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Considering the ideal gas law,  there are 279.42 moles of acetylene in the tank.

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:

P×V = n×R×T

In this case, you know:

Replacing in the ideal gas law:

17.4192 atm× 390 L = n×0.082 [tex]\frac{atmL}{molK}[/tex]× 296.5 K

Solving:

[tex]n=\frac{17.4192 atmx 390 L}{0.082 \frac{atmL}{molK}x296.5 L}[/tex]

n= 279.42 moles

Finally, there are 279.42 moles of acetylene in the tank.

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The buret should be conditioned before loading it with the titrant.

This is defined as laboratory apparatus which is used in quantitative chemical analysis to measure the volume of a liquid or a gas.

It should be conditioned with the titrant solution to prevent dilution from occurring as a result of cleaning it with water.

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Answer:

The number of carbon atoms is twice the number of magnesium atoms

Answer:

khate ko ban randi ko ban

Answer:

isobars

Explanation:

How?

So they are isobars

Answer: 139.2 g

Explanation:

2.9 mol KClO3 (3 mol O2 / 2 mol KClO3) (32 g / 1 mol O2) = 139.2 grams :)

The extraction of metal usually makes use of the method of precipitation in which a reagent is added which is able to precipitate the required metal in its pure form without impurities.

The process of extraction has to do with the removal of a substance from another. It is usually the way that pure substances are obtained in chemistry. The question is incomplete but I will try to give a general idea.

The extraction of metal usually makes use of the method of precipitation in which a reagent is added which is able to precipitate the required metal in its pure form without impurities. We can not make numerica;l calculatiosn as the values are missing.

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Answer:

chemical change i think

Explanation:

As the drops of vinegar fall through the oil to the bottom of the bottle, it reacts with the baking soda to make carbon dioxide gas. These bubbles attach themselves to the colored vinegar and cause them to float to the surface. When the bubbles pop, the color sinks back to the bottom of the bottle.

The final pressure or the air pressure on the top of the mountain is 0.818.

Air pressure is the pressure exerted by air in the atmosphere of the earth.

By the Gas law

[tex]\dfrac{P_1V_1}{ T1} =\dfrac{ P_2V_2 }{T_2}[/tex]

Given, the pressure of the valley floor is 1 atm. = P1

The temperature is 25° C = T1

The volume of the bag is 0.985 L. = V1

The temperature at the top of the mountain is ° C = T2

Now, the volume of the bag is 1. 030 L = V2

To find P2

Put the values in the formula

[tex]\dfrac{1 atm \times0.985 L}{ 25} =\dfrac{ P_2 \times 1. 030 L }{22}\\\\0.03832 = 0.0468 \times P_2\\\\P_2= 0.818[/tex]

Thus, the final pressure is 0.818.

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Entropy is the degree of disorder of a system. The entropy of b is 168.95  j/mol ･k.

The term entropy refers to the degree of disorder in a system. We have to know that the change in entropy of a system is the entropy of the product minus the entropy of the reactants.

Hence;

-277. 1 = [2(b) - 3(205. 0)

-277. 1  = 2b - 615

b= -277. 1 + 615/2

= 168.95  j/mol ･k

The entropy of b is 168.95  j/mol ･k.

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The partial stress of H2 is 737.47 mmHg Let's observe the Ideal Gas Law to find out the whole mols.

We count on that the closed vessel has 1L of volume

These are the whole moles. Now we are able to know the moles of water vapor, to discover the molar fraction of it.

Mole fraction is a unit of concentration, described to be identical to the variety of moles of an issue divided through the whole variety of moles of a solution. Because it's miles a ratio, mole fraction is a unitless expression.

Thus it is clear that the partial pressure of H2 is 737,47 mmHg.

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Answer:

7. H

8. F

9. G.

10. D

11. A

12. E

13. B

14. C

Moles are an estimation of the smallest unit of the molecules and the atoms in a sample. The moles of ammonium nitrate in a sample are 0.5010 moles.

Moles are calculated by dividing the mass of the substance in gm by that of the molar mass in gram per mole.  

Given.

Mass of ammonium nitrate = 40.10 gm

The molar mass of ammonium nitrate = 80. 0432 g/mol

Moles of ammonium nitrate are calculated as:

[tex]\begin{aligned}\rm moles &= \rm \dfrac{mass}{molar\; mass}\\\\&= \dfrac{40.10}{80.0432}\\\\&= 0.5010 \;\rm mol\end{aligned}[/tex]

Therefore, moles of ammonium nitrate present is option d. 0.5010 moles.

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Answer:

B . Water molecules can collide with other particles more than neon atoms can.

The answers to your questions are as follows

A) The number of aluminium ions present = 1.62 * 10²³ ions

B) The number of chloride ions present = 9.86 * 10²³  ions

C) The mass of one unit of aluminium chloride = 133.34 grams

Given data :

mass of aluminium chloride = 37.2 g

molar mass of aluminium chloride = 133.34 g/mol

note : I mole of a molecule has 6 * 10²³ molecules  

Number of moles = mass / molar mass = 0.27 moles

A) aluminium ions present

moles of AlCl₃ * 6 * 10²³

= 0.27 * 6 * 10²³   = 1.62 * 10²³ ions

B) Chloride ions present

moles of AlCl₃ * 6 * 10²³  * 3

= 0.27 * 6 * 10²³ * 3

= 4.86 * 10²³ ions

C) The mass of one formula unit of aluminium chloride = 133.34 grams

Hence we can conclude that the answers to your question are as listed above.

