Name:
Computer Science
Modified
Python Coding Section C
Directions: Circle the best answer.
1. If the code below, what is the maximum amount of gold that can be in a treasure chest?
def treasure_chest():
gold = random.randint (1, 10)
print ("the treasure chest contains", gold, "pieces of gold.")
#Main program begins here
import random
player_gold = 5
print("There is a treasure chest here.")
treasure_chest()
+ None
C. Five
b. One
d. Ten
2. What is the output of this program?
def say_hello() :
print("Hello World)
say_hello)
say_hello
a. Hello world! Hello world!
b. "Hello World" "Hello World!"
C. Hello Hello
# None of the above

Answer: A loop will continue running until the defined condition returns false . ... You can type js for , js while or js do while to get more info on any of these. ... initialization - Run before the first execution on the loop. ... But it can be used to decrement a counter too. statement - Code to be repeated in the loop.

Explanation:

Answer:

The function in Python is as follows:

def printTwoLargest():

   chk = 0

   list1 = []

   num = int(input("Enter: "))

   while num > 0:

       for i in list1:

           if i == num:

               chk+=1

               break;

       if chk == 0:

           list1.append(num)

       chk = 0

       num = int(input("Enter: "))

   list1.sort()

   if len(list1) >= 2:

       print("Largest:", list1[-1])

       print("Second:", list1[-2])

   else:

       print("Length of list must be at least 2")

Explanation:

This defines the function

def printTwoLargest():

This initializes a check variable to 0

   chk = 0

This initializes an empty list

   list1 = []

This prompts the user for input

   num = int(input("Enter: "))

The following loop is repeated until input is 0 or negative

   while num > 0:

The following for loop checks for duplicate

       for i in list1:

           if i == num: If duplicate is found

               chk+=1 The check variable is set to 1

               break; And the for loop is exited

The input is appended to the list if the check variable is 0 (i.e. no duplicate)

       if chk == 0:

           list1.append(num)

This sets the check variable back to 0, for another input

       chk = 0

This prompts the user for another input

       num = int(input("Enter: "))

This sorts the list

   list1.sort()

This prints the two largest if valid user input is 2 or more

   if len(list1) >= 2:

       print("Largest:", list1[-1])

       print("Second:", list1[-2])

if otherwise, this prints that the length must be at least 2

   else:

       print("Length of list must be at least 2")

Answer:

I should be C! :D

Answer:

B

Explanation: