Answer:
49 m/s
Explanation:
This is the question from the document:
1. A bag dropped from a helicopter falls with an acceleration of 9.8m/s2. What is its velocity after 5s?
We can find the answer by using the equation a = (v-u) / t
Acceleration a = 9.81m/s2
initial velocity u = 0 m/s (the bag is only dropped, so there's no initial velocity already existing)
time t= 5s
final velocity v = unknown
9.8 = (v -0) / 5
v - 0 = 9.8x5
v = 49 m/s
A14 is running toward the goal. her teammate, a12, kicks the ball toward a14. a14 did not see the ball coming and the ball strikes her in the back of the hand as her hand is at her side. the proper call would be to:
The Available options are:
A. Award an indirect free kick to Team B for incidental contact.
B. Award a direct free kick to Team B.
C. Allow play to continue as the handling was incidental but issue a caution to the player at the next stoppage of play.
D. Allow play to continue.
Answer:
Allow play to continue.
Explanation:
IFAB (International Football Association Board) has approved various means to clarify the issue of handball in foodtball.
Hence, some of the cases include:
1. Should the the ball touches a player's hand/arm immediately from their own head/body/foot or the head/body/foot of another player.
2. the ball touches a player's hand/arm close to their body and has not made their silhouette unnaturally bigger.
3. a player is falling and the ball touches their hand/arm when it is between their body and the ground (but not extended to make the body bigger).
4. Additionally, should the goalkeeper attempt to clear a ball from a teammate but fails, the goalkeeper is allowed to handle the ball.
Hemce, Since a14 who did not see the ball coming and the ball strikes her in the back of the hand as her hand is at her side. the proper call would be to: ALLOW PLAY CONTINUE
The earth attracts an apple with a force of 15 Newton. taking this as an action force, how much is reaction force? who accepts the reaction force? on which body does a reaction force act?
Answer:
action = reaction
land accepts
reaction force acts on the apple
Answer:
15 Newton
Explanation:
According to Newton's third law of motion, "Every action has a reaction which is equal in magnitude but opposite in direction" (Right now, we're not talking about direction, so we'll ignore it)
So,
Action Force = Reaction Force
Reaction Force = 15 N
The action force is by the Earth on the Apple, So the reaction force will be by the Apple on the Earth.
A drop
of
oil volume 10 m
Spreads out on water to make a
Circular fils of diameter 10
What is that thickness?
Answer:
[tex]27.5\ m[/tex]
Explanation:
As we know that volume of cylinder is
[tex]v=\pi r^{2} *h[/tex]
Where v=volume , h= height or thickness and r= radius
Here,
[tex]v= 10 m ,\ diameter= 10, \ r=\frac{diameter}{2} \ r=\frac{10}{2}\\ r=5[/tex]
Putting these values in the previous equation , we get
[tex]10\ = \frac{22}{7} *5 *5*h\\ 14\ =\ 110*h\\h=\frac{110}{14} \\h=\frac{55}{2} \\\\h=27.5\ m[/tex]
Therefore thickness is 27.5 m
With all his gear, Neil Armstrong weighed 360 pounds on Earth. When he landed on the Moon, he weighed 60 pounds. Why? A. His mass changed while traveling to the Moon. B. The gravity on the Moon is six times the gravity on Earth. C. The gravity on the Moon is less than the gravity on Earth. D. He experienced the effects of a gravity slingshot.
Answer:
C
Explanation:
Answer:
C) The gravity on the Moon is less than the gravity on Earth.
Explanation:
Since Moon is smaller than Earth, any mass on Moon will experience less gravitational force and so that mass will weigh less on Moon.
Quantum mechanics applies to A) subatomic, atomic, nanometer-size, and micrometer-size systems. B) nanometer, micrometer, and kilometer-size systems. C) atomic, nanometer-size, and micrometer-size systems. D) subatomic, atomic, and nanometer-size systems.
Answer: D) subatomic, atomic, and nanometer-size systems.
Explanation: Quantum mechanics applies to subatomic, atomic, and nanometer-size systems.
a skier traveling 11m/s goes up a 19 degree inclined plane, and glides up 15m before coming to rest. what is the average coefficient of friction?
Answer:
do you mind telling me what is it your asking so i can help ?
Explanation:
Where is the energy in a glucose molecule stored?
