Answer:
Step-by-step explanation:
use a protractor if you have one or ask for one
Find x and y values that make both y = 2x – 5 Y=-2/3x+ 3 true.
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Use the sketch tool if it helps you with your thinking.
Submit
Answer:
See below ↓
Step-by-step explanation:
Let's find the x and y values.
Step 1 : Equate the y expressions.
The two equations have given different values for yTherefore by equating them, we can solve for x2x - 5 = -2/3x + 3Step 2 : Convert fractions in the equation to whole numbers.
The value -2/3 is a fractionWe can make it a whole number if multiply throughout by the value of its denominator ⇒ 33(2x - 5) = 3(-2/3x + 3)6x - 15 = -2x + 9Step 3 : Bring x terms to one side and constant terms to the other.
6x + 2x = 9 + 158x = 24x = 3Step 4 : Solve for y by plugging the value of x into one of the given equations.
y = 2(3) - 5y = 6 - 5y = 1Evaluate UV if possible.
Answer: B
Step-by-step explanation:
Multiply U and V:
[tex]\begin{pmatrix}-9&1&0\\ \:4&0&2\\ \:0&1&5\end{pmatrix}\begin{pmatrix}2\\ \:-2\\ \:1\end{pmatrix}[/tex]
[tex]\mathrm{Multiply \ the \ rows \ of \ the \ first \ matrix \ by \ the \ columns \ of \ the \ second \ matrix:}[/tex]
[tex]\begin{aligned}&\left(\begin{array}{ccc}-9 & 1 & 0\end{array}\right)\left(\begin{array}{c}2 \\-2 \\1\end{array}\right)=(-9) \cdot 2+1 \cdot(-2)+0 \cdot 1 \\&\left(\begin{array}{ccc}4 & 0 & 2\end{array}\right)\left(\begin{array}{c}2 \\-2 \\1\end{array}\right)=4 \cdot 2+0 \cdot(-2)+2 \cdot 1 \\&\left(\begin{array}{lll}0 & 1 & 5\end{array}\right)\left(\begin{array}{c}2 \\-2 \\1\end{array}\right)=0 \cdot 2+1 \cdot(-2)+5 \cdot 1\end{aligned}[/tex]
[tex]=\begin{pmatrix}\left(-9\right)\cdot \:2+1\cdot \left(-2\right)+0\cdot \:1\\ 4\cdot \:2+0\cdot \left(-2\right)+2\cdot \:1\\ 0\cdot \:2+1\cdot \left(-2\right)+5\cdot \:1\end{pmatrix}[/tex]
[tex]\mathrm{Simplify\:each\:part:}[/tex]
[tex]=\begin{pmatrix}-20\\ 10\\ 3\end{pmatrix}[/tex]
Therefore, the correct answer is B
how do i solve (2[tex](\frac{2}{3} r^{2} s^{7} )^{2} * (\frac{1}{6} r^{3}s)[/tex]
Answer:
5x+1=7
Step-by-step explanation:
Find the x- and y-intercepts of y=−x/2−1.
Step-by-step explanation:
y = -x/2 - 1
the y-intercept is right there : -1.
it is the y-value when x = 0
the point of y-intercept is therefore (0, -1).
the x-intercept is the other way around. it is the x- value when y = 0.
