Mean and standard deviation of sample proportions

Suppose that 35% of students in a school can sing their national anthem correctly. The music teacher takes an SRS of 30 students from the population of 750 students at the school and finds that 40% of students sampled can sing their national anthem correctly. The teacher plans to take more samples like this. Let p represent the proportion of a sample of 30 students in the school who can sing their national anthem correctly. What are the mean and standard deviation of the sampling distribution of p?​

Mean And Standard Deviation Of Sample Proportions Suppose That 35% Of Students In A School Can Sing Their

Answers

Answer 1

Answer: D

Suppose that 35\%35%35, percent of students in a school can sing their national anthem correctly. The music teacher takes an SRS of 303030 students from the population of 750750750 students at the school and finds that 40\%40%40, percent of students sampled can sing their national anthem correctly. The teacher plans to take more samples like this.

Step-by-step explanation: Khan Academy Explanation

Answer 2

The mean and standard deviation is given by -

μ = 0.35 and σ = 0.09.

What is mean, median and mode in statistics?Mean : The "average" number; found by adding all data points and dividing by the number of data points.Median : The middle number; found by ordering all data points and picking out the one in the middle (or if there are two middle numbers, taking the mean of those two numbers).Mode : The most frequent number—that is, the number that occurs the highest number of times.

Given is that suppose that 35% of students in a school can sing their national anthem correctly. The music teacher takes an SRS of 30 students from the population of 750 students at the school and finds that 40% of students sampled can sing their national anthem correctly. The teacher plans to take more samples like this. Let {p} represent the proportion of a sample of 30 students in the school who can sing their national anthem correctly.

The standard deviation is given by → [tex]$\sigma={\sqrt {\frac {\sum(x_{i}-{\mu})^{2}}{N}}}[/tex]

        where -

        {σ} = population standard deviation

        {N} = the size of the population

        x{i} = each value from the population

        {μ} = the population mean

The mean and standard deviation is given by -

μ = 0.35

σ = √(0.35)(0.65)/(30) = 0.48/5.5 = 0.09

σ = 0.09

Therefore, the mean and standard deviation is given by -

μ = 0.35 and σ = 0.09

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Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answer:

[tex]\bold{-2x-20}[/tex]

Step-by-step explanation:

Hi there!

Let's clarify what the Distributive Property is.

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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Answers

Answer:

222 mL

Step-by-step explanation:

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Example 3
he two In a class of 60 students, 46 passed Biology
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Let U = students in the class
cps​

Answers

Answer:

28 students passed in both subjects.

Step-by-step explanation:

We solve this question treating each event as a Venn set.

I am going to say that:

Event A: Passed Biology.

Event B: Passed Chemistry.

46 passed Biology

This means that [tex]A = 46[/tex]

42 passed Chemistry.

This means that [tex]B = 42[/tex]

Every student passed at least one of the two subjects.

This means that [tex]A \cup B = 60[/tex]

How many students passed in both subjects?

This is:

[tex]A \cap B = A + B - A \cup B[/tex]

From the values we have above

[tex]A \cap B = 46 + 42 - 60 = 28[/tex]

28 students passed in both subjects.

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