Myiah rides her bike from home to the park to meet a friend. When she arrives at the park, Myiah and her friend sit at a park bench and talk. Myiah then rides her bike home at a slower rate. Which graph represents this situation?
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Myiah rides her bike from home to the park so there is a distance from home, then she and her friends stay some time at the park, then the distance vs time is a horizontal line because they don't move while the time is moving. Finally, she rides her bike home at a slower rate, so she takes more time to get home.
In conclusion, the graph that represents this situation is the third.
Related Questions
Soccer: The rules for the soccer state that the playing field must be from 100 to 120 yards long and 55 to 75 yards wide. The 1999 Women's World Cup was played at the Rose Bowl on a playing field 116 yards long and 72 yards wide. the diagram below shows the smallest possible soccer field, the largest possible soccer field, and the soccer field at the Rose Bowl.
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Given:
b) The 1999 Women's World Cup was played at the Rose Bowl on a playing field 116 yards long and 72 yards wide.
The area is given as,
[tex]\begin{gathered} A_1=\text{Length}\times Width \\ =116\times72 \\ =8352\text{ square yd} \end{gathered}[/tex]The largest field have length 120 yd and width 75 yd,
The area is given as,
[tex]\begin{gathered} A_2=Length\times Width \\ =120\times75 \\ =9000\text{ square yd} \end{gathered}[/tex]The percentage increase is given as,
[tex]\begin{gathered} \text{Percentage increase=}\frac{A_2-A_1}{A_1}\times100 \\ =\frac{9000-8352}{8352}\times100 \\ =\frac{648}{8352}\times100 \\ =7.7586\text{ } \\ =7.8(\text{nearest tenth of percent)} \end{gathered}[/tex]Answer: Percentage increase is 7.8 %
(practice test help!!)In the image below, DE || BC. Find the measure of EC. Set up a proportion and solve for the measure. Show your work, round to the nearest tenth, and label your answer.
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we are given two similar triangles, therefore, we have the following proportions:
[tex]\frac{2}{9}=\frac{EC}{AE}[/tex]Solving for EC by multiplying both sides by AE:
[tex]\frac{2}{9}\times AE=EC[/tex]replacing the value of AE:
[tex]\frac{2}{9}\times4=EC[/tex]Solving the operation:
[tex]\frac{8}{9}=EC[/tex]In decimal notation we get:
[tex]0.9=EC[/tex]x = 8 is a solution for the equation x/2 = 4 true or false
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x/2 =4
Multiply each side of the equation by 2:
(x/2) 2 = 4 (2)
x = 8
True
A flight costs $12,500 to operate, regardless of the number of passengers. Each ticket costs $131. Express profit, P, as a linear function of the number of passengers, n, on the fight. Profit = Revenue - CostP=
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SOLUTION
Write out the given information
[tex]\begin{gathered} \text{Fight cost=\$12,500} \\ \text{Cost per ticket=\$131} \\ \text{Number of passengers =n} \end{gathered}[/tex]The profit is given by
[tex]profit=revenue-\cos t[/tex]From the data given above, the revenue will be
[tex]\begin{gathered} \text{ Revenue=cost per ticket x number of passengers } \\ \text{hence} \\ \text{ Revenue=\$131}\times n=131n \end{gathered}[/tex]Hence
[tex]\text{Profit}=131n-12500[/tex]Therefore
P=131n - 12 500
1 3/4 converted into percents
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Given:
[tex]1\frac{3}{4}[/tex]The decimal number is:
[tex]\begin{gathered} \frac{3}{4}=0.75 \\ 1\frac{3}{4}=1+0.75=1.75 \end{gathered}[/tex]To turn this to percent, we know that:
1 = 100%
and
[tex]\frac{3}{4}=0.75*100=75[/tex]3/4 = 75%
Therefore:
[tex]1\frac{3}{4}=(1+0.75)*100=100+75=175[/tex]The answer is: 175%.
FIND SIDE a. Round to the nearest tenth.A. 36.9B. 31.3C. -18.1D. 13.3
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Side a= BC =?
Then
BC /34 = Cos 23°
BC = 34 • Cos 23°
. = 31.29
rounded it gives
SOLUTION IS
OPTION B) 31.3
The fat cat weighs twice as much as the tiny dog.There are two unknowns in this problem, the weight of the cat and the weight of the dog,Both unknowns need to be described with the same variable. Do not use two differentletters. Give the variable to the unknown we know the least about, then use the given info tocreate an expression for the second unknown using the same variable.1. We know least about the weight of the dog, so let x equal the weight of the dog. Definethe weight of the cat in terms of x. See earlier examples if you need help.2. Write the simplified expression that models the combined weight of the cat and the dog.