0 = -x/2 - 1
1 = -x/2
-2 = x
the point of x-intercept is therefore (-2, 0)
Please help
Simplify:
Answer:
-9 3/4a+10 2/5
Step-by-step explanation:
-12 * 5/6a = -10a
-12 * -7/8 = 10 1/2
1/14 * 3 1/2a = 1/4 a
1/14 * -1 2/5 = -1/10
Put it together: -10a + 10 1/2 + 1/4a - 1/10
-10a+1/4a = -9 3/4a
10 1/2-1/10= 10 2/5
-9 3/4a + 10 2/5
Find the midpoint of AB A(-1,2) B(0,-14)
Answer:
given ,
two points A ( -1 , 2 ) and B ( 0 , -14 )
to find - coordinates of midpoint of A and B______________________________________
[tex]\fbox\pink{Solution -}[/tex]
let the midpoint be P ( x , y )
using midpoint formula ,
[tex]P(x,y) = ( \frac{ x_{1} + x_{2} }{2} , \frac{ y_{1} + y_{2} }{2} ) \\ \\ P(x,y) = ( \frac{ - 1 + 0}{2} , \frac{2 + ( - 14)}{2} ) \\ \\ (x,y) = ( \frac{ - 1}{2} , \frac{ - 12}{2} ) \\ \\ x = \frac{ - 1}{2} \\ \\ y = \frac{ - 12}{2} => - 6[/tex]
thus ,
the coordinates of the midpoint are
[tex]\red{P( \frac{ - 1}{2} , - 6)} \\ \\ or \\ \\ \red{P( -0.5 , - 6 )} [/tex]
hope helpful :D
Answer:
Step-by-step explanation:
A(-1,2) x₁ = -1 & y₁ = 2
B(0 ,-14) x₂ = 0 & y₂ = -14
[tex]\text{ \sf Midpoint = $\left(\dfrac{x_{1}+x_{2}}{2} ,\dfrac{y_{1}+y_{2}}{2}\right)$ }[/tex]
[tex]= \left (\dfrac{-1+0}{2} ,\dfrac{2+[-14]}{2} \right) \\\\\\=\left(\dfrac{-1}{2}, \dfrac{-12}{2}\right)\\\\\\=\left( -0.5 , -6 \right)[/tex]
Please helpppppppppppppp <3
Answer:
Part 1: -10, -5, 0, 8 Part 2: -3/2, -15%, 0.80, 143%, 2 1/4
Step-by-step explanation:
Part 1: The lower the number, the lower the temperature
Part 2: Convert the fractions into decimals
2 1/4 = 2.25
-15% = -0.15
143% = 1.43
-3/2 = -1.5
0.80 = 0.80
The order from least to greatest is -3/2, -15%, 0.80, 143%, 2 1/4
Hope this helps :)
A team sells their jerseys for 40% more than it costs to have them made. What is the selling price of a jersey that cost the team $25.
Answer:
$35.
Step-by-step explanation:
SP = 25 + 0.40*25
= 25 + 10
= $35.
What is the explict rule for the geometric sequence? 9,6,4, 8/3 Enter your answer in the box. an=
Answer:
an = 9(⅔)^(n-1)
Step-by-step explanation:
The formula for explicit is: An = a1(r)^(n-1)
Consider the graph of the quadratic function. Which
interval on the x-axis has a negative rate of change?
-2 to -1
-1.5 to 0
0 to 1
1 to 2.5
The only interval with a negative rate of change is the last one:
[1, 2.5]
When the rate of change is negative?
For an interval (a, b) and a function f(x), the rate of change is defined as:
[tex]r = \frac{f(b) - f(a)}{b - a}[/tex]
So the rate of change is only negative when the function evaluated on the first value of the interval is larger than the function evaluated in the second one.
For example, on the interval [1, 2.5} we can see that:
f(1) = 3
f(2.5) = -1
Then on this interval, the rate of change will be negative, meaning that this is the correct option.
If you want to learn more about rates of change, you can read:
https://brainly.com/question/8728504
Answer:
It's D: 1 to 2.5
Step-by-step explanation:
It's D: 1 to 2.5
Describe and correct the error in using the percent proportion to answer the question below
“6 is 6.25% of what number”
Using proportions, it is found that the error was treating the 100% value as a percent(100) instead of a decimal 1, hence the correct value is of 96.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In this problem, we have that 100% = 1 of the number is w, while 6 is equals to 6.25% = 0.0625. Hence the rule of three is given by:
1 - w
0.0625 - 6
Applying cross multiplication:
0.0625w = 6.
w = 6/0.0625
w = 96.
The error was treating the 100% value as a percent(100) instead of a decimal 1, hence the correct value is of 96.
