \\ v=-0.504\text{ }m \end{gathered}[/tex]Since this distance is negative, we say that the image formed is a virtual image and it is formed 0.504 m in front of the lens.
A. O 33.836 kg m/sB. O31.903 kg m/sC. O 12.883 kg m/sD. O 19.2 kg m/sE. O 23.979 kg m/s6. An object of mass 9.5 kg was acted by a force of 14.2 N for3.6 seconds. If its initial speed was 4.0 m/s,calculate its final speed. (1 point)A) 14.189B) 16.584C) 2.015D)3.015E) 9.381
Given:
The mass of the object is m = 9.5 kg
The force acting on it is F = 14.2 N
The time duration is t = 3.6 s
The initial speed is
[tex]v_i=\text{ 4 m/s}[/tex]To calculate the final speed.
Explanation:
An impulse of an object is calculated as
[tex]Impulse\text{ = F}\times t[/tex]It can also be written as
[tex]\begin{gathered} Impulse\text{ = change in momentum} \\ =mv_f-mv_i \end{gathered}[/tex]So, the final velocity can be calculated by equating both the formula
[tex]\begin{gathered} F\times t=mv_f-mv_i \\ mv_f=F\times t+mv_i \\ v_f=\frac{(F\times t)+mv_i}{m} \end{gathered}[/tex]On substituting the values, the final speed will be
[tex]\begin{gathered} v_f=\frac{(14.2\times3.6)+(9.5\times4)}{9.5} \\ =9.381\text{ m/s} \end{gathered}[/tex]Thus, the correct choice is E
which of the following is most suitable when handling nuclear fuel?
The best suitable equipment for handling nuclear fuel is lab coat,
The gap between electrodes in a spark plug is 0.0006 m. Producing an electric spark in a gasoline-air mixture requires an electric field of 3.0x10^6 V/m. What minimum potential difference must be supplied by the ignition circuit to start a car?
In order to find the necessary potential difference to start the car, we can just multiply the electric field required by the gap between electrodes.
So we have:
[tex]\begin{gathered} V=E\cdot d \\ V=3\cdot10^6\cdot0.0006 \\ V=1800 \end{gathered}[/tex]So the necessary potential difference is 1800 V.
X-rays typically have a wavelength of around 1x10^(-9)m. What is the frequency of the X-ray
The speed v of a wave is related to its wavelength λ and its frequency f as follows:
[tex]v=\lambda f[/tex]X-rays are electromagnetic radiation, whose speed is the same as the speed of light c:
[tex]c\approx300,000,000\frac{m}{s}[/tex]Isolate f from the equation and substitute the values for the speed and the wavelength to find the frequency of x-rays:
[tex]\begin{gathered} f=\frac{v}{\lambda} \\ =\frac{300,000,000\frac{m}{s}}{1\times10^{-9}m^{}} \\ =3\times10^{17}\frac{1}{s} \\ =3\times10^{17}Hz \end{gathered}[/tex]Therefore, the frequency of the X-ray, is:
[tex]3\times10^{17^{}}Hz[/tex]So I got stuck on this question
The initial speed is 0, then while he falls down the speed increase