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From the instructions on point number 1, let x be the weight of the dog.
Since the cat weighs twice as much as the dog, then the weight of the cat is equal to 2x.
The combined weight of the cat and the dog is the sum of their individual weights. Therefore, it is equal to 2x+x, which is equal to 3x.
Solve t/−5=−7.What is t?
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In the graphic below,
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The external angle is suplementary to the internal angle close to it. We also know that the sum of all the internal angles of the triangle are equal to 180 degrees, this means that the angle "a" is suplementary to the sum of the angles "b" and "c". Through this logic, we can conclude that since:
[tex]\begin{gathered} \angle d=180-\angle a \\ \angle b+\angle c=180-\angle a \end{gathered}[/tex]Then we can conclude that:
[tex]\angle d=\angle b+\angle c[/tex]Therefore the statement is true, the exterior angle is equal to the sum of its remote interior angles.
Let's use an example:
On this example, the external angle is 120 degrees, therefore the sum of the remote interior angles must also be equal to that. Let's try:
[tex]x=75+45=120[/tex]The sum of the remote interior angles is equal to the external angle.
The following data set represents the math test scores for a class of 20 students.90, 85, 95, 100, 100, 90, 100, 70, 100, 85, 80, 95, 80, 100, 85, 75, 100, 90, 90, 75How many outliers are in this data set?Enter your answer as a number.Provide your answer below:
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Given:
The data set represents the math test scores for a class of 20 students.
As shown most of the scores are between 80 and 100
The outlier will be the score that is more or less of most of the data
The least score = 70
So, the answer will be:
the number of the outliers = 1
Write the function that describes the transformation from Figure KLMN to Figure K'L'M'N'.
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Dilation centered at the origin whose scale factor is k=1/2
1) We need to locate two points from each figure, the pre-image and the image.
2) So, let's locate them:
K(0,11) K' (0, 5.5)
L (-9,3) L' (-4.5, 1.5)
3) As we can see the pre-image is larger than the image. And so, the scale factor of this Dilation has to be lesser than 1.
4) Therefore, the answer is:
Dilation centered at the origin whose scale factor is k=1/2
Match the correct value with each expression. Answers may be used more than once. (-8) – 2 (-8) + 2 (-2)-(-8) 11 (-2) + (-8) (-8) - (-2) :: -16 :: -10 :: 10 * 16
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The values of the expression can be determined as,
[tex]\begin{gathered} (-8)-2=-8-2=-10 \\ (-8)+2=-8+2=-6 \\ (-2)-(-8)=-2+8=6 \\ (-2)+(-8)=-2-8=-10 \\ (-8)-(-2)=-8+2=-6 \end{gathered}[/tex]Thus, the above expression gives the required values.
Find the area of the quadrilateral with the given coordinates A(-2, 4), B(2, 1),C(-1, -3), D(-5, 0).25 square units20 square units10 square units50 square units
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Determine the length of side AB.
[tex]\begin{gathered} AB=\sqrt[]{(-2-2)^2+(4-1)^2} \\ =\sqrt[]{16+9} \\ =5 \end{gathered}[/tex]Determine the length of BC.
[tex]\begin{gathered} BC=\sqrt[]{(-1-2)^2+(-3-1)^2} \\ =\sqrt[]{9+16} \\ =5 \end{gathered}[/tex]Determine the length of CD.
[tex]\begin{gathered} CD=\sqrt[]{(-5+1)^2+(0+3)^2} \\ =\sqrt[]{16+9} \\ =5 \end{gathered}[/tex]Determine the length of side DA.
[tex]\begin{gathered} DA=\sqrt[]{(-2+5)^2+(4-0)^2} \\ =\sqrt[]{9+16} \\ =5 \end{gathered}[/tex]All sides of quadilateral are equal. So quadilateral is a square or rhombus with side of 5 units.
Determine the length of diagonal AC and BD.
[tex]\begin{gathered} AC=\sqrt[]{(-1+2)^2+(-3-4)^2} \\ =\sqrt[]{1+49} \\ =\sqrt[]{50} \end{gathered}[/tex][tex]\begin{gathered} BD=\sqrt[]{(-5-2)^2+(0-1)^2} \\ =\sqrt[]{49+1} \\ =\sqrt[]{50} \end{gathered}[/tex]Diagonals are equal so quadilateral is a square.