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C. Walking on wet floors shows that Friction is undesirable

The solute in the scenario where a chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride is sodium chloride.

A solute is a substance that forms a solution with another substance called solvent in a process called solubility.

According to this question, a chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves in the water.

This shows that the sodium chloride is the solute added to the water (solvent).

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Answer:

the ice cube feels cold  

Explanation:

heat transfer is like how the sun gives us and the radiation of it put heat transfer but we dont have radiation

The reaction which shows the bronsted-lowry acid reacting is HCl + H₂O → H₃O⁺ + Cl⁻.

According to the Bronsted-Lowry theory, the species which donates H⁺ ion to the solution is known as Bronsted-Lowry acid and which accepts H⁺ ion is known as Bronsted-Lowry base.

Among the given reactions, only the reaction which is showing Bronsted-Lowry acid is:

HCl + H₂O → H₃O⁺ + Cl⁻

Here HCl is a Bronsted-Lowry acid as it gives H⁺ ion in the aqueous solution.

Hence, option (3) is correct.

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For an unknown using the retention times 1. 6 min for ch4, 12. 8 min for octane, 15. 4 min for the unknown, and 19. 6 min for nonane, the kovats retention index is mathematically given as

I = 807.857

Generally, the equation for the Kovats index(i)  is mathematically given as

[tex]I= \frac{100[n + (N - n) x (Log tr (unknown) - logtr (n))}{ logtr(N) - logtr(n))]}[/tex]

Therefore

[tex]I= \frac{100[ 1+8*(log(14.7) -log (1.5)}{log (19.8) - log (1.5)) 0]}[/tex]

I = 100[ 1+8*(0.991/1.12)]

I = 807.857

In conclusion, Kovats retention index

I = 807.857

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Kovats retention index is a system that converts the retention time into the independent constants of the system. The Kovats retention index for the unknown is 807.857.

The Kovats retention index (I) is the system used in analytical techniques like gas chromatography for the conversion of the retention time.  It is given mathematically as:

[tex]\rm I = \rm \dfrac{100[n+(N-n)x(Logtr(unknown)-logtr(n))}{Logtr(N)-Logtr(n)]}[/tex]

Substituting values and solving further,

[tex]\begin{aligned} \rm I &= \rm \dfrac{100[1+8 \times (Log(14.7) - log (1.5))}{(log (19.8) - log (1.5))0}\\\\&= 100 [ 1 + 8 (\dfrac{0.991}{1.12})]\\\\&= 807.857\end{aligned}[/tex]

Therefore, the Kovats retention index for an unknown is 807.857.

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#SPJ4

The number of moles of air present is 0.056 mole

The ideal gas is one in which molecules do not attract or repel each other.Many gases like oxygen,nitrogen, carbon di oxide can be treated as the ideal gases as particular temperature and pressure.The real gases at high temperature and lower pressure can be treated as ideal gases.

The given data in the question is

Volume = 1.35 L

Pressure (P) = 750 torr

Temperature (T) = 17 °C = 17 + 273 = 290 K

Gas constant (R) = 62.396 L•torr/mol•K

The number of moles (n) =?

How to determine the number of moles:

The number of moles present can be obtained by using the ideal gas equation as illustrated below:

[tex]PV=nRT[/tex]

Divide both sides by RT

[tex]n=\dfrac{PV}{RT}[/tex]

[tex]n=\dfrac{(750\times 1.350}{62.396\times 290)}[/tex]

[tex]n=0.056\ moles[/tex]

Hence, the number of moles of air present is 0.056 mole

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Answer:

answer in picture

Explanation:

Answer:

Mendeleev left some gaps in his periodic table because he believed that in future more elements will be discovered.

Explanation:

"Mendeleev left gaps in his table to place elements not known at the time. By looking at the chemical properties and physical properties of the elements next to a gap, he could also predict the properties of these undiscovered elements."

Since K3 is greater than 1, the reaction is thermodynamically favorable.

Data;

This states that the heat change in a given chemical reaction is the same irrespective of the number of process in which the reaction is effected.

Using Hess Law;

[tex]rxn_3 = rxn_1 * 2rxn_2\\k_3 = k_1 * k_2^2\\k_3 = 2*10^-^6 * (1*10^3)^2\\k_3 = 2[/tex]

substituting this using Gibbs law,

[tex]\delta G^0_3 = -RT\ln K_3\\\delta G^0_3 < 0[/tex]

Since K3 is greater than 1, the reaction is thermodynamically favorable.

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Answer:

These clouds extend through the lower and mid-layers of the troposphere bringing rain to the surface below.

Explanation:

The bases of clouds in the middle level of the troposphere, given the prefix “alto,”

Answer:

you are not posted question

Answer:

9   I believe

Explanation:

Answer:

According to the kinetic theory of gases, in an ideal gas between two successive collisions, a gas molecule travels in a straight line.