Answer:
The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. Newton's first law of motion is often stated as. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.
Explanation:
Answer:
Newton's first law is also called the law of Inertia.
Explanation:
What is inertia ?The property of a body by virtue of which it wants to remain in its position, is called inertia.
Mainly there ae three types of inertia-
Inertia of restInertia of motion Inertia of directionInertia was discovered by Galileo and it was modified by Newton.
What is Newton's first law of motion ?If a body is in motion or in rest, it wants to remain in its position unless any external force is applied.
Thus Newton's first law of motion is also called law of inertia.
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How Can the human ear detect the sound
Answer:
Sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.
Explanation:
The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear. These bones are called the malleus, incus, and stapes.
4. Which type of compound is sugar?
find weight of 45 kg at height 800 km from earth's surface?
Answer:
The weight is 348.4 N
Explanation:
Effect of the Altitude on the Acceleration of Gravity
The effect of gravity decreases with altitude because greater altitudes mean greater distances from the Earth's center.
The practical formula to calculate the gravity as a function of the altitude h is:
[tex]{\displaystyle g_{h}=g_{0}\left({\frac {R_{\mathrm {e} }}{R_{\mathrm {e} }+h}}\right)^{2}}[/tex]
Where go is the conventional gravitational acceleration = [tex]9.80665\ m/s^2[/tex]
R is the Earth's mean radius at the equator = 6,378 Km
h is the altitude.
At a height of h=800 Km, the acceleration of gravity is:
[tex]{\displaystyle g_{h}=9.80665 m/s^2\left(\frac {6,378 Km }{6,378 Km+800Km}}\right)^{2}}[/tex]
Calculating:
[tex]g_h=7.74\ m/s^2[/tex]
The weight is the product of the acceleration of gravity by the mass of the object, thus:
[tex]W=45\ Kg\cdot 7.74\ m/s^2=348.4\ N[/tex]
The weight is 348.4 N
You row a boat perpendicular to the shore of a river that flows at 3 m/s. The velocity of your boat is 4 m/s relative to the water. What is the velocity of your boat relative to the shore?
Answer:
The velocity vBW of the boat relative to the water is 4.0 m/s, directed perpendicular to the current, as in Figure 3.18.
Explanation:
The boat is perpendicular to the shore. Then the net velocity of the boat with respect to river is 5 m/s. The observer feels like the boat is moving slower than they appear actually.
What is relative velocity ?Relative velocity is velocity of an object measured with respect to other object which can be of stationary or moving with a speed. Thus speed relative to another object is called the relative velocity.
The relative velocity is what's the speed for an observer but it differs from actual velocity. Sometimes it may slower or faster depending on the object with which a we are relating the speed.
Given that the speed of the boat = 4 m/s
speed of river = 3 m/s.
Both are perpendicular and the net velocity of the boat is :
r = √(3² + 4²) = 5 m/s.
Hence, the velocity of the boat relative to the shore will be 5 m/s.
Find more on relative velocity :
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4. Why do chemists use relative masses of atoms compared to a reference isotope rather than the
actual masses of the atoms?
a. The actual mass of an electron is very large compared to the actual mass of a proton.
b. The actual masses of atoms are very small and difficult to work with.
c. The number of subatomic particles in atoms of different elements varies.
d. The actual masses of protons, electrons, and neutrons are not known.
Answer:
B
Explanation:
Answer:
answer is B
Explanation:
took the test
A car is traveling 30m/s and slams on the breaks, coming to a complete stop in 5 seconds.
Calculate its acceleration (assuming it was constant). Draw a graph of x-t, v-t and a-t.
Answer:
-6
Explanation:
a=vf-vi/t
vf=0
so that we you subtract vf to vi it will be -30/5=-6
how many seconds are there in 3 days and 36 hours
The answer is 388 800 sec
Answer:
388800 secs
Explanation:
1 day = 24 hrs
so 24 times 3 = 72
and 1 hour is equal to 60 min
108 x 60 = 6480
and 60 secs in a minute
6480 x 60= 388800
Which of the above beak depth vs time graphs represent the change in finch beak depth that would occur due to successive years of above average rainfall?
Answer:
A
Explanation:
I just did it :)
Answer:
It is A
Explanation:
I did it and got a 100
true for false; "Acceleration is inversely proportional to mass."
Answer:
True
Explanation:
F = ma
We can rearrange to a = F/m
So if we increase a and F is constant, then m has to decrease because it is in the denominator.
difference between simple machine and complex machine?