Determine the area of square with side 5.
[tex]\begin{gathered} A=5\cdot5 \\ =25 \end{gathered}[/tex]So area is 25 square units.
A spherical storage tank has a length of radius of 2 ft. What is the surface area (in square feet) of the storage tank? Use the calculator value of . (Round your answer to two decimal places.)ft2The storage tank needs to be painted, and you can only purchase full pints of rust-proofing paint. Determine the number of pints of paint that must be purchased to paint the tank if 1 pint covers approximately20 ft2.(Round your answer up to the nearest whole number.)pt
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The formula for the surface area (A) of a sphere is,
[tex]A=4πr^2[/tex]Given:
[tex]r=2ft[/tex]Therefore,
[tex]A=4\pi(2)^2=50.26548\approx50.27(2\text{ decimal places\rparen}[/tex]Hence, the surface area of the sphere is 50.27ft².
Given that
[tex]\begin{gathered} 1pint=20ft^2 \\ \therefore50.27ft^2=\frac{1pint\times50.27}{20}=\frac{50.27pint}{20}=2.5135\approx3pt \end{gathered}[/tex]Therefore, you need to purchase 3pints.
Which graph below represents the equation 3x + 4y = 12?
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ANSWER :
Graph A
EXPLANATION :
From the problem, we have the equation :
[tex]3x+4y=12[/tex]Get the x and y-intercepts :
Let x = 0,
3(0) + 4y = 12
4y = 12
y = 12/4
y = 3
The y-intercept is (0, 3)
Let y = 0
3x + 4(0) = 12
3x = 12
x = 12/3
x = 4
The x-intercept is (4, 0)
The option that a line intersects the x-axis at (4, 0) and the y-axis at (0, 3) is graph A
The missing sequence (I tried to many times not getting it)
Answers
Answer
Missing term in the sequence = 36
Explanation
Looking at the sequence, we can see that it is a geometric progression.
And the general form for the nth term of an geometric progression is
aₙ = a (rⁿ⁻¹)
where
aₙ = nth term = 3rd term
a = first term = 4
n = number of terms = 3
r = common ratio = ratio of consecitive terms = (second term)/(first term) = (fifth term)/(fourth term) = (12/4) = (324/108) = 3
For the third term now,
aₙ = a (rⁿ⁻¹)
a₃ = 4 (3³⁻¹)
a₃ = 4 (3²)
a₃ = 4 (9)
a₃ = 36
Hope this Helps!!!
Robin and Dimitri want to build a pool in their backyard. The length and width of the pool can be represented by the equation feet. What is the area of Robin and Dimitri's pool? You must show your work, and include your units of measurement.
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Solution
The given function is
[tex]f(x)=(x-3)(x+4)[/tex]The area is given as:
[tex]\begin{gathered} f(x)=x(x+4)-3(x+4) \\ f(x)=x^2+4x-3x-12 \\ f(x)=x^2+x-12 \end{gathered}[/tex]Therefore the area is
[tex]f(x)=x^{2}+x-12[/tex]The weekly salaries (In dollars) for 8 employees of a small business are given below.(Note that these are already ordered from least to greatest.)554, 626, 649, 702, 718, 855, 896, 1184Suppose that the $1184 salary changes to $968. Answer the following.(a) What happens to the median?(b) What happens to the mean?it decreases by s]It increases by siIt stays the same.It decreases by saIt increases by siIt stays the same.Х?
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Answer:
a) The Median stays the same
b) The Mean decreases by $27
Explanation:
We were given the following weekly salaries:
[tex]554,626,649,702,718,855,896,1184[/tex]The mean & median for the data above is shown below:
[tex]\begin{gathered} Mean=\frac{\text{Sum of elements}}{Number\text{ of elements}} \\ Mean=\frac{554+626+649+702+718+855+896+1184}{8} \\ Mean=\frac{6184}{8} \\ Mean=773 \\ \\ Median=\frac{702+718}{2} \\ Median=\frac{1420}{2} \\ Median=710\text{ (the middle number in the array)} \end{gathered}[/tex]Suppose that the $1184 salary changes to $968, we have:
[tex]\begin{gathered} Mean=\frac{\text{Sum of elements}}{Number\text{ of elements}} \\ Mean=\frac{554+626+649+702+718+855+896+968}{8} \\ Mean=\frac{5968}{8} \\ Mean=746 \\ \\ \text{The Median remains unchanged since the position of the salary changed is the same} \end{gathered}[/tex]Therefore,
a) The Median stays the same
b) The Mean decreases by $27
What is the greatest common factor of 40a^2b and 48ab^2?