More can be learned about proportions at https://brainly.com/question/24372153
A cone has a hight of 18 meters and a radius of 10 meters what is its volume use 3.14
[tex]\textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=10\\ h=18 \end{cases}\implies V=\cfrac{\pi (10)^2(18)}{3}\implies \stackrel{using~\pi =3.14}{V=1884}[/tex]
ome friends went to the local movie theater and bought four large buckets of popcorn and six boxes of candy. The total for the snacks was $46.50. The last time you were at the theater, you bought a large bucket of popcorn and a box of candy, and the total was $9.75. How much would 2 large buckets of popcorn and 3 boxes of candy cost?
Type the price of one bucket of popcorn here.
Type the price of one box of candy here.
How much would 2 large buckets of popcorn cost?
How much would 3 boxes of candy cost?
How much would 2 large buckets of popcorn and 3 boxes of candy cost?
Answer:
One bucket of popcorn: 6$
One box of candy: $3.75
2 buckets of popcorn: $12
3 boxes of candy: $11.25
2 buckets of popcorn and 3 boxes of candy: $23.25
Step-by-step explanation:
We can find the cost of one bucket of popcorn and one box of candy using a system of equations
[tex]4P + 6C=46.50\\P + C =9.75[/tex]
We can use the elimination method and thus multiply the second equation by -4:
[tex]4P + 6C = 46.50\\-4(P+C=9.75)\\\\4P + 6C = 46.50\\-4P -4C=-39\\\\2C = 7.5\\\\C = 3.75[/tex]
We can plug C into the second equation to find P:
[tex]P + 3.75 = 9.75\\P = 6[/tex]
Thus, the cost of two buckets of popcorn is 6 * 2 = $12
And the cost of three boxes of candy is 3.75 * 3 = $11.25
And the cost of both two buckets of popcorn and three boxes of candy is (6*2) + (3*3.75) = 12 + 11.25 = $23.25
how to express 1 cm as a fraction of 1 meter in decimal form
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♫[/tex]
Let's see ~
Remember : value of 1 meter = 100 centimeters
[tex]\qquad \sf \dashrightarrow \:1 \: m = 100 \: cm[/tex]
[tex]\qquad \sf \dashrightarrow \:1 \: cm = \frac{1}{100} \: m[/tex]
[tex]\qquad \sf \dashrightarrow \:1 \: cm = 0.01 \: m[/tex]
・ .━━━━━━━†━━━━━━━━━.・
As we know
100cm=1mSo
turn down to fraction
[tex]\\ \rm\rightarrowtail \dfrac{1}{100}[/tex]
Turn to decimal
[tex]\\ \rm\rightarrowtail 0.01m[/tex]
Need Help Asap!!
[tex] \: \: \: \: [/tex]
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Let's check I the given pairs of triangles are congruent or not ~
problem 1[tex]\qquad \sf \dashrightarrow \:ABC \cong FED[/tex]
These triangles are congruent by SSS congruency, as it's three sides are equal.
・ .━━━━━━━†━━━━━━━━━.・
problem 2[tex]\qquad \sf \dashrightarrow \:LMN \not \cong PQO[/tex]
・ .━━━━━━━†━━━━━━━━━.・
These triangles are not congruent because they don't fulfill any congruency criteria.
problem 3[tex]\qquad \sf \dashrightarrow \: XVW \cong YZA [/tex]
These triangles are congruent by AAS congruency criteria, since two angles and one of the side is common.
・ .━━━━━━━†━━━━━━━━━.・
problem 4[tex]\qquad \sf \dashrightarrow \: GHI \not \cong IJG [/tex]
These triangles are not congruent because they don't fulfill any criteria.
・ .━━━━━━━†━━━━━━━━━.・
problem 5[tex]\qquad \sf \dashrightarrow \: PQR\cong QPO[/tex]
These triangles are congruent by SSS congruency, as it's two sides are equal and one side is common.