Answer:
Energy is stored in the bonds between atoms
Answer:
Energy is stored in the bonds between atoms
Explanation:
Ape-x
A lever and fulcrum are used to lift a fallen tree, which has a weight of 480N. if the lever has a mechanical advantage of 5.5, what is the input force that will begin lifting the tree of the ground
Answer:
The input force is 87.27NExplanation:
Mechanical advantage (M.A)of a machine is the ratio of load to effort
GivenM.A= 5.5
load= 480N
effort= ?
Applying the formula and substituting to find the effort we have
[tex]M.A= \frac{load}{effort}[/tex]
[tex]5.5= \frac{480}{effort}\\\effort= \frac{480}{5.5} \\\effort= 87.27N[/tex]
8. what force will exert apressure of
50000 PA
0.5 meter
Square ?
Answer:
25000 N
Explanation:
[tex]force \: = pressure \times area \\ = 50000 \times 0.5 \\ = 5000 \times 5 \\ = 25000 \: N[/tex]
Why is it advisable not to look directly at the Sun? Please Give scientific reason for your answer
Answer:
your eyes would get seriously damaged
Explanation:
when you look directly at the sun, the sun shines it's rays directly to your eyes , which damage them. that's why you should always wear sunglasses in that type of weather, and never point directly at the sun. if you find this answer helpful, mark it as brainliest.
A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he slows to 3 m/s in 1 minute. What is the cyclist’s acceleration? –0.08 m/s2 0.08 m/s2 –12 m/s2 12 m/s2
Answer:
-0.08m/s²
Explanation:
A lizard leaps 2.1\,\text m2.1m2, point, 1, start text, m, end text to the left in 0.52\,\text s0.52s0, point, 52, start text, s, end text. What was its average speed in \dfrac{\text m}{\text s} s m start fraction, start text, m, end text, divided by, start text, s, end text, end fraction
Answer:
v = 4.03 m/s
Explanation:
It is given that,
Distance covered by a lizard, d = 2.1 m
Time taken by lizard, t = 0.52 s
We need to find the average speed of the lizard. The distance covered divided by time taken is called the average speed of lizard. So,
[tex]v=\dfrac{d}{t}\\\\v=\dfrac{2.1\ m}{0.52\ s}\\\\v=4.03\ m/s[/tex]
So, the average speed of the lizard is 4.03 m/s.
Answer: 4.02 not 4.03
Explanation: I did on khan academy
output work is always less than input work,why
Answer:
Output work is always less than input work due to effect of friction. Machines are frictionless in practice, the efficiency of a machine can never be 100%.
Hope this helps..
Good luck on your assignment..
Answer:
Friction
Explanation:
Will mark brainliest for the first person who answered correctly Which of the following is an example of non-renewable energy? Hydroelectric Gas Solar Wind
Answer:
gas is non-renewable resource
Explanation:
Answer:
Gas
Explanation:
There are two types of energy sources, renewable and non-renewable.
Solar energy, wind energy, and hydroelectric are an example of renewable energy.
Fossil fuels like gas, coal, and petroleum are an example of non-renewable energy.
What is mean by physical quantity?
Answer:
Anything that can be measured is called a physical quantity. It is described with the help of magnitude and the unit. There are two types
1) Base quantity
2) Derived Quantity
Answer:
A physical quantity is the quantity that can be measured directly or indirectly and consists of a magnitude and a unit. Mass, length, time, density, temperature etc are some examples of physical quantities. Happiness, sadness etc cannot be measured. So, they are not physical quantities. We cannot find the exact value of any physical quantity without measurement.
There are two types of physical quantity. They are:
Fundamental quantityDerived QuantityHope this helps...
Good luck on your assignment...
A wind blows at 100 km / h from the east. An aircraft points due north and sets off. In still air its speed is 150 km / h. What will the aircraft's actual velocity be?
Answer:
180.28 km/h
Explanation:
Let north and south represent the positive and negative y axis and east and west represent the positive and negative x axis.
Given;
Velocity of wind vx= 100 km/s
Velocity of aircraft in still air vy = 150 km/s
The resultant velocity Vr is;
Vr = √(vx^2 + vy^2)
Vr = √(100^2 + 150^2)
Vr = 180.2775637731 km/h
Vr = 180.28 km/h
As the distance between a satellite in a circular orbit and the central object increases, the period of the satellite .
Answer:
As the distance between a satellite in a circular orbit and the central object increases, the period of the satellite increases .
Explanation:
Answer:
Increases
Explanation:
A 22.8 kg rocking chair begins to slide across the carpet when the push reaches 57.0 N. What is the coefficient of static friction?
Answer:
0.255
Explanation:
The following data were obtained from the question:
Force (F) = 57 N
Mass (m) = 22.8 Kg
Coefficient of static friction (µ) =...?