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Answer:
The greatest common factor GCF is;
[tex]8ab[/tex]Explanation:
Given the terms;
[tex]\begin{gathered} 40a^2b \\ \text{and} \\ 48ab^2 \end{gathered}[/tex]Let us expand each of the terms;
[tex]\begin{gathered} 40a^2b=2\times2\times2\times5\times a\times a\times b \\ 48ab^2=2\times2\times2\times2\times3\times a\times b\times b \\ \end{gathered}[/tex]then we will write out the greatest common factor;
[tex]\begin{gathered} \text{GCF}=2\times2\times2\times a\times b=8ab \\ \text{GCF}=8ab \end{gathered}[/tex]Therefore, the greatest common factor GCF is;
[tex]8ab[/tex]
During the first year of opening a law firm , a lawyer served 46 clients .in the second year, his number grew to 58 . If the linear trend continue, write an equation that gives the number of clients (c) the lawyer will have have (t) years after beginning the firm
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The equation of a line with slope m and y-intercept b in slope-intercept form is:
[tex]y=mx+b[/tex]The slope represents the rate of change of the variable y with respect to the variable x, and the y-intercept represents the initial value of y when x=0.
In this case, let c represent the number of clients as a function of time, and let t represent time in years.
Then, c=46 when t=1 and c=58 when t=2.
Use the slope formula to find the slope of the line that passes through the points (1,46) and (2,58) in a c vs t graph:
[tex]\begin{gathered} m=\frac{c_2-c_1}{t_2-t_1} \\ =\frac{58-46}{2-1} \\ =\frac{12}{1} \\ =12 \end{gathered}[/tex]Replace 12 for the slope and substitute a pair of corresponding values of c and t into the equation to find the initial value. For instance, substitute t=1 and c=46:
[tex]\begin{gathered} c=12t+b \\ \Rightarrow46=12(1)+b \\ \Rightarrow46-12=b \\ \Rightarrow34=b \\ \therefore b=34 \end{gathered}[/tex]To find the equation that gives the number of clients the lawyer will have as a function of time, replace 12 for the slope and 34 for the initial value:
[tex]c=12t+34[/tex]We can verify that we obtain the correct values for c when t=1 and t=2:
[tex]\begin{gathered} c_1=12(1)+34=12+34=46 \\ c_2=12(2)+34=24+34=58 \end{gathered}[/tex]Therefore, the equation that gives the number of clients (c) the lawyer will have (t) years after beginning the firm, is:
[tex]c=12t+34[/tex]
All three of a triangle’s angle bisectors meetat a single point. This point is called the_________________.incenterorthocentercircumcentercentroid
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The point where all three of a triangle's angle bisectors meet is called the incenter.
The incenter is equally distant from all the sides of a triangle as well. It is also the point that serves as the centre of a circle to be inscribed in a triangle
Therefore, the correct answer is incenter.
What is the domain ?A.All real NumbersB Y≥-4C. Y>-4D X≤4
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x ≤4
1) The Domain is the set of entries, a function is defined.
Examining the graph we can state the Domain is:
Note there are three ways to represent, formally this set Domain:
D =(-∞, 4] or ]-∞, 4] or {D ∈ R :-∞
Simply put
x ≤4
SAT scores were originally scaled so that the scores for each section were approximately normally distributed with a mean of 500 and a standard deviation of 100. Use the empirical rule to estimate the probability that a randomly-selected student gets a section score between 400 and 700.
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Given:
a.) SAT scores were originally scaled so that the scores for each section were approximately normally distributed with a mean of 500 and a standard deviation of 100.
b.) Use the empirical rule to estimate the probability that a randomly-selected student gets a section score between 400 and 700.
What does Cofer use to symbolize a lack of freedom in "Primary Lessons"?speaking Spanishthe gypsy lifestylethe cool New Jersey apartmentcolor coding on the island
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1) To find the solution, we have to substitute the values in the equation.