・ .━━━━━━━†━━━━━━━━━.・
problem 6[tex]\qquad \sf \dashrightarrow \: JIK \cong HIG [/tex]
These triangles are congruent by SAS congruency, since two sides and Angle between them are equal.
・ .━━━━━━━†━━━━━━━━━.・
Problem 7These given triangles are congruent by SSS congruency, because they have two equal sides and one common side in there.
・ .━━━━━━━†━━━━━━━━━.・
problem 8[tex]\qquad \sf \dashrightarrow \: BCD \cong FED [/tex]
These triangles are congruent by ASA congruency, because they have one pair equal angles, one pair of vertical opposite angles (they are equal) and a side between them equal.
・ .━━━━━━━†━━━━━━━━━.・
problem 9[tex]\qquad \sf \dashrightarrow \: LKM \cong LNM [/tex]
These given triangles are congruent by SSS congruency, because they have two equal sides and one common side in there.
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
Logan and Rita each open a savings
account with a deposit of $8,100. Logan's
account pays 5% simple interest annually.
Rita's account pays 5% interest
compounded annually. If Logan and Rita
make no deposits or withdrawals over the
next 4 years, what will be the difference in
their account balances?
Answer: 134. 89 $
Step-by-step explanation: Dina wishes to 1000$ deposit into an investment account and then withdraw the total in the account in five years. She has the choice of two different accounts. Blue Star account: interest is earned at an annual interest rate of 6.13% compounded weekly (52 weeks in a year). Red Star account: interest is earned at an annual interest rate of 5.95% compounded continuously. Which investment account - Blue Star or Red Star - will result in the greatest total at the end of five years? What is the total after five years for this account? How much more is it than the total for the other account?
This is the question
Check the picture below, so the lines look more or less like so, so the shape that we'll be getting will be the shape of a bowl with a hole in it, thus we'll use the washer method.
the way I use to get the larger Radius is simply using the "area under the curve" method, namely f(x) - g(x), where g(x) in this case is the axis of rotation.
so to get "R" and "r" we can get it by
[tex]\stackrel{y = 1}{(1)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies 1+3\implies \stackrel{R}{4} \\\\\\ \stackrel{y = \ln(x)}{\ln(x)}~~ - ~~\stackrel{\stackrel{\textit{axis of rotation}}{y = -3}}{(-3)}\implies \stackrel{r}{ln(x)+3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{R^2}{(4)^2}~~ - ~~\stackrel{r^2}{[\ln(x)+3]^2}\implies 16~~ - ~~[\ln^2(x)+6\ln(x)+9] \\\\\\ \ln^2(x)+6\ln(x)+7~\hfill \boxed{\displaystyle\int~[\ln^2(x)+6\ln(x)+7]dx}[/tex]
Please help! Consider the given circle with the shaded sector xy and central angle 225. The circumference is 30 units
[tex]\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=30\pi \end{cases}\implies 30\pi =2\pi r\implies \cfrac{30\pi }{2\pi }=r\implies \boxed{15=r} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ r=15\\ \theta =225 \end{cases}\implies \widehat{XY}=\cfrac{(225)\pi (15)}{180}\implies \boxed{\widehat{XY}\approx 58.90} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad A=\pi (15)^2\implies A=225\pi \implies \boxed{A\approx 706.86}[/tex]
Find the volume of the triangular prism? (PLEASE HELP ILL MARK BRAINLIEST)
Answer:
▲ Base and height. This is the basic volume equation of a triangular prism: Volume = 0.5 * Base * Height * Length. ...
◣ Right triangle. Probably the most popular type of prism! ...
▲ 3 sides. Volume = 0.25 * √( (a+b+c) * (-a+b+c) * (a-b+c) * (a+b-c) ) * Length.
Step-by-step explanation:
A city that has an elevation of 15 meters is closer to sea level than a city that has an elevation of -10 meters.