Next, we shall determine the normal reaction (R). This is illustrated below:
Mass (m) = 22.8 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (R) =?
R = mg
R = 22.8 x 9.8
R = 223.44 N
Finally, we can obtain the coefficient of static friction (µ) as follow:
Force (F) = 57 N
Normal reaction (R) = 223.44 N
Coefficient of static friction (µ) =...?
F = µR
57 = µ x 223.44
Divide both side by 223.44
µ = 57/223.44
µ = 0.255
Therefore, the coefficient of static friction (µ) is 0.255.
Answer:
.255
Explanation:
I'm also on acellus and it's the right answer
Arace car starts from rest and accelerates uniformly to a speed of 40 m/s in 8.
seconds. How far will the car travel during the 8 seconds?
meters
Type the correct answer, then press Enter.
Answer:
160 m
Explanation:
For computing the distance first we have to determine the acceleration which is shown below:
v = u + at
where,
v = 0 = initial velocity
u = 40 = uniformly to a speed
t = 8 = time
So, the a is
= 40 ÷ 8
= 5 m/s
Now we have to use the distance formula i.e
d = ut + 1 ÷ 2 at^2
= 1 ÷2 × 5 × 8^2
= 160 m
Basically we have to applied the above formulas so that the distance could come
What are some of the major differences between the ancient Olympics and modern-day Olympics? List and describe at least two differences.
Answer:
Women are now allowed to participate in the Olympics. The original Olympic Games were open only to men.
Modern Olympic Games include many more events. The first Olympics included only a running event. Today, there are more than 20 different sports and almost 300 events.
The Olympics are held every two years, alternating between summer and winter. The ancient Olympics were originally held every four years in Olympia.
Athletes from countries around the world participate in the modern Olympics. The ancient Olympics consisted of athletes only from ancient Greece.
Explanation:
plato
Planets revolve around the sun why
Is Einstein's equation E=mc^2 is applicable on our earth if it is not why?is it applicable in space can a body moves through speed of light
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◦•●◉✿What does E mc2 actually mean?
E = mc2. It's the world's most famous equation, but what does it really mean? "Energy equals mass times the speed of light squared." On the most basic level, the equation says that energy and mass (matter) are interchangeable; they are different forms of the same thing.✿◉●•◦
a disc starts from rest with an angular acceleration completes 10 revolutions in 2 seconds. the time taken by it to complete 10 more revolution from that instant is
Starting from rest, the disc completes [tex]\theta[/tex] revolutions after [tex]t[/tex] seconds according to
[tex]\theta=\dfrac\alpha2t^2[/tex]
with angular acceleration [tex]\alpha[/tex]. It completes 10 rev in 2 s, which means
[tex]10\,\mathrm{rev}=\dfrac\alpha2(2\,\mathrm s)^2\implies\alpha=5\dfrac{\rm rev}{\mathrm s^2}[/tex]
Find the time it takes to complete 20 rev with this acceleration:
[tex]20\,\mathrm{rev}=\dfrac12\left(5\dfrac{\rm rev}{\mathrm s^2}\right)t^2\implies t=\sqrt8\,\mathrm s\approx2.83\,\mathrm s[/tex]
so it takes approximately 0.83 s to complete 10 more rev.
An electron is in motion at 4.0 × 106 m/s horizontally when it enters a region of space between two parallel plates, as shown, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 102 N/C and separation between the charged plates is 2.0 cm. Determine the horizontal distance travelled by the electron when it hits the plate.
Answer:
xmax = 9.5cm
Explanation:
In this case, the trajectory described by the electron, when it enters in the region between the parallel plates, is a semi parabolic trajectory.
In order to find the horizontal distance traveled by the electron you first calculate the vertical acceleration of the electron.
You use the Newton second law and the electric force on the electron:
[tex]F_e=qE=ma[/tex] (1)
q: charge of the electron = 1.6*10^-19 C
m: mass of the electron = 9.1*10-31 kg
E: magnitude of the electric field = 4.0*10^2N/C
You solve the equation (1) for a:
[tex]a=\frac{qE}{m}=\frac{(1.6*10^{-19}C)(4.0*10^2N/C)}{9.1*10^{-31}kg}=7.03*10^{13}\frac{m}{s^2}[/tex]
Next, you use the following formula for the maximum horizontal distance reached by an object, with semi parabolic motion at a height of d:
[tex]x_{max}=v_o\sqrt{\frac{2d}{a}}[/tex] (2)
Here, the height d is the distance between the plates d = 2.0cm = 0.02m
vo: initial velocity of the electron = 4.0*10^6m/s
You replace the values of the parameters in the equation (2):
[tex]x_{max}=(4.0*10^6m/s)\sqrt{\frac{2(0.02m)}{7.03*10^{13}m/s^2}}\\\\x_{max}=0.095m=9.5cm[/tex]
The horizontal distance traveled by the electron is 9.5cm
Ratio of acceleration due to grabity and universal gravitational constant
Answer:
acceleration due to gravity = 9.8m/s^2
universal gravitational constant= 6.67×10 ^_11 nm^2 kg_2
now, ratio=9.8/6.67×10^_11.
