Answer:
p=6 and r=48
Step-by-step explanation:
19=4p-5
19+5=4p
24=4p
24/4=p
6=p
check
19=4p-5
19=4x6-5
19=24-5
19=19
3)r/2-8=16
r/2=16+8
r/2=24
r=24x2
r=48
check
r/2-8=16
48/2-8=16
24-8=16
16=16
What is the next number in this sequence? 3, 7, 11, 15….
17
21
19
22
Answer:
19
Step-by-step explanation:
Please give brainliest.
Answer: 19
Step-by-step explanation:
hope this works
The dog knows it should not be traveling at this time, but follows his owner. Would this be an example of an internal or external conflict? Why?
Answer:
internal conflict
Step-by-step explanation:
bc the dog cares about his owner but he also knows he shouldn't b traveling rn so its a problem within him. Hope this helps
PLEASE HELP ME ;-; ILL MARK AS BRIANLIEST IF ITS RIGHT
The event coordinator asks you to determine how many students participated in the
track-and-field day. The total number of students in seventh and eighth grade
combined is 584; 5/8 of them are seventh graders and 3/8 of them are eighth-graders. If 4/8 of the seventh graders participated in track-and-field day and 7/8 of the eighth graders participated, about how many total students participated? Describe the process you used to find your answer.
Answer:
374.125 students. Not sure if you're supposed to round up or down considering you can't have a fraction of a person, but I would round down.
Step-by-step explanation:
(5/8) (584) = 365 seventh graders in total
(3/8) (584) = 219 eighth graders in total
(4/8) (365) = 182.5 seventh graders who participated in track-and-field day
(7/8) (219) = 191.625 eighth graders who participated in track-and-field day
182.5 + 191.625 = 374.125 students in total who participated
Answer:
First, I took 5/8 out of 584 for the seventh graders which came out to 365 seventh graders. Then, I did the same thing with 3/8 and it came out to 219 eighth graders. Then I took out 4/5 out of 365 which resulted as 292. Then I did the same thing for 7/8 and the results came out as 191. So in total 483 students participated in track-and-field day.
Step-by-step explanation:
What is the circumference of the circle defined by x^2+6x +y^2-12y-4=0.
Answer:
44.0
Step-by-step explanation:
Mark me as brainliest
Who else hate khan academy?
Answer:
samme
Step-by-step explanation:
Answer:
Me i tho im forced to watch it for school
Step-by-step explanation:
How many 2/5’s are in 5
Answer:
12.5, 2/5 are in 5
Step-by-step explanation:
2/5*12.5=5
Have a beautiful day and stay safe!
Chance rode his bike for x minutes, and Jaden rode his bike for 3/8 more than that.
Part A
Write and equation using fractions that relates the number of minutes Chance rode with y, the number of minutes that Jaden rode his bike. (write your answer as a fraction)
y= __ x
Part B
Write an equation, using decimals, that relates the number minutes chance rode with y, the number of minutes that Jaden rode his bike.
y=___ x
Answer:
Part A = 6/16
Part B .15
Step-by-step explanation:
Think about how you can use absolute value notation to express the distance between two points on a coordinate graph. For each pair of points below, find the distance between the given points and express your work using absolute value symbols. Show your work.
(4, 9) and ( –5, 9)
(7, –1) and (7, –4)
(0, 9) and (0, –7)
(4, –8) and (–10, –8)
Answer:
(4, 9) and (-10, -8)
Step-by-step explanation:
The following linear equation is shown: y = 2% + 5
Using this equation, what is the value of the missing space on the table
Oy=8
Oy=9
O y = 18
I don't know
Answer:
y=8
Step-by-step explanation:
Answer:
13
Step-by-step explanation:
Between 9 and 11 the gap is 2. Add 2 to 11 and you get 13
Which equation can be used to find 75 percent of 200?
(A) StartFraction 75 times 1 Over 200 times 1 EndFraction = StartFraction 75 Over 200 EndFraction
(B) StartFraction 100 times 26.7 Over 75 times 2.67 EndFraction = StartFraction 267 Over 200.25 EndFraction
(C) StartFraction 200 times 2 Over 100 times 2 EndFraction = StartFraction 400 Over 200 EndFraction
(D) StartFraction 75 times 2 Over 100 times 2 EndFraction = StartFraction 150 Over 200 EndFraction
Find the value of x in each pair of similar figures. Use proportions to solve.