Answer:
Step-by-step explanation: Your answer will be -10 because even though -10 is much lower than 15 it’s still closer to sea level.
find x correct to 2 decimal places
Answer:
Step-by-step explanation:
find the equation of the line that passes through point a and b
Answer:
y=2x-1
Step-by-step explanation:
Each letter in the word THEORETICAL is written on a separate slip of paper and placed in a hat. A letter is chosen at random from the hat.
d. Find a word for which the probability that you choose R when you randomly choose a letter from the word is 2/5.
Answer:
parry
Step-by-step explanation:
You are looking for a 5-letter word that has two letters R in it. One such is ...
parry
- - Use the Quadratic Formula to solve the equation x2 – 2x = -9.
Which set shows an average of 4?
A) A
B) B
C) A and B
D) none of the above
Answer:
B
Step-by-step explanation:
A) 1 + 1 + 1 + 1 = 4
4 / 4 = 1
B) 4 + 4 = 8
8 / 2 = 4
Answer: B
Step-by-step explanation:
Find the scale factor and ratio of perimeters for a pair of similar octagons with areas 9 ft^2 and 16 ft ^2 .
Answer:
3/4 ratio
Step-by-step explanation:
This is the answer
100 Points and Brainly.
Graph The equation: y=(-x)-6
Gibberish for points WILL NOT be tolerated.
Please, if you can, try to make the mark ON the picture I have provided, in red.
function : y = (-x) - 6
Find x-intercept :
(-x) - 6 = 0(-x) = 6x = -6Find y-intercept :
y = (-0) - 6 y = -6mark these two points on both the axis and draw a straight linear graph.
passes coordinates : (0, -6), (-6, 0)
[tex]\\ \rm\rightarrowtail y=-x-6[/tex]
Take some point s
(1,-7)(2,-8)(3,-9)Graph it
multiply (−3/4b^2)(−6a^2b^5)
Step-by-step explanation:
(−3/4b^2)(−6a^2b^5)
= 9 a²b³
Determine the type of symmetry of r=-7+ 2cos3ø from the equation, if any. Make sure to confirm graphically. Symmetric with respect to the:
A) pole
B) none of these
C)line /2
D) polar axis
well, hmmm to check for polar symmetry, hmmm say we simply replace the value for either "r" or "θ" or both in the original equation, if the equation rendered is the same as the original, there you have it, symmetry, so let's do that.
[tex]\underline{\textit{testing for symmetry to the }\frac{\pi }{2}~line\qquad \qquad r=-r~~,~~\theta =-\theta } \\\\\\ r=-7+2cos(3\theta )\implies (-r)=-7+2cos[3(-\theta )]\implies -r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{-r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\implies r=7-2cos(3\theta )\impliedby \textit{woopsie, no dice} \\\\[-0.35em] ~\dotfill[/tex]
[tex]\underline{\textit{testing for symmetry to the polar axis}\qquad \qquad \theta =-\theta} \\\\\\ r=-7+2cos(3\theta )\implies r=-7+2cos[3(-\theta )]\implies r=-7+2cos(-3\theta ) \\\\\\ \stackrel{symmetry~identity}{r=-7+2\stackrel{\downarrow }{cos(3\theta )}}\impliedby \textit{low and behold\qquad \Large \checkmark}[/tex]
now, we could run a test for "the pole" or namely the origin by simply changin r = -r, however we already know where the symmetry is, so no need.
Check the picture below.
If told that |A|=48 what are the possible values for X.
Please help!
If the value of |A| is 48 the possible values for x in the matrix is 4 or -2.
How to use determinant to find a value in a matrix?The determinant of the matrix A is as follows:
|A| = 48
Therefore,
48 = (3x × 2x) - (4x × 3)
48 = 6x² - 12x
6x² - 12x - 48 = 0
3x² - 6x - 24 = 0
x² - 2x - 8 = 0
x² + 2x - 4x - 8 = 0
x(x + 2 -4(x + 2) = 0
(x - 4)(x +2) = 0
Therefore,
x = 4 or -2
learn more on determinant here: https://brainly.com/question/19206601