2) Substituting x = 1
[tex]\begin{gathered} 2x-4\ge2 \\ 2\cdot1-4\ge2 \\ -2\ge2\text{ - FALSE} \end{gathered}[/tex]3) Substituting x = 2
[tex]\begin{gathered} 2x-4\ge2 \\ 2\cdot2-4\ge2 \\ 4-4\ge2 \\ 0\ge2-\text{FALSE} \end{gathered}[/tex]4) Substituting x = 3
[tex]\begin{gathered} 2x-4\ge2 \\ 2\cdot3-4\ge2 \\ 6-4\ge2 \\ 2\ge2-\text{TRUE} \end{gathered}[/tex]5) Substituting x = 4
[tex]\begin{gathered} 2x-4\ge2 \\ 2\cdot4-4\ge2 \\ 8-4\ge2 \\ 4\ge2-TRUE \\ \end{gathered}[/tex]6) The solutions are x = 3 and x = 4.
Alternative C - {3,4}.
Answer:
color coding on the island
Step-by-step explanation:
A carpenter cut a 12 ft board into two pieces. One piece is three feet less than twice theshorter piece. How long is each piece?Use X In the equation
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Let the shorter piece be called "x"
The longer piece is "3" less than TWICE shorter, so we can write the equation:
Longer is:
[tex]2x-3[/tex]Since the board is 12 feet, we can say:
Longer + Shorter = 12
we know longer = 2x - 3 and shorter is x, so we can write:
(2x - 3) + (x) = 12
We simply solve this equation for "x":
[tex]\begin{gathered} 2x-3+x=12 \\ 3x-3=12 \\ 3x=12+3 \\ 3x=15 \\ x=\frac{15}{3} \\ x=5 \end{gathered}[/tex]So, shorter piece (x) is 5 feet
Longer piece, thus, is 12 - 5 = 7 feet
-6x = 12
/-6. /-6
x = -2
Which graph shows the solution to the system of linear inequalities?x+5y25vs2x+46Save and ExitNextSubmitMark this and retum
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Given inequalities are
[tex]\begin{gathered} x+5y\ge5 \\ y\leq2x+4 \end{gathered}[/tex]The solution region is shown below.
J(2, 2), K(7,4), L(9. - 2), M(3. – 1) Polygon + Redo 110 2 -- 2 10 10 a
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Join the points and you will get the polygon.
If c = 13 and angle B = 25degrees, find a.BсAСьa = [ ? ]Round to the nearest tenth.Enter
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To determine the length of side "a", given that we know the length of the hypothenuse (side c) and the measure of angle B, you have to apply the trigonometric ratio cosine. Which is defined as:
[tex]\cos \theta=\frac{adjacent}{hypothenuse}[/tex]"θ" represents the angle, for our triangle it is ∠B
"adjacent" represents the side next to the angle, for our triangle, it is "side a"
"hypothenuse" is the longest side of the triangle, in this exercise, it is "side c"
Replace the expression with the known measures:
[tex]\cos 25=\frac{a}{13}[/tex]Multiply both sides by 13 to determine the value of 13
[tex]\begin{gathered} 13\cdot\cos 25=13\cdot\frac{a}{13} \\ 11.78=a \\ a\approx11.8 \end{gathered}[/tex]a= 11.8 units
what is the midpoint of (4,-5) and (10,3)
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The formula for the midpoint of the given coordinate is,
[tex](x,y)=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Now, applying the formula to the given coordinate,
[tex]\begin{gathered} (x,y)=(\frac{4+10}{2},\frac{-5+3}{2}) \\ (x,y)=(\frac{14}{2},\frac{-2}{2}) \\ (x,y)=(7,-1) \end{gathered}[/tex]So, the required mid point is (7,-1).
Avery sets up a passcode on her tablet, which allows only 9 digit codes. A spy sneaks a look at Avery’s tablet and sees her fingerprints on the screen over nine numbers. What is the probability the spy is able to unlock the tablet on his first try? Express your answer as a fraction.
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We will have the following:
Since the spy sees fingerprints in 9 digits, then she used 9 different numbers for the password, so the posibility will be the following:
[tex]P=\frac{1}{10}\cdot\frac{1}{9}\cdot\frac{1}{8}\cdot\frac{1}{7}\cdot\frac{1}{6}\cdot\frac{1}{5}\cdot\frac{1}{4}\cdot\frac{1}{3}\cdot\frac{1}{2}\Rightarrow P=\frac{1}{5443200}[/tex]