Answer:
a simple machine has way less parts than a complex machine like just one pulley or lever. A complex machine has multiple different parts that lead up to one thing being done in the long run.
Explanation:
Estimate the total mass of ocean on earth
A jet airliner moving initially at 538 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 937 mph in a direction 23 degrees north of east. What is the new speed of the aircraft with respect to the ground. Answer in units of mph
Answer:
The speed is "1447.576 mph".
Explanation:
The given values are:
Direction (north to east)
= 23°
Wind's speed
= 937 mph
Jet moving at a speed
= 538 mph
Now,
The velocity of jet airliner with respect to the ground will be:
⇒ [tex]v=v_{1}+v_{2}[/tex]
⇒ [tex]v=\sqrt{(538)^2+(987)^2+2(538)(937)\times Cos23^{\circ}}[/tex]
⇒ [tex]=1447.576 \ mph[/tex]
On the Moon, astronauts can “bounce” from location to location, but on Earth they cannot move in this way. What physical property changes based on the gravitational force of a planet or moon?
Cody’s car accelerates from 0M/S 245 in/at Northwoods and 15 seconds what is the acceleration of the car
Answer:
3m/s^2
Explanation:
Acceleration is change in velocity / time = 45/15 = 3m/s^2
How long will it take to travel 150 km traveling at 50 km/hr?
Answer: 3 hours
Explanation: 150 km / 50 km = 3 hrs.
a pulling force carried by a rope is called what
Answer:
The pulling force that acts along a stretched flexible connector, such as a rope or cable, is called tension, T. When a rope supports the weight of an object that is at rest, the tension in the rope is equal to the weight of the object: T = mg.
Explanation:
In the real world could the roller coaster car reach the top of the second hill if the second hill were as high as the firsts hill
Answer: No, it couldn’t. Energy leaves the system in the form of heat as the roller coaster cars travel from the top of one hill to the next. The vehicles have less total energy, so the potential energy at the top of the second hill must also be less. The cars wouldn’t be able to achieve the height of the first hill.
Explanation: Make sure to change some of it because it's from Edmentum!!
According to Newton’s First Law of Motion, what will happen to a baseball thrown in outer space
Answer:
The baseball will stay in motion until another force act upon it.
Explanation:
Answer:
Newton's First Law of Motion is that an object in motion will stay in motion unless acted upon by an outside force. Due to the lack of gravity in space, until a different outside force acts upon the object, the baseball will continue to move at a constant speed in the same direction for all time (until acted upon by something else).
draw a diagram of a seismometer showing how the movement of earth is lated into a siesmogram
idk but it seems hard.
Why does an object slow down when going uphill
Please explain properly
Answer:
The change in speed on slopes is due to gravity. When going downhill, objects will accelerate (go faster), and when going uphill they will decelerate (slow down). On a flat surface, assuming that there is little friction, they will then maintain a constant speed.
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The maximum tension that a 0.80 m string can tolerate is 15 N. A 0.35-kg ball attached to this string is being whirled in a vertical circle. What is the maximum speed the ball can have at the top of the circle? 3.74 m/s 9.67 m/s 5.86 m/s None of the above
Answer:
v=5.86 m/s
Explanation:
Given that,
Length of the string, l = 0.8 m
Maximum tension tolerated by the string, F = 15 N
Mass of the ball, m = 0.35 kg
We need to find the maximum speed the ball can have at the top of the circle. The ball is moving under the action of the centripetal force. The length of the string will be the radius of the circular path. The centripetal force is given by the relation as follows :
[tex]F=\dfrac{mv^2}{r}[/tex]
v is the maximum speed
[tex]v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{15\times 0.8}{0.35}} \\\\v=5.86\ m/s[/tex]
Hence, the maximum speed of the ball is 5.86 m/s.
A cyclist rides at a velocity if 12m/s.if the cyclist deceleates a rate of 1.5m/s.how long will take her to reach a velocity of 3m/s?
1)identify your variables -what is what ?
2)pick your equation
3)plug in and solve
Answer:
t=6s
Explanation:
v=3m/s
u=12m/s
a=-1.5ms-²
t=?
v=u+at
3=12+(-1.5)t
3-12=-1.5t
t=3-12/-1.5
t=6s
I am not sure if me is correct.
A scientist who conducted an experiment obtained an unexpected result. What will she most likely do with the unexpected result? leave it out of her analysis and final report stop the experiment and begin again change the procedures and try again develop a new question to be investigated
Answer: stop the experinment and begin again sometimes the result of the experiment may give you unexpected results due to the fact that you may have missed a certain step or you didn't follow the procedure accurately to the dot, hence it's important to redo the experiment and see if every step was followed accurately before you can discard the results or change the procedure.
Explanation:
Answer:
d
Explanation:
HEY CAN ANYONE PLS ANSWER DIS IN YOUR OWN WORDS!!!
Answer:
11. A small number of alpha particles being deflected at large angles suggested that there is a concentration of positive charge in the atom
12. describes properties of the atom
13. 1913
14. quantum state with all observable (atoms) independent of time.
15. the lowest energy state of an atom or other particle
Explanation:
How are the frequencies of the color (visible light) spectrum similar to the Electromagnetic spectrum?
Answer:
[tex]this \: is \: due \: to \: both \: spectrum \: having \\ \: the \: same \: or \: almost \: the \: same \: wave \: speed.[/tex]
A driver of a car traveling at -15m/s applies the brakes, causing a uniform acceleration of +2.0m/s2. If the brakes are applied for 2.5s, what is the velocity of the car at the end of the braking period? How far has the car moved during the braking period?
Given :
Initial velocity, u = -15 m/s.
Acceleration , a = 2 m/s².
Time taken to applied brake, t = 2.5 s.
To Find :
The velocity of the car at the end of the braking period.
How far has the car moved during the braking period.
Solution :
By equation :
[tex]v = u+at\\\\v=-15 + 2\times 2.5\\\\v=-10 \ m/s[/tex]
Now, distance covered by car is :
[tex]s=ut+\dfrac{at^2}{2}\\\\s=(-15)(2.5)+\dfrac{2(2.5)^2}{2}\\\\s=-31.25\ m[/tex]
Hence, this is the required solution.
explain the relationship between physics and biology
Answer:
Biology is the study of living organisms. Physics is the study of matter and the laws of nature to understand the behavior of matter and the universe.
how does shape of object affect friction
Answer:
There are three types of friction.
1. Slanting friction
2. Sliding friction
3. Rolling friction
In the first two types of friction, the body of the object will come in contact with the irregularities on the surface more than in the case of rolling friction, thus a heavy box in square shape will have more friction than a heavy-duty vehicle.
This is also the reason why all vehicles are having wheels as they reduce friction and makes transportation easier and many people suggest to use a small log of wood to be placed on the bottom of a heavy box with flat bottom so it can moved easily due to reduction of friction
You throw a ball straight up into the air at a velocity of 15 m/s. You want to know how high above your hand the ball will be at exactly 2.5 sec after you released it. You must SHOW ALL WORK to receive credit!!! Of the 5 motion variables - Vi, Vf, a, ΔX, and T, identify which one you are solving for and the magnitudes and directions of all of the others that are known: Which of the motion equations is best to use to determine the height of the ball? How high is the ball above your hand at 2.5 sec after you throw it?
Answer:
6.875mExplanation:
Given
Velocity = 15m/s
Time = 2.5secs
Required
Distance above your hand the ball will be at exactly 2.5secs
using the equation of motion:
ΔX = ViT + 1/2aT²
ΔX is the distance
Vi is the velocity of the ball in air
a is the acceleration due to gravity
T is the time taken
Since the ball is thrown straight up, a = -g
ΔX = ViT - 1/2gT²
Substitute
ΔX = 15(2.5) - 1/2(9.8)(2.5)²
ΔX = 37.5-30.625
ΔX = 6.875m
Hence the ball will be 6.875m above your hand at 2.5secs after you throw it.
POSSIBLE POINTS: 5
A student throws a ball upward with a force of 50.0 Newtons. The ball reaches a maximum height of 15.0 meters in 2 seconds and then returns back to
his hands. What is the direction of the acceleration at the top?
There is no acceleration at the top
O The acceleration is directed upwards away from the Earth
O The acceleration is directed downwards towards the Earth
O None of the above
Answer:
A
Explanation:
Given that a student throws a ball upward with a force of 50.0 Newtons. The ball reaches a maximum height of 15.0 meters in 2 seconds and then returns back to
his hands.
At maximum height which is the top, the velocity is equal to zero.
According to definition of acceleration, which says; the rate of change of velocity.
Since velocity equal zero, acceleration also will be equal to zero.
Therefore, there is no acceleration at the top.