which glass is used in astrology?
Answer:
The answer is either looking glass or stained glass.
Explanation:
The popular glass used in astrology is stained glass which is popular in symbolization of huge astrology figures. As for looking glass, it's more popular in astrological souvenirs or objects.
Answer:
i think answer is pisces horoscope
How do you calculate the speed of a 3.1eV photon and a 3.1eV electron?
Explanation:
We need to find the speed of a 3.1eV proton and a 3.1eV electron.
For proton, using conservation of energy such that,
[tex]\dfrac{1}{2}m_pv_p^2=eV\\\\v_p^2=\dfrac{2eV}{m_p}\\\\v_p=\sqrt{\dfrac{2eV}{m_p}}[/tex]
[tex]m_p[/tex] is mass of proton
[tex]v_p=\sqrt{\dfrac{2\times 3.1\times 1.6\times 10^{-19}\ J}{1.67\times 10^{-27}\ kg}}\\\\v_p=2.43\times 10^5\ m/s[/tex]
For electron,
[tex]\dfrac{1}{2}m_ev_e^2=eV\\\\v_e^2=\dfrac{2eV}{m_e}\\\\v_e=\sqrt{\dfrac{2eV}{m_e}}[/tex]
[tex]m_e[/tex] is mass of proton
[tex]v_e=\sqrt{\dfrac{2\times 3.1\times 1.6\times 10^{-19}\ J}{9.1\times 10^{-31}\ kg}}\\\\v_e=1.44\times 10^6\ m/s[/tex]
Hence, this is the required solution.
Samuel applies a horizontal force of 35.0 N to a sleigh over a distance of 1.50 m along a level surface. Calculate the work done on the sleigh by samuel. show your work.
Answer:
52.5 J
Explanation:
Work done (W) is the product of the force (F) applied on a body and the distance (s) moved in the direction of the force.
i.e W = F × s
It is a scalar quantity and measured in Joules (J).
Given that: F = 35.0 N and s = 1.50 m, then;
W = F × s
W = 35.0 × 1.5
= 52.5 J
Therefore, the work done on the sleigh by Samuel is 52.5 J.
The springs in a car’s suspension have a spring constant of 50 000 N/m. The elastic potential energy store is 0.025 J. Calculate the extension of the springs.
Answer:
1 mm
Explanation:
E = ½ kx²
0.025 J = ½ (50,000 N/m) x²
x = 0.001 m
x = 1 mm
Un automovil circula a 126km/h por una autopista. Su conductor observa que a 150 m delante de el, se encuentra un árbol caído que ocupa toda la calzada. Inmediatamente presiona los frenos con una aceleración de -3,5 m/s². Determinar si logra evitar el choque.
Answer:
El conductor no puede evitar el choque.
Explanation:
Primero, convierta la velocidad del conductor a m / s:
1 km/h = 0.277778 m/s
126 km/h = 126 * 0.277778 = 35 m/s
La velocidad del automóvil es de 35 m / s.
El conductor presiona los frenos con una aceleración de -3.5 m / s² para evitar un choque a 150 m por delante.
Veamos qué distancia se moverá el automóvil después de que comience a desacelerar.
Utilizaremos una de las ecuaciones de movimiento lineal de Newton:
[tex]v^2 = u^2 + 2as[/tex]
donde v = velocidad final = 0 m / s (el automóvil debe detenerse)
u = velocidad inicial = 35 m / s
a = aceleración = -3.5 m / s².
s = distancia recorrida
Por lo tanto:
[tex]0 = 35^2 + (2 * -3.5 * s)\\\\=> 1225 = 7.0s\\\\s = 1225 / 7 = 175 m[/tex]
Esto significa que el automóvil se detendrá a 175 m.
Por lo tanto, a esa velocidad y aceleración, el conductor chocará contra el árbol caído porque el automóvil no podrá detenerse antes de alcanzar la posición